0 like 0 dislike
23k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 23k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** *** ** * * * ** * * * %d",&a ,&b );

* **** *** * * ** *** i=a;i<b;i++){
* * * * * * * * * ** ** * * **** *** *** j=2;j<=b;j++){
* * * * ** ** * * * ** ***** *** * * * * * *** * ****** ** * **** ** ** * && i%j==0) break;
** **** *** *** * * * * ** ** ******* * ** * * * * ** ** * * ** * * * if(i==j){
** * * * * * * * ** ** ** * * * ** ** * * **** ** ** ** * ** ** * **** ** ** * ***
* * * * ** **** * * ** * * ** * * ** * * * * **** * ** * ** ** * ** ** * * ** * ** * ** ** *** * ** * * ** *** ** *
* *** ** * * ***** * * * ****** **** * * ** *** * * * ** * * *** ** * ** * ****** *** ** ** * *** * *
* ** *** ***** *** * *** * * ***** * * * * * *** * * * * * ** *
* * * *** ***** * **** * * ** * * ** ** **** ** * * ** * * * * ** * ** ** * * printf(" %d",i);
* **** * *** * * ** * ** * ** * ** **** ** **** * ** * ** ****** **
* **** ** ***** * ****** * * * ** * ** * * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* *** * ******* **
* *** * ** ****** ** * ***
** * **

int main()
{
int i,n,m;
* * *** ** * ** ** *
* * **** * * **
* * * ** ** *

{



* * *** **** **
{
* **
*
}
** *** * *

**


* * * **


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ****** **
* ** *** * * * ** *
* *** * * * *** **

int main()
{
int i,n,m;
*** ** ** * ** ** ** *
** *** * * ** ****** ** ** * *
* * * ** ***

{



* ** * ** ****
{
* **
*
}
* ** * * *****




* * ** *** ** * * *


}}
* * 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* * ** **** *** * ** * %d",&a ,&b );

* * * * * * **** * *** * i=a;i<=b;i++){
* ** **** *** * ** **** ***** * ** ** * * * ** * j=2;j<=b;j++){
**** * * * ******* ** ** * * * ** * * * ** * ** ** *** ** * && i%j==0) break;
***** * ** * * ** ** ***** * *** * * * ** ** ** **** ** if(i==j){
* * ** * * * * ** ** ** * ** * * * * * *** ** * *** * * * * * ***** ** ** ***
* *** * * * * ** **** *** *** * ** * ** ** * ** ** ** ** * * *** * *** ***** * * ******** ***** *** * *** *
** *********** *** ****** * * ** * * * ** * * * * *** *** * * * ** *** ** ****** ** * * * *
** * ** ** * *** ******* *** *** ** * *** * * * ** * * ***** * * ** *** ***** * **
* ** ** ** *** * * ***** * ** ** ***** ** ** ** * ** *** * * **** *** * * * * printf(" %d",i);
* ** *** ******** * ** * * * * ** ** * * * * *** * ** * *** * *
* * * ** ** * * * *** * **** * ** * *

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * * * * * ** ** ** a,b;
**** ** * *** * * * *** %d",&a ,&b );

* ** ** * ** ** * ***** ** i=a;i<=b;i++){
* *** ** * * * ** ** ** * * * *** * * j=2;j<=b;j++){
** *** * ******* ** **** * ** ******** * * *** * ** ** * * * * && i%j==0) break;
* * * *** * ** * * ** ** ***** ** ** ** * * * * ** ** ** * * * * * ** if(i==j){
** * * ** *** *** * * **** * * * ** * * * * * *** **** * * ** * * * * * ** ** * ",i);
* ********* * **** * * * ** * * * * * ** * ** * ** * * *
** *** ** *** * *** *** ****** * * ** *

******** ****** *** **
**** ** **** * *** * * *** ** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** * * * **
** * ** * * *
int main(){
** ** ** * * * * a,b;
* ******** *** ** ** ** * **** ** ,&b );

** * * * ** **** * * *** i=a;i<=b;i++){
** ** * ***** **** * **** * * *** ***** j=2;j<=b;j++){
** * ** ** *** ** * ** ** * * * ** ** * * **** * * ******* * ******* ** ***** * && i%j==0) break;
* ****** *** * ** *** * **** * * *** * ** ********* ** * ** * *** ** ** * if(i==j) printf("%d ",i);
** ** * * **** *** * * * * * * * *
* * *** **** * *****
* ** * ** *** * * * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** *** ** * *** * ** m, n, divider, prime[100], cnt=0, i=0;

** *** **** ******** * ** * * ** **** %d", &m, &n);

** * * ** * * **** * * = m + 1; m < n; m++)
** *** * *** * *
*** * * * ** * **** * * ** *** *** * ** * * = 2; divider < m; divider++)
*** *** * *** ** * ** **** *** * * *** * *
* * *** ** *** ** *** ** ** ** * ** * *** ** ***** % divider == 0)
*** *** * * * ** ** * * * ** * *** **** ** * ***** * ** ** * * * ** *** ** * * ***
* * *** **** ** ** * *** ***** ** *******
* **** * ** ******* ** ** ** *** * * ** ** == divider)
* ** ** ****** * * * * * ** *** *
*** **** * ** * * ** * * ******* * ***** ** * ** * ** * * * ** * * * * = m;
* * ** * * *** ** ** * **** * ** * * ** * * *
* ** *** * ** * ***
*** ** * **** ***** * * ** i<cnt;i++)
*** ***** * ** ***
***** ***** * ** *** **** * ** ** ** ** * * ** ** ** prime[i]);
** * ** ** * **** ***** ** ** ** * ** * +1 < cnt)
* * ** * ** * ** * ** ** *** ** ** ** * * * * **** *** * ** * ** * *** ***** ** * ");
    }

*********** * * ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
* * * * * * ****** ** * ** *
**** * * * ***** * * ** * *** ** * ** ** * * * ** * **
*** * *** **** ** *** * *** * ** * * * *** ** * * * *
** ** **** * *** **** * * * ** * * ** * ** * ** **** * ******* ** ** * **** * * * *
** **** * * *** ** * ** * ** * ***** ******** ** *** ** * * *****
* ** **** * * * * * * * * ********* * * *** ** *** *** *** **** * * * * * ** ** * * * ",i);
** ** ** * * * **** * ** * * ** * **** * *** * ** * * * ****** * *** * *** ***** ** **** * * **
** *** * **** ***** * *** * * ** * ** ** * * * * ********
**** ***** * ** ** * * ** * ** **** * **** ** * ** **** ** *** if(k==0){
***** ** *** *** * * * * **** ** * ** *** ***** * ********* * * * ****** **** * **** ****
**** *** ** * **** * * *** ** * * *** ********** * ** ** * * * *
* * *** ** * * * ** ****** *** *
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * ** * ,&b);

for **** **** **
{
* ** ***** ** * ** ** * * *** is testing\n",i);
* * ** ****** **** * * ** * j=0;
**** * * * * *** * = 1;
**** * * * *** * * (j=2;j<i;j++)
* * * * * *** * *
* * *** ** **** *** * ** ** ***** **** * * ***** ** *   %d is mode\n",j);
** * * ** ** * *** * ** * *** * ** * * ** reminder=i%j;
* * * ** ***** ** ** * *** ****** * ****** * ** (reminder == 0)
* * * ** * * * ** ** ***** * ***
* * ** *** ** * * * * * * ** ** ** *** *** * *** *** ****** * *** ** * * **** * * ** ** * * * **
* ** ** * ***** ** *** * * **** * **** * * * ***
* ****** ** * * * * ***** * * * * * *** * ** ***** ** ** *
**** * ** ** ** **** * * ** * ** *** * * *** *
* ** * ** * * ** ** * **
** * * * ** ** *** * **** ** (flag==1)
*** * * ******* * * ** * *** ** * * ** ***** * * * ** * *** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 15.7k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 19.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users