0 like 0 dislike
24.8k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m),找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited

edited by | 24.8k views

99 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
* *** * * **** **** * ** * ** * * %d",&a ,&b );

**** * *** * ** *** * ** * i=a;i<b;i++){
** *** * ** **** * ** ** * ** * * ** * j=2;j<=b;j++){
* ** * * * **** ** ** ****** * ** * ** *** * ** ** *** * ** * * * ** && i%j==0) break;
* * ** ** * ** *** **** * ** ** *** * * *** * * * * **** *** **** if(i==j){
* * * * **** ** ** * ** **** ** ** *** * *** ******* ** * ** *** * *** ********** *
***** * ** * **** * * * * * * ****** * ** ** ** ** * ** * * ***** * ** * * * * ****** ******* * ** ******* * ** ** * * * * ***
** * *** **** * ******** * * * * * * ** * *** * * * ** * *** * *** *** ** * ** *
* **** * * ** * ** * * ** ** * * *** * * * ** * ******* ** ** * * ** ** * **
***** ** * * * ** * * ** *** * *** ** * * ***** ** ****** * **** * ** **** printf(" %d",i);
* ********* * *** * ** * ** *** *** * ** ********* *
** * * * **** ** **** * * * ** ** * *****

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ***
** * ** ****** ** ***
** *** *** **

int main()
{
int i,n,m;
** * * * ****** *
** * * * ** *** * * *
* * **** *****

{



**** * ****** * *
{
* * *
*
}
** * **** * *

* *


* *** **** ** ***


}}
**** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * *
* * * ** ** ***** * * *
* **** * * **** **

int main()
{
int i,n,m;
** **** *** * *
** ***** ** * ** **
** ***** *** ***

{



*** * **
{
****
****
}
* ** * * * *** *

** *


** *** ** *** * ** *


}}
** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
** ** ** * * * * * ** *** * ** %d",&a ,&b );

* ****** *** ** * i=a;i<=b;i++){
* * *** * * * * *** * * *** *** ***** ** j=2;j<=b;j++){
** ***** * ** * ** ** * * * * **** ** *** * *** * * **** ** * * ** && i%j==0) break;
*** ** * ** *** ** ****** * ** *** ** * * *** * * * ** * ** if(i==j){
* * * * ** * *** ** ** *** ** * ** ** ***** * * ***** *** **** * * * * ** * * *
* ** * ** ** *** * ***** *** * **** * **** * * ** ****** * ** * * **** * **** ***** * ****** ** *** * * ** * ***** ** *** *
** * ** * **** * * ** * *** *** * *** * * ** ** * ** * ** * *** *** ** *** ** ** ** * * * ** *
** * * ** ***** ******* ** ** ** ** * * * **** * ** * * * ***** ******** **** **
* ***** * *** * * * * * * ** * * ** *** *** ** ** * * * * ** * * * ** * ** * * * * printf(" %d",i);
** * * * ** * ***** ** * * * ** *** *** ****** *** **** *** ** ** * **
* * *** * * * * * **** ** * *****

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
int main(){
* * *** ** ** *** a,b;
* * * * * * *** ****** * %d",&a ,&b );

** * ** * ** ** * ** * i=a;i<=b;i++){
* * * *** * * * * *** ****** * * * ** ** *** **** ** j=2;j<=b;j++){
** ** ** * * ** * * ** ** * **** **** ** *** * ** **** * * *** * * * && i%j==0) break;
* ** * * * ** *** **** ******** * ** * ** * * ** ** * if(i==j){
* * * **** **** ** *** *** ****** * ******* * ** * ** ** * ** * * * * * * ** * * *** *** * *** *** * *** ** ",i);
***** * * * ***** *** * * * **** ** *** ***** *** * ** * ** * ** *
*** * * * *** * * ** ** ********* * *

* * **** *** * * **
* *** **** ** ****** ****** 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** ** **
** *** * * *
int main(){
* * * ** * * ** *** * * a,b;
**** * **** * * * * * ** ** ****** **** ,&b );

*********** ** ** * i=a;i<=b;i++){
*** * * * ** ** * * **** **** ** j=2;j<=b;j++){
** **** * * * * * * * *** * * * * ** * * * **** * **** ** * ***** * * && i%j==0) break;
* * ** * * **** * * *** * ** ***** ***** ** ** * * * ** * * if(i==j) printf("%d ",i);
* * **** * *** **** **** * ** ** ** * ** * * ***
** * ** * **** * * *
* * * * * *** * *** * 0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * ** * * *** * m, n, divider, prime[100], cnt=0, i=0;

* *** * * ****** * * * * ** %d", &m, &n);

** ** *** * * *** * * ** = m + 1; m < n; m++)
***** * * * *
** * ** ** * * ** ***** * ** * * ** ****** = 2; divider < m; divider++)
*** * * ** *** * *** ** * * * * * * * * * * **** **
* *** ******* **** *** * * ***** ***** * ** * ** ** ** * * * **** * *** * * % divider == 0)
* ** * *** * *** * * ** ***** * * ** * * ***** *** **** * ** * ** ** * ********
** * * * * ** * ** * * * * * *** *
* ** ** *** * *** ** *** ***** * ** * *** == divider)
* ********* * ** ** ******** *** ** * *
****** ** ** * * ** ** *** * * * ** *** *** * *** * *** ** * = m;
* ** * ** *** ** ** * * * * * *** * * * **** *
*** * * * * ** **** ****
** ********** * ****** ** i<cnt;i++)
**** * * * *** *** ***
* * *** ** * * ** * * **** * ** *** * ** * * * * prime[i]);
* * * * *** ** ** *** ** * * ** * *** * ** +1 < cnt)
** * *** ** * * **** ***** * ** * *** ** * * **** ** * * * ***** ** * ** ");
    }

* ** **** * **** * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 0
Nice haha
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*** ** * * * **** * * ***** ** ** * *
**** *** * * * ** * **** * ****** * * ** ** * ****** *
* ***** *** * * * * * ** ***** * *** *** ****** ** * ** * *
*** * * * * **** ** * ** *** ** *** * ******* * * * *** **** * ** * ** * ****
* * *** **** * *** * ***** ** * ** ***** ** * *** * ***** * *
* * * * ** *** * *** ** *** * * * *** * *** ** ** * ** ** * *** ** * * * * ** *** **** ** ** * ",i);
*** * * * *** ** * * * * ** ** ** * ** ** * * ** * ** ** * * * ** *** * ** * * * *** ** *
* ** ** ** ** *** ** *** * *** * ** ****** ** ** ****** *
* * ** ** * **** * *** *** ** ** * * * * * ******** * * if(k==0){
* * **** * ********** ** *** * * **** **** * ** * * * *** * ** * * * * * ** *** **** * *** * *
** * ** *** * *** * ** * * * * ** * ** * *** * ** ****** * * * ** **
* ** * *** *** ** * * *** ***** * ** **
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d * ******* * ,&b);

for ** * ** * * *
{
* ** * * * ** ** ** ** * * is testing\n",i);
**** * **** * j=0;
* *** * * * * *** ** ** ** = 1;
* ** ** * ** * ***** (j=2;j<i;j++)
*** ***** ** ** * ****
** *** * *** * * ** ** * * * * ** **** * ** *   %d is mode\n",j);
* * * *** ** * * ** **** * * * *** reminder=i%j;
** * * ****** ** * ** ** * ****** **** (reminder == 0)
** * * *** ** ** * ***** * ** ** *** * *
* ** * * ** ** * * * * **** * ** * ** *** ** *** * * * * ** * ** * * * *** ** * * *
* * * * ** * * * * * * * * *** * * *** *** * ** ** ** ** *
* * ***** ** * * * * ****** ** * * *** ** ** * *** ** ** ** *
** ** * * *** ** ** * ** ** *** ** ** * * **
* * * * * * * * * *
*** ****** ****** ** * * * (flag==1)
* ** * * ** * ** * * ** * *** *** ** ** *** ** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.10
©2016-2026

Related questions

0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 16.9k views
0 like 0 dislike
93 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 21.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users