11-01 Exercise 1: Find out all prime numbers between n and m

0 like 0 dislike
21.3k views

Write a program that get the input of two integers n and m(n < m). Find out all prime numbers between n and m (not include n and m), then display them on the screen.

寫一個程式 輸入兩個整數n和m (n < m)，找出所有n到m之間的質數(不包含n和m)。

Example input 1

1 10

Example output 1

2 3 5 7

 

Example input 2

10 20

Example output 2

11 13 17 19

 

[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 29829 - Available when: 2017-11-02 18:00 - Due to: Unlimited
edited by | 21.3k views

99 Answers

0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
 *    *     *  * *  *  *****   *  * **  * *** %d",&a ,&b );

* ***    ** *  ***** *  * ***  * i=a;i<b;i++){
*  **** *      * *** **** ***   * ** **    * *      ** j=2;j<=b;j++){
   **  * *   * * * *  *   ***   *  *** ***       *     *** **     ** *     *  *  *  && i%j==0) break;
  *******     *   *  *  ** * *  *    ** ****  ******    ** *** * **      *     *   * if(i==j){
**     **** **  **** **  *   *  *     * **      * * * **** **  *   * *   * **  **  * *   ** ** **  ******   *  *
*  ** ***** *** ** * **  *  ** ** *    *    * *  *   *  *  ********** * ***  *** ***     **   ** * ** *****  ** *     * *      * * *     *  * * **    *     *   
*  *   * * *      * * *  ** ****** *  *******     * *** *  **  **  *  **** **  *   **   * * *   ******  * **    *****   **  *  *    * ** * 
**    *  * *** *     **  ** *** ***** * ** ***   ** *   *   ****** ** *  *****  * ***    *   **    ***  * *   
***  *  ** ** * * * ****   ******  *  *** **  ****  * * **  *  *     * * **       *** *    *   **  *  *   ***  printf(" %d",i);
 *  ** ** *  * *   *** * **** ***** *** ******* ****** * *      * ** **    * *  * 
 * *   *  *  * **  **** ** * * ***   * *   *     *  

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 ** ***  * ** ****** * 
*     * * **** * **
** *** ***** *   *  

int main()
{
int i,n,m;
  *  ** ** * * * *****  **
**  * * *  *  * **   ****  **
 *****    * **    **** 

{



*  *** ** * *     *
{
*** **  *
 **  *
}
******  *** ***

  * *


 ******* *** *  *  * 


}}
 *  0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*   *  * *** *
  ** **   * *   **    **
   * **  *  * *  ***    *  

int main()
{
int i,n,m;
***   **  **  *   *   
  **     ***  ** ***     **     * *
**    * **** *****   

{



 ***  **** ** *  * * ***
{
 * * *
 * 
}
*  **  **    * *** 

*   


**     * *   * *   *  *


}}
 * ** 0;
}
answered by (-336 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
    int a,b,c=0;
     * *   * **  *  ** * ***   *  * * **  %d",&a ,&b );

*        ** * **** **     *   **   i=a;i<=b;i++){
* * ** ** * * ***** * * *   * *   *  * * *  **   ****  *  j=2;j<=b;j++){
 * * * * ******  ******** *    **  * *     *  *   *  * ***  ***   * ***      *    ** && i%j==0) break;
***  *  ***  **    * * * ** ***** ** ****** *  * * ** ***  *  ** ***  ****   *    *  **  if(i==j){
* *****        ****  * *  ***  *  *** ** *   * *     ** ******  * ***  ***  * *   *   *  * *   ** ******  * ***
*  **    **  *         **    ** **** * * **   ***   ** *  *   * * ***   ****  ** * * **   * * **  ****** * *  *  * ***  * ******  *** *  * ***  **        **  *
**** **  *      ***  * ** *  *  *  *  **  *     *  ** *****    *   * ***  *  *  *  * * *      *******  *  *  **  ** *  **   * *  *  
* **      * ** * *** * *    * ** *  ***      * ** **  * *  *  * ***** * *        * ** *    ***     ***      
* **   ***    * * * *   **    ** **  ** *****   ** ***** *   * ****** ** *  *  ** * *  *** *    ** **   * printf(" %d",i);
***    *  **** *    * * *  * **   ** ***      ** *   * *       ** *   **    * *  *** 
    ****    **   *****  * *****  **  ** ** *** ** ****

    }

    return 0;
}
answered by (-116 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>
int main(){
* *  *** **** **  * **  ** ** a,b;
 *   * ******   *  * ***    * **  ***** **   %d",&a ,&b );

    *   * * * *    **  * * i=a;i<=b;i++){
*** *   *    ** * * *  **    *  *****  *** ***  *    * *  *  j=2;j<=b;j++){
  ** ***   *** **** **  **     ***** ** * *  *** *  * * * ****** ** * *    *** **** *  && i%j==0) break;
** *  ***  * **   *  *  *  ********  *     **  ***  ***  ** **** *** * ***   *** *** *** if(i==j){
* * *   *      *  *  ****  ***  ** **     ***   ****  *   *  * * ***   * *    *   *    ** *  *****   ***** * *     *      ** ",i);
 **  **  ** ** ***        **   * * **    * * ** *** *  * *  * ***** **  ** ***  * *
  * *   ****  * * *   **   ******  * ** ** *  ** *  * * 

 * ** *** * *  *   *   ** ***
* ** *** **** ** ****  *   ****    0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
*  **   *   *  *  **  
   * *  *****      ** * * 
int main(){
*   * ** ***    * *   * *  * *   a,b;
*   * * * ********   *** * ** **   *  *  *     *   ,&b );

** *** **  * * * * **** ********    * i=a;i<=b;i++){
  *  * *    *** * **  **   ***  * **   **** ******     *   * j=2;j<=b;j++){
  *      * * * * *    ***     **   *** * *  *   *  *     ***   * ** * *  **     *   **** && i%j==0) break;
   ***  *   * * **  *  *  *  * ****   ** *  **** *  *   *  *****  **    *  * *      * *  if(i==j) printf("%d ",i);
   ** * * * ** ** ** **  *   *  ** ******  *  * * 
***  **  ** ****    ** * * *
*** **  *  ***  * **     **** ****   0;
}
answered by (-116 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***  **** * * ** *   *** * **** m, n, divider, prime[100], cnt=0, i=0;

**  * **    *  *  * *** ***  ***  **** %d", &m, &n);

   **** ****   ** **  * * * *** = m + 1; m < n; m++)
   **  ****** *   *** * * 
 *  ** * **   * ** **  *     *  **  ***  *** **  ***     ***** *  **  = 2; divider < m; divider++)
* * *   *** ** * *  * * ****   * ******  **  * *  * 
** *  * *   ** * * * *  **  * ** *   *****  **  *** *** * * **  *     *  * ***    % divider == 0)
*     *  ****  **  * *  **   * ** ** ***    **** **** **   *   *****  * * * * *  ****** *****  * * * ***   * 
*  * **    *     * *    ******** *  *  * * * * *** * *
 *      **  *****  *  *  *  **   * *      *  *   *   ***  *  == divider)
    *** ***    **** *  *   *       *  *  * *   *** 
    ****     *  * ** *** *  ** ****      ** *** * *    *  *      *    * * ** * **  *  = m;
**  *   * **   ** * ** ** *  ** * *  *** *  **   *** *  *   *
 **** *   **  * * * * ******
** *  ***  *   **  ***** ** i<cnt;i++)
 **  *  *  ********* * **
***** *    * **         * *   *   ** *  **   ** **   *   * ****  *    *      prime[i]);
**** *   *****  * ** *****      * *  *  *   **  **  ****  * +1 < cnt)
* * **    *  ****  * * *   ** *** *  *   * *  **   **   * **   *******   *    * ** *   ***** ");
    }

 * * *** *** *** * * ** * *  * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
commented by (4.3k points)
0 0
Nice haha
commented by (12.1k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
    int n,m,i,j,k;
    scanf("%d %d",&n,&m);
*      *  **     *  *  *  * * *  *** *** ** ***  *
* *  ** * *   *    **********   * * * ***  *  * * **  **** *       * 
*   *** *  * *** **  ** **   * *** *   * *   * **** **   *** ****   ** * *   ***
  *    * * *    *   * *   ** *  *  *  ***      * *  **   ** * *****  * *  ***  * *  *  * * **** ** **   *  * ***** 
*  * *    *****  * **     *  ***    *   *    * ** **  * *** * *  ***   **     *    *
*  ******  *** *    *  *   ** * *  *** ****      * *  *  * * * ***   * ** **        **  * *  * *   *  * * ** **** *** ** *  ** ",i);
* **** **** *** ** *   *****  * ***   *      ******    * *** **** * ** **    * ***** *      ********  ** *****
   ** *    ****   ** ** *** * *  ** **** * * * **   **    * *     *** * * * * * **
* * ******    *  ****  ** *   ****   * *    ** ** ***  ** *      *****  **   *  if(k==0){
  ** **  ****  * ** *    * *  *** *   * ***  *    *** **  *   *** ** **   **** *  *  * **  *         *** 
 *** *  ***  ****   *   *  *** *****   ** ** * *  *  *  ** ** * ** * **   ****  *
    *** ** **  **   ****** *   ** * *  * ******      **
    }
    return 0;
}
answered by (54 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(){
int i, a , b;
int flag;
scanf("%d     * **** **** ,&b);

for *  ****  **  *
{
 * * **** *  *  ** **      ***   **    ** is testing\n",i);
*** **    ***  *** **  **      j=0;
 ** **** * * *  *   **** ******* *   = 1;
  **  * *   *  ** **   ** * (j=2;j<i;j++)
*    * ****** * ***   **  
  *      **  ** **** ** ****** *** *****  *   * * *   ****    %d is mode\n",j);
*****  * * *** *  ***  **    *  ** ** * ****** reminder=i%j;
* ***  * ****  **  **   * ****   ****** ** ***** ***   **  (reminder == 0)
 ** ** *        * * *     *  **   *  *  ****  ** * ** ***  **
 * ** **   * * **    *   ***** **  *     ** **  ***        ***** * *** * * **    *** ** **  * **** **  **  * *      ***    *   
**** * *** * * **  *     ** *  ** ** ****  *** * **  *  ** *   * ****** *  ****
***    **  **  * * * ****   * * * ** *     * *   * *  ** *  ** *** **  *** ***     
**  * * ***** * *  **      ***  * ** **  **  * *  **
**  ******  * ***  **   * * **
 **   * ***** *   *  ****    ** (flag==1)
***  *** * *  * * *  * ***    * *** ***    ***  *  **   **  ** **** ",i);
}

return 0;
}
answered by (-141 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.247
©2016-2025

Related questions

0 like 0 dislike
72 answers
11-01 Exercise 2: Find out all the factors of N
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 14.7k views
0 like 0 dislike
93 answers
11-01 Exercise 3: Fibonacci numbers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29830 - Available when: 2017-11-02 18:00 - Due to: Unlimited | 17.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users