0 like 1 dislike
14.7k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.7k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** *** *
int main()
{
* * ** * * * * * ** ** *** ** * ***
** * * ** * *** *** *** * %f ** ** * ***** ** *******
* * ** * * ** * = (b*b-4*a*c);
* ** * ** * ******* * * = (-b + sqrt(D))/(2*a);
*** * ** * * ** * ** ** * ** = (-b - sqrt(D))/(2*a);
* * *** * ** **** **** *** = -b/(2*a);
** *** * ** * ** ******* **** =sqrt(-D)/(2*a);
**** ***** * **** * **
** ******* * *** * *
* ***** ** ** ** ** * * *** ** *** ** ** * *** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * ***
** ** **** ** * ** *** * * **** * * * *** = %.2f\nx2 = %.2f",x1,x2);
** * * * * * * * *

* * * ** * ** * * ** ** if(D==0)
* * * ** *****
* * ** * ** * * ** * * * * ** * ** ** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ******* ***** **** * *** **** * * ** * ** ** * ** *** ** = x2 = %.2f",x1);
*** * *** ** * * ** *
***** * *** ** ** * **
***** ** *** * * * *
* * * * * ** ** *** *** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** ** ** * **
** * ** ** * **** ** ** * * *** * *** ****** * * ** * = * ** * * * *** ** *** *
* *** * ** ** * *** **** ** ** ******** *** * **** * = *** * **** **** * * ** *
* * * ** ** ** ** **
* * **** ** ** ** **** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ** ****

int main()
{
* ** ** * * * * * * ** **** n, i;

* ** * **** * * ** * ** * * * * *** * &n);

** ** * * * * * **** * * = 1; i <= n; ++i)
***** * ** * *** ****
* ***** * ** * * * * * ** **** *** ***** ** ** % i == 0)
** * * ** * *** ** * * * * ***** ** *** ***** * * * ** * * * * * ** * * ", i);
* ** *** ** ** **

* ** **** * * *** **** ** *** *** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
****** **
* ** ** **** * *

int main()
{
** ***** * *** **** * ** * * * ******
* *** * ****** * * * ** ** ** *** ** * * * *** ** *
* ** *** ** * * * = **** * *
** * * **** ** ** ** * * *
* ** *** * * ***** **
** * * * * * * * *** ***** **
**** **** ** * * *** ** = -b /(2*a);
** * ** * ***** **** ** * ** *
* **** ** * ** ** = (-b)/(2*a);
* ** *** ****** *** ** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * * *** * *** * * *
* * ********* *** * **
* *** * * * ** * * if(D==0)
* **** * * *** ****
* * * ** * ** ** = (-b + * * *** **
* *** *** * * * = (-b - * * *
* * * *** **** *** *** * ***** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * * * *
** ******* *** * * *
* ** *** * * ** ** if(D>0)
**** * **** * *
***** * * *** ** *** * ** = -b/(2*a);
** * * ** * * ** = (-b + *** **
* ** * ** * * * * = (-b - ** *****
* ** * **** * ******** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** * ** ** ** *
*** * *** * * ********
**** ** ** ** * **** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ** ***
#include * ** * **
int main()
{
* *** ** ** * * ** * ** ** a,b,c;
** * * * ** * * ** **** **** ** * *** *** ******** * * *
*** * ** **** * ****** *
*** **** **** * ** * ** * ** ***
* ** * * *** **** * * ***
** * ** * ****** * **** * ** * ** * * * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ******* * * + ** * * ** * *** - * *** * ** * **
** ** * * * * * *** ****
*** * * ****** ** *
* ** * * * * ** * * * if (b*b-4*a*c==0)
* * * ** * ** **** *** * *
* ** * ** * * * * * * **** **** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** ** **** + *** ** * * *
** * ** * ** * * *
** * * *** **** **
* * * * ** * * **
* * ** * * * **** *
* * *** ***** **** * ** ***** ***** * * * * ***** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * * ****** ** * ** **** * *** ** * ** ***
** * * * * * * ***
*** ** * *** ** * ** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** * *
#include *** * * * *
int main()
{
* * ******* ** ** ** * a,b,c;
* * * ****** ** *** * * *** * **** * ** * * * **
* * * **** ** * ** *
* * *** **** * *** * * * *** *
*** * * ** ******* * ** **
* *** * ****** ** *** ** * ** * * *** * * ** *** ** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** ** *** + ** *** ** * * - ** * * * *
** * ** ******* *
** ** ***** ** * ** *
* *** **** * ** if (b*b-4*a*c==0)
** ** ** * * ** ***
*** * ** ** * * * * ** **** * * ** * * * ** ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * ** * + * * * ***
***** *** ** * * * * *
* * **** * ** ** **
* * *** * ** * * * * * **
* ***** ** * * **
* * * ** *** * * * * *** ** *** * *** ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * * ** * *** ** * *** ** ******** * *** * ***** * *
*** ** *** * * * ** *******
**** * * * * *** * ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** **** ** * ** *** * * *** a,b,c,d,x1,x2;
********* *** *** ** * * ****** * ** ** * **** * ** * * **
** * *** * ** * ****** **
** *** *** * ** * * * ** * * *
* * * ** *** * * * * * * **
* *** ** *** **** ** * *****
*********** * ** ** ** ** *
** * * ** *** * ***** ******* *** * * * ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** * * **
*** *** ** * * ** ** * * * * ***** *** * ** * * * ** = %.2f\n",x1);
* ***** * *** * ** **** **** * *** *** * * * ** ** * = %.2f",x2);
* ** ** * * * *
* *** *** * * * **** * if(d==0)
* * *** * * ****** *
**** ** * ** ** * ** ** * **** * * * * * *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * *** * ** * ** * ** * * *** * *** = x2 = %.2f",x1);
******* *** * * ****
* * * ** * * * * *** **
* ** ***** *** ** ** *
*** *** ** * ** *** **** ** * * *** * * * ** *** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * * *
* ***** ** *** ***** * *** * ** * *** ***** * * = *** **** *** ** * * *
**** * ** **** * * *** * * *** * * * * * * *** ** * * * = * ** ** ** ** * ** * ****
** ** **** *** ** * **
* *** **** * *** * * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** ***** *** *** ** *** * * * ** ***** ** * * * * ** ** ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* *** ****** ****** * * ** ** * ** ** - (4*a*c);
*** ********** * ** *** * * * * ** ** **
* * ** * * * * * ** ******* ** * * * *** * *** ** * *** ** * ** * * ** ***
* * * **** *** ** * * * ** * ** * * * ** * * **** ** (-b+spD)/(2*a);
* * * ** * *** *** * * * ** ** * * *** * * ** ** ** (-b-spD)/(2*a);
** * * ****** ** **** ** * ** ** **** * * * **** *** ***** ** (x1==x2){
* ** * ** * * * *** ** * **** ** * *** ** * ** * * * ** * * * *** * * ** ** *********** * * * * **** * **** * * ** ***** X=%d\n", x1);
*** *** *** * ******* **** * **** *** * ** ******** * *
* * * * ***** ** **** * ** ** * * * * * ** ** * * {
* * * ** * * ** ****** * * ** * * * * ** ******* ** ********* * ** * * * ** * * ** ** * * * * ** ** ** **** *** ** ** ** X=%d或%d\n", x1, x2);
** ** * **** * * ** ** * *** * *** * * * * * * *** * * *** ** * *
        }
******* *** ****** **** ** **** * *** * **** * * ** if(D==0){
* ** ******* ** ** * ** * * * * * * ** * * ** ** * ** *** **** * (-b)/(2*a);
**** ** *** *** *** * * * ** * ** * ** **** ** * ** * ******* **
* ** * * *** * * * ******* ** * ** *** * * * ****** ** * * ** *** * * * **** *** ** ******* * * X=0");
* * ** * * * *** ** ** ** *** ** * **** ** ** * * * *** * ** *** *
** * ** * * * * * ** ******* ** ** ** * * * * * *** ** * ** **
* * * * * ** * *** * *** *** ** * * **** **** *** * ****** *** *** * ** ** ** ***** **** * * *** * X=%d\n", x1);
* ****** * ***** * ****** * * * *** * ** ** ** *** * ** ** ** *** * **
        }
** * **** ** * ** * * ** ** * * ** **** *****
* **** * ** * *** * * * ** *** *** ****** * * ** * ** * ** ** * *** *** ** * * * * * ** * ** ** *** *** * ** *
* ** ** * * * * **** * ** * **** *** * * *
    }
* *** ** *** ** ** **** * * * * * *** ** *** * * **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
******* * * * *** *** * a,b,c,D;
* ** *** ** ** ** x1,x2;
* ** * * * * *** * %d *** * ** * * * ****** **

* * * ** *** ******** * * * *
*** ** ** * * ** * ** * ** *
** *** *** * ** ** ** *****

* ** * *** ***** **** ** ** * A,B,C;
***** * * * * *

* ** * ** * * ** ** * * **
* * * * ** * **** * * * **** ****** * ** * *** * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * * ** * **
* * ** * * ** ***** * ** ** * * * * *** * ** ** * * **** * = %.2f\n",x1);
*** * ** ******* * * ** * * * * * * *** ** * * **** **** = %.2f",x2);}

* ** * **** ** **** if(D==0)
**** * * ** ** * ** ******** * * ** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * ** * * ** * **** **** *** * * * ** ** ** ** * * ** * * * = x2 = %.2f",x1);}

* *** **** ** ** * if(D<0)
* *** ****** ******** ** *** * ***** ** * ***** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and ***** ** ***** *
* * * **** * * *** *** *** *** * * ** * * ** ** * bb,d,dd;
* * ** * * ** *** ** ** ** * * * * ******* *
*** *** ** *** *** ** * * * ** ** *** ** ** * ** * * ******* * ** *
**** * ******* * ** * ** ** **** * *** * * **** * = * ********* *
** * * * * ** ******* * * * * * * * * * ** ** * * ** * * = * ** * **** * ** *

** **** **** * ***** * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * *** * ***
int main()
{
* * ***** * * *** ** * *** * * ***** * *** *
* ** * * ** * ***** ** **** * %f * * * * * ** ** * * ** ** *
******** * *** *** * * = (b*b-4*a*c);
** ** ** *** ** ** ** = (-b + sqrt(D))/(2*a);
* * * * *** * * = (-b - sqrt(D))/(2*a);
* ** * * ** ** ** * = -b/(2*a);
** *** * *** ** ** *** =sqrt(-D)/(2*a);
*** * * ** * * ** * * ****
* ** ** * ** *
** ** * * ** * ** * *** **** * **** * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * * *
* * ** *** ** *** ** ** ** *** **** * * * * * ** = %.2f\nx2 = %.2f",x1,x2);
** ** * ** ** ** ****

* *** ** ** * * if(D==0)
** * * ** * ***** *
*** ** ** * * ** * ** ** * ** * * ** * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * * **** * * ** ***** ** ** ** * * ** * * * = x2 = %.2f",x1);
* * *** * ** * ***
* ** ** ** **** * *
** ** * * ** **
** **** ** * ** * * * * ** ** * * ** *** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ***** ** ** ** * *
*** * ** * * ** * *** * * * * * ** * ** * ** * = * **** ** * ***** ** * **
* * **** * ** ** * * * * ***** * *** * ** ** ** ****** = ** ** **** *** ** * *** * *
* ***** ***** ** * *
*** **** *** * * * * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ** *** * ****
int main()
{
** * *** *** * * *** *** ** ** **** * *
********* * * * * ** * ** * * %f *** ** *** * * ** **** ** **
* *** *** ** * * = (b*b-4*a*c);
** **** *********** * * = (-b + sqrt(D))/(2*a);
** * * **** ** ***** * = (-b - sqrt(D))/(2*a);
* * *** *** ** * **** *** = -b/(2*a);
* ** * * ** ** * ** * *** =sqrt(-D)/(2*a);
** ** ** *** * **** * * * *
** **** ** * * ** **** *
** *** ** ** ** * ** * * *** * * * * * * *** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ***** *
** * ***** * ** *** ** * * ** *** **** * **** *** = %.2f\nx2 = %.2f",x1,x2);
*** ** * * * * *

* *** * *** * **** * ***** if(D==0)
***** ** *** * * * **
* ** ** * * ** * * ** * * ** ** *** **** * ** **** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ***** * **** * ** ** ** * * ** * ** ** * *** = x2 = %.2f",x1);
* *** * ** * * ** *
** * * *** * * **** * * *
* * *** ** * *** ** *
* ** *** ****** ** ****** ***** ** * ** * ***** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * ** * * ** *
** * ** ** * * ******** *** * * * *** ** * ****** * = * ***** *** ** * * ** *
* * * * ** *** ** * ** * * ****** ******* * *** * * = * *** * * **** * * * * **
** *** ** ** *** * ** * *
** * * ** ** * ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.239
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users