0 like 1 dislike
8.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 8.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** ** * * ** *
int main()
{
* ***** * ** * ** * * ** ** * * *
* * * * ** * ** ** ** * * %f *** **** *** ** * *
**** *** * ** *** ** = (b*b-4*a*c);
** ******** * ********* ** = (-b + sqrt(D))/(2*a);
* ********* ** ** * ** * * * * = (-b - sqrt(D))/(2*a);
*** ** * * ** * * ** ** * ** ** = -b/(2*a);
***** * * **** * * ** =sqrt(-D)/(2*a);
* ** ** * * * * * ** *
** ** * * ** ** *
* * **** * ** * * * ********* * * ******* *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and **** ** ** * *
* * * ****** * * ** ****** * *** *** **** ** * * * * = %.2f\nx2 = %.2f",x1,x2);
* ******* ** ** * * * *

** * * ** * *** if(D==0)
** * * * * * *** ** * *
* ** *** * ** * * *** * ** *** * ** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ***** *** * * *** * * ****** ** * * * * * ** * = x2 = %.2f",x1);
* **** * ** *** ** * * *
** * ** * ** ** *** **
* * * * * * ** *
* * ** *** *** * *** ** * * * * * * *** *** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ** *
* ** * ** * *** * * * *** ** * ****** *** * * * = * * **** ** * * * *** *
* * ** * ** *** ** * ** ** * * * ***** ** * ** = * ** * ** *** * *
* *** *** * **** ***** *
** ** ** * ** * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *

int main()
{
*** * * * *** * * ** ** n, i;

* * ** * ** * ** *** * ** * * * ** ** * &n);

* * *** * * * ** ** * * = 1; i <= n; ++i)
* * * *** **** ** *** ***
*** * * **** * ** * * * * ** *** ** ** ***** % i == 0)
** ** * * * * * * * * **** ** * * * * ** * * ****** * ** ** ", i);
* * * * **** **

** * ** * *** ** *** ** ***** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ** * * * *
** ** * * * * *

int main()
{
*** ** ** *** * * * * * * *** ** * *
* ******* * **** ** * ** ** * ** ****** ** * * * * ** * ** ** *
* * *** * ** *** ** * = * ***
* * ** *** ***** ** * ** ** *
***** ***** *** * ***** ****
** *** * * * * *** ***** *****
* * * ** *** * * ** = -b /(2*a);
* * *** * * * ** * * *** *** ** * *
* ** * * ** ** ** ** = (-b)/(2*a);
* ** ** ***** **** * * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** * * ** *
** **** * * ** **** ****
***** ** ** * *** ** * if(D==0)
***** * * ** ** *** * * *
* * * * ***** = (-b + ** *
* ** * **** ** **** * = (-b - * *
********** * * *** * * *** ** ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * ** * *
*** ** * *** *** * * *
********** ** * * ** * *** * if(D>0)
* ** ** * * * *** ****** *
* ** * * * * * * ** *** = -b/(2*a);
* * *** * *** * * **** = (-b + ** *** **
*** * *** * * * * ** **** = (-b - * **** **
* * ** ** * * ** * ** ** * * ** *** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * ***** **
** * *************** ** **
*** *** * * ** ** * ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * ****
#include **** ***
int main()
{
* ** ***** ** *** * a,b,c;
** ****** * * ** *** *** ** * * * ** **** * * * * ** * *
* *** * * * ** **
* ** * ** * * ***** ** *
* * * * * ** ***** ** ***
** * ** ** * ** * ** * * ** * ** * *** * ** * * ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * **** * * + ** * ** ** - * ** ** *
** ** * * *** * *** *
** * ** * * ***
**** * ** * *** * if (b*b-4*a*c==0)
* ****** ****** *
* *** *** * ******* * * ***** ** * *** * * *** ** * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * * + ** * *
*** * *** ** * * *****
**** * *** * * * *
**** * *** ****
** ** **** ** ** *
****** ** * ** ** * * * ** *** ******** * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * * *** ***** ** * * * *** * * ** ** * **** **
* ** ** * * **** * *
**** *** * * * *** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ** *
#include ****** ** *
int main()
{
* * * * * * ** ** * * a,b,c;
** ** * ** **** * * * * * * **** ** * **** ** * *
******* * ** **** *
** **** * ** ** *** * **** ** ** *
* * ** * * * ** * * *
* * ** ** * * ** * ** * * * **** ***** *** ** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ** * ***** + **** * ***** - * ** * * ** **
* * *** *** *****
**** ** * * ** * **** *
***** * * * *** ****** if (b*b-4*a*c==0)
* * * ** * * * **** * *
** *** ** ** * ** **** * * ** ** ** ** *** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * *** * + * * ** * *
* * * ** ** **** *
**** * * ** * **
** ****** * * **
****** * * ** ***
*** * * * ** * *** * ** ** *** * ** **** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * ** *** * **** * * * ** ** ** ****** * *** *
** * * * * * ** * * * ***
* *** **** ** * * ** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** **** ** * ** * ** a,b,c,d,x1,x2;
*** * * ******* * ** **** ** ****** **** * * * * * ** ***
* ** ** * * * * *** * * ** * **
* *** * * * * * *** *** * * *
* * ** **** *** *** * * ***
*** * * ** **** ** * ***
**** * *** *** ******* ** *
** * * ** * * * * ***** ** * ****** ****** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** ** * **** *
* ** * **** * * ***** * * ** ** ** * ** * * * * *** = %.2f\n",x1);
* ** ** ** * ***** ** *** * * * * * * *** ** * * = %.2f",x2);
*** ****** ** ** ** *
* ** *** * * * * * **** if(d==0)
** * * * * * * ***
** * * * **** * * * * * ****** * * * * ** ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * * * ** ** * *** * * ***** ** *** * * = x2 = %.2f",x1);
********* ** ** *
******* ** ** * **** ****
*** ** * ** *** * * ** *
* * ** *********** * **** * *** ***** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** **** *** * ***
* * * * * * * ** ** ** * * * ** * ** ******* ** = *** ****** * ** * **** **
* * * * **** ** * * * * *** ** * * ** ** * = * ** ** ** ** * ** *
** * ** * * * * *
* * ** * * * * 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * ******* * *** * *** * *** * *** ** ** * * ** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
**** ** ** * ** * ***** ** **** *** - (4*a*c);
* *** * * * * ****** * *** ** ** * * *** **** *****
* * ** * ** **** * * ** ** * * * ** ***** ** * ** * * * * ******* * * ** * *
* ******* * * ********** *** * *** * * *** * * *** ***** ** * * * (-b+spD)/(2*a);
* ** * ** ** **** *** *** ** * ** *** * * **** **** * (-b-spD)/(2*a);
** ** ****** ** ** ** ** * *** * * * *** * * **** * * **** ** (x1==x2){
***** *** *** *** * * * ** ** * * ** ** ** * * * ***** * ** **** * * ** ** ** * ***** * * * * * * * ******* * *** ** * * * * * ** X=%d\n", x1);
* * **** * ** *** ** * * **** ***** ** ****** * ** ** *
* * * *** * *** * * ** *** **** *** * *** *** * * ** * ***** * {
***** * *** *** * * * *** * ** **** ** * * ** ****** *** * ** * * ** *** * * **** * ** * **** * * ** * ** * * * * X=%d或%d\n", x1, x2);
** *** ******* * * ***** ** * ** * *** ** * ***** * * * ******
        }
* ** * * ******* * *** **** * *** * ** if(D==0){
* * *** *** ** *** * ** ***** *** ******** *** * ** ** * * * * (-b)/(2*a);
* * * ** * ** * * * ****** ** * ***** * ** * * ** * ** ** * *** ** *** * **
* * *** ****** * * ***** * ** ** ****** * ** * * *** ** * ** * * * ** * ** ** * ** ******** * X=0");
* ** * * ** *** *** **** **** * ** * ***** * * ** * * * ******* * *
* * * ** ** **** * ** ** * * * ** *** **** ** * *** * ** *** *
** * * ****** * * ** * **** ***** *** ** ****** * ** * ** ** * ** ***** **** ** * *** *** ** * X=%d\n", x1);
*** ** * * *** * ** * ** **** * **** * * *** ** * * *** * ** *
        }
* *** * * ***** *** ** * * *** * * ** * *** ** *
* * * * * ** * * *** ** * ***** ** **** ** * * ** * ** ** * ******* * * *** * *** ** * * ** * * *******
* *** * ****** ** * * **** ** ** * * * *** * * *
    }
* * *** * * * * * * * ** ** ** * ** **** * *** **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** *** * **** ** *** * * a,b,c,D;
*** ** *** **** ** * x1,x2;
***** * ** * * * ** *** ****** ** * ** * %d *** * *** * *** **** * *

* * ******** * * **** *******
*** * * ** ** * * * * ** *
** ** * ***** * *** * * ** ***

** ******* ** ** * ** * A,B,C;
* * * ** * ** * *** *** *

*** ** * * * * ** * *
*** * ***** ** ** * * * ** * * * * ***** * *** ***** * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * * *** **
** ** *********** * *** *** * * ***** *** *** ** ** * *** = %.2f\n",x1);
* * * * * * ****** *** **** * ** * *** * ** * * * = %.2f",x2);}

**** ** * * *** ** **** if(D==0)
* * ** *** *** * **** *** * * *** ** * ** * ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** *** ** * * * * * * ***** * * * * * ** ** ** * = x2 = %.2f",x1);}

** * * * ***** * ** * * if(D<0)
** * ** * ** *** * * * ** ** *** * ** ******* * *** ** of %.2fx^2 + %.2fx + %.2f = 0  are complex and * * * * *
* ** ** * * * * *** * * ** ** * * ** *** * * ** * bb,d,dd;
* **** * * * * * **** ** * *** * * ** * ** * ***
* * * *** * * ***** * ** ** * * * ** * * * ** * * *****
* * * * * ** * ** ** * * ** ** **** * * ** = * * * * *
** * *** *** ** * ***** * * *** * *** * ** ** * * * = **** * * * *****

**** * ** ** * ****** * * ** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** *** * * * *
int main()
{
* ** *** * *** ** * * * * *** * ** * ***
** * ** *** *** * ****** *** %f ** * * * * ** ** * *** *
**** * * ** * *** * ** = (b*b-4*a*c);
***** * **** * * ** ** ** = (-b + sqrt(D))/(2*a);
**** * *** * * * = (-b - sqrt(D))/(2*a);
**** * * ** * * * * = -b/(2*a);
*** * * *** * * *** * ** =sqrt(-D)/(2*a);
** * **** ***** * * ** **
* ******** ****** *** *
** * * *** *** **** *** ** * * * * * * * *** ****** of %.2fx^2 + %.2fx + %.2f = 0 are real and * *** * * *
* * * * * * * **** * * ****** ***** * * ** * * * ** = %.2f\nx2 = %.2f",x1,x2);
* *** * **** * * * * ** *

* ** **** ** ** ** ** * * if(D==0)
** * *** *** ****** * **
**** *** **** **** * ** ***** *** ******* ** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * **** *** ** ** * * ** *** *** ** *** * **** * *** ** = x2 = %.2f",x1);
* **** * *** * *** *
** ** * * * * ** *
* ** * *** ** * ** *
* ** ***** ******** * * ***** **** ** ** **** * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** ** *
***** * * * *** ** * * ** *** *** * *** ** = ** * *** * * * * **** *
** * * * * ** *** * ** * * ** ** ********* ** ** = * ** *** * * ** **** ***
* ** **** * * * * **
*** * ** * ** * * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** * ** ** * *
int main()
{
*** * * * * ** ** ** ** ** ****** * * *
* ** * ** * ** * * * * ** * %f * * ** * * * **** ** * ** ** * *
**** * ***** *** = (b*b-4*a*c);
****** * **** * ***** * * = (-b + sqrt(D))/(2*a);
* * * * * * = (-b - sqrt(D))/(2*a);
* * * * * *** * ** = -b/(2*a);
** * ** ******* * * * * * =sqrt(-D)/(2*a);
* * * * * ** * * ** *
* * * * ******
***** * * ***** ** ** * ** * *** * * ** * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * *** * ****
*** * * *** ** * * * * ** ** * * ** * * ***** = %.2f\nx2 = %.2f",x1,x2);
* ** *** * ***** *** ** **

* * * * *** * ** if(D==0)
* * * ** * * ****** *
* *** ** * * * * ** **** * * * ******* * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** ** *** * * * *** ** ** ** * * *** * ** **** * ***** * **** ** = x2 = %.2f",x1);
* ** * * ** ** **** ** * *
* * ** *** * * * *
* ** ** * ** * *** *
* * ** * * * * *** * * ******** * * * * * * ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * *** * * * ****
*** * * ** * * * ** ** *** ** * * *** ** * * * *** = * * *** *** ** *** ***** ** *** *
*** * ** ** *** * ** **** ** * *** * * ** * = ***** * *** ****** ***
* ** * * * * *** * **
*** * *** * * * ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.47
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users