0 like 1 dislike
7.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 7.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ** * * *** **
int main()
{
* * * * * ** ** **** * * * ***** * ** *
* *** * * ** ** ** * * ** * ***** %f * **** * ** * * * * * ****
** **** ***** * ** * = (b*b-4*a*c);
** * ** * ** * ***** * = (-b + sqrt(D))/(2*a);
* ** ** ** * = (-b - sqrt(D))/(2*a);
* * ** * * * *** ** * * * * = -b/(2*a);
** * ** ***** * ** **** =sqrt(-D)/(2*a);
* ** ** * * * * ***** * *
** ** * *** * **********
* * * *** * * ** * *** * * ** * ***** * ********* ** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ** *
* * * **** ** * * * ** ***** * * *** * *** ** * ** ** * = %.2f\nx2 = %.2f",x1,x2);
** ** ** ** * * ** * *

** ** ** * *** ** * ** *** if(D==0)
** *** ** *****
* ** * * ** * *** * ** ** *** ** *** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * * * ** ** * ** ** ** ***** * **** * * * * * * ** = x2 = %.2f",x1);
*** * ** * ** * * *** **
* ** *** ** * **
** * * * * ** * ****
** ** ** ** ** ****** *** * ****** * ** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * * ** *
**** **** * ** ** **** * * ** ** * * ***** = * * * * *** * **** *** **
*** *** ** ***** ** ** * **** ** * ** * * * * * * ** * = *** **** *** *** * * * *
** ** **** **** * *** * **
*** ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *

int main()
{
*** * * * ****** **** * * n, i;

*** *** * * ** **** * **** *** *** &n);

*** ****** **** ** * ***** * = 1; i <= n; ++i)
*** * * * * * *** **
* *** *** * ** ** *** * **** * * * ** * * % i == 0)
** * * *** *** ** ** * *** * ** *** * ** * **** * ** *** ** * ***** *** * ", i);
* * * ** * *** ** ***** **

** ** ** * ** *** ** * * ** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
*** ** * * **
* * *** * * * * *

int main()
{
*** **** *** *** *** * * *** ******* ***
** **** *** *** * **** ** ** ****** * * ** **** * *
* ** * * * * * **** = *** * ** *
*** *** * ** *** * * * *** *** **
* *** ** * * * * * **
* ******* ** ** * ** ** * *
**** * * * * * *** *** ** * = -b /(2*a);
* ** *** *** ** * *** * ** ** * *
** * * *** * ****** * * * = (-b)/(2*a);
**** ** * * ** *** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = **** *** * ** * *
* * ** **** *** * * *
* *** * * * ** if(D==0)
***** ***** * ** ** *
* * ** * * * *** * * ** = (-b + * * *
**** * * ** ** * = (-b - * * * *
**** * ** * * * * ** ** ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** * *
* ** * *** * * * *
**** * ** ** * ** * * * * * * if(D>0)
* * ***** * ******
* * * * * ***** ** = -b/(2*a);
* * **** * ** * = (-b + *** * ** *
** **** **** ** * * * **** * = (-b - ** *** *
* ** * **** ** * * * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * *** * *
* * * * *** *
** ** * * ***** *** **** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** *** * ** * * *
#include **** ** * * *
int main()
{
** ** * *** * * ** ** * a,b,c;
* ** * ** *** * *** ** *** **** ** * ** * * * *** ** * *
** ** * *** * * * **
** * * ** ** * * * *** * *
** * ***** * ***
*** * * * * ** * ** *** * *** *** ** ***** * ** *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** **** * + * * * * * * - * ** * ** **
** ** * * * ** * *
**** * ** * * **
** * * **** ******* ** ** ** if (b*b-4*a*c==0)
***** *** * * *** * *
* * * * * * ** ******* ** *** * * *** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * **** + * **
** * **** * * * * * * *
* ** * ** * ** *** * *
* ** ** * * * ***
* ***** **** * **
** * * * ** ** **** ****** ** * * ** ** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** * ** * ***** **** * ** ** * * ** ** * * * * **
** *** *** ** * ** *
** * ** **** * *** ** ***** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ***
#include * * **
int main()
{
* * * * * * * * * **** a,b,c;
* * * * **** ** * ***** *** ** * * **** * * * * * ** ** * **
** *** *** * ** * **
* * * * * * ** * * * ** ***** *
*** **** * ******* * *
** *** *** ** ** * *** * * * ** *** * ** * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * *** ** + ** **** * * * - * * ** ******
* * ** * ** **
** * * * *** **
** * * **** if (b*b-4*a*c==0)
*** * * * * **** *
*** ** * **** *** ** *** ** ***** * * * * ** *** **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * * ** **** + ** * * * *
** * * *** ** **
* *** * * ** * * * **
* * ** ****** * ** ** * ** * *
******** * ** * * **
* * * ** *** *** * * * *** ** * **** * * * * **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ** * *** * * ** * * * * *** *** * * ****
** ** * * * ***
** ** ** * ** *** **** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
** ** * * * ** * ** * * a,b,c,d,x1,x2;
* * *** * *** ** * ** *** *** *** * **** *** ** **
** ** * ** ** ** ** ** * ** *
* *** * * * ** ** * * * *
* *** *** ** * * * * * * ** ** *
* * ****** ** ** ** ** * **** ** *
**** ** * ***** * **
* * * * *** * ** ****** * * ******* * * * * **** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * **** * ** *** **
* ** * * ** **** * * * **** ****** * * * = %.2f\n",x1);
** * ** * **** * *** * * * * * * ** ** ** ***** *** * = %.2f",x2);
* * **** * * * **
* *** ***** ** ** ** * * if(d==0)
* ** **** ** **** * **
**** * ** * * ** * ** *** * * *** * ** * * * * * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * ***** * ****** ** * * * ** ****** ***** ** * *** * = x2 = %.2f",x1);
** ** * * * * * *
* ****** ** ** ** ** **
* ** ** * * ** ** **
** * * * * * ** ** * * * ***** * ** * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ****** ** ****
* *** * ***** * * * * * ******* * * **** *** * ** = * *** * ** * * * * *
*********** * * ** ** ** *** * * * * * * ******* ** = * *** ** * * *** * *** *
* *** **** * **** *
** * ****** *** ** * ** **** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
** *** ** * * ** * * ***** ** ** * * *** ***** *** *** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
***** ***** ** ** ** * * ** * * *** * ** ** - (4*a*c);
*** * * * **** * ** ******* *** ** * ***** * *** **
**** *** *** * * ** ** * * ** * * ** * * * **** ** * ** ** * *
* * * * **** * * * * * * **** *** *** * * * ******* * * * (-b+spD)/(2*a);
* *** * * * * * * *** ******** *** ** ** * ** *** *** * ** **** (-b-spD)/(2*a);
** * **** **** * * * ****** * ** ** ***** ** *** * * * * * * (x1==x2){
*** * ****** * * * * *** *** ** * * *** ** * ** * * ** *** ****** * **** * *** * * ** * *** * * * ** * ** *** * X=%d\n", x1);
* * *** * * * ** ****** * ** * ***** * * * * * * * * **
* * ****** * * *** * * ** ** ** ** *** ** ** * * **** * ** *** * * {
**** * ** ** ** * * ** ** * * * ** ** ** * ** * ** **** * * ** *** ** *** * **** ** * ***** ** * * * **** * * X=%d或%d\n", x1, x2);
** * ** ** ** * * *** * * * ** * *** *** * ***** * *** *
        }
* * * * ****** * * ** *** ************ **** * if(D==0){
** *** * ** **** *** * * *** ** ** * * *** * ** ** * *** * ** * **** * ** ** (-b)/(2*a);
*** * * * * * ** * * ** ** * * ** ** ** ***** * ** * ***
** ** * * * ******* * * * ** * * ** * * **** * ** ********** *** ** * ** * *** ** * * *** ** X=0");
** ****** * * * * * ** * * *** * * ***** ***** ** * * ****** **
* * * ** * *** ** ** ** ** ****** * ** ** *** ** ** ** * **
*** ** *** ** * ***** ** **** * ******* * *** * *** * * **** **** * ** *** * * * * ** ***** * X=%d\n", x1);
* * * * * ** ** *** * * * *** ** * *** ** * ** ** *
        }
****** ** * * ****** * ***** * **** * ****
** ** ** * * ** * *** * * ** * *** ** *** ** * * * *** * ******** * ** * * *** * ** * ** * * ****
*** * * ** * * ** * *** * ** * **
    }
* ** * * *** *** ** **** ***** * ****** * * ** *** ** **
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
* * ** * * *** * *** * a,b,c,D;
* ** ** *** **** * ** ** x1,x2;
* ** ** * ** * * **** * * * * **** ***** * %d ***** * * * * * * **** *

* ***** * *** ** * ** *** * ***
** * ** ** * * * * * * ** * **
*** * **** * ** ** ** * *** *

* ** * *** * * ** ** A,B,C;
* * * * * ** * ***

** *** ** *** * * ** ***
** * * ** ** *** ***** *** * ** * * * * * * *** * of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * ***** *
* * ***** * * * *** * ** ** ** * **** ** ** ** * * * * = %.2f\n",x1);
*** ** * * * * * ** * * * * **** * ** * * * * *** ** * * = %.2f",x2);}

* ** * *** * * *** * ** ** if(D==0)
* ** ** * * * * * * ** ****** * * * * * * *** *** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
*** * ** **** * *** ** ** * * ***** * ** * * * * *** * = x2 = %.2f",x1);}

** ***** * *** * ***** if(D<0)
** * * * * * * ** * ***** * ** * *** ** **** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** * * ****
* ** * ** * * *** ** ** * ***** **** * ** bb,d,dd;
** * * * ** * * * * * **** *** *** * ** * * *
** * ** * ** * * ** * * ******** * ** ** *** *** **
** ** ******* ** *** * * ** * * ** * ** * * ** ** * * * ** * * = ** ** * *** *
** *** * * ** * * ** **** * * ** *** ** *** = * * ** * * *

** **** * ** ** * ** ** * ****** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * ** *** ** *
int main()
{
* *** * ** **** *** * **** ** * *** ** *
****** ** ** ****** * ** ** ** %f * ** **** * *** * **** * ** ***
* ** * * ** ** *** * * **** = (b*b-4*a*c);
*** * *** * ******** ** * = (-b + sqrt(D))/(2*a);
** ** * * **** * * ** * = (-b - sqrt(D))/(2*a);
* *** * * ** **** * = -b/(2*a);
* **** *** * *** * ** * **** =sqrt(-D)/(2*a);
* * * **** *** * ** * * * ***
** * * * ** *** * * * * *
** * * ***** ** ** **** ** * ** ** * *** ** * *** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** **** *** *
** ****** ** * ****** **** * * *** * * ** * **** * = %.2f\nx2 = %.2f",x1,x2);
** * ** * ***** **** **

* * * ** * ** *** ** if(D==0)
* *** * **** * ****
* ** *** ** * * * * * * *** ** ****** **** ** * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * *** *** * ** ** *** ** ** ** * ****** *** * * = x2 = %.2f",x1);
* ** * ** ** * ** * *****
**** * * * * *** *** *
**** * * * ** *** *
**** * ** * *** * * ***** * *** * * * **** ** * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ** * ****** *
* * ***** * ** * * ** ** **** **** ***** * * *** = * * **** * * ** **
* * ** * ** *** * * *** * ** ** ** * ** *** ****** = * ** ** * ** ** *** ** **
*** * *** **** * *** *
** * **** * ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
*** * ** * **
int main()
{
** * ***** ** * * ** *** *** * ** ****
* ****** ** *** * ** * * *** %f *** * ** * * * ** * *
* ** *** ** *** ** ******** * = (b*b-4*a*c);
*** *** ** ** ** *** * = (-b + sqrt(D))/(2*a);
** *** **** * ** = (-b - sqrt(D))/(2*a);
*** * * *** ** **** * = -b/(2*a);
*** ********* * **** ** **** =sqrt(-D)/(2*a);
** *** * * * * ** ****** **
* ** * * * *** * * **
** ** ** **** * * * *** ** * * * *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * *
*** * * ** ****** ******** ** * * *** ** * * = %.2f\nx2 = %.2f",x1,x2);
** *** ** * *

* * * * ** *** *** * if(D==0)
*** ** ** *** **** ** *
* * * ** * * * *** * ** **** ** * ** *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * *** **** * ** ** *** * ** ** ** * *** *** = x2 = %.2f",x1);
* * * *** *** ****** *
* * * * * ** *
* * ** * *********** *
*** ** * * ** * * * ** * ** * * * ** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ****** ** ** *
* * * * *** * *** * * * * ** *** * ********* ***** = ** ****** ** * ** ** **** *
* * * * * **** **** ** ** *** ** * ******* ***** = **** * * * * * **
* * ********* * **** **
*** * ***** * * * ** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.24
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users