0 like 1 dislike
15.2k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 15.2k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** ** * **
int main()
{
** * ** ** * * * ****** * * * * * * *** ** * *
* *** ** * **** * * * * * %f * * * * * *** *** *
** * * *** * ** * ** = (b*b-4*a*c);
* *** *** * ** * ** = (-b + sqrt(D))/(2*a);
* * * * * * **** * ** ** * * = (-b - sqrt(D))/(2*a);
** * * * ** * ***** = -b/(2*a);
** ***** * * ** **** ** ** ** * =sqrt(-D)/(2*a);
* * *** ****** * *** ** ***
* * * **** ** * *** **
* ** * * * * * * * **** * * * ** **** ****** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * * **
*** ******* * ** * ** ** * ** * * ** ** * * * ** ** *** = %.2f\nx2 = %.2f",x1,x2);
** * *** * **** ** *

** ** ** ** ** * * * * if(D==0)
* * * *** ** *
* ** *** **** ** ** * * *** *** * * * *** **** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * ** ****** *** * ** *** ** * ****** ** * ** ** = x2 = %.2f",x1);
******* * ** * *** *
** * * ***** *** ****
** ** * * *****
*** * ** * *** **** ** *** ** **** * * * * * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * * *
*** * * ***** * * * * **** *** ** * ** ***** * * = * * * * * * * * * **
** ** * * * ** * *** ** ** *** * * *** * = ** * * * * ***
* * * * ** * *** **
** **** **** ** ** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** * *** *** **

int main()
{
*** * ** ** ** * *** n, i;

* * * * * ** * * * * *** ** * * &n);

* *** *** ********* * ** * = 1; i <= n; ++i)
* ******* ** * * ** ****
* * **** * * **** * * *** * *** * ** ** * ** % i == 0)
* ** **** * * **** * * * ** * * ** * * * * ***** * *** *** ** ** * * ", i);
** * ***** * * ** ** *

* ** *** * ** * * * * ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* * ** * * * *
* ** ** ** * **

int main()
{
*** * * * ** * ** *** * * ** * ** ** ******
**** ** * * *** *** ** * * ** *** * * * * * * * *
** * *** * * * ** * * = * * * *
* * * * * *** *** ** **** *
** * *** ******* * *
** * ** * * * *** * ***** *** * * * ***
** ** *** **** **** * *** ** = -b /(2*a);
* * * ** ****** * * * *** * * *
** * * *** ** ** *** = (-b)/(2*a);
**** ***** * ** * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * **** ** ****** ** * *
* ** * ****** ** * ** * **
** * * *** * * * * if(D==0)
* ** * ** * **** *
* ** * * * * = (-b + ** * **
* * * ** **** * * * = (-b - * *** *
*** * * * * *** * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * **
** * *** * * ** ****
** * *** ** **** *** * ** if(D>0)
* * * * * ** * * **
*** * **** * * ** * *** = -b/(2*a);
* **** * * * * ** * = (-b +
** *** * ***** * *** * ***** = (-b - ** *** *
**** ****** ** * * ** *** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ****** * ** * *** **
********* * ** ** **
* ** * * ** * * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** *
#include * **** **
int main()
{
** * * ** * * * * * *** a,b,c;
** **** * *** ** * * * * *** * * * * ** ** * *****
*** * *** **
*** * * * * ** *** *** * * * *** **** *
* * ** **** * ** *
** *** * ** ** * *** *** ** * ** * * * ** ** * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ***** * ** *** * + * * * **** - **** **
** * ** * * ** * * *
* *** * **
*** ** * * * * * * * if (b*b-4*a*c==0)
* ** * * *** ******
* *** * * ** *** ** * * * * * * * * **** *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * *** + * * * ******
**** *** ** ** **
* ** * * **** * *** *
** ** ** * ** **
* *** ** * * ** *
* **** * * ** ** * * * * * * ******** ****** * * * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = *** ** * *** * ** *** ** ****** * * * * * * *
* ** ** * ** ** * *
* ***** * ** * ***** * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** *
#include **** * **
int main()
{
* ** ** ** *** * * *** ** *** a,b,c;
** * * * **** ** * * ** * ** ******* ** * * *** **
* * * * * *** * * *
* * ** * ** * **** * ** ** **
* * ** **** *** * **
*** *** *** *** * ** *** * * ** * * ** ** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ** * * + ** *** *** - ** * * *** ****
* **** *** * * ***
* * * ** ** ** * **** * *
* * ** ***** ** ** ** ** *** if (b*b-4*a*c==0)
* ** * * **** ** * *
*** * * * ** * *** * * ** * ***** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ******* * * ** + *** * * * *
** * ** * *** **
*** ** * * * ***
** * * ** * * **** **
** * * ** ******
* ** * ** * * * * * *** * * * *** ** * * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= ** * * ** ** ******* ** ** ** * ******* * *** * * *** *
* * ***** * * * *****
*** ** **** *** * * ******* 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
*** ** * * *** * *** * a,b,c,d,x1,x2;
**** * * * *** ** ** * *** ** ****** ** * * * **
** * ** * **** * * * ** *
* ***** * * * * * * ** * ********
* ** *** * * **** * * ** ** * * *
*** * ** * * * *** **** *
** * * ****** **
** *** ** * * * * * **** ***** **** * * * * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** * ** * * *
* * ** * ** ** * * *** * * * * ********** **** * **** = %.2f\n",x1);
** ** * ** **** * **** ** * ** * *** ** * * * = %.2f",x2);
* * ** * ** * ** ** *
* * **** * * * * * if(d==0)
* * * ** * ** * **
*** *** * ** * ** * * *** *** * * * * ** ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** **** ** * *** * * * * * * ***** **** * ** ** ** = x2 = %.2f",x1);
** ** * ** ** * ** *
**** * *** ** ***
* * * *** *
** * ** ** * * ** *** * *** * * * ** *** ** * ** * * ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ****** * **** *
** ** * * * ***** ** * * ** * * ** ** ** * * ***** * = ** * * * *** ******
*** * ***** ** * *** ** **** * ** * * * ***** ********* * = * * * ** * * * * * ** * * *
* * ***** ** * * *
* **** ****** * *** ** ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * **** * * * * **** * * * ** * ** ********* * * *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
* * * **** *** * ***** * ** * * ** * **** *** - (4*a*c);
** ** **** **** * * ** * *** * ** * * * * ***** ****
** ** ** ** *** *** *** ** * * * *** *** *** *** * * **** * ** * **
** *** *** ****** * ** ** ** * *** ** * * * ** ** **** * * ******* (-b+spD)/(2*a);
* * * *** * * * *** ** *** * ********* ** ** * * * **** ** * *** ** * * (-b-spD)/(2*a);
** *** * * * * * ** *** ** * * *** * * ** * * ** (x1==x2){
*** * * * * * ********** * * * * *** ** *** * * * * ** * * ** * **** *** ** ** ** ** ** * * *** ** ***** ** X=%d\n", x1);
* **** * * * * * * * ** ***** ** * **** * *** * * * * ** ** *
*** ***** *** * * *** ** * *** ****** ** ** * *** * * *** {
****** * ** * * ** ** ** *** * * * * ** * * ** * ****** * ** ** ** * *** * * ** **** *** ** *** ** ** * X=%d或%d\n", x1, x2);
* * ** * ** *** * * * *** * * *** * ** * * *** ** * ** **
        }
* * * *** **** * ** ** **** * * ** * ** * if(D==0){
* * * * ** * * *** *** *** * * * * ** * * ** * *** (-b)/(2*a);
* * ** ********* * * * * * ** ** * ** ****** *** * ** * *** * * * *
** ******** ** ** ** * ** * * ** * **** ** ** * * ** * ** * ** **** * *** * ** ***** X=0");
* ** * * * **** * * * *** * * * * * ** * **** *** * *******
* ** * ** ** ** * * *** * ** ***** * * * ** * ** * **** ** *****
* ** ** * * * ** * * * ** * * * * ** * **** *** * **** ** * ** * * ** ** * **** * * * * *** ** *** X=%d\n", x1);
* ** *** *** ** * * ** **** * ** ** * ***** * * * *** *
        }
*** * ** **** * * * ** * ** ** **** *****
****** * * * ** * *** ** ** **** * **** *** * * **** * ** * **** * * *** **** ** * ** *** * ***** * ***
** **** ****** ** * * * ** ** ********* * ****
    }
* **** *** * * * ** ****** * **** *** **** ** ** *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** ** * *** * * a,b,c,D;
** ** * *** * ** * * x1,x2;
** * ***** ******** * * * ***** * %d *** * ** * * * * **

*** ** *
*** * ** ***** * *** ** *
**** * * *** * **** * ***

* *** **** * * * A,B,C;
*** *** ** ****** * ** ** *

** * * * * * * **** ***
** ** *** ** *** * * *** **** * *** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** ** ** *
* **** ** * ** * * ***** * **** *** * * ** * * * * ** ** * * = %.2f\n",x1);
* * * * * * ** * ** * * ** * ** ** * ********* * ** ** ** = %.2f",x2);}

* * * ** * * ** * ** if(D==0)
* ****** * * ** **** ** * ** * * ** ** *** *** ****** ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
**** * * * ** * * **** * * * ** * * ** * * **** *** = x2 = %.2f",x1);}

* * ** * * ** ** * * ** * if(D<0)
*** * * ** ** ***** * * * ** ** ** * *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and * **** * ** **
* ** **** * * ** **** *** ** * ** **** * *** ** * bb,d,dd;
* * * * * * ***** **** * **** * * ** ** ** ** ** ** *
* * * ****** ** * * * ** ** ** * ***** * ** *** * * *** ***
* * * * ** ** ** ** ** * * * * *** * *** * *** **** * * = *** * * * **** *
* ** * ***** * * * * ** ** *** ** ** * *** * ** * * * * = ** *** * ** ** ** ** **

*** ** * **** * **** * ***** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ******* * *** *
int main()
{
** * *** *** * *** ** * ** **** * * ** *
**** ** ** * * **** * %f ** * * * *** ** ** * *
*** * * *** * * ** ** * = (b*b-4*a*c);
** * * ** * * * * ** * * = (-b + sqrt(D))/(2*a);
** * ** * * * * = (-b - sqrt(D))/(2*a);
* * * * * *** ********* = -b/(2*a);
* * * * ** ***** * * * * ** ** =sqrt(-D)/(2*a);
* ** * **** ***** * * * * * * *** * *
* * ** ** * * * ****** *
* ** ** *** * * * ** ** ** * ** *** * ***** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** *** * *** *
* * ******** ** ** * ***** * *** * *** *** * ** * = %.2f\nx2 = %.2f",x1,x2);
* ** * *** *** *** ***

* * ****** * * *** * * if(D==0)
* * *** * ** ** ** **** *
*** ** *** *** * * * ** * * * *** ****** *** **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** * * * *** * ** * ** * *** ****** * * = x2 = %.2f",x1);
* * * ** * ***
*** * * * ***** ** **
*** * * ** ** *
** * * ** ** * ** *** ** ** * * * *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ******* *** * *
** * * ** * **** ***** *** ** ** * ** *** * ** = ** *** * * ** **** **
* ** ** * * * ******** ** *** *** * * ** * *** * *** * ** * = * * * ** * ** ** **
* *** *** * ********* *
* *** ** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
** *** * * *****
int main()
{
** ** ** * * ******* ** * ***** * * *******
* * * * * * *** * ********* *** ** *** %f * ** ******** * ** ****
** * ** ********* *** = (b*b-4*a*c);
* * * * * ***** * * ** = (-b + sqrt(D))/(2*a);
* * * *** * ** ** = (-b - sqrt(D))/(2*a);
** * ** ** ** * * ** ** = -b/(2*a);
******* *** *** * * * * * * =sqrt(-D)/(2*a);
* ** * * ** ** *** ** ** * *
* * ** * *** *** **
***** **** * **** *** ** **** * * * * * * ** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * ** * *
* * *** * * ** * ****** * * * * *** * ** **** *** = %.2f\nx2 = %.2f",x1,x2);
* ** ** ***** **

** ** * *** **** * ** ** if(D==0)
** * * ** *** * *
* **** * * **** * ** * ** * **** *** * ** * * * ** *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * *** * * ** *** * * * ** * *** * * *** ** * *** = x2 = %.2f",x1);
* * * * ***** *** * * *** *
* * *** * ** ****
** ** ** * * **** ***
* * * * * ** * * * * * * ******* *** * * ****** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** **** *
*** * ** **** ** * ** * * *** * * ** ******* * ** ** * = * ** *** * *** ***** **** **
*** ** * ** ** * *** ** ** **** * * * ** * * ** * ** = ** ** *** ** ** ******** *
* * **** *** * * *
*** * * * ** ** *** ** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.254.105
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users