0 like 1 dislike
14.8k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 14.8k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
** * *** *
int main()
{
*** *** * * * * ****** * * * * **** * * * * ***
*** ** * *** ** ** * * * %f * *** * * ** ** *** *
* * ** *********** * ** = (b*b-4*a*c);
* **** ** * * ** * *** = (-b + sqrt(D))/(2*a);
***** * ** * * * = (-b - sqrt(D))/(2*a);
** **** * * * * ** * * = -b/(2*a);
* * ******* ** **** =sqrt(-D)/(2*a);
*** *** ***** * ** * * * **** ***
* * * **** **** ** * * **
* * *** ** *** * ** ******* ** *** * * **** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * * * * *
* * *** ** * * * *** * * * ** * ****** ** ** = %.2f\nx2 = %.2f",x1,x2);
* *** ** ** ** ** * ** * *

** *** ****** **** ****** ** if(D==0)
*** * * * * *** **** **
*** * ** * ******** *** ******** * **** ** ****** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * * ** * *** ** * * ** ** * ** *** * * ** * = x2 = %.2f",x1);
* *** ****** ** * *
**** **** ** ** *** **
* * * **** * ***** *
** * * *** * ** *** *** ** ** * * * * ** * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and *** ******* **** *
* ** ** **** * * * * ** * * * ****** * **** * * = ***** *** ** ** * *
** * * ** * *** **** *** ****** **** *** * ** ** ****** = *** * *** * * ** *
**** ** * * * *** * * * ***
*** ** * ** * ** *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** **

int main()
{
** *** * ***** * * ** n, i;

* * * *** * **** ** ******** &n);

* ** * * * * **** * * = 1; i <= n; ++i)
* * * **** ****** * ***** * *
* * ** * * ** ** * ****** * ** * * ** ** * * * % i == 0)
* * *** * * ** ** **** * ** ** *** * *** * * * * * *** * * ** * * ** ", i);
* * **** * ** * ***

* ** ** * * * * * *** *** 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** *** * **
* ** ***** ***

int main()
{
* *** *** *** ** * *** ** ** *** * * * **
* ** * ** ** *** ** *** *** * * ******* ******* ** * * *
*** * * ** * **** *** * = ** ***
* * * * ** *** * ** **** ** *
* * ** * ** *
**** * ** ** *** ** ** ****
*** * * * ** ****** *** * * = -b /(2*a);
* * *** ** **** ** * * ***
* ** * * * * * * = (-b)/(2*a);
**** * * **** * * ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * *** ** * ** *
* * ** ** *** * * **
* *** * * ** * ** if(D==0)
*** * * ** ***** * **
* ****** ***** ** = (-b + * ** *
**** *** ** * * *** * = (-b - * ** **
* * ** * ****** ** * ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ***** *
* ********** **** **** * *
* **** *** **** * ***** * if(D>0)
* **** ***** **** * * * *
* * ** * * ** ** * * * = -b/(2*a);
* *** ** * **** * * = (-b + * ** *
* ** * **** * ** * **** = (-b - **
** ** ** * * * * * * **** * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * * *** *****
* ** * * * * * * *
* * ** * *** * * *** * * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * * * *
#include ** ** ** *
int main()
{
***** * *** **** ** * * * a,b,c;
* **** ***** *** * **** *** ** ** * * ****** **
*** ** ** *** * **
** ** * ** ** *** **** ** ***** * *
****** * ** ** * *
**** ****** * ** * * ** ** * ** ** ** ** ***** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * ** * + * *** ***** * - ** * ** * * * *
* * * **** * ** *
* * ** *** * ** * ** *
* * ** ** * ** * *** if (b*b-4*a*c==0)
* ** * * * *** ** ***
**** *** ** * * *** *** **** * ** ***** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * **** * * ***** + ** **** * * *
** **** ** *** ** * *
** *** * * * ** * **
* *** ***** * ***** * *****
** * * * ** * ****
*** * ** * *** ***** ** * ** ** ** ***** * * *** ** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** ** ** * ** ** * ** ******** ** **** * **** *** *
*** * * ** *** * * * ****
* ***** * * ** **** **** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *****
#include ** *** ***
int main()
{
* ***** * ** * * *** * a,b,c;
** * ***** **** * * *** * *** * ** ** ** * * ** *** * **
* *** * ** ***
* * ** **** * * * ** * * * *
* *** * ** *
** ******** **** **** * ** ***** ** * * * ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = *** ** *** + * *** ** * * ** - * ** *****
** ** ** * ** **
* * ** *** * * *** *****
* * * * *** * ** ** * if (b*b-4*a*c==0)
* *** * ** * *** *
**** * * *** * **** ********** ** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** * ** * ** + * **** ** **
** * * *** * * ** *
**** ** *** ** ******
*** *** * * ** **** *
* * ** ** ******** *
*** * * ** * *** * * ** * ** *** ** *** * ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * * * * ** *** * * ** ****** * ** ** ** * *** *
* * * *** * * **
* ****** *** * ***** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* ** * * ***** **** *** a,b,c,d,x1,x2;
* * **** * * * ** ** **** * ** * *** ** * * * *** **
**** ***** ******* * * ** * ** **
*** *** ** ** * * * * **** ********* * **
**** * * ** ** * ** ** *** * * *
** *** ****** * * *** ***
* * *** ** ** ** **** *
** ** * ** * **** * *** * * **** **** **** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** ** ****
* * * ** ** * ** * ** * *** * * ** ** **** * * *** * = %.2f\n",x1);
***** **** *** * * * * * *** ** ** * * ** * * ** = %.2f",x2);
* * ** * ** ***** *** ** **
** * * ** * ** ***** * ****** if(d==0)
** * * * * ***** *** *
* * ** * ** * *** * ** ***** ** * * * **** *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** *** * ** * * ***** **** * * ** * * *** = x2 = %.2f",x1);
*** *** * ** **** *
**** * ** ** ** ** * ** *
* *** * **** ** *
*** * ****** ** *** ******* **** * ** * * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * ** * ** * **
* *** ** * * **** * * * ** ***** * * * *** ** **** * = ** * * * ** ** ****
***** * * * * * ** * ** *** * * * * ****** ********* = * * ** * ** * ** ** *
** *** * *** *
****** ** * * * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
*** * * * * *** ** * *** * * * * * ** * * * ** * * * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** ** ** * * * * * ** *** ** ** * ** ** ** * * **** - (4*a*c);
*** * * ** * * ********* ** ** ****** ** * ****
* * ** ******** *** * * * *** * *** ***** * * * * * *** * * *
**** ** * ******* * **** ** * * ** * ** ** ** * *** * * **** (-b+spD)/(2*a);
***** * * ****** ** * * * * ** *** **** * ****** ** * *** * * ** ***** (-b-spD)/(2*a);
**** *** ** ** * ** *** * * ** ** ****** * * ** *** * ** (x1==x2){
* ** ** * ** *** * ** ** * ** ** ** ** *** * ***** * ******* * * *** *** ** * ** * * * ** * *** * ** ***** X=%d\n", x1);
* * ********* * * *** * *** * * * ***** ** *** **** * *****
* *** * ***** ** * **** **** *** ** * * *** * * ** * * * ** ** {
** * *** * * ** ** * ** * * * ****** * ********** ** ** ** *** *** **** * * * *** *** * *** * **** * ** **** ** ** * X=%d或%d\n", x1, x2);
**** **** ****** * * ** *** * * ** *** **** * * * ** * *** ***
        }
* ** * * * * *** * * * * * if(D==0){
* ** ** * *** * **** ** **** * ** *** * **** * * * * ** *** * * *** * *** * (-b)/(2*a);
* * ***** * * *** ** * * * * * **** *** * ** **** * ** * * **** *
* ***** * ** * ****** * ** ** * * ***** * *** * ** ** * * * * * **** ****** * *** ** * * ** X=0");
** **** * *** * ** * ****** * * * ** ** * ** *** * *** ** *** ****
** * * * ** * ** * * ** * **** * **** * ** ** ** *****
* ** * *** * * ** * * ** * * * ** * ** * * * ** * * * *********** **** ***** ** ** * **** **** * X=%d\n", x1);
* *** ** ***** * * ** ***** * ****** ** * *** * **** * ** ** ** **
        }
** * ** *** * * *** ** ** * ** **** *** * ** ** *
* * **** * ******** * * ** * ** *** ** *** * ** ** *** ** ** * * *** *** * * ** * * ** * * *
* * * *** *** **** **** **
    }
* *** ** ** * * * * * * * * * ****** * * * ** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** *** * * ** ** a,b,c,D;
* * *** * ** ***** * x1,x2;
** * * * ** *** * ** ** * * ** %d ** * * *** * *** *

* ** * * *** * * * * ** ** *
* **** ** * * ** * ** ***** ***
**** ****** * * * * *** * ***

****** * * *** * * ** A,B,C;
* * ** * *** *** * *** ** *

* ****** ** * **** * * ** *
* ** ****** * ** *** ** *** ** *** ** * *** ** * ***** of %.2fx^2 + %.2fx + %.2f = 0  are real and * * * **** *
** ** * * ** * ** * **** * * ** **** ** = %.2f\n",x1);
*** ** * *** ** ***** * * ** ** * **** * ** *** ** * ** = %.2f",x2);}

** * ** * * * ** ** * ** if(D==0)
** **** **** * ** * ** ** * ** * * ** ******* of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
** * * * * * ** * *** * ***** * *** *** *** ** ** * = x2 = %.2f",x1);}

** ** **** * * * if(D<0)
** **** * ** *** * * ******* * * ** ** *** *** * * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** ** ***
* * ** ***** * * * ** *** ** * * * ** ****** ** * * ** bb,d,dd;
* * * ** ** *** ***** * * **** * * ***** *** * *** * * ****
* * ** * **** **** * *** *** * * * **** *** * *** **
* * * ** * * * * **** **** ** * * *** * ** * = *** ** * ** ** **
*** * * *** *** ** ** * ** **** ** * **** * ** * ** ** * ** = ** *** * * * ****

* *** * * * * *** * *** * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* ***** *** ****** *
int main()
{
**** * **** **** * ** * ** *** *** ** *** **** **
* * ** ** ** ** * * ** ** * ****** %f * * ******* * *** * **
** ** * *** ** * ** = (b*b-4*a*c);
* ** * ** ** * * ** ** = (-b + sqrt(D))/(2*a);
** * ** * * ****** * * = (-b - sqrt(D))/(2*a);
* * * **** *** *** ** = -b/(2*a);
** * **** * * ** *** * ** * =sqrt(-D)/(2*a);
* * ** *** **** ** ** ** *
********** ** *** **
*** ** ** * ** *** * * ** * * * ** ****** * * * *** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and ** ******* **
** **** * * ** * * ** ** * * * ** **** ** * * * = %.2f\nx2 = %.2f",x1,x2);
* ** ***** * ** ** *** *

** ** ** * * *** ** * if(D==0)
**** ** * *** *** *** *
** * ** ** * * * ****** * *** * ** ** **** * **** ** * **** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * * ** ** * * * ** * * * * ** * ******* = x2 = %.2f",x1);
* ******* *** ** * * *
*** ** ** * * ** *
** * ** * * * ***** * * *
* **** * * ** * ** ******* * ** ** **** ** *** * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** ** ****
****** ***** * * ** ** ** ** **** * * * ** * * ** = ***** **** * * * **
**** * * ** ** ** * ***** ** ** ******* ** ** ** *** = *** *** ** * ** ** * *
** *** * * **** * *
** * *** * * ** * * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * * * ** * **
int main()
{
* * *** *** * * ** * *** * * ** ** *** ** *
** *** * * * ** * *** ** * * * * %f ** *** * ** * **** ***** ** *
*** * ******** ** ** * * = (b*b-4*a*c);
** * ** ** * *** ** = (-b + sqrt(D))/(2*a);
** * * * ***** *** * * ** = (-b - sqrt(D))/(2*a);
** ********** * ** *** * * *** = -b/(2*a);
** * ** * * *** * ** ** =sqrt(-D)/(2*a);
*** * * * * * * ****** *
* ** ** *** *** * * *** *
* ** ** ** **** *** * * * **** ******* ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and * * * ***** * *
** * ****** ** ** ** *** * ** * ** *** * * * = %.2f\nx2 = %.2f",x1,x2);
******* * ** ** ** ** * * *

* ***** **** ** * *** if(D==0)
* * * ** * * * ** **
* * * ** * * * * *** * ** ** * * * * *** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** **** ** * * ** * * ** * ****** * ** * ***** = x2 = %.2f",x1);
** ***** * * ***
* ** ** * ** ** ****** ** *
*** * * * ** * *
* * ***** * * * ** ***** * * * ***** * **** **** *** ** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * ***** * **
*** **** * **** * * * ** * * ** ***** *** * * * ****** = * **** * * * * ** * * *
** ** * * * ** * *** * * * * * ** ********* ** * * *** * *** * = * * *** * ** * *** * **
*** *** * * ** ** ** ****
* * ** * * **** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.33
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users