0 like 1 dislike
11.9k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 11.9k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* * *** * ** **
int main()
{
** * * ** ** * *** * *** * * *** ** * * * * * * *****
* * * **** * ** *** * *** %f ** * *** ** ** * *** ****
** * * * * * ** * = (b*b-4*a*c);
*** ** ***** * * ** * = (-b + sqrt(D))/(2*a);
* ******** *** * * *** = (-b - sqrt(D))/(2*a);
** * * * * * * * * *** = -b/(2*a);
* * * * * **** * ***** * ** =sqrt(-D)/(2*a);
*** * *** ** * ** * * ****
*** ** * ** * * ** **
*** * * * * * *** **** * ** * * ******** * ** * * * * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ***** * * ** ******
* * * * * * * * * * * * ** ** ** * * * * ******* = %.2f\nx2 = %.2f",x1,x2);
* * * ** * ** ** ** ** **

** * ** * ** * * * **** if(D==0)
** ** ** ** * *** *
* ** * ** * *** * ** * ** * ** *** * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* * *** * * *** * ** * * * ** *** *** * ** = x2 = %.2f",x1);
** * * * ** * ** * *
* ** * *** * ****
* ** * * * * ** * *
* ** ** ** * * * * *** * * * * **** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** * *
** * ** ** ** *** * *** *** * *** * * * * ** * * ** ** = ** * ** ** * **
* ** *** ** * * * * **** * * ** * * ** ** ** * = ** * * * * * * ** ** * *
* ** * *** *** *** * *
** ** **** * *** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** ** *

int main()
{
**** * * *** *** * * n, i;

** ** * * * ** * * * * *** ** &n);

*** ** * * **** **** * = 1; i <= n; ++i)
** ** ** * * ** *
*** ***** * *** * * * * ****** **** % i == 0)
* * * * ** *** * * * * *** * * * ***** * * * * *** *** * * * **** ** * ** ", i);
* ** * ** **** ** * * * ***

* * ** ** *** ** * * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
** * * * ** *
**** * ** * * * **** *

int main()
{
** * *** * * ***** * ** *** ** ** * * * *
* * * ***** * ** *** *** *** *** ** *** ** * ** * * ***
** * * ** ** ** ** * = * *** *
** ** ****** *** * * *** *
*** * * * * * *
** ** * * *** * ** * *** *
* * ** ** *** ** ** * ** = -b /(2*a);
* * * **** * **** ** * * ** * *
* ** * * ** ** *** * * ** = (-b)/(2*a);
******* * *** * * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * ** ***** ** * ** **
** **** ** * ** ** **
** * * ***** ** if(D==0)
** ** *** ** ***** ** * *
** ** * *** * *** = (-b + * **** *
* ** ** * *** ** ** ** = (-b - * ****** **
* * **** * *** * * ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ****** ****** *
* * * * * * ** * **
* * *** * * *** ** ** * if(D>0)
* * ** * * ** ** *** * *
*** * * * * ** *** * *** * = -b/(2*a);
** *** * * * = (-b + **** *
* * * **** * ** * **** **** = (-b - * * * ***
** ** * * *** ** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ***** * **
** * *** ***** **
** ** * * **** * ** * 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** **
#include * * *** *
int main()
{
*** * * ** * * ** ** a,b,c;
*** * * ** *** * * * ****** * ** ** * ** * * ** * * *
* * * * **** * *
** * ** ** * * * *** ** ***** *** *
** *** *** ** ** * *
****** ****** **** ** *** **** ****** * *** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * ***** *** * **** + *** * * * ** - ** * * *
* * ****** ** **** * * *
* **** *** ** ** * ***
*** * ** * ** * *** *** ** * if (b*b-4*a*c==0)
* * ** ***** ** *** * ** *
** ** ***** ** ** * * * *** * *** * ***** * ** * * *** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * * **** + * ** *** *****
* ******* * *** * * *
** * ****** ** ********
*** *** ** **** * ***
**** **** * * ** ****
*** ** * ** * ** * ** * ** * ** ** * * ** **** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * **** ** * ******* ** * ** *** ****** ****** * *
** * * * * * **
* * * ** *** ** *** *** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * **** *****
#include *** ** * **
int main()
{
*** * ** * * ***** a,b,c;
* ** ***** * *** * * ** * *** ** * ** * *** ** ** ** *
* ** ** **** * ** ** * ***
**** * *** *** ** ** ** * *
******* * * *** *
** ** ******* * * * * ** ** ** **** * *** * **** * of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** * ***** *** + **** * ******* - ***** * * **
** ********* * * ** ****
* * *** * * * * *
* * ** *** * * * ** * ** if (b*b-4*a*c==0)
* * * * **** ** **
**** * * ** * * * ***** *** ** * ***** * ***** * * *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ** *** + **** * * *
** ** ** ** ** * **
* *** * *** * * *
* * * * * * ** ******
* * * ******* * * *
******* * * ** ** ***** * *** ** * ** * * * * * *** ** *** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * ***** ** * **** *** *** * ** * * ** * ****** *
** * * * ** ** * * * * *
** * ** * **** ***** * * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
* * * *** ** **** * * a,b,c,d,x1,x2;
**** ** * * * *** *** ***** ***** * * * * ***** ** **
* * ** * * * *** * * ** ** * *
*** * ** ** * ****** * ** ** * **
* * * ** * ** * ** * *** **** *
* *** ** ** **** * * *** **
** ***** * ** * * * * *
***** * * * *** *** ** * ** * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and ** **** ***** *
* * * ** ** * *** * * ** ** * * * *** ** * * = %.2f\n",x1);
** ** ** ** * *** * * * *** * *** * ** ** * * *** ** = %.2f",x2);
*** * * * * ** ******* * *
***** * * * ** * **** * if(d==0)
* * **** * * * ** * *
* *** ** *** * * ** ***** ** ** * ** **** ** * * ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * *** ** * *** * * * * ******** *** * * = x2 = %.2f",x1);
* * **** ** ** * *
***** *** * * * ** * ***
* * * **** * * * **
** ** ** ***** ** ****** **** ** * * ** *** ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * * *** *
* * * * * *** * * * *** **** * **** * ** *** * * * * = * ** * *** *** ** * **
**** ** **** * *** **** * * * ** * * ** * ****** = * *********** * * ***** **
* ***** ****** ** *****
* * * * * * *** * *** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
***** ** ** ** * ** * * * * * *** *** * ** * aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** ****** * * *** **** * *** * * * **** * *** * *** * - (4*a*c);
* * *** * *** * ** * * * ** * * * * * ** *** * **** **
*** * * * * ** * * * *** ** * * ***** * * * * ** * ** * * ** * **** *
***** * ** * * ** * *** * * * * * ** * ** ** ** ** * (-b+spD)/(2*a);
* * ** ** **** **** ** * * * *** ** *** **** ** * ** * ** * (-b-spD)/(2*a);
** ** ** *** ***** * * * *** ** **** ** ** * ** (x1==x2){
* *** **** * * ** **** **** * ** * * ** * ** ** *** *** *** ** * ** * *** ** * * * * * **** * ** * * * ***** * ** X=%d\n", x1);
* ** ** ****** ** * *** *** * ** ** * ***** ** ***** * * *** * ** *
* * * *** * * * ** * *** * * * * ** * * ** * ** * *** **** * {
* * * ** ** *** * ***** **** ********** ******* * **** *** ***** ** * ***** *** * ** ** **** ** * * * * * * *** ** *** * * X=%d或%d\n", x1, x2);
* ** * * * ** * ** * * * ** * * ***** *** * ** * * *
        }
* * ** * * * * ** ****** * * *** *** * if(D==0){
* * * * *** *** * ** ** *** * **** * * * ***** ** * * (-b)/(2*a);
**** * ***** * **** * * * **** * ** * * * ** * * * ****** *** **
* * *** * **** ** * * *** * **** * * * *** ** * * * *** ** ***** ** * * ** * ** *** X=0");
* **** ** ** * ** * ** *** * **** * ** ** * * *** **** * *
*** * **** ** * * * * ** *** * ****** ***** ** * ************ * *
* ** ** * ** ** ** * ***** * **** * *** * *** * *** *** *** * * * *** * ** *** *** * ** * * *** X=%d\n", x1);
*** * * * *** ** ** ** * * * * * * ** * **** * * ** *****
        }
****** * * * ** ** * ** **** **** * * *****
** * ** * *** * ** * ****** ** *** * * ***** * *** * * ** * *** ** ** *** ** ** ** ****
** *** ** * * * * **** ** *
    }
* **** * * * * * **** * ** ****** ** * ** ** ****
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
** ** * **** * ** * *** a,b,c,D;
*** * ***** * * * ****** x1,x2;
** *** *** ** * ***** *** ** ** %d * * * ** *** ** *** *

* ** * *** ** * * * * *** ** **
* * ** ** * * * * **** ** ** * * *
**** * * * * * * * ** * *** * *

** * * ** *** ** * ** ** A,B,C;
* *** * * ** * * *** * * *

** * * * **** ** ***
** * *** * **** *** ** * ** *** **** **** ** ** * ** * * ** * ** of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** **** * *
* * * ***** * * * * * * * ** *** ***** * ** * ******** ** * ** = %.2f\n",x1);
* ** * * * * * ** **** * * * ***** * ** ***** *** = %.2f",x2);}

* ******* *** * * ** ** *** if(D==0)
* ** *** ** ** * * ** * * * * *** * **** ******* ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * * *** * ** ** ** * * * * * ** * = x2 = %.2f",x1);}

** ** ** ***** if(D<0)
* * ** * *** *** ** ** **** * * ** * *** *** ** ** ** * * ** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and ** *** * *
* * * **** **** * * ** ** ** ** *** * * * * bb,d,dd;
* * * * ** ********* ** * ** * *** * **** *** **
** * *** * * * *** * * * * * * * **** *** * *** * * ** ** *** *
** *** * *** ** ** * ****** * * * ** * *** *** * * **** * ** = * * * * **** ***
* * * ** * * **** *** **** * ** * * * * **** * ** *** *** * ** *** = ************ * *** **

***** * * * * ** * * 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
***** ** *
int main()
{
*** ** ** * * ** **** * * ** * ** ** ** *
** ** ** ** *** ** *** * * * %f ** * * **** ******* **** *
** ** * ** * * *** * = (b*b-4*a*c);
** ** * *** * ** **** = (-b + sqrt(D))/(2*a);
** ** * * * **** = (-b - sqrt(D))/(2*a);
* ** ** ***** ** * * * = -b/(2*a);
** * * *** ** * * * * ** * =sqrt(-D)/(2*a);
*** *** * ** ** * **** ***
*** * * * * * ** **** *
*** * *** * * ******** * ** ** *** ** * ***** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * * ***** ** *
* * *** * * ** * ** *** **** *** * ** ***** ** = %.2f\nx2 = %.2f",x1,x2);
** * * ******* * *** **

******* ** * ** ** ****** if(D==0)
** ** ** ** * ***** **
* ** *** ********* ****** * * *** ** * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* ** * ** * * *** * *** **** * * ** * * * * ** ** * = x2 = %.2f",x1);
* * ** ** * * **** * *** ** *
* **** * * * **
* ** ** ** * *
* ** ** * * ** ***** * * **** ** * *** ** * * *** ***** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and **** * ** **
* * *** *** *** ** * * * *** * *** ** * ** * = * *** ** ** ** * ****
* ** * ** *** * ** * *** *** * ** ** * **** = * * * ** ** * *
*** ** * ** * * ** *
* ****** * ** * * *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
**** ** ***
int main()
{
* * * * * * ** * * ** * * ** * ** * **
* * * **** *** ** * * *** ** * %f * * *** ** *** * * *
* ** * ** **** **** ** * * = (b*b-4*a*c);
* * * * * ** * = (-b + sqrt(D))/(2*a);
* * * * * ** **** = (-b - sqrt(D))/(2*a);
* ** **** ** ** * * = -b/(2*a);
**** ** * * *** ** *** *** * * =sqrt(-D)/(2*a);
*** * ** ** * ** *****
** *** * ** ** ***
* * **** * * *** * * ** *** *** ** ** * ** ** * * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and **** *** *** ** * *
** *** * * * * * * * * ** ** ***** * * ** **** *** = %.2f\nx2 = %.2f",x1,x2);
* ** **** * * *** **

* *** **** ** * if(D==0)
** * ***** * ** ** ** **
** * * *** **** ** * * *** * * ** ** * ***** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
** * * ** * **** ** * ** ***** ** * ** ** * ** ** **** = x2 = %.2f",x1);
**** **** **** * * *
** ** * ** ** ** ** ** **
* **** * * *** ** * * * * *
** ** ** *** * * *** * * ***** * ** ** **** * * *** *** of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** *** ***** *
* * * ***** * ** * * ** * * * * **** ** ** * * * = * * ** ** * *** * *
* * * * * *** ** ** * ****** * * ******** * ** = * ** ** ** * *** * ** ** *
* * *** * * * * * ****** *
*** * * ** * ** * ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.33
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users