0 like 1 dislike
16.9k views

Write a program to find roots of a quadratic equation

quadratic equation is a second order equation having a single variable. Any quadratic equation can be represented as where a, b and c are constants ( a can't be 0) and x is unknown variable. 

寫一個找二次方程的求根程式

For Example

 is a quadratic equation where a, b and c are 2, 5 and 3 respectively.

To calculate the roots of quadratic equation we can use below formula. There are two solutions of a quadratic equation.

使用下列公式:

x = (-b + sqrt(D))/(2*a)
x = (-b - sqrt(D))/(2*a)

where, D = (b*b-4*a*c) is Discriminant (判別式), which differentiate the nature of the roots of quadratic equation.

For the complex result (複數根):

realPart = -b/(2*a);
imaginaryPart =sqrt(-D)/(2*a);

Note: We have used sqrt() function to find square root which is in math.h library.

 

Example input 1:

1 2 1

Example output 1:

Roots of 1.00x^2 + 2.00x + 1.00 = 0 are real and same
x1 = x2 = -1.00

 

Example input 2:

1 -3 2

Example output 2:

Roots of 1.00x^2 + -3.00x + 2.00 = 0 are real and different
x1 = 2.00
x2 = 1.00

 

Example input 3:

1 2 2

Example output 3:

Roots of 1.00x^2 + 2.00x + 2.00 = 0 are complex and different
x1 = -1.00+1.00i
x2 = -1.00-1.00i
[Exercise] Coding (C) - asked in Chapter 5: Selection Statements by (5.2k points)
ID: 28934 - Available when: 2017-10-26 18:00 - Due to: Unlimited

reopened by | 16.9k views
0 0
We will continue this question in few days
0 0
Everything is fixed. Enjoy your time with The Judge :)
0 0
ANNNNNNNNNNNNNNNNNNNNNNNNNNGRYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
0 0
Your code has newline at the end sometime. You learned this lesson many times!
0 0
After i correct the newline in my code,there is still wrong output.However,I had run the program in Codeblocks.The output is still as well as the result. Seeking for help.
0 0
your output lack of 1 space at line 8 when print out "Roots of ...". Please be careful with all small details when working with online judge

56 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
* ***** * * *** *
int main()
{
** * * * * * * * * * * * * ** * * * * * * *
* * ** * *** ****** * * * %f ** * * * * *
* * ** * * * ***** = (b*b-4*a*c);
*** ** * ** ** * ** = (-b + sqrt(D))/(2*a);
** ** * ** * * ** * = (-b - sqrt(D))/(2*a);
* * ***** * ** ******* = -b/(2*a);
* **** * * *** ** *** * =sqrt(-D)/(2*a);
*** ** * **** *** * **** *
* **** *** ** *** *
**** ***** * * *** *** ** ** ** *** * ** ** ** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and *** *** ***
* ** *** ** * **** * *** **** ** ** * * * ** = %.2f\nx2 = %.2f",x1,x2);
** ** ** **** * **

* *** **** *** **** **** if(D==0)
**** **** ****** ** * *
* ***** *** ***** * * * ** *** * *** ** *** ** ** ** * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
* *** * * * * * ** * * * * * ** ** *** * ** * = x2 = %.2f",x1);
* ****** *** * ** ** * *
* ** ** * ***** * * **
* * ** * **** * *** *
* * * ** * * * * * **** ** **** ** *** ** * ** ** * ** of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** ** ** **
** ** * * * ** * * * * * ** * * ** ** ***** ** * * = * * * ** * * ** * ***
* ** * * *** ** * * * * ** * ** * * * ** ** = ** * *** *** * * * **
* *** * *** ** **
* ** * *** * * *** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *

int main()
{
* * ** * **** *** * ** * n, i;

* ** * * ******* ** * ** * ******* ** &n);

* ** * ** ** ** ** = 1; i <= n; ++i)
* * *** * ****** *** * * *
* * *** * **** * ** * *** * * * ** * * ** * * * % i == 0)
****** * ** * *** ** * ** * * ** * ** **** * ** ** * * * ** * * **** ", i);
*** * * ** ** *** * * ***

** * * * * ** *** ***** ** * 0;
}
answered by (-284 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
* ***** ** *
* **** *

int main()
{
** * *** **** * ***** * * ***** **** *
** *** * *** * **** * ** * ** * *** **** ** * * *
** ** *** *** ** * * ** = ** * * *
** * ****** **** * ** * ** *******
*** *** ** * * *****
** * * ** ** * * ** * * * * ***
* * ***** * * ***** = -b /(2*a);
**** * * * * * * ** *** ** * **
* ***** *** * * ** * * = (-b)/(2*a);
*** ** * ** * * ** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = ** * *** ** ** *
* ****** *** **** * **
* *** ** * * *** * ** ** * if(D==0)
* ** *** * ** * *
* * * * ** * * * * = (-b + * **
* * * *** ** * *** = (-b - *** * * **
* ** *** * * **** * * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * ** ** * ** *
* *** ** ***** **** * *
* * * * **** *** * * *** * if(D>0)
* * **** * ** * **
*** ** *** * * ** = -b/(2*a);
** * * ** ***** * ** = (-b + ******** *
** ** * *** ** * = (-b - ***** *
** ** ** * ** ** * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = **** * ********* *
*** ** * *** * ** * *
** * * * * * ** * * *** 0;
}
answered by (-323 points)
edited by
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** *
#include **** **
int main()
{
* * * *** * * ** *** a,b,c;
**** ****** * * * * ** ** ***** * * ** *
* * **** ***** *
** ***** * * ** *** **** * ** *
* ** ** *** * ** * * *****
*** * * * * * **** * * ** * *** * * * * * ** ** ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = ** *** * ** ** + ** ** * * - * * **** * *
*** * ** **** * ** **
* * * * **** * * * ***
* * *** ** **** *** if (b*b-4*a*c==0)
** * ** ****** * * **
** * * * * * *** **** * ** ** * **** ** ** ** *** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = * * *** ** * + ** * * * ***
* * * * * * *
* * ** * * ***** *
* ** * ** * * * * *
** *** * ** *** * * ***
* ***** *** ** * * ****** **** *** * * *** * * **** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2 = * * * * ** * ** * *** ****** * **** ** * ****
* * ** * ** *
*** * *** * *** * * 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ***
#include * ******
int main()
{
* ***** ***** ** * * * * ** a,b,c;
** * * * **** ** * *** * * * ** ** * **** *** *** ***
* * ** *** **
*** *** ******* * *** * **** *
* ******* ***** * * **
* ** * ** * * * *** *** ** * ** ** *** * * * * * * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and different\nx1 = %.2f\nx2 = * * * * * ** + * *** - * ** ** ** *
*** * * *** *** *
* ** * * *** ******* * *
*** * * * **** * if (b*b-4*a*c==0)
* ** * **** ** **
**** ****** ** * ***** ** ** ** * ** *** * **** * * ***** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and same\nx1 = x2 = ** * ***** * + *** ****
* * *** **** * ** **
** * ** **** * * *
** * ** *** ** * * *
* ** **** * * ** ***
* * * ** *** ** ***** ** ** **** * * * **** *** * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and different\nx1 = %.2f+%.2fi\nx2= * *** * ** * ***** ** ** *** ******** ** * ** *
**** *** ******* ** *
** * * ***** * * ***** ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main()
{
*** ** ******** ** ** a,b,c,d,x1,x2;
* *** * * * * * ** ** *** * *** ** ** *** ** * ** * * * *
* ** * ** * * ******
*** ** * *** ** ** ** * * * * *
* * ** * * * * * **** **** ** *
* * *** ** * ** **** * ** **** **
* ** ** ********
*** * * *** * *** * * *** *** ** * ** ******* *** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * *
* ** * * **** *** * * ** * ** * *** * * ** ***** = %.2f\n",x1);
** **** ** * ** *** **** * ** * * ** ******* = %.2f",x2);
*** * ** * * *** *****
*** *** *** ** ** * if(d==0)
*** ***** ** * *****
** *** * * ****** * * * ** **** * *** * * * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
*** * ****** *** **** * *** ** * ** * ** **** * * ** * * * = x2 = %.2f",x1);
***** * ** ** * ** ***
* * ** * ** * * *** * *** *
* ** ***** * ** **** *
* * ****** ** ** ** ***** ** ***** * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** * *** ** **
* * ** *** ** * ** * * * *** * * ** *** * *** ** ** = ** * **** **** * ****** *
** * * ** ** * * * * ** * * * *** ** * * *** ** = *** **** * **** * * * *
* * * ******** * ****
** ** ***** * * ** **** ** 0;
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
int a, b, c, D, spD, x1, x2;
* * * * * * * ** * ** * * * * ** * * ** ** * * * *** aX^2 + bX + c = 0\n以a b c表示\n");
    while(scanf("%d %d %d", &a, &b ,&c)==3){
** * ** ** * *** * * *** ** ** ****** * * * * * * - (4*a*c);
** ** ** * * * * **** **** * * * * ** *
* ** ***** * * * * ** ** ** **** ** * * ** ********* * ***** * *
**** * * ** ** ** * * * ** *** * * * * * ** ***** * ***** * (-b+spD)/(2*a);
*** * ** **** ** * ****** * **** ** * * *** ** ** * * * * (-b-spD)/(2*a);
** * * * *** * * ** * * * * ** ** * *** ** * * * * * ** ** (x1==x2){
** *** ** ** * * * * ** * * * * *** ** ****** ****** * * **** * * * * ** *** *** * ** ****** * * ** *** * * * ** ** * X=%d\n", x1);
** ***** **** * * * ** ** * * * * ** *** *** ** * ***** ** *
** * ** ** * *** * ** *** ** * * ** ** * * * * * * ** *** ** {
** * ** * * **** *** *** * * ****** *** ** ** ** ** *** ** * ** * * * * * **** *** ** ** ** ** ** ** ** * ** * **** **** * X=%d或%d\n", x1, x2);
** * * ** ** ** ** ******** * **** ** ** ** * ** * **** * ** * *
        }
*** ***** ** ** ** * ***** * **** * *** * * * * **** * * if(D==0){
******* *** ** *** * * ** ***** * ** **** * * *** ******* (-b)/(2*a);
** ** * **** * * ** ** ** * ** ********* * ****** * * ******** ***
* * ***** *** * *** * * * * * * * ** * *** * *** ** ** * ** * ** ** * ** ** * * * *** ***** X=0");
* **** *** * * *** * * *** * ** * ** ** ** * ** *** ***** *
** * * ** ** *** **** *** * * * *** * * * ** ** * * * * * *** * * *
** *** *** * * * *** * * ** ** * * ** * * **** ** *** ** * * * * * * * * * **** ** * ** ** * * X=%d\n", x1);
*** * * * *** * * * **** * ** **** * * ** * * ** **
        }
**** * ** * ** ******** ** * ** *********
* * * ** * **** * * * ** ** *** * ** * * * ** ****** **** * * * ** *** * * ** ** *******
* ** *** * * * *** * * * * * ***
    }
*** * * ***** *** * * **** * *** ** * * ****** *** *
    system("PAUSE");
    return 0;
}
answered by (-32 points)
0 0
prog.c:2:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe4\xb8\x80\xe5\x85\x83\xe4\xba\x8c\xe6\xac\xa1\xe6\x96\xb9\xe7\xa8\x8b\xe5\xbc\x8f\xe7\x9a\x84\xe4\xb8\x89\xe5\x80\x8b\xe4\xbf\x82\xe6\x95\xb8\xef\xbc\x8c\xe5\xa6\x82 aX^2 + bX + c = 0\n\xe4\xbb\xa5a b c\xe8\xa1\xa8\xe7\xa4\xba\n");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:3:5: error: expected identifier or '(' before 'while'
     while(scanf("%d %d %d", &a, &b ,&c)==3){
     ^~~~~
prog.c:29:12: error: expected declaration specifiers or '...' before string constant
     printf("\xe8\xab\x8b\xe8\xbc\xb8\xe5\x85\xa5\xe6\xad\xa3\xe7\xa2\xba\xe7\x9a\x84\xe4\xb8\x89\xe9\xa0\x85\xe4\xbf\x82\xe6\x95\xb8");
            ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
prog.c:30:12: error: expected declaration specifiers or '...' before string constant
     system("PAUSE");
            ^~~~~~~
prog.c:31:5: error: expected identifier or '(' before 'return'
     return 0;
     ^~~~~~
prog.c:32:1: error: expected identifier or '(' before '}' token
 }
 ^
0 like 0 dislike
Hidden content!
#include <math.h>
#include <stdio.h>
#include <stdlib.h>

int main ()
{
**** * * *** ** ** a,b,c,D;
*** ** ** * * * * x1,x2;
* * ** ** *** ** * * *** * ** %d ** ** ***** *** * *****

* *** * * *** * * *** ****
* * **** * ** ** * *** * ** ** * *
* * ** ** ** ** ***** * *****

****** * ** * * * ** A,B,C;
*** * ** * ** ** * * *

* * ** * * ** *** ** **
* * *** * * ** * ** ** ** *** * ** * ** ****** *** * **** of %.2fx^2 + %.2fx + %.2f = 0  are real and * ** * ** * **
*** *** ** ****** * ******* ** ** * * * ** *** * * ** = %.2f\n",x1);
* * *** *** * **** * ** * ** *** * *** *** * * ** ** *** * * ***** * = %.2f",x2);}

* ** ** * ** * ** * if(D==0)
**** * * * *** ** * * ** ** ** * * ** ** * ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",A,B,C);
* * *** * ** ** * ** ** *** ** **** * ** * **** * * = x2 = %.2f",x1);}

***** * * ** * * * * ** ** if(D<0)
* * * * ***** * * *** ** * * * ** ** *** ***** *** * of %.2fx^2 + %.2fx + %.2f = 0  are complex and * ** * ** * **
****** * * * * ** * *** ** * * * * * **** *** *** bb,d,dd;
*** * ***** ** *** **** * * ** * * * *** ** **
*** * ** ** *** * * *** * ** * **** * ** *** * * **
****** ** * *** * ** * * * * ** **** * * * ** * ** * ** ** = *** * ** * **
* ** ** *** * * * * ** * * **** * ** * *** ** ** = * **** **** *******

* ** * *** *** * *** 0;
}
answered by (-16 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* * ********** ***
int main()
{
* * * *** *** **** * * ****** * * ** * * * *
* * *** ** **** * ** * * %f * ***** ***** * ** ** **
* ** * * *** * *** = (b*b-4*a*c);
*** * * * * **** * = (-b + sqrt(D))/(2*a);
** *** **** ** * * = (-b - sqrt(D))/(2*a);
** * * ** ***** * * ***** * = -b/(2*a);
* * ** * * * ***** *** =sqrt(-D)/(2*a);
* * * * * ** **** **** * **** * *
****** * *** **** * * * ** *
** * * * *** * * ** ** * *** * ***** * * * ** ** * of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * *
* ** * ***** * ** ** * * ** ** * **** * * ** * * = %.2f\nx2 = %.2f",x1,x2);
**** * * *** **** ** *

* * *** * * * **** if(D==0)
**** * * * ** ****** *
*** ** * * * *** ** *** * *** * * * * *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
***** * **** *** *** * ** ** **** * *** * * ** * *** * * = x2 = %.2f",x1);
* ** *** ** **** *
* * * * ** *****
* * * ** ** * * **
*** ** ** * * ** ** ** * * * ** *** *** * * * of %.2fx^2 + %.2fx + %.2f = 0 are complex and ** *** *** *
** *** * * * **** **** * **** ** ** ** = * ** * ** ** * ** *** * *
* * * ** * * ** * ***** ** ** *** ** * * * ** *** ** = * **** * **** * * * *
*** ******** * * * ****
* ** ** * * * * ** ** * ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
* *** *** **** * *
int main()
{
**** * ******** ** * **** ** ** ** * ****** *
* * ** * ** * * ** ** * * %f ** ** * * ***** * ****
** ** **** ***** * = (b*b-4*a*c);
** * * * * *** * ** * = (-b + sqrt(D))/(2*a);
* * * ** ***** * * * = (-b - sqrt(D))/(2*a);
* *** * * * ** * ** * = -b/(2*a);
*** **** * ***** * ** * * * *** =sqrt(-D)/(2*a);
* ***** * * ***** * ***
**** ** ***** ***
**** *** **** * **** * * *** ** * * ** ** ** * **** * ** of %.2fx^2 + %.2fx + %.2f = 0 are real and * ** * * *
* * * * ** ***** * ** * **** **** * * * *** = %.2f\nx2 = %.2f",x1,x2);
* * * * ***** * *

* * * * * * ** if(D==0)
*** ** *** ***** ** * **
** * ** * * * * * *** ****** * * * ** * * * ** * * of %.2fx^2 + %.2fx + %.2f = 0 are real and same\n",a,b,c);
***** *** * * **** ** *** ***** ** * ** ***** = x2 = %.2f",x1);
* * *** ** * * * * **
* * * **** * ** ** *
* * * ** *** *** ** ** *
******* * * **** *** ***** ***** * * * * **** * * ** * of %.2fx^2 + %.2fx + %.2f = 0 are complex and * * ** * **
** * ************ **** ** * * * **** ** ** * ** * * = ***** * * *
* ** * * ** * ******* *** ** *** *** * * * ** *** * = ** ***** ****** * * ** *
* * ** * ** *** * * ** *
* *** ** * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.32
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users