Toggle navigation
Courses
Questions
Tags
Users
AC 20161201 第二次期中考 第二題
0
like
0
dislike
7.2k
views
時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18067 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
|
7.2k
views
comment
Please
log in
or
register
to add a comment.
62
Answers
0
like
0
dislike
Hidden content!#include <stdio.h>
#include * * ** * ***
#include <ctype.h>
#include <math.h>
#include * * ** ** *** *
int main(){
* * ** **** *** *** * ** * * h,m;
* * ** ** ** * * * * * ** ** * ** * * * * * *** * * * * *
*** * * * * * * ** * * arch,arcm,sum=0;
* * * ** * * * ** ** ** * * * *
* * * *** * ** * * * * ** * ** * = m * 6;
*** * * * * * * * * ** ** * = h * 30 + m * 0.5;
* * * *** * ** ** * * * * > arch){
* * * ** * * * ** ** * * ** *** * * * *** * * * = arcm - arch;
*** * *** ** *** ** ** * * * *** ** *** *** * * * * * * * * * * * **
* * * ** * * * *
* ** * * * * * ** * **** ** < arch){
** * * * *** ** * ** ** * * **** * * * **** * * ** ** * = arch - arcm;
* * * * *** *** * * * * * ** * * * * * ** * ** ** ** * * * * * ** ** **
** * * * ** ** ** **
* * ** * * * * * * * * ** * ** == arch){
* * * * * ***** ** * ** *** * * * * * * * * * * * * * * ***** * * **
* * ** * * * * * * * ** *
*** * ** * * * *** * ** * * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
(
-216
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * * *** * * * *
#include * * * * * * *
#include <ctype.h>
#include <math.h>
int main()
{
** * ** * ** * * * * a,b,c,d,e;
* *** * ** ****** ***** **** * **** ** * ** * * * * * *
* * * * * * * ** * ** ** * * * ** ** * **
* * ** *** * * * * * *
* * * * ** *** *** * * * *
** * ** * * * ** * * * * * **
** * * ** ** *** * ** * * * (c>=d)
* * * * * * * * ** * **
*** * ** ** * * * * * * ** (c<d)
* *** * * * ** ** * ** * ** ** *
* * * * ** * * * ** (e>180)
* * * ** * ** * ** ** ** *
* * * * * * * * * ** ** * ** ** *
**** ** * * ** ** * ** * * * 0;
}
answered
Dec 1, 2016
by
410523016
(
-136
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include * * * *
int main()
{
* *** * * * * * * * * * * * ,j ,n=0;
* * * * * * **** * ** ** i;
* * ***** * ** * *** * * * * *** * ** * * * *
* * * * ** ** * = i % 12 ;
* * * ** * * ** * ** * =( i * 30 )+( j / 2) ;
** * ** ** ** = j * 6 ;
* * * ** ** ** ** =k-l ;
if(m < 0)
* * * * * * **
* * ** ** * ** * * * * *** * * * = - m;
* * * * **
*** * * ** ** ** * * if(m > 180)
*** * * ** * * * *
* ** ** * ** *** *** ** * ** ** * * *** * * = 360 - m ;
** * **** *
* ** * * * **** ** * * ** * * * * * ** * **
* * * ** ** * * ** ** * 0;
}
answered
Dec 1, 2016
by
ert5179693
(
-60
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** * * * h,m;
* * * ** * * ** ** ang1,ang2;
* ** * * * ** * * * * * * * ** * *** * * * * *
* * * * ** * * *** * ((30*h+0.5*m)>6*m)
* ** ** * * *
* *** * *** * * ** * * * * * * * * = (30*h+0.5*m) - 6*m;
*** * * * * * ** * ***** * * ** * * * = 360 - ang1;
* * ***** * ** * * * ** * * * ** * * ** * * *** * (ang1 > ang2)
** ** ** * *** ** ** * * * * *** * * * * * * * * * ** * * * * * * * **
* *** ** * ** * * * *** * * ***
* * **** * * * * ** * * * * * * ** * * ** ** * ** * ** ** * * *
**** *** * * *** * *
** * * * ** * * * * **
* ** * * * ** * **
** * * * * * ***** * ** ** * * * ** * ** = 6*m - (30*h+0.5*m);
* * * * * * * ***** *** *** = 360 - ang1;
** * ** ** * * * * * **** ** (ang1 > ang2)
* * * * * * * * ** ** * ** * **** * * * * ** * * ** * * * * * **
* * ** * * *** * ** ** *** * * * *
** * * ** *** * ** * * * ** ** * * ** * *** ** * * * *
}
** * * ** ** * **** ** 0;
}
answered
Dec 1, 2016
by
莊長穎
(
-42
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include ** * ** ** * * **
* * * ** * * * *
int * *
** * * **** * * a ,b ,i;
* * * ** * * *** ** * c;
**** * ** *** ** * * ** ** * * * * * *
* * ** * *** *** * ** * * * * ** ** * * *
** * * **** ** ** * != 12)
*** ** * ** * * * * * = b*6 - b*0.5- a * 30;
* ** ** * * * * * *
** * * ** * * * * * = b*6 - b*0.5;
* * * ** * * ** * * c ** * 0 )
* ** ** * ** ** * * = -c;
* *** * ** ** * * * * * * * *** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include ** * **** **** *
int main()
{
**** *** * * * * m=0,k=0,l=0 ,j ;
* * * * * ** ** i;
** * * * * * ** ** ** ** ****** * * ** * * * *
* * * * ** *** * * * * = i % 12 ;
* *** * * * * ** * * =( i * 30 )+( j / 2) ;
* * * * * ** ** = j * 6 ;
* * * * *** * * =k-l ;
* * * * * ** * * * ** < 0)
* * * * ** * * *
** * * ** * * * * * * * ** * * = - m;
** * ***** * ** ** *
** * * * * ** if(m > 180)
* *** * *** ** *
** * ** * * * * ** ** ** *** * * = 360 - m ;
*** * *** * * * * *
* * ** * ** * * * * * * * * * *
* * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
(
-60
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * * * * * * a,b=0;
** * * *** * * * * * * c,d=0;
* * * * ** * ** ** * * ** * * * * * * * * * * *
** ** * * * * * **** * * ** ** ** * ** * * * * ** * *
* * * * *** * * *** * * * * * ** **
*** *** * * ** * ** * * *
* * * ***** * * * * *** *
* * *** * * * * ** * * * *
**** * ** * * ** * ** ** * * *** * ** * * * * ** ** ** * * * *
}
*** ** *** * * ** * **
* * ** * * ** * * * * * ***** * * * *** ** ** * * * * * * **** * * * *
}
* * * * * * * ** ** ** * ** 0;
}
answered
Dec 1, 2016
by
SRFX
(
-140
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * * * * * * ** ** hour,min;
** * ** * ** * * * * ** * d,k,a1,a2;
* * * ** * * * * ** * ** ** * ** *** * ** ** *
* * * * *** * * * * (hour==12)
* * ** * ** *** * * * * *
** * *** ** **** * * * **
*** * *** * * * * * * * *
* * **** * * * ** ** **
* ** ** * * * * * * ** *** ** * * * *
* * * ***** ** * ** **** ** ** *
* * * ** ** * * * * ****
** ** * * * * ** * * * **** * ** *
* * * ** * **** * ** *
* * ** * * * * * ** * *
* *** * *** * * * * * * **
* * * * *** * * * * ** * * ** ** * *
** * ** * ** * *** * ** *
* * ** ** * * * ** * ** * * * * * * **
* * * * * * * *** * ** **
**** ** ** * * * * * * * 0;
****** * *** * *** *
* ** ** * *** ** * *** *** *
answered
Dec 1, 2016
by
Gulang
(
-122
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * *** ** * ** * ** * a,b;
** * * * *** **** * * ** * * q,w,e;
* ** *** * * * ** ** *** ** ** * * * *** * * * * * *
* * * * *** * * ** * * *
{
* *** ** * * * ** * ** * * * * * * * * * * **** == 0)
* * *** * ** * ** ** * ** *** * * ** ** ** **** * = 6*b - b/2;
** *** * * * * * * * * * ** * * * if(b%2 != 0)
* * * * * ** * * ** ** * * * * = 6*b - b/2 - 0.5;
* * ** ** * * ** *** ** ** * ** * * * * ** * * ** ** * ** * ***
* **** * * * * * * * * * * ** ** * * * *** = 360 - q;
* * ** ** ** * ** * ***** * * * * * * if(q<0)
** * * *** ** * *** * * * * * ** = 360 + q;
}
* * **** *** ** * * * ***
{
* ** ** * * * * * ** * ** * * * * * ** ** * * *** * * * == 0)
* **** **** * ** **** *** * * * * * * * * * ** * = 6*b - b/2 - 30*a;
** * * * * * * ** * *** * * * * * * * ** * if(b%2 != 0)
* * * * *** * * * * ** * * ** * * ** * * * = 6*b - b/2 - 0.5 - 30*a;
* ** * ** * *** * * * ** * * * ** * * * *** * * *
* * * * * ****** * * * * * * * * * *** * * = 360 - q;
* ** ** * *** * * * ** * * ** * * * * ** * * * * * ** if(q<0)
* * * * * ** ** ** * * * * ** * * * * ** * * = 360 + q;
}
* * * ** * * * * * * * * * *** ** *** *** * **
*** * * * * * * ** * * ** * * * * * ** * * * * * * * * * * * ** * ** ** ** ** ** * ** *
* ** * ** * * * ** * ** * * * * **** if(w>q)
* * *** ** * * * ** * * * * * **** * * * *** * * * * * ** *** ** * * * * * * * * * *
* * ** * * ** ** * ** * * * * * ** * * * * = b%2;
* ** * * ** * * * * * *** * ** 0;
}
answered
Dec 1, 2016
by
410323020
(
-85
points)
ask related question
comment
Please
log in
or
register
to add a comment.
0
like
0
dislike
Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * * * *** ** * a,b=0;
* * **** * * * * * c,d=0;
* * *** * * * * * ****** * *** * * * ** * * *
* * ** * ** ** * ** * **** * ** ** * ** * **** * *
* * ** * * * * * * * *** * *
* * * * * * * * * * * *** ** **
** ** **** * **** ** *** ** **
* * ** ** * * **** * ** * * ** ** * ** * * * * * **** * * * ** ** * *
* * * * ** * * * * *
** *** * * * * * * ** *** * *
***** * * *** * * ** ** * * * * *** * ** ** * * *** * * *** **
}
* * * ** ** ** * ***** ** * 0;
}
answered
Dec 1, 2016
by
SRFX
(
-140
points)
ask related question
comment
Please
log in
or
register
to add a comment.
Page:
« prev
1
...
3
4
5
6
7
next »
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English
中文
Tiếng Việt
IP:108.162.216.74©2016-2025
Related questions
0
like
0
dislike
16
answers
AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18075 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
2.7k
views
0
like
0
dislike
86
answers
AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18071 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
9k
views
0
like
0
dislike
49
answers
AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18070 -
Available when:
Unlimited
-
Due to:
Unlimited
|
5.2k
views
0
like
0
dislike
21
answers
AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18066 -
Available when:
2016-12-01 18:30:00
-
Due to:
2016-12-01 21:00:00
|
3.1k
views
0
like
0
dislike
0
answers
AC 20161201 第二次期中考公告
[Resource]
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
(
18k
points)
ID: 18085 -
Available when:
Unlimited
-
Due to:
Unlimited
|
10
views
12,783
questions
183,442
answers
172,219
comments
4,824
users