0 like 0 dislike
7.1k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 7.1k views

62 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include *** * * * *

#include <ctype.h>

#include <math.h>

#include * * * **



int main(){
* ** ** *** ** ***** * * * h,m;
* **** * * ***** * * * ****** *** ** * *** * *
** * * * *** ** * * * * arch,arcm,sum=0;
**** * ***** * * *
* * * * * ** * = m * 6;
* ** ** *** * * * = h * 30 + m * 0.5;
** **** ***** * ** * * > arch){
* * **** * * ** ** * ** ** ** * *** ** ** * = arcm - arch;
* * * * ** * * *** *** * * * *** ** * *** * * ** ****
***** ** **** * * *
* * * * * * * * * ** * * * < arch){
* * * * * * *** ** * *** * * *** *** ** * = arch - arcm;
* ** * *** ** * *** * ** * ****** * ** ** * * *** * ** ** * **
* ** ** ** ** ** * **
** *** * * *** * * == arch){
* * * * * ** * ** *** *** ** *** *** * ** ** * * * ** * * ** * *
* * **** * ** * * * * *
****** * *** * ** * ******* 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * * ** ** * * *

#include * * **

#include <ctype.h>

#include <math.h>



int main()

{
* * ** ** ** *** ******* a,b,c,d,e;


* *** **** * *** *** * *** * ** * *** ***
** * **** * * ** *** * *** * ***** * ** *


** ** * * * ** * ****
* ** **** ** * * * * *


** * **** ****** * ** * **




* **** ** **** (c>=d)
*** * * * * **** *
**** * * *** * * * (c<d)
* ** ** ** * * * * * **


** ** ********* ** ** (e>180)
** * * * **** ***




* * ** ** *** * ***** * **** * * ** **
**** ** ** * * *** * * * 0;



}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include * * ** **



int main()

{
*** * * * ** * ** ** * * * ,j ,n=0;
* * ** ** ****** ** *** i;
* * * *** ** * * *** * ** ***** ** **** * * * **
** ** * * *** * ** = i % 12 ;
*** *** * * =( i * 30 )+( j / 2) ;
** ********* ** * = j * 6 ;
**** * ** * =k-l ;

if(m < 0)
**** *** * * ** **
** * ** ** * * ** *** ** = - m;
** * ** * ** * * * *
** ** * * * * if(m > 180)
** * * *** *
** ** ** * **** * * * * ** * * = 360 - m ;
* * *** *** * *
* * *** ** * ** * * ** **
* * ** ** * ** 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** ** *** * ** h,m;
** * * * *** ** * ** ang1,ang2;
** *** *** ** * * **** * * * * * * ***** * ** *****


*** ** ** ** * ((30*h+0.5*m)>6*m)
** ** **** * *
* * * * ** * * **** * * * * = (30*h+0.5*m) - 6*m;
** ** * ** ** ***** * * * * * = 360 - ang1;
*** ***** ** * * ** (ang1 > ang2)
***** *********** * * * * ***** * ** * * ** ** *** * ** *
* *** *** * * * ****** *
** *** * * ** ** * * * * ** ** ** *** * * *** ** *** *
* * ** ***** *
** * * *
* ** * ** ** * *
* ********** * * * * * ***** **** * = 6*m - (30*h+0.5*m);
* * * * * * ** * * *** ** * * = 360 - ang1;
* ** * ** *** ** * ** * ** *** (ang1 > ang2)
* * * ** * * * * ** * * * *** ** ** ***** *
** * ***** *** *** **** ** *** * * **
********** * * * *** ** * ** ** * ** * ** ** * * ** * * *

   }
******** * ** * ** 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include *** ****
** * **



int * * **


* *** ******* * a ,b ,i;
*** **** *** * c;


** ** * * * ******* **** ** **** ***
** ***** ** * ***** * ***** * * * * * * *


* * * * ** * *** ** * != 12)
** ***** *** = b*6 - b*0.5- a * 30;
* *** ** * ** ** *** **
** ** *** * ** * = b*6 - b*0.5;


* *** * ** * * ** * c * 0 )
* ** *** ** * = -c;


* * *** ** ** * ** * ***** ** c);



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ** * * **



int main()

{
*** ** ** *** *  m=0,k=0,l=0 ,j ;
* * ** * ** ** * i;
* * * ** * ****** * ** * ** ** * ** * * *
** * **** * * = i % 12 ;
*** ** ***** *** =( i * 30 )+( j / 2) ;
** * ** * * ** = j * 6 ;
* * ** ** * *** =k-l ;
***** ****** *** < 0)
* ** * *
* * * *** ***** **** * ***** * * *** * = - m;
* ** * * * *
*** *** * ***** * if(m > 180)
* * * *** ** ** *
*** * * ** *** ** * * = 360 - m ;
* **** ** * ****
*** ******* * *** * *** * ** *
* * * * ** * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
***** * ** *** * * a,b=0;
* * * ***** * ** *** ** * c,d=0;
** ** *** * * ** * * ** **** *** ***** **
* * ** * * **** *** ***** *** ** * ********
*** * *** **** *** * ** ****
* * *** ***** ** *
** **** * ** **** **
** * * *** ** * *** * **
** * ** * * * * * ** * **** *** ****** * ** *** *

    }
* * * *** *** ** *
* * ** * ** ******* * *** *** * * * *** * *** * * *** * ** * *

    }
** *** * * ** * ***** **** * 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** ** ** *** * hour,min;
*** * * * * *** * d,k,a1,a2;
* ** * * * *** ** ** * * * * * ** * ***
* ** ** ** (hour==12)
** * * ** ****** *** ** ** **
* ** * ** * ** ***
** * * * * * * ***** ** *** * *
* *** * * * ** * **

    
* * ** **** * * **** * * **** ***
* ***** * ** ** *** *** * **
***** ** ** ***** ** *
* *** * ** * ****
* *** * * ** ** *
* ** **** ** * ** *** *** *

    
* * * * * ** * ****** *
** * * ** * * * * * *** * *** ** *****
* * * * ******* *
***** ** * *** * * * * * * **
** * * ** ***** *
* ** ** *** * * ** * 0;

    
*** * *** ** ** ** *
* * *** * ** ** *
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** * * * * **** * * a,b;
**** ** * * * ** * * * q,w,e;
** ** * * * * ******** * * * **** * * * * * * **
* ** * * ** ** ** * *

    {
* * * ** * * *** ** * ** * **** ** ** *** *** * == 0)
**** * ** * * * * ** ** * **** ** ****** * *** = 6*b - b/2;
* *** **** * ** * * ** * * * * * ** * ** * **** * if(b%2 != 0)
*** *** *** * * *** ** ***** * * ** = 6*b - b/2 - 0.5;
* * * ******** ****** * * ** ** * *
* **** * * *** ** ** * ***** ** ** = 360 - q;
* * *** *** * ** ** *** * *** *** * *** if(q<0)
***** *** *** ** * **** * *** * **** * *** * * * * * = 360 + q;

    }
*** ** * * *** **

    {
* * *** * **** * * *** *** ** * ** *** * ** == 0)
* * ** *** * * * *** * *** ****** *** * = 6*b - b/2 - 30*a;
*** * *** ******* * * ** * ** * * if(b%2 != 0)
* * * **** * * ** *** * **** * ***** * ***** = 6*b - b/2 - 0.5 - 30*a;
* * *** * *** *** ** * *** * ** * ** * ** *
***** * ** *** ** *** ** ** * * *** ** * * *** * = 360 - q;
* * * *** * ** * *** ** * ** **** ***** * if(q<0)
**** * * *** ** * ** * * * * ** = 360 + q;

    }
****** * * * ****** * * ** *** ** *** * * * * * *** *
*** ** *** * * * * * ** * *** * ** ******* * ** ***** ** ** ****** * *** * *** * *
* * ** ** * * * ***** * * * ***** ******* * if(w>q)
* ** * * * * **** ** ** ** * * * * **** * * * ** * * * *** ** * *** * **
*** * *** **** * * * *** *** * **** * * ** ** * = b%2;
*** * ** ***** * * * * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
** ******** * ** a,b=0;
* * ** * * * * *** * ** c,d=0;
*** **** ** ** * * ** **** ** ***** ** *** *
**** *** * * ** * *** ** ** * * * **
* * * ********* ** *** * ****** **
* *** *** ** ** * ****
* ***** **** * * * * **
** * ** * *** ***** * ** ** * ********* * ** *** * * **
** **** ** ** ** * ****
* * * * * * * * *** * *
* * * ***** * ** ** ***** ****** * * * ***** * *** * ** *

    }
*** ** * * * * ** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.7k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 8.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users