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時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 7.5k views

62 Answers

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Hidden content!
#include <stdio.h>

#include *** *** * * * *

#include <ctype.h>

#include <math.h>

#include **** ** ** *



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answered by (-216 points)
0 like 0 dislike
Hidden content!
#include **** * ** ****

#include ***** **

#include <ctype.h>

#include <math.h>



int main()

{
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}
answered by (-136 points)
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Hidden content!
#include * * * * **



int main()

{
* * * ** **** * * * ,j ,n=0;
** * * * *** i;
** *** * * ** * ******* **** ** * *** * ** ***** *
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**** *** * **** =( i * 30 )+( j / 2) ;
*** *** *** ** = j * 6 ;
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if(m < 0)
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*** ** ***** * ** * * * * ** * * *
* * **** * *** * ** 0;

}
answered by (-60 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** * * * *** *** h,m;
******** ** * ** * * * ang1,ang2;
* *** * ** ** ** * ***** * *** **** * *


* * *** ** ** * * * ((30*h+0.5*m)>6*m)
**** ** * ** *
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* *** *** * ** * ** * * * *** * = 360 - ang1;
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******* **** ***** * * ***** * * * * = 6*m - (30*h+0.5*m);
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* ** * *** **** * 0;

}
answered by (-42 points)
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Hidden content!
#include * * * * * *
* * * *** ****



int *****


** ** ** * *** *** * ** a ,b ,i;
* ** * * * * * *** c;


* *** **** ** ** ** * ** *** *
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**** * * * * ** * ** = b*6 - b*0.5- a * 30;
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** * * ** * ** = b*6 - b*0.5;


**** * ** * c * * 0 )
* *** ** * * * * = -c;


** * **** * * *** * ** *** c);



return 0;

}
answered by (-122 points)
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Hidden content!
#include * ** * *



int main()

{
** * * *** ** *** *  m=0,k=0,l=0 ,j ;
* * ** * * * * * i;
** * * *** * ** * ** * ** * * **** * * *
* * ** = i % 12 ;
* * **** *** * =( i * 30 )+( j / 2) ;
** * ** * = j * 6 ;
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* * * ** * * * *** * * ** * ** ** = - m;
**** ***** ** *** * *
*** ** * ** if(m > 180)
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* ** * *** * * *
** * * * ***** ** * ****** * **** * **
* *** *** ** *** ** 0;

}
answered by (-60 points)
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Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* *** * * *** a,b=0;
** * * * *** * *** * c,d=0;
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**** ***** ** ** * *
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    }
*** * * *** * *** ******** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * ** *** * ****** hour,min;
*** ** ** *** * ** * d,k,a1,a2;
** * ** ***** * *** ** ***** ** * * ** * *** * **
**** * * * ** **** * * (hour==12)
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answered by (-122 points)
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Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* * * ** *** * ** * a,b;
** * * * ******* ** * * * q,w,e;
* *** **** * *** ** * * ** * **** ** * *** ** * * * *
** ** * ** * *** ** * * *

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* ** * * ** ** **** ****** * *** ** * * *** ** = 6*b - b/2;
* *** *** ** ** ** **** * * * **** ******** * if(b%2 != 0)
* * * *** * ***** ** ** *** ** * * ** * *** ** = 6*b - b/2 - 0.5;
* **** * ** * * ***** ** * ** *** * ** * *** * *
** * * **** * * ** ** * * ** * * ** ** * = 360 - q;
* * * * ** *** * ** * *** * * * * if(q<0)
** * ** * ** * * * ** ** ** * * * * * = 360 + q;

    }
** ** ** ** * ** ** * ***

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* ** ** * ** * * ** ** * * == 0)
** ** ***** ** * * *** ** * * * * ** * = 6*b - b/2 - 30*a;
* * **** * * * ** * *** ** ** ** * *** ** * * * if(b%2 != 0)
* * * *** *** * * ***** * * * ** *** = 6*b - b/2 - 0.5 - 30*a;
* ** * * *** *** **** ** * * * * * * *** **** ***
** ** *** ** ** ** * *** * * ** * ** ** = 360 - q;
* * *** ** * * * ** * ** * * * *** * if(q<0)
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**** * * **** * ******* * ***** * * *** if(w>q)
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****** * * **** * ** ***** ** * * **** *** = b%2;
* *** * ** * *** * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
** *** ***** *** *** * *** a,b=0;
** *** * * * * * * * *** * c,d=0;
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    }
* * * * ********* ** 0;

}
answered by (-140 points)
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