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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
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Hidden content!#include <stdio.h>
#include ** * **
#include <ctype.h>
#include <math.h>
#include * * ** ** ****
int main(){
* ** * * * ** ** * * * * * ** ** h,m;
***** * * * * * * ** * * ** * *** *** * * * ** ** * * * ** *
* ** * * * * * * * * arch,arcm,sum=0;
***** * * * * * * * ** * * * * ** * ** ****
** ** * * * * ** ** * * ** * ** * * * = m * 6;
* * * * * * * * * * * * = h * 30 + m * 0.5;
****** * * * * ***** * ** * * > arch){
* * ** * * *** * ** * *** * * * * * * * * = arcm - arch;
* * * * * * ** *** * ** ** * * * * * * * * * ** *** *** * *
** * * * * ** * *** *
*** * * * * * ** ** * * * < arch){
* * * * ** * * ** * ** * * * * * * * * ** * * **** = arch - arcm;
*** ** ** ** ** **** ** *** * * * * * * * * ** * * * * * * * * * ** **
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*** * * * ** * * * * * * ** ** * * * * * * * *** * ** * ** * * *
**** ** * * ** ***** * ***
* * * ** ** ** * * * * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * * * *
#include *** * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
*** * ** * * * ** * * * * ** * * a,b,c,d,e;
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* *** * ** * *** * * * * * *** * * * * * * ** *
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* * ** * * * * * ** * (c>=d)
* * * * * * * * * * * * ** * *
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** * * * ** ** ** * * * 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include ** ***** * **** *
int main()
{
* * * * ** * ** * ** ** * * ,j ,n=0;
** * * *** *** * * **** * i;
** *** ** * * * * * *** * **** *** ***** * * ***** *
* * ** * * * * = i % 12 ;
* * * * * *** =( i * 30 )+( j / 2) ;
*** * ** * * * * = j * 6 ;
* ** *** ** =k-l ;
if(m < 0)
* * * * *** * * * ** *
* * * * * * ** * * * * * * * = - m;
** * ** * * * *
* * * * * * ** **** if(m > 180)
* ** * ** * **** * * *
** ** * * **** * * * *** * ** * * * = 360 - m ;
** *** * * *
* * * ** * ** * * * * * ** *
* ** *** * * ***** * ** ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * * * * ** * h,m;
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* * * * ** * ((30*h+0.5*m)>6*m)
* **** ** * * *
** * * * * * * * ** * *** = (30*h+0.5*m) - 6*m;
* * * *** *** * * ** * * * **** * * * * = 360 - ang1;
* ** * ** * *** * *** * * * * *** (ang1 > ang2)
* * * * ******* *** * **** * ** ** ** * * ** * * * ** *** *
** * ** * * **** * * ** * * * * * * *
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* * * * * * * * * * ** **
* ** * * * * *
* * * * * * * *** * *** * * **** * = 6*m - (30*h+0.5*m);
* * * ** * * ** ** **** * * * * *** * = 360 - ang1;
*** *** * * ** *** ** * * * * ** * (ang1 > ang2)
** * * * ** * * * * * ** * **** * * * * * * * ** * * * ***
* * * *** * * * * * ** * *** * **
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}
* * * * * **** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ** * * ** ***
* * * ******
int * ** **
** * * * ** * a ,b ,i;
* ** * * * * * c;
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* *** ** * * * * * * * **
* * **** * * * * ** * ** != 12)
* * * * * * * * * = b*6 - b*0.5- a * 30;
*** ** * ** * * * ** *** *
** ** * * ** * ** = b*6 - b*0.5;
* * ** * * * * * c * * * 0 )
*** * ** * * * * * = -c;
* * * * * ** ** * * ** *** ** * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * ** * * *
int main()
{
** * *** * * * * * m=0,k=0,l=0 ,j ;
* ***** * * * * ** * *** i;
* * ** * * * * * ***** * ** * * ** ** * ***** *
** * * * ** ** *** * * = i % 12 ;
* *** * * * *** ** * * =( i * 30 )+( j / 2) ;
** ** * * * * * * * * * = j * 6 ;
* * **** * * * * *** * * =k-l ;
* * * *** * * * * ** **** < 0)
* ** * * * * *
* ** * * * ** * * * * * * ** * = - m;
* * ** * * * *** *
** *** *** * * * if(m > 180)
** * * ** ** ** **** *
* ** * * * * ** * * * * ******** * ** = 360 - m ;
** ** ** ** * ***
*** * ** * * * * ** * ** * * ** * * * **
* * * ** *** ** * *** * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * *** * * * * * * * * * * a,b=0;
* * * ** ** * * ** **** **** c,d=0;
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}
* * ** * ** * ** ** * ** * *
* *** ** * ** * ** * * ** * * * * * * ****** * * ** * * * *
}
** * * ** * ** * * * ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ****** *** * * ** * hour,min;
* * * * * * * * * * ** * * ** d,k,a1,a2;
* * * * ** * *** * * **** * * * * * * * *
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*** * ** ** ** ** * * 0;
** * ** * * ** * ***** ****
* * * * *** * * * * * * *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** *** * * * * * * * * * ***** a,b;
** * * ** * ** ** *** **** ** ** * * q,w,e;
** ** ** ** * * ** * ** * ** ** * ** * *** * * *
* * ** *** * *** * * * ****
{
* * * * * * * * *** * ** * * ** ** ** ***** ** == 0)
* * ** * ** ** ** * * ** ***** ** * * = 6*b - b/2;
* **** * ** **** * * * * ** * * * *** ** ** ** if(b%2 != 0)
** * * * ** * * **** * **** * ****** * * * * * * = 6*b - b/2 - 0.5;
*** * * ** ** * ** * ** * * ** ** *** * ** ** * * * ** *
* ** * ** ** * * ** ** ** * * * * **** = 360 - q;
* * ** * * * ** ** * * ** * * * * * ** * ** if(q<0)
* * ** *** ** * * * * * * *** * * ** * = 360 + q;
}
* * ** * * * * ** **
{
** * * * ** ** * * * * * * * *** ** * ** * * * == 0)
* * **** * * * *** * * * * * * ** * ** * ** ** * = 6*b - b/2 - 30*a;
* * ** * * ** * * *** * * * * * ** * * * ** if(b%2 != 0)
** * * ** * ** *** ** * * * ** ** * * = 6*b - b/2 - 0.5 - 30*a;
** *** ** * * * * * * * * * ** ** * * * * * * ** * *
* * * * * * * * * * * * * * * * * ** ** = 360 - q;
* ** * * ** * * * * * * ** ** * * * * ** ** if(q<0)
*** ******* * * ** * * * * * * * **** * * * = 360 + q;
}
* * * * *** * *** * * * *** * * * *** * * * * *** * * ***
* * * ** * *** * * ** * * * * * * * * * ** ** * ** ** * * *** * * ** * * * * **** * *
* * ** * ** * ****** * * ** ** * ** * * * * * * *** *** if(w>q)
* * * * * ** * ** * **** * * ** * ** *** * * * * * *** * * * ** * * *** *
** * ** * * ** ** * ** * * ** ** * ** *** = b%2;
* * * * **** ** ** * 0;
}
answered
Dec 1, 2016
by
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * * * * * * * a,b=0;
* * * * * * * * * * * * c,d=0;
* * ** ** * * ** * *** ** * ** * * * * * *
** *** * * * * * ** ** * ** * ** * * * ** * *
*** * ** ** ** *** * ** * * ** * **** **
** *** * ** * * * * * *** *
* ** * ** * * * * * * * ***
** ** * ** * * * * * ** * ** * ** * * ** * *** * ** ** **
** ** * * * **** * ** * * **
* * ** * * ** ** * * * **
** * * * *** * * * * * *** *** ** ** * * * * *** * ** * * * ***
}
* * ** ** * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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