0 like 0 dislike
9.6k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 9.6k views

62 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * * **** * *

#include <ctype.h>

#include <math.h>

#include * *** *******



int main(){
*** * *** * * ****** h,m;
**** * ** * * * ** *** * * * *** * **** ** **
** ** * *** ** **** * * arch,arcm,sum=0;
*** * ** ** *** *** * ** *****
** *** * * * **** ** * * ** = m * 6;
* * ***** *** * * ** * = h * 30 + m * 0.5;
* * * * * * ** * *** * * > arch){
* * **** ****** * * **** * * ** * ** *** * * ** = arcm - arch;
** * * * ********* *** * * ** ** ** * ** * * * * * * ** *** *** ***
* * *** * *
* **** * * * ** ** < arch){
** *** * *** ** * **** ** ** * * ** * ** * = arch - arcm;
** ***** *** * * ** * *** *** *** ** * *** * * * * *** * * *** *
* * * * * * *** **
* * **** ** *** * * * * * * == arch){
**** * * * * ** ** ** * *** **** ** * ** * * **** * **** **
***** * * **** * ** ** * ****
****** *** * *** ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include * ** ***

#include * **** *

#include <ctype.h>

#include <math.h>



int main()

{
**** ***** * * * * a,b,c,d,e;


* * ** * **** ** * ***** * * *
* * * ** ** *** ******** * ** ** *****


** * * ** * * * * * *****
* ****** ** * * *** **


* * * *** ** ** *** * ****




*** * ** ***** (c>=d)
** ** ** ** ** * ***
** ** * ** ** ******* (c<d)
* * **** * ** * * *


**** ** *** * ***** * (e>180)
* ***** * ***** * **




* ******** ** ** *** *** *** * * * * *** ***
** * ** **** * *** * * *** * 0;



}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include * ** * * * *



int main()

{
** * **** ****** ** * ** ** * * ,j ,n=0;
**** ** * * *** * * * i;
* ** * * * * * *** * * * * * * *
* * * * ***** ** = i % 12 ;
* * *** *** **** =( i * 30 )+( j / 2) ;
* *** ** * * * = j * 6 ;
* ** ** **** ** =k-l ;

if(m < 0)
** *** * **
** ***** * * * *** * *** * ** = - m;
** *** * *** *
* ** * ** * *** if(m > 180)
* ** * * ** *
* * ** * * * ** ** *** * * * = 360 - m ;
* * * * ******* *
* * ** ** *** ** * * ** *
*** ** *** ***** * * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** *** * *** h,m;
** * * ** * ** ***** ang1,ang2;
* ** ** * * * * *** * * * * * *** * ** *** * * * *


** * ** * ** ((30*h+0.5*m)>6*m)
* * * ** * *
** *** * * * * * *** **** ** * * ** ** = (30*h+0.5*m) - 6*m;
** * ** * ** **** * * * ** ** * *** * = 360 - ang1;
* ** * ***** **** ** ** **** ** * (ang1 > ang2)
**** * * *** * * **** * ** ***** ** *** ** ** *** **
* *** * * *** * * ** * ** * *
* * ** * ** * ** ** * ** * * ** * ** ** **** ** ***** * * * * *
* * **** *** *
* * ** * * * * *
* *** *** * ** **
* ** * * * *** * * * * ** ** ** * = 6*m - (30*h+0.5*m);
* * * * * *** *** * * ** * * ** **** = 360 - ang1;
* ** * * * * * * * * *** ** * * ** (ang1 > ang2)
* * **** ** * ** ***** * ** ** * * * * * * **** * **
** * * ** * ****
* *** *** * *** **** ***** * **** * *** *** * **** * *** * ** *

   }
**** ** * *** * *** * * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * * * * *
* * ** ** * * * *



int * *


** * ** * a ,b ,i;
* * * ****** * **** c;


* * ** *** * ** *** * *** ** * * ** *** *
** * * ***** * * * * * * * **** * ** *


** * * *** * * * != 12)
* * * *** * ** * * * = b*6 - b*0.5- a * 30;
** * * *** * * * * *
* * * *** ** * ** = b*6 - b*0.5;


*** * *** * * * * * * c * * 0 )
**** * ** * ** = -c;


* * * * * * ** * ** * * * ** ** c);



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include * * ***** *



int main()

{
** ** * * * ****  m=0,k=0,l=0 ,j ;
** * ** * ** *** * * i;
* *** * * ***** **** * *** ** ** *** *
*** * *** ***** *** = i % 12 ;
* * **** * * =( i * 30 )+( j / 2) ;
******* * * ** ** * ** ** = j * 6 ;
* **** ** ** =k-l ;
* * * * ***** **** *** < 0)
* ****** * * **
* * * * ** ** * * * * ** ** **** ** = - m;
** ** * * * ***** *
* *** * * * * * * ** * if(m > 180)
** *** * * *****
* ** **** * **** ** * * * *** * * = 360 - m ;
** * ** **** ** **
* * * **** *** * * ** * ** *
* * *** *** * * * 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
***** ******** ** *** * * a,b=0;
*** * ** *** ** * * c,d=0;
** **** ***** * ***** * ********* *** ** * ** * ***
** *** ** * * * ** ** * * ***** **
* * * * * ********* **** *
* * *** ** ****** *
* * * ** *** * * **
**** ***** * * *
* * ** * ** ** * * ** *** ** *** ** * * *** * * * * * *

    }
*** * ** * * **** ** * * **
** ** ** * ***** * * ** * *** * ** ** ** *******

    }
* ** ** ***** * ** **** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
* ** *** * * * * * ** hour,min;
* * **** * * ** d,k,a1,a2;
**** * **** ** *** * ** ** * ***** * ** ** **** * *
* * *** ** * * (hour==12)
*** * * ** * * ** ** *
** * * * * *** * ****
*** ** * ** *** ** ** ***
** * *** *** **** * * *

    
* * **** ************ * ** * *
** * * * ***** * ** ** * **
**** * *** ** * ** * *
* *** * ***** * * **
* * * * * *** * *** *
* **** * **** * * * * * ** *

    
* * **** * * * * *
** ** ******* * * *** ** *** * * * * * **
* * * ** *** **
* *** **** * ***** ** * * * ** * *** ***
**** * *** ** * ** *
* ***** * * ***** ***** 0;

    
* * ***** * * ** ****
** *** * * **** * * * * **
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
****** **** ***** * * * * * a,b;
** *** ** * **** ** ** * ** q,w,e;
** ** * * ** * * * * ****** * * *** *** * *** ** *
** * *** * * ** ** * **

    {
* ******* ** ** * ** ** * * *** ***** == 0)
* * * ******* ** * * ** ** ** * ** * ** *** * *** = 6*b - b/2;
* * * * * * **** ** * * * *** * **** ** if(b%2 != 0)
* * ****** **** ** *** **** ******* ** * *** * = 6*b - b/2 - 0.5;
* * ***** * * * ** * * * * * * * ** * *
* * ** ** ** ** **** * * * * *** * ** *** = 360 - q;
* * ** ****** ** * **** ** * **** * if(q<0)
* ** * **** * * ** * * * * * * ****** = 360 + q;

    }
** ** ** *** ** * *

    {
** * * * * ** * * * * ** * * ** * * ***** == 0)
*** ** * ** * *** *** *** *** *** ** * * * = 6*b - b/2 - 30*a;
* * *** ***** * ************ * * ** * * if(b%2 != 0)
** ** ** * * * * * ** * ** *** ** = 6*b - b/2 - 0.5 - 30*a;
****** ** ***** * * **** *** **** *** * ** * * **
* ** ** * ** **** * * ** **** ** *** = 360 - q;
** * * * * * * **** * * ** * * * ** ** if(q<0)
***** * ** * ** * * ** ** * * * *** ** * = 360 + q;

    }
**** ** **** * * ** ** * ** ** * ** *** * ** * * ** *
** ** ** ** * * * * **** * * * ***** * * * ** ****** * ******* ***** **
** ** ** **** ** * *** * * * * * **** ** ** * ***** if(w>q)
*** *** * ** * ** *** * ***** * ** * *** * * ** * * * * ** * *** * *** * ** *** * * *
** * ** * * ** * ** ***** **** * ***** = b%2;
* ** * ************ * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
** ** *** *** * *** ** a,b=0;
***** * ** ** ** * **** * c,d=0;
* * **** * * * ** **** *** ** ** ** * ***
* * * * * * ** * * *** ** * * ** ** * * *
* * * ** **** ** **** * * * **
**** **** ***** ** ***** *
*** ** ** *** * *** * * ****
* ** ** *** * *** * * * * * * ** * * * ** ** ** *
** * ** * ***
* * ***** ** * * * **** ** *
* *** * * * ** * *** ** ** * * ** *** ** * * * *** *

    }
* * **** **** ** * * **** *** *** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.159.115.31
©2016-2026

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.6k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 12.1k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 6.8k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 4.1k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users