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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
by
Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * * * **
#include <ctype.h>
#include <math.h>
#include * * * * ** * ** * * *
int main(){
* *** * * * ** ** * * * * ** h,m;
**** * * * * * * * * * * * * * ** * * * * * * * *
* ** ** ** * * * * *** * * * arch,arcm,sum=0;
* **** * * *** * *** ** * * * **** ** *** *** **
* * * * * * = m * 6;
** *** * * ** *** = h * 30 + m * 0.5;
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*** * * ** ******* * * * * * * * * * * ** * * ** = arcm - arch;
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* * * * * ** * * * * * * * ** * ** * * * ** * = arch - arcm;
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** ** * * * * * *** * ** ** * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * *** *** ***
#include * * * * *
#include <ctype.h>
#include <math.h>
int main()
{
** * ** ** ** * ** ** * * * a,b,c,d,e;
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** * * *** ** **** ** * * 0;
}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include * **** * * *****
int main()
{
* * ** ** *** * ** * ** * ** ,j ,n=0;
* * * * * * i;
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* * ** * * * * ** * * = i % 12 ;
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if(m < 0)
* * * **
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* * *** **** * * * * * * * * * * * ** * * = 360 - m ;
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*** * ** * ** * *** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * * h,m;
* * * * * * * * * * * ang1,ang2;
* *** * ** * * * * * * ** * * ** *** * * * * * * *
* *** ** * * ** * * ((30*h+0.5*m)>6*m)
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* * * * * * * * * ** ** * * ** ** = 6*m - (30*h+0.5*m);
* * * * * * * * ** * * * * * = 360 - ang1;
** * * ** * * * * * * * * ** (ang1 > ang2)
* * * *** *** *** * * * **** * ** * ** * * * ** * ** ** *
*** ** * * * * * *** * * ** * * * * *
** * *** * *** *** * * * * ** * * ** * ** * ** * * * * * * ** * *
}
** *** ** * *** * ** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * ** *
* * * **
int *** *
* ** **** * * *** * * *** a ,b ,i;
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* ****** ** **** * * ** != 12)
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* * * * * * * * = b*6 - b*0.5;
* * * * * * * * *** c * * 0 )
** * * * * = -c;
* ** * **** * * * * * * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * ** * ** *
int main()
{
**** * * *** ** * * m=0,k=0,l=0 ,j ;
** ** * * * * i;
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** * * *** * * * = i % 12 ;
** * * ** ** ** * * * =( i * 30 )+( j / 2) ;
* * * * * * ** * = j * 6 ;
** * * * * ** * * * =k-l ;
* *** * * *** * * * * < 0)
* ** * * * * * * * *
* ** * *** * * * * * = - m;
* ** *** * * * *
* * * * * ** if(m > 180)
* ** ** ** * * * **** *
* * ** *** * * * *** ** ** *** * * = 360 - m ;
* *** * * *
**** * * * ** ** *** *** * *
* * * * * * * *** * ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
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}
** * * ** * *** * * * *
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}
* ** *** * * * * * ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * *** * hour,min;
* * *** ** * * ** * * * d,k,a1,a2;
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** * * * * * * * a,b;
** * * * * ** * * **** q,w,e;
* * **** * * * * * * * * * * ** * * * * * *** ***
** * * * * * ** * * * *
{
** * * * * * * ** ** * * * * * *** * * **** * == 0)
*** * * *** ** * ** * * ** * * * * * * = 6*b - b/2;
* ** * * ** * * *** * * ** ** * * *** * * if(b%2 != 0)
** * ** *** * * * * ** **** ** * * ** * = 6*b - b/2 - 0.5;
** ** * * * *** * *** ** ** *** ** ** * * *** * *
* * * * ** * * * * ** * ** * * * = 360 - q;
* * * * * * * **** **** * * * * ** * * * ** if(q<0)
* * *** * * * * ** *** * * * * * * * * * * * * **** ** = 360 + q;
}
* * * ** * * * *
{
** * * * ** * * ** * * * * * ** * * * * * * == 0)
* ** * * * * * * ** * ** ** * * * * * ***** = 6*b - b/2 - 30*a;
* * * ** ***** * * * * * * *** * * * ** * * * if(b%2 != 0)
** * * ** ** ** ** ** * ** ** *** * ** * * * * = 6*b - b/2 - 0.5 - 30*a;
* ** **** * * * * * * ** * ** * * *** * * * ** *** **
** * * *** * ** ** ** ** * * * * ** ** * * * *** ** = 360 - q;
* ** ** * * * * * * * ** ** * * * * ** * * * * if(q<0)
** * ** ** * * **** * ** * **** * * ** * * * * * * * = 360 + q;
}
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* **** * ** ****** * * * * * ** * * * * * * ** * * if(w>q)
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** ** ** * * * * * * * * * * **** **** * ** = b%2;
* * * **** * * * ** * ** ** * ** 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * ** * * * **** *** *** a,b=0;
*** *** * *** * * * * *** c,d=0;
* ** * *** * * * * * * *** * *** * *
** * * ** ****** * * * *** * * *** ** ** * * *****
** ** ** * * *** ** ***** * * **
* * ** * ** * * * * * *** * *
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* * * ** * ** * * *** * *
* * ** * ** **** * * ** *
*** * *** * ** ** **** * *** * * * ** * * * ** *** * * ** * ** * *
}
* * * *** ** ** * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
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ID: 18085 -
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