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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * ** * * ***** * * *
#include <ctype.h>
#include <math.h>
#include * * * * * ** *
int main(){
* * * * *** **** * *** ** ** * *** h,m;
* * * * * ** * * * * **** * * * * ** ** * * * * * * ** * *
* * * **** * * * ** * ** * * * arch,arcm,sum=0;
* * * * * * *** * ** * * **
** * ** * * * ** ** * * = m * 6;
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}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * ** * *
#include * * **** **
#include <ctype.h>
#include <math.h>
int main()
{
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}
answered
Dec 1, 2016
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410523016
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Hidden content!#include * ** ** * *
int main()
{
* * * * * ** * ** ** * ** ***** ,j ,n=0;
* * * * * * * * *** * * i;
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** * ** ** * * * ** * = i % 12 ;
* ** * =( i * 30 )+( j / 2) ;
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* ** * * ** * =k-l ;
if(m < 0)
** ** * ** * *
*** * ** * * ** * * * *** **** * ** = - m;
** ** ** ** * * **
** * * **** * * * *** **** if(m > 180)
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* * ** * * * * * * * * * * = 360 - m ;
*** * * * *
**** ** * * * * * * * * ** * *** ****
* ** *** *** ** * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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** ** * *** * * ** * * (ang1 > ang2)
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* * ** * ** ** * * * ** * * **** * * * *** ** (ang1 > ang2)
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}
*** * * * * * * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ** * * * *****
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int ** *
** * * * * * * *** ** * a ,b ,i;
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* * ** * c * * * 0 )
* * * * ** * **** * * = -c;
* * * ** * * * * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * ** * * * * *
int main()
{
* * * ** ** * ** m=0,k=0,l=0 ,j ;
* * * ** * * i;
* * * * * * * * ** ** * ** ** * **** * * ** *
*** * * * ** *** * *** = i % 12 ;
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* * * * ** * =k-l ;
*** *** * * ** ** * < 0)
* * *** ** * * * * *
** * * * ** ** * ** * * * * * * * *** = - m;
** * * * *** * *
* * * * ** ** if(m > 180)
** *** * * * * * *
*** * * ** * * ** ****** * * * ** * * * = 360 - m ;
* * * ** * **** *
* * * ***** * ** ** ** * * * *** * *
** * ** * * * *** ** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
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}
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}
* * **** *** ** *** * * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * *** * * ** * * * * * * * * hour,min;
* *** ** ** * * * *** d,k,a1,a2;
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** *** * * ** * a,b;
* * ** ** * * ** *** ** * q,w,e;
* * * * *** * * ** ** * ** **** * * * * * *** * ***
** ** ** ***** * *** *** * ** ** *
{
* * * ** * * ** * *** *** * **** ** ** * * ** * * **** * * * * * == 0)
* * * ** * ** * *** * * ** ** * ** * * = 6*b - b/2;
** * * * * *** * * * * * * * ** * * ** ** * * * * * * if(b%2 != 0)
** * * * *** ** **** ** * * * ** * ** = 6*b - b/2 - 0.5;
* * * ***** * ** ** * * * ** * *** ** * ** * * * * * *
* ** ** * * * * ** ** ** ** * * *** ** * * **** = 360 - q;
* * ***** ** * * * * * * ** * * * * * * ** * * **** if(q<0)
** * * * * ** * * * ** * * * **** ** ** * = 360 + q;
}
* * * * * * ** *
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* * * * * ** * *** * * * * * * * *** * * * * * * == 0)
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* * * * * * ** ** * * * ** ** * *** * ***** ** **** if(b%2 != 0)
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* * * * * * * *** * * * * * ****** * ** * **
* * * ** * * * ** * * * * *** * * ** ** **** * * * = 360 - q;
** ** * * ** * * ** * * ** ** * * * * * * * * ** * if(q<0)
** *** * *** * ** * * * * ** * * * * ** *** = 360 + q;
}
*** * ** ** ** ** * ** * ** * ** * * * * * * * * * * * * *
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* * * * * * ** ** * * * * * ** ** * * * * ** * = b%2;
* ** *** * ** ** ** * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* **** * * * * * **** * a,b=0;
** * ** *** ** ** ** ****** c,d=0;
** ** * * ** ** * *** **** * * * * * * * * * **
* ** ** * ** * * * * * ** * * * * * * * ***
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* * * ** * *** * * * *
* * ** ** *** * **
* * * * ** * **** ** * * ** * * * ** * ** * * **** *
}
* * * * * * ** * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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Shun-Po
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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