0 like 0 dislike
7.8k views
時鐘上有時針有分針,分針每一分鐘跳一次,分針每跳一次時針也會前進相對應的角度。請設計一程式,由使用者輸入一個時間,程式會計算出時針與分針間的夾角後輸出。

輸入說明:輸入包含兩個正整數,兩個數之間由一個空白隔開,第一個數字代表時,第二個數字代表分。

輸出說明:請輸出時針與分針間較小的那個夾角。

輸入範例:

12 31

輸出範例

170.5
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 7.8k views

62 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * ** * * *

#include <ctype.h>

#include <math.h>

#include * * *



int main(){
* * *** * ***** ****** * *** * h,m;
* *** ** **** ** * ** ** ** ** ** * ***** * * * * **** ** ***
***** ******* * ** * * ** arch,arcm,sum=0;
* **** *** * *** **** ** * **
* * * ** * * * * ** *** **** = m * 6;
*** ** ** *** * * ** ***** = h * 30 + m * 0.5;
* ** * ***** * ** ** * * * > arch){
*** * * ****** ******* *** *** *** * ** ****** * = arcm - arch;
*** * * * * *** *** * *** * * * * * ** ***** * * * * **** *
** * * *** **** * *
* * * * ** *** ** ***** < arch){
*** *** *** ** * ** ** * ** * ** **** **** = arch - arcm;
*** * * * ** ** ** *** ** * *** * * * ***** * ** * *
** *** * * ** * * *
* *** * ** ** ** * ** == arch){
* * * * * * * ** * ** ****** * * * ** * * * ** ** * ******
* ** ** * *****
* * * * * ***** **** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
#include ****** *

#include *** * ** *

#include <ctype.h>

#include <math.h>



int main()

{
** *** * * *** * **** a,b,c,d,e;


* **** ******* * * ** * * * ** **
** ** * * *** * **** * * * * * ******


** * *** * ****** * ** * *
** * ******* * * ** ***** *


** ** ***** * ** * **




** * ** * * * ** (c>=d)
* * * * * * * ***** * ****
* *** ** *** ** ** * * *** (c<d)
* *** *** * * * * **


** ** ** *** * * ** ** * * (e>180)
* * *** *** * * * ****




* * ********** ** ** **** ***** * *
* *** * ** ** ** 0;



}
answered by (-136 points)
0 like 0 dislike
Hidden content!
#include ** * * *** *



int main()

{
* **** *** * * * * * ** *** * * ,j ,n=0;
* ** * * * *** * i;
*** * * ** * * * * * ** ** *** * **
* * * * = i % 12 ;
* * **** * * * =( i * 30 )+( j / 2) ;
** * ** * ** * = j * 6 ;
** ** *** **** * =k-l ;

if(m < 0)
** * * *** ***
* * ** * *** ** ********* * = - m;
** **** ** ** *****
*** * ** ** *** ** if(m > 180)
**** * ** * ** **** * **
* ** * **** * * ** * *** * * * = 360 - m ;
*** *** * ** ***
*** ** * * ** * * *** *
****** ***** ** 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * *** * ** h,m;
** ****** ** * * ** ang1,ang2;
* * *** * * * ** ** * ** ** * ** * *** **


** ** * **** * ((30*h+0.5*m)>6*m)
* * * *** *
* * *** * * * * ** ****** * ** ** * * = (30*h+0.5*m) - 6*m;
* ***** * ** *** ** ** **** * * = 360 - ang1;
* * * * * *** * * *** * ** * (ang1 > ang2)
** *** * ** ** * * * *** *** ** * ** * * **
* ** * *** ** ** * * * ** **
*** ** * * ** *** ****** * *** * * * *** * * * * * * ** *
* **** * ***** *
******* * ******* *
* * ** * * *
**** * * * ** **** **** ** = 6*m - (30*h+0.5*m);
*** **** * * ** * * * * ** * = 360 - ang1;
* *** *** * ** **** * *** * ***** (ang1 > ang2)
** * ** * ** * **** ** *** ** ** ** * * * * * ***** ** * *
** * **** ***** * ** * * ** * * * *
* ***** * ******** ** * *** **** ** * ** ***** * * ***** ** ***** *

   }
* * * ** * ** **** * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include * **** *
*** *** * * **



int *****


* ** ******** ** * ** a ,b ,i;
** * * ** * *** * c;


** ** * *** * * **** ** ** * ** * **
* * ** * ** *** ** *** * * * *


*** ** * ** * ** ** != 12)
*** ** **** * * * = b*6 - b*0.5- a * 30;
* **** ** ** **
* * * ********** * = b*6 - b*0.5;


** * ** ***** * c ** 0 )
* **** * * *** * = -c;


* **** * ***** ***** * ** ** * * * * * c);



return 0;

}
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include **** ** ** * **



int main()

{
** * * * * * * *  m=0,k=0,l=0 ,j ;
* * * **** *** * *** i;
* * * * * * * **** ** **** ***** * * *
* ** *** ********** ** = i % 12 ;
******* ** *** ** =( i * 30 )+( j / 2) ;
*** **** ** * = j * 6 ;
* *** * **** * * =k-l ;
*** **** **** * * ** < 0)
* ** * * * ** * *
*** * **** *** ** * * ** * = - m;
** * * * *
* ** ** * * ** ** if(m > 180)
* ** * * ** * ******
** * ** **** * * **** **** * * ** = 360 - m ;
**** ** ** * ** * *
* * * * ** * **** * ** *
* * ****** * ** 0;

}
answered by (-60 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
*** * *** * * ** ** a,b=0;
* * ** ** *** * * * ** c,d=0;
* ** * ****** ******** * * * * * **** * ** *
** *** ** ** ** * * **** * * *** * *
*** * * ** *** ** ***** ** **** *
* * * ****** * ** * *
* ** * * * ** ** * * **
**** *** ** *** *** **** * * ***
**** ** *** * ** * * * ** *** **** * **** * ** ** * ** * * * *

    }
* ** * **** ** * * *** *
* ** **** * * ** **** * * * * * ** ** * ** * *** * *** * *

    }
* * ** ***** *** * **** ** 0;

}
answered by (-140 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
** ** * *** * ** * hour,min;
* ** ** ***** *** ** ** d,k,a1,a2;
* **** ****** * ** * ** * * ****** ***** ** * * * *
**** *** ***** ** ** *** (hour==12)
* * ** ** * * ** * * *** * **
* * * ** ****** ** **
* *** *** *** * * * * **
* ***** * * *

    
* *** ** * *** *** ** ** ** ***
* * ** * ** ***
** ** * **** * *
*** * ** * * * ** ** *
* * * * * ** ** ** **
** * * ** * ** ** ** ****

    
* *** * **** ***** * **
*** ** *** *** * * ** *** ** * **** * ***
** * ** * ** ** * ** *******
******* * *** * ** * **** * *** * * ****** **
*** * *** * ** ***** *
*** *** * * 0;

    
******* * ** ** *****
** *** * * * *****
answered by (-122 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{
*** * *** * ******** a,b;
*** ** *** * *** * q,w,e;
* *** ** * ******** * ** ** *** ** **** ** ** * *
** * ** * **** * ** ****

    {
* * * **** * * **** * *** ** *** * * *** ** * * == 0)
* **** * *** ** **** *** * ** *** * * ** * *** = 6*b - b/2;
* ** * ** *** * * ** ****** * **** *** *** if(b%2 != 0)
* * * * * * ** * *** ** * * *** * ** ******* * = 6*b - b/2 - 0.5;
* * ** ** * ** * * ****** ** *** ****** * **
******* **** * * * * ** ** * ** *** ** ** = 360 - q;
* ** *** **** *** ** * *** * * * * **** * * * if(q<0)
******* * * ** **** ** * ** * * * **** * * = 360 + q;

    }
* *** * ** * * ***** * *

    {
* ** *** ***** *** ** **** * == 0)
**** **** * * *** * * * * * * * * ** * **** * = 6*b - b/2 - 30*a;
* * * ** * * * * *** * ** *** ** * if(b%2 != 0)
** * * ** * ** **** * ** * * * * *** * = 6*b - b/2 - 0.5 - 30*a;
* ** * ***** ** ** * *** ****** * *** * ** * ** * * *
* ** ** ** * *** *** * **** ** ** * **** *** ** ** ** = 360 - q;
** * * * ** ***** * ** ** ** ** **** *** if(q<0)
** * ****** * ** ** *** * * *** * ** * ***** = 360 + q;

    }
** * * ** ** * * * * * * * * * * *** ** **** * *
* * ** ** ***** ***** ** *** * * **** *** ** * *** * * ** ** ***** * ** ** *
* * ** * ** * ** * ** *** ** * * * if(w>q)
* ******* * ** *** * * * * * * * * ** * * * * ***** ** * **** ** * * *
* ***** * * * ** *** ***** ** * = b%2;
** * ** * *** **** **** 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main(){
* * * * * * * * ** * * *** a,b=0;
* *********************** c,d=0;
** * * * * *** **** ** *** * * *** * * * ** * * *
** *** ******* ** **** ****** *** * ** * ** **
* * ** **** * **** ** *******
* ** **** ** * ** * * **
* ** ** ** ** * * *
*** ** * * * * ** ******* * *** * *** * *
* * ****** ** ** * *
* * ** * * * **** **
** * **** * * * * * * ****** * **** ** ** * * ** * * **

    }
* *** ***** * ** * **** 0;

}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.190.40
©2016-2025

Related questions

0 like 0 dislike
16 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 2.9k views
0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 9.8k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 5.6k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 3.4k views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,442 answers
172,219 comments
4,824 users