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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * * *
#include <ctype.h>
#include <math.h>
#include ** ** **** ****
int main(){
***** * * *** * * * * ** h,m;
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* * * ** * * * * * ** * * * arch,arcm,sum=0;
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answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * *** ** * *
#include * * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
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answered
Dec 1, 2016
by
410523016
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Hidden content!#include ** *** * *
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{
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}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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}
** ** * * * * ** * * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * *
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** ** * * * * * *** *** ** * * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include *** * * * * ***
int main()
{
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** ** * ** * * * * ** =k-l ;
* ** ** ** * * * * * < 0)
* * ** ** ***** ** * * *
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** * ** * ** * * *** * if(m > 180)
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* ** * * * * * *
** * ** * * ** * * * * * ** * * ****
** * * * ** * ** * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
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}
* * * * ** * * * * ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * ** ** * ** ** * * * a,b;
*** * *** ** * ** * * * * * * * q,w,e;
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{
*** ** ** * * * ** * ** * * * ** ** **** ** * * ** *** == 0)
** ** * ** * * ** ** ** * * * * ** * * = 6*b - b/2;
** ** ** * * ** * *** * * ** ** ** ** ** * * * *** * * if(b%2 != 0)
* * * * * * **** ***** * * ****** * * * * * ** * ** ** * = 6*b - b/2 - 0.5;
*** * * ** * * * ** ** * * * ** * * * *** ***
** * * * *** * * ** * * ** *** * * * ** * **** = 360 - q;
* **** * * * * * * * * ** ** * *** * * * * * * * if(q<0)
** * * * * * * * * ** * * * *** * ** * * = 360 + q;
}
* * * **** ** * * * * * **
{
** * * * * * * * * * * * ******* * ** * == 0)
** ** * * * * * ** * * * * ** * ** * = 6*b - b/2 - 30*a;
*** ** ** * **** * * *** * ** * * * * * * ** if(b%2 != 0)
* * * * **** * * * * *** * **** * * ** * ** * = 6*b - b/2 - 0.5 - 30*a;
** * *** * ** **** ** * * * * *** * ** ** * * * * ***
**** * * *** * * * * * **** ** * * ** ** * * ** **** = 360 - q;
* * * * * * * *** * *** * * * *** * * * if(q<0)
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}
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*** * * ***** * ** * * * * * * ** * * * * *** * ** if(w>q)
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* * ** * *** * * ** ** * * * * * * ** * * = b%2;
* *** ** ** * ** ** * * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* * * *** * * ** * * * a,b=0;
**** ** * * * * * *** * ** c,d=0;
*** *** ** *** * * ** * * * * * ***
*** * * * * * * * ** *** * ** *** * * * ** ** **
* * * *** * * * ** * ** * ***** * ** ** *
* ** ** * * * * * ***
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* ** * * * * ** * *
**** * * *** *** ** * * ** ** * * * ** ** * ******* ** ** **** ** *** * * * *
}
* * ** * *** * ** ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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ID: 18066 -
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AC 20161201 第二次期中考公告
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