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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
by
Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * * * ***
#include <ctype.h>
#include <math.h>
#include * * * * ** ** **
int main(){
** *** * * * ** ** *** * * h,m;
** * *** * **** * * ** * * ** * * ** * * *** * *** **** **
* * * *** *** * * * * * arch,arcm,sum=0;
* **** ** * *** * *** **** ** * * ** **
** * ** * * * * * ** * * = m * 6;
* *** **** * * * ** * = h * 30 + m * 0.5;
* * * ** * * **** * * ** * > arch){
* * * * * * ** *** * * ** * * * * * * * **** * = arcm - arch;
* * * * * ** * ** * * * *** * * **** * *** ** * * * * ** * * *
**** * * * * * *** * * * * *
** * ** * * ** ** * < arch){
* ** ** **** * ** * * * * * * * * ** ** ** = arch - arcm;
* ** * * * * ** * * * * * * * ** * ** **** * ** ** * ** *** * ** **
* * *** * ** * * ****** ** * *
** *** * * * **** ** * *** == arch){
* * ** *** * **** * * * * * * ** * * * ** *** * * * * *** **** * * * *
* ** * ** ** * * ** * * * *
* * * ** **** * * * * * * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * **** ** *
#include * ** ** * * *
#include <ctype.h>
#include <math.h>
int main()
{
* * * * **** * * * a,b,c,d,e;
*** ** * **** * ** ** * ** **** * * * ** * *** *
*** ** * * * ****** * *** *** * *** ** * * **
** * ** * ** ** * *** ** *
** * *** *** * * * * * *
* *** ** * * * *
* ** ** * * ******* * * * * ** * * (c>=d)
* * * * ***** ** **
* ** * ** * * *** * ** (c<d)
** * * * * * * * * ** * *
* * ** * ** * * * * ** (e>180)
* * * ** * * ** * * * **
* * * * * ** * * * * * ** * * **** * ** * *
* *** ** * * *** ** * * * ** * 0;
}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include *** * * * *
int main()
{
** * * * * * * * * ** *** ,j ,n=0;
* * * **** * * * ** i;
* * * * ** *** ** * * *** * ** **** ** * * * * * *** **
** * ** *** * ** * = i % 12 ;
** * ** * * =( i * 30 )+( j / 2) ;
* * * ** * ** * * * = j * 6 ;
** * ** * * *** ** =k-l ;
if(m < 0)
*** * * * * ** **
** * * * * * * * * * ** * * = - m;
* ** * ***
* * * * * ** * * if(m > 180)
* ** * *** * ** *
* * * * * * ** * * * ** ** * * * * = 360 - m ;
** ** * *** **
** ** ** * * * * * * *** * * * *
* * * * * * * * *** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** * * * ** * * h,m;
** * *** * * * * * ** ** ang1,ang2;
*** * * * * * ** * * ** * *** ** * ** *** * * ** * * * *
* * * * ** * * **** ** ** ((30*h+0.5*m)>6*m)
* * * **
* * ** * * ** * * * * * * ** = (30*h+0.5*m) - 6*m;
*** * * * * * *** * * * * ** * * * = 360 - ang1;
** * * * * * * * * *** ** * * * * * * (ang1 > ang2)
* * ** *** ** * ** ** * * * * * * * * * ** * ***** * * * *
** * ** * * * * * * * * ** * * * * * * *
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* * * * * * ** * * *
* ** * * * * ***
*** * ** * ****
*** * * * **** * * * * ** * ** ** * * ** * = 6*m - (30*h+0.5*m);
* ***** ** * * * * * ** *** ** * * ****** * = 360 - ang1;
* ** * * *** * ** * * ** * * * ** * *** (ang1 > ang2)
* * * * * *** * * * * * * * * * * * * ** ** * ** ** * * * *
* ** ** * * ** * ** * ** *** * *
* * ** * *** ** * * ** * ** ** * * *** * ** ** * ** *** * ** ** * * * ** *
}
* *** * *** * ** ** ** ** * 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * *
* * * *** *
int *
* * * * **** *** a ,b ,i;
* * * * * * ** c;
* * **** * * * * ** ** *** * * * * * * *** ** *
* * * * ** ** *** * * ** * *** * * ** *
** **** ** * * * * * ** != 12)
** * * * * * * * = b*6 - b*0.5- a * 30;
***** ** * * * * **
* *** * * ** *** = b*6 - b*0.5;
* * * * ** * * *** * * * c *** 0 )
* ** * * * ** = -c;
* ** * ** * * **** * * * * ** * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * *** * **
int main()
{
**** * * ** ** * * * *** m=0,k=0,l=0 ,j ;
* * * ** * * * * ** i;
** * ** **** * **** *** **** ** * * *** * *
** * * * * * * * = i % 12 ;
** ** * * * * ** * =( i * 30 )+( j / 2) ;
* * * ** * * * * ** = j * 6 ;
* * * * *** * =k-l ;
* * * * ** * < 0)
** * * * * * * **
* ** ** ** * * * *** *** * * ** = - m;
* * * * * * * * *
*** * * * * * * * ** ** if(m > 180)
** * * * * ** * **
* * * * * * ** *** * * ** *** * **** * = 360 - m ;
* * ** *** * ** * *
**** * ** * *** *** * ** * * * * *
* * * * * * * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* *** * * * *** * ** * * ** * a,b=0;
* * * * * *** ** * * * * * * c,d=0;
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* * ** * * * * * * ** * * * ***** * **
** ** * * * * * * * * ** * * * * **
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** ** * ** * * * * * ** ** * * ***
* *** * * * * * * *** ***** ** * * * * * * * ** * * * ** * * * ** ** * * **
}
* **** * ** * * ** **
* * * ** *** ** * * * * ** * *** * ** * ** ** * ** * * ** *
}
* ** ** * * * * *** ** ** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** *** ** * * * * ** hour,min;
* ** * * ** * * ** * ** * ** * * *** d,k,a1,a2;
* * * ** ** *** ** * *** * * ** * * * * * * * ***
* * * * * * *** * * * (hour==12)
* * * * * ** * ** *
** ** * ** ** *
* * * * * ** * ** * * ** ** * * * * *
* ** * ** * *** * ** **
**** * ** * * ** * ** ** ** *
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* * ** *** ** ** * * ** ** * * * *
** * *** ** ** * * **
* ***** * * * ** ** * 0;
* * ***** ** **** ** * * *
* * * ** * * * *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ********* *** * * * * a,b;
** * * * ** ** *** * * q,w,e;
* * * ** ** * * * * ** * * * ** * ** ** * * **** **
* * * * * ** * * * * *
{
** ***** * ** * * * * ** ***** ** * * * ** * * *** == 0)
* * * *** * * ** * * *** ** * ** ** *** * = 6*b - b/2;
** * ** * * ** ** ** * * **** * * * * *** ** * if(b%2 != 0)
** * **** * * * * ** **** * ** ** * = 6*b - b/2 - 0.5;
** * * *** * * ** * ** * * * ** ** ** ** * * ** * * *
** * * **** ** * * * ** ** ** ** * ** * * ** * = 360 - q;
** * * ** * * * * ***** * * * ** ** ** ** **** if(q<0)
* * * * ***** * ** * *** * * ** ** * *** ** = 360 + q;
}
*** * ** * ** * *
{
** * ** ** * *** * * ** ** * * ** * * ** * * == 0)
*** * * * ** * * * ** * * **** ** * ** ** * = 6*b - b/2 - 30*a;
* * * * * * *** *** * * * * * * * * * * * * * * if(b%2 != 0)
* * *** * * * * **** *** * * * ***** * * * * = 6*b - b/2 - 0.5 - 30*a;
* * ** *** ** * * * ** * ** * * *** ** * * * * * * **
* * ** ** ** * * ** * ** ** * * * *** ** * = 360 - q;
** * *** * * * * ** * * * * * * * * ** * * * if(q<0)
* * * * * * ** *** * * * * *** * ***** **** ** = 360 + q;
}
* * * *** * * ** *** ** * * * * * ** ** * * * * **
* ** * ** * ** * * * * * ** * ** * * * * *** * * ** * * **** * *** ** ** * ** ** * * * ** * *
*** * * * * * * *** * * ** * * ** if(w>q)
*** *** * **** * ** ** ** * * * ** ** * ** ** * * * ** ** ** ** * ** * * * *** *** * * * ** *
* **** ** ** ** * * * *** ** * ** * * * * ** ** = b%2;
* ** * * * * * ** * * * * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* ** * * * ** *** * *** a,b=0;
** * ** * * * ** * * * c,d=0;
* * * * * * * ** * * ** *** * * ** ** ** **
** * * ** * ** * * ** * *** * * *** * * * *
**** * * ** ** * * * ** **
** * * ** **** ** ** * * * *
* ** * * * ***** * ** * * *
** * ** * * ** *** ** * * ** * * * * * * * * ** **** * **
* ** * * * * * *
* * * * * * ** * ** ** *
** *** * * ** *** * * * * * * * * * * * * * * ** * * * * *** * * * *
}
* * ** * * * *** * ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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18k
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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Dec 1, 2016
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ID: 18085 -
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