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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
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Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * * * *
#include <ctype.h>
#include <math.h>
#include * ** * * *
int main(){
* * * ** * * **** * * ** * * * h,m;
** *** * ** * * * * * * ** * * * *** * ** * *
* * * * * * ** arch,arcm,sum=0;
** * * * ** * **** * * * * ** *
* * * * * * * * * *** = m * 6;
** * ** * * * * * * * = h * 30 + m * 0.5;
** ** * * ** *** ***** * * ** * *** > arch){
* * * * ** ** * * * * * ** ** * * * * ** *** ** = arcm - arch;
* * * * * ** ** ** * * * ** * * * * * * * ** * *
* ** * * *** * ** * *
** * * * *** * ** * * * * < arch){
* * *** * * * * ** * * * * * * * * * ** = arch - arcm;
*** ** * * * ** * * * *** ** *** * * *** * ** * * * * * * * * ** ** * * *
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* * * * * * * * *** ** * * * ** ** * *** * ** * ** *** * * ** * * * *
* * * * * * ** * *
* * *** * *** * ** ** 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * ** * **
#include ** * ** **
#include <ctype.h>
#include <math.h>
int main()
{
** ** *** ** * * * * a,b,c,d,e;
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* **** * ** * * * * *** **** ** * ** ** * ** * * *
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**** * *** ** ** * ** *** **
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* ** *** * * * ** ** * * * 0;
}
answered
Dec 1, 2016
by
410523016
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Hidden content!#include * * ** ** ** *
int main()
{
* * * * * ** * * * *** * * * ,j ,n=0;
** * * * * * * * * ** * i;
* * *** * **** ** * * * ** * * * * * * * * * *** *
* * * * * * * * * = i % 12 ;
* * *** * * * =( i * 30 )+( j / 2) ;
* * * * ** = j * 6 ;
* * * * * =k-l ;
if(m < 0)
*** ** * *
*** * * ** ** * * * * * * * * * * * * = - m;
* * * * * ** *
* * * * * * ** * ** if(m > 180)
* * * * **
* *** * ** * * ** * ** ** * * * * = 360 - m ;
** * ** ** ***
* * * ** * *** * * * * ** * * *
* * ** * ** ** * * ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * * * *** * * h,m;
* * * * * * *** * *** * ang1,ang2;
*** * *** * *** * * *** * ** ** ** *** ** ** * *
* ** ** * * *** * * * * * ((30*h+0.5*m)>6*m)
* **** *** ****** * *
* ** * * * * * ** **** ** * * * * = (30*h+0.5*m) - 6*m;
** * * * ** * ** * ** * * * = 360 - ang1;
** * ** **** *** * * * * ** *** * * (ang1 > ang2)
* * * ** ** * * * * * ** ** * * ** * * * * * * * * *
* ** ** * * * * ** ** * * ** * * ** * *
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* * * ** * ** * ** *
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* * ***** * * ** * * * * * * * * * = 360 - ang1;
* ****** *** * *** **** * *** * * ** * * (ang1 > ang2)
* * *** ** ** * * * * *** ** * * * * ** * * * * * ** * * * * *
* * ** * * ** ** * * * * * **
* ** * ** * * * * * * * ** * * * * *** * ** *** ** * * * * ** * * ** * *
}
** ** * * * ** ** * *** 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include ** * * ** ****
* **** * * * * **
int * ** *
* ** *** ** * * a ,b ,i;
** * * ** * * * c;
* ** * * * * * **** * * * ** * * ** * *
* * ** * *** * * *** * ** * ** ** *** *
** * * * ** != 12)
** *** ** * * * ** * = b*6 - b*0.5- a * 30;
** ***** *
* * * *** * * *** * * * = b*6 - b*0.5;
** * ***** ** * * * **** c * * * * 0 )
* * * * * * ** * * = -c;
* * * ** * *** * * * * * ** * * * c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * ** * * **
int main()
{
* ** * * * ** * * * ** ** m=0,k=0,l=0 ,j ;
** **** * * * ** i;
* ** *** ** ** * * * ** * * * * ** * * * * * *** * * ***
* ** * * * *** = i % 12 ;
* ** ** * * * ** *** =( i * 30 )+( j / 2) ;
** ** ** * * *** ** = j * 6 ;
*** * * **** * * =k-l ;
*** ** * * * ** < 0)
**** * * *** ** **
* * * * ** * *** *** * * * *** ** = - m;
* * * * * * *
* ** ** * ** * ***** if(m > 180)
* * * * **** * * **
**** * * * ** * ** * * * * * ** = 360 - m ;
* * * * * * **
* * * * ** ** *** * * * * * * *** * *
* * ** ** **** * * 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** * * * *** *** * * a,b=0;
** *** * * * * * * ** * * *** c,d=0;
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}
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*** * ** * * * ** * * **** * * * ** * * ** * * * * * *** * * * * * *
}
* * * * * * * * * * * * * ** * * 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * * * * * ** * * * hour,min;
* ** *** * * ** * * * * d,k,a1,a2;
* ** * * ** ** * **** * ** * * * ** * ** * * ** *
* *** * * * * ** (hour==12)
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** * * * * * * * ** ** ** *** * 0;
*** * ** * * *** * *
* *** * * ** * * * * * * * *
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * ** * **** * ** ** ** a,b;
** ** * *** *** * * * * q,w,e;
* * * * **** * * * ** * ** * * * ****** ** *** * * ** * **
* * * * * * * * * * *** **
{
* * * * * * * * * * * * *** ** * * * * == 0)
** * **** * ** * * ** * * ** * ** * * * * * = 6*b - b/2;
* ** * * *** *** ** * ** * ** * * * ** * ** * * ** if(b%2 != 0)
* * * * *** * ** ** * ** * ** ** * * * * * * * = 6*b - b/2 - 0.5;
* *** * *** * * ** * * * * * * * ** ** * ** * * * * * ***
*** * ** * ** * * **** * * * * * ** * * * * * = 360 - q;
**** * * ** * * ** ***** ** * * * * * * if(q<0)
** * * ** * ** * * * * ** * * ** * * * * * ** * * ** * = 360 + q;
}
* * ** * * * * * *
{
* ** * * * * * * * ** *** **** * * **** * * * ** * * == 0)
** * *** * * ** ** *** * ** ** ** ** * * ****** * * **** * = 6*b - b/2 - 30*a;
* * * * * ** * * * * ** * * * ** ** * * * * * * if(b%2 != 0)
** * ** *** *** * ** * * ** * * *** = 6*b - b/2 - 0.5 - 30*a;
* * ** ****** * ** * ** * ** ** ***** * * **** * **
* * * * * ** * * ** * ** * * ** ** ** * * * * = 360 - q;
* * * * *** ** * ** * * ** * * * * * ** **** * if(q<0)
** * * * *** ** * * * ** * *** * * ** ** * * * * = 360 + q;
}
** * * ** ** * * ****** * ** * * * * * * * * ** ** * *
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* * * * ** ** * * * * * * ** * * ** * * ** if(w>q)
* * ** ** * * * * * * *** * * * * * * *** ** * * ** *** * * * ***** **** * * * * * * ** *
* *** * ** *** * * * * * * * ** ** * *** *** ** * = b%2;
* ** * ** * ** * * * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
*** *** ** ** * * * * * * a,b=0;
* ***** * * * * * * * c,d=0;
** * ** * * * ** ** **** * ** * * * *** *
** **** * * ** ** * * * * * * * *
* * ** ** * * * *** * * * ****
* * ** ** * * * *** *
* * * * * * ** * *** * **** *** * *
* ** * * * ** * * * * *** * * * * * * * * *** *** * *** * * * ** *
** * * ******* * *** ** **** **
* * * * * ** * ** ** *
* * * * ** * **** * * * ** * * ** * * * * * ** * * * * * * ** * **** ** * ** * *
}
** **** * ** ** * * ** * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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Shun-Po
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ID: 18066 -
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AC 20161201 第二次期中考公告
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ID: 18085 -
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