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AC 20161201 第二次期中考 第二題
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時鐘上有時針有分針，分針每一分鐘跳一次，分針每跳一次時針也會前進相對應的角度。請設計一程式，由使用者輸入一個時間，程式會計算出時針與分針間的夾角後輸出。
輸入說明：輸入包含兩個正整數，兩個數之間由一個空白隔開，第一個數字代表時，第二個數字代表分。
輸出說明：請輸出時針與分針間較小的那個夾角。
輸入範例：
12 31
輸出範例
170.5
[Exercise]
Coding (C)
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asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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ID: 18067 -
Available when:
2016-12-01 18:30:00
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Due to:
2016-12-01 21:00:00
reshown
Dec 1, 2016
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Shun-Po
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Hidden content!#include <stdio.h>
#include * * * *** *
#include <ctype.h>
#include <math.h>
#include ** *** ** * *
int main(){
* ** ** * * ** * * * h,m;
* * ** * * * * * * *** * * ** ** *** * * *** * * * * ** ** *
* ** *** ** ** * * * * * * * arch,arcm,sum=0;
* ** * * * * * ** * * * * * * * * *
* * *** * * * * ** * *** = m * 6;
** ** * * * * * * * * * ** = h * 30 + m * 0.5;
** ** * ** * ***** * * ** ** * ** * > arch){
* **** * * ** * * * * * * * * ** * ** * * * = arcm - arch;
**** *** ** * * ** * **** ** * ** *** ** ** * *** ** ** *
** ** * * * * * * ** * * *
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* * *** * * *** ** * * * * * ** * *** * * * * = arch - arcm;
* **** * * * * * ** * * * *** ***** * * * * * * * *
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*** * * ** * * * * * * ** * * * ** * *** * ** * *** * * * ****
* * *** * * * ** * * * ***
* * ** * ** ***** * * *** * ** * 0;
}
answered
Dec 1, 2016
by
loyfree0706
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Hidden content!#include * * * *** ** *
#include * * * * ** *
#include <ctype.h>
#include <math.h>
int main()
{
** ** ** * * * * * a,b,c,d,e;
** ** * * ** ** * ** * * * * * * * * ** * * * *
* * ** **** ** * * * ** * ** * * * * * * **
*** * * * ** ** * *** * **
*** * ** * * * ******* *
* *** * * * * * * * * * * **
* * * * * * * *** * * (c>=d)
* **** ** * * ** * * * *
** * **** * * * * * (c<d)
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* * * * ** ** * * * * (e>180)
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*** ** ** ** *** * * ** * *** * * * * * *
* * * * * * ** * * * * * ** ** 0;
}
answered
Dec 1, 2016
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410523016
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Hidden content!#include ** ** * *
int main()
{
* * ** ** * *** * * ** * * * * * * * ,j ,n=0;
*** * *** ** ** *** i;
** ** ** ** ** * ** * ** * * ** ** * * * ***
* * ** ** * * ***** = i % 12 ;
* * * * ** * * * =( i * 30 )+( j / 2) ;
* * ** ** * * * = j * 6 ;
** * * * * *** *** * =k-l ;
if(m < 0)
* ** * ** * * *** *
* * ** * * * * * ** ** * * ** * * * * = - m;
* * ** ** * * *
* * * * * if(m > 180)
* *** * * * * ***
**** ** * * * * * * * * *** *** = 360 - m ;
* * ** * * *
** ** * ** ** * ** ** ** ** ** * * * *** **
* ** * * * * *** ** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * * ** * ** * * h,m;
* * * * * * * **** ** ang1,ang2;
** * * * ** * * ** ** ** * * * * ** * * * **
* * ** **** * ** ** ((30*h+0.5*m)>6*m)
* ** ** *** ** * **
** * ** ** ** * * * *** * * * * * * * = (30*h+0.5*m) - 6*m;
** ** * * * * * * ** * * * * * * * ** = 360 - ang1;
* * ** * * * * ** * * * * * * (ang1 > ang2)
* * * * * * ** * * * * * *** ** * * * ** * ** * *
* * **** * * * **** * * ** * ** * * * * **
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* * * ** * *** *
** * * *
** * *** * * * * * * * * * * = 6*m - (30*h+0.5*m);
* * * * ** ** *** * * ** * * * * ****** = 360 - ang1;
** * * *** * * * ** *** * * ** ******* * (ang1 > ang2)
** * **** * * * * * ** * * * * * * ** * * * * **
* *** * ** ** ** * * * * ** ** * **
* * *** * * * * **** * * * * * * * * ** * * * ** *** ** ** * * * * * ** *
}
* * * ** * * * ** **** 0;
}
answered
Dec 1, 2016
by
莊長穎
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Hidden content!#include * * * * **
** * *** **** * **
int ** ** *
* * * * * *** *** * a ,b ,i;
* * * ** * ** * c;
* *** ** * * * ** **** * ** * *** * *** * * ** ****
** ** * **** * ** * * * ** * * * ** * * * ** ***
* * * *** * * * * * != 12)
* *** * * * * * *** = b*6 - b*0.5- a * 30;
*** * ** * * * *
* * * * ** * * * * * = b*6 - b*0.5;
* * * * * ** ** * ** c * * * 0 )
* * * * *** = -c;
* * * * *** * * * ** ** *** ** c);
return 0;
}
answered
Dec 1, 2016
by
Doloa
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Hidden content!#include * * * * *
int main()
{
* * * ** * * * * * m=0,k=0,l=0 ,j ;
** * * ** * * i;
* * * * * ****** ** * * * ** * * * * * ** **
* * * * * * ** * = i % 12 ;
*** *** ** * * * * =( i * 30 )+( j / 2) ;
* ** * * * *** * ** = j * 6 ;
* * ** * ** * ** =k-l ;
**** ** * * * * * < 0)
** * ** * * * *
* * *** * ** * * *** * * * ** *** * = - m;
* * **** * * * *
* ** *** *** * * * * if(m > 180)
** **** * * ** * **
* * ** * * ** ** * * ** * ** *** * *** = 360 - m ;
** ** * *
** * ** * * * * * **** * * * * *
* * ** * ** ** **** 0;
}
answered
Dec 1, 2016
by
ert5179693
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
* **** *** * * * * * a,b=0;
* * ** ** *** * * *** * * c,d=0;
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}
* * * ** ** ** * *** ** * *
* * ** * * * * * **** * * * * ** ** * * ** * * * ** ** **** ***
}
* * ** * * * * * * * * ** **** 0;
}
answered
Dec 1, 2016
by
SRFX
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
** ** ***** * * *** ** * ** * hour,min;
* * ** ** ** * * * * * d,k,a1,a2;
** * * * * * * * * ** * *** * * * ** ** * * * ** * *
* * *** ** * * * ** * (hour==12)
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* * * * ** ** * ** ***** 0;
** * * ** * * * * * **
** ** ** * ***
answered
Dec 1, 2016
by
Gulang
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* * * ** ** * *** * * * * * a,b;
*** * ** * *** * ** * * ** *** q,w,e;
** * * * * ** * * * * * *** * * * **** * ** * ** ** *** **
* * * * * * * * * * *** * *
{
** * ** * *** ** * **** *** * * * * * * * ** ** **** * == 0)
* * * * *** * ** ** * ** * *** * * * * ** * * * * = 6*b - b/2;
* * ** * * * *** *** ** * * * * * * *** *** * * * if(b%2 != 0)
* * * * * *** * ** ** * * *** * * * = 6*b - b/2 - 0.5;
* ** * * * *** * * * **** ** * *** * * * * * *
* * * * * ** ** ** * * * *** * *** * ** * *** = 360 - q;
**** * * * *** * * * * * * ** * *** * * **** * * * if(q<0)
** * ** * ** * *** **** ***** * * ** * * * ** = 360 + q;
}
* ** * * ** * * * * * * ** * *
{
* * * * * * * * * * * * ** * ** * ** **** * * * == 0)
* * * * * * * * * ** * * ** *** *** ** * *** ** * * = 6*b - b/2 - 30*a;
* *** * *** ** *** * * * * **** * * * *** * * ** if(b%2 != 0)
** ** * * ** * * * **** * * * * * *** * ** ** = 6*b - b/2 - 0.5 - 30*a;
* * * * * **** * * * * * * * * * * * * * * *** * ***
*** * * ** ** * * * * * * * * * = 360 - q;
* ** ** * ** * * * ** * * * * * *** * * if(q<0)
* ** * * * ** ** * * * * * * * * * * *** * = 360 + q;
}
* * * * * * ** * ** * * * * **
* ** *** * * ** ** ***** * ** * * * * ** * * * * *** ******* * **** * ** * *** * ** * *
* ** * ** ** * * * * ** ** * ** * * ** * * if(w>q)
** ** * * * * * * * * * ** * ** * ** ** * * * * * * * * * * * ** *** * * * * * * * *
* * * ** * ** * * ** ** ** * * * * * = b%2;
* * * * * *** * ** * 0;
}
answered
Dec 1, 2016
by
410323020
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main(){
** ** ** ** * *** ** * * * *** a,b=0;
** * ** * * * * * * * * * *** c,d=0;
* * ** * * * * * * * * * ** * * * * ** * *** * ** *
* * ** * * ** * * * * * ** * * * * * **
* ** * * * *** * * ** ** * * * *
* * * * * * * * * ** * **
* * * * * * * ** * * *** *
* * * * * ** * * * * * * * * * * * *** ** **** * * *
* ** * * * **** * * *
***** * * * * ** * * * * * ** *
* * * * * ** * * * * ***** ** ** * * * ** **** * *** * * ** ** *
}
*** ** * * * ** * * * 0;
}
answered
Dec 1, 2016
by
SRFX
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AC 20161201 第二次期中考 第五題
[Exercise]
Coding (C)
-
asked
Dec 1, 2016
in
2016-1 程式設計(一)AC
by
Shun-Po
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18k
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ID: 18075 -
Available when:
2016-12-01 18:30:00
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Due to:
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AC 20161201第二次期中考 第四題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18071 -
Available when:
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AC 20161201 第二次期中考 第三題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18070 -
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AC 20161201 第二次期中考 第一題
[Exercise]
Coding (C)
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Dec 1, 2016
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2016-1 程式設計(一)AC
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ID: 18066 -
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AC 20161201 第二次期中考公告
[Resource]
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ID: 18085 -
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