2 like 0 dislike
14.4k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 14.4k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
** * * ** * **** * * ** * ** * **
for(;;)
* * * * * * ** * ****
for(i=1;i<(a+b);i++)
{
* ** * **** ** *** ** * **** *** * *
*** * *** * **** **
* * ** * ** * *
** * *** ** *** * * * * * **
* * ** ** * ***** * * ** * *******
* * ** **** **
}

i=1;
j++;
if(j==10){break;}
* ** * ***** *** *** * * **** **

** * * * *** *** ******* * * * ** *** * * ** *
** ***** ** ** * ** * **** ** ******* * *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* ** ***** * * ** **** * * ** * ** *
** * * * * * * *
*** *** * ** * **** ** * * ** ** * ******** *** * *
*** * * * ** * * * * * * * * **** * *
    {
* *** **** ****** ** * ** ** * * ** * * ** ** * *** * * ** * *
* * ** * ** *** * **** * ******* ** * ** * * *
* * * *** *** ** * * ** ** *** * *** ** * * ** ***** * **** ****
** * * * * * * *** ** *** ***** * * *** *** * * *** * * * * ****
* * * *** *** * * * ****** ***** * *** *
    }
* ** * ** * * *** * * * ** ****** *** * ** *** *
* ** * ** * ** ** * * * ** *** *
    else
* ** * * * ** * * * ***** * *** **** *** *** ** ** **** ** ** ***
*** ***** *** ******* * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * *** * * ** ** nom,denom,i,a;
*** *** *** ** * **** * ** * ** * %d", &nom, &denom);
****** *** * * ** * ** ** *** i<=denom; ++i)
    {
* ** * ** * *** **** **** * * ** * ** * * * ** * ** *
***** * **** * * *** * ** **** * * * * * * && denom%i==0)
*** ** * * ** ** *** * ** ** *** ** * * * *
* * **** * *** ** * *** * ** * * **** * * * * * * * = nom/i;
* * * ** * * *** ** * * ** * ** * * * ** *** ** *** ** * *** = denom/i;
* * ** ** **** * *** ** *** * ** * * *** * *** ** ********** * ** *
* *** * *** * *** ** * * *** * ** * * **** *** * * ** ** *** *
** * * ** ***** * ***** ** * *** * ***** ***** * *** ** *******
* **** * **** * *** **** **** * * *** ** ** **** **** * ** * * * * * **** ** *** *

** ****** * * *** * *** ** ** ** ** * * * **** **

    }
* *** ** ** **** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** **** * **** * * nom,denom,i,a;
** * ** * * ** **** %d", &nom, &denom);
** ** * * * * * ** *** i<=denom; ++i)
    {
******* * ****** ***** ** ***** * * ** * * ** ** *** * * **
** ******** ****** * ** * * *** ** * *** && denom%i==0)
* ** **** **** ***** ******* * * ** ** *** ** ** * *
** * ** * * ** ***** * ** * *** **** ***** * ** *** ** = nom/i;
** * * * * * *** *** * ** * **** ** * * * * * **** ** ** = denom/i;
*** * ** * ** *** ****** * * ** ** * * ** * ** * * *** *** ***** * * *
* ** * * * * ****** * * * **** * * * ** * * * *** ** * * * *
* * ** * * *** *** * * * * **** * * ** * ** **** * ****
****** ** * * * *** **** ** * ****** *** * * ** *** ** * ** * ** ** ** **** *

***** * *** ** ** ** ** * ** * ****

    }
* * * ** ** * * * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
**** * *** ****** ** * * nom,denom,i,a;
* * *** * * * * *** *** * * * ** %d", &nom, &denom);
* *** * * * * ** * ** i<=denom; ++i)
    {
* ** *** * * ** * * * * * ****** **** * * * *
** ** * * * * * ***** * * * **** ** * * * ** * * && denom%i==0)
* * * * * * ** * * **** ** ** ** * **
** ** * ** * ***** * * * ****** * * ** * * *** ** * ******* = nom/i;
***** *** * * * ********* ** ** ***** ** * * * * *** * ** = denom/i;
* **** ** * ** * * * ** * ***** ** * * ** **** * ****** ** **** **
** *** * * * * * * * * ** ** * * *** *** *** *** ****** * ****
* * ** * * * * ** ** ** * * * ** *** * ** * ** * * * * * * * *
* ** * ** * *********** ** * * * *** ** * * *** * ** ** ** * *** ** *

********* ** ** *** ** * ** * * * ** * * *

    }
*** * **** ** * * *** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* * * * * * *** *** **** *** * ****** * * *
** * * * ** * ** * * *
* * ** * * * *** * * ** ** ******** * ** * * * ***** ***
** * ** * * ** ** ** * * * **** **** *** ** * * * **
    {
*** **** ** ** * * ** * * ** *** * ** **** ** * ** * **
* * *** * ** **** * **** *** ***** *** **
* * * * * * * **** ***** * ** * * * * ********** *** **** *** * * * *
*** * ********* *** **** * * * ** * **** * * *** *** * * ** ***** * ** * * ** ** *
* ** * * ** *** ****** * ** * *** ** ** *
    }
** ** * * ** * ** * * * *** * ** ** *
* ** *** ** ** **** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
***** ** **** * ** * * a, b, rem, n, d;

******* *** * * * * * * * *** ***** &a, &b);

** ** * * * * = a;
* ***** * * * = b;

* ****** * ** * *** ** ** * ** != 0)
* * * ***** * ** ****
*** * * * ** *** *** * * * ** *** **** = a % b;
** *** * ***** ** * ** ** **** ** *** * **** = b;
******** * *** ** * ** * **** * * * ** * = rem;
** ****** ** *

** * * ** ** * * *** % d == 0)
** * * *** * * ** ** *** ** * *********** **** ** ** * * * * ** n/d);
**** **** * * * ***** *
** * *** ** * * * * ** * * ****** *** ** * ** * **** * ** n/a, d/a);

** ** * ** * * * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.238
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 14.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 14.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 18.6k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 14.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users