2 like 0 dislike
11.9k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 11.9k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
********** ** * * * * * *** * **
for(;;)
**** *** * * *
for(i=1;i<(a+b);i++)
{
* * *** * ** ** *** ** * **** *
*** * * * * ** * *** ** **
*** ***** * * ** **
* **** * * * ** * ** * *
** *** * ** ***** ** *** * * ** * * * * * * ******
* ** * * ** * ** ******
}

i=1;
j++;
if(j==10){break;}
******* ** * * * * * *** *

*** * * * * ** * ** *** * * ** ** ** * * ** * * *
** ** * ** * * * ** *** ***** * * *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* ***** ** * ** * ***** * * *** ** * * ******* * ****
* * * ** * ***** ** * * *****
** *** *** * *** ** * * * * **** *** * ** * ** *
*** ***** * * * ** ***** ***** *** ** * ** **
    {
*** * *** * * ** **** **** ** ** ** * *** ** * **** * *** * ***
* * **** *** *** * ** *** * * ** * *** * * **
** *** * * * * **** * * ** ** ***** ***** ** * * ********** * ** * *******
******* ** * **** *** ** * * ** * * ** **** *** * * ** * * * *
*** ** * ** **** * * *** * * *** ****** * ***
    }
* **** * * * * * * * * *** * * **
* * * *** ** **** * *** ** *** ** *
    else
* ***** ******* ** * * ** ** ** * * **** ** * * ** *** ** *
** * * * * * *** 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* *** * *** ** ** * ** nom,denom,i,a;
*** * * * * * * ** * ** ** %d", &nom, &denom);
*** * * * * *** * * **** * i<=denom; ++i)
    {
* * * *** **** *** ** ** * * ******* * ** *** * **** * ** *
** *** * * * ** * *** *** * ** ****** * * && denom%i==0)
* **** * ***** ** * ** * * * **** ** * ** *
*** * *** * * ** ** ** * * *** ***** * * * * * * ****** ** *** ** = nom/i;
*** ****** * ** ** ** * **** * * ** ** ** *** * * * *** = denom/i;
* ** * * ******* **** * ** * *** ** ** * ** * **** *** * * * *
* * * ******* * * ** ******* * * ** * * * * ** * * * * * * ** ** ** * * *** * *
* **** ** * ** ***** ** * ***** * * * * * **
*** ** ** *** * ** * ** *** * ******* *** * * *** * *** ** ** ***** ** ** * ** ** ***

* * * * ** ** *** * ** * * * * *** *** ** * * ** *

    }
** * * ** *** * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** ** ** ** ** **** ** * nom,denom,i,a;
** * * ** ** * *** *** ** ****** ** %d", &nom, &denom);
**** ** **** ** * * ****** i<=denom; ++i)
    {
**** * * ** ** * * * ** * **** * *** *** *** ** **
* **** * *** * * ** * * * ** **** * *** * && denom%i==0)
** ** * ** * **** * * * ** * *** * * *
* * **** * * ** **** * **** ** ** * * ** *** **** ** **** = nom/i;
* ** ** *** * *** *** ** *** * ** ** ** * ** ** * ** **** = denom/i;
** * * **** **** ** * * * * *** * ** ** ** * * ** * *** *** **
* * *** * **** * ** *** * * * * *** * ***** ** * ** ** * * * ** *** * * ** * * * *
* ** * * ***** ** * * ** *** * * ** ** * * * * * * * * ****** * ***
** *** ** * * ** *** *** * ***** * ** * ** * ** * * *** *** * * ** *** ** * * * ****** *

** ** * * ** **** **** ** ** ** * * ** *** ***

    }
*** *** * * ** * * ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* **** ** ** ** *** ** nom,denom,i,a;
* *** * ** * * * ** * **** %d", &nom, &denom);
* * ** * *** *** ** ** *** i<=denom; ++i)
    {
*** ** * *** ** * * ** * * * * * ** * ** * * *
** * * * ** * * * * * ******* ** * ** *** * && denom%i==0)
*** ** * ** * ****** ** * ** **** * * ** ** **
**** * * * *** * * * * * *** * **** * ** * * * * * = nom/i;
* * ** * *** * * * ********** * * ** * * * ** * ** * ** * = denom/i;
* ** * * * * * *** * *** ** ***** * * ** * * **** * * * * *
** **** ** ** * ** *** ** * * * * ** *** * ******* ** * * * ** * ** *
* * * ** *** * ** ** * **** ** ** * **** ** * ** * *** *
** ** ** ** ***** * * ** ** *** ** * * *** * * * * * ** * *** *** **** ** *** *

*** * *** * ** ** * * ** * ** * * ** ** *** ***

    }
****** * *** ** * **** ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
*** ** ** * ******* *** *** * * * ** * * * * * *
* ***** **** *** * ** *****
* ** ** * *** * ******* ***** * ** *** *** ******* *
** * * ** *** * **** *** *** * * * * * ** ** ** *
    {
* * ** *** ** ** ** * * *** ***** * ** * * **** * ***** **** * *** * ***
* ** * **** **** * * ***** **** *** ** *** *
* * * ** *** ** **** ** ****** * * *** *** ** *** * ***** *
** * * ** ** ** * * *** ** ** *** * * * ** * *** *********** *** ** * *
* **** * * * ** * * **** ** ** ** ** ** **
    }
* ** * * * *** ** * *** * * *** * ***
*** * * ** * * * ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* ****** * ** ** ** *** a, b, rem, n, d;

** ** * * * * * ***** * ** ** &a, &b);

* * ** * * * * ** * ** = a;
* * * **** ***** * = b;

***** ** ***** * * * * * != 0)
* *** * *** *** ***
** ** * ** * * * * * ** *** ** * ** * ** = a % b;
* *** ** * ** * *** *** ***** *** ***** * ** * = b;
** * ** * * * **** *** * ** ** ** = rem;
*** ** * * * *

***** ** ****** * *** * * % d == 0)
* * ** * * * *** * * * * ** ** ***** ** * * ** **** * * n/d);
**** ** * ** * **
** ** * * * * * * * * * ** ** ** *** **** ***** * * * n/a, d/a);

* * * * ** * * * * *** ** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.250
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 12.2k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 11.8k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 15k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users