2 like 0 dislike
9.7k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 9.7k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
*** ****** * * ***** ** * * ** *
for(;;)
**** * * * **** ****
for(i=1;i<(a+b);i++)
{
** * * ** ** * * * *** ** *** ** ****
* * *** ** **** * ******
* * * ** * * * *** *
* **** ** ***** * * *
***** * *** ** *** * ***** ** *** *** ***
* * * * ** * ***** *
}

i=1;
j++;
if(j==10){break;}
* * *** * *** ***

*** ****** ** ** *** *** ****** * ** * * * ** ** ****** *
** ***** ** ** * * *** ** * ** ** ****** **


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
* * ******* * * * * ** *** * * * * **** * *
* ** *** ** ** *** * *
* ** ** *** * ********* ** ** * * ** ****** ** * * *
*** * *** ** ** ****** ** ** * ** ** ** ** *** ***** * *
    {
* ** * * * ** **** **** * * *** *** * ** ** * ** * *** * * ***
** ** *** ** * * * * * **** * **** * * ** * **
***** ** **** * ** * ** ** * ** ** ***** *** * * * * * *** ** * * * *** *
** *** ** * *** *** ** * ************* ** * ** ** * * * * **
* * *** **** ** *** * ** * * * ** *
    }
**** * * ** **** ** **** *** ** *** * * *
********* * ****** *** * **** * ** *** *** * * *
    else
***** * * * ** * * **** *** ** * ***** *** * * *** * * * ****** ** ****
**** *** * * ***** ** ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* ** * * * *** ** *** ** nom,denom,i,a;
*** * *** ** * * *** * ** ** %d", &nom, &denom);
* * ***** **** * **** *** i<=denom; ++i)
    {
** * **** ** ** *** *** * ** * * *** *** * *** * ** **
** * ** * * *** ** *** ** ** ** ** * * **** * ***** * * && denom%i==0)
*** * * *** *** * * * *** ** ** ***
* * ****** * *** ** * * * *** * ** ** ** ** * * ************ = nom/i;
*** * * ** * ***** * *** * ******** **** * ** * * ** * ** * ** = denom/i;
** *** ****** *** ** ** ***** ** * * **** * * **** ** * * *** * * ** *
* ** * *** *** ** ** **** *** ******* ** *** ** * * * ********* **
* *** *** ** * ** ** ** * ** **** * * * * ** * *
**** * * ***** * * * ** ** * * * ** ** * * * * * **** * ** ** * **** * * * ** * * *

*** ** *** * * * ** * ******** * * * * * * *

    }
** *** ** *** *** ** ** * *** * * * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
* * * ** ** **** ** * nom,denom,i,a;
* * *** * * ** * ** ** *** * * %d", &nom, &denom);
*** ** ** ** * * * * i<=denom; ++i)
    {
* ** ** * * ** * * * * *** * * * * * *** * ** * * *** * * *
* * **** * * ** ** * *** *** ** ** ** * && denom%i==0)
* * * ******** * ** * ***** * ** * ** *
* ** *** * * * ** * * ** ** * * *** * * ** *** * *** *** = nom/i;
* ** ** ** * * ** ** ** * ** ******* ** * * ** ** **** * * ** = denom/i;
* **** *** ** **** * ** ** * ** * * * ** * *** * ** *** * * * *
**** * *** *** ** * * ** ***** * *** **** *** * ** * * * * * ********** *
** * ** *** *** ** * * *** ** **** * ** * **** ** * ** **
* ***** * ** * * ** * * * * *** *** * ** * ** * * * ******* * * ** **** *** * * *

** * *** ** **** * ** * * *** ** * * ** * * * *

    }
** * *** * * * * ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
*** * *** * * *** * ** nom,denom,i,a;
* ** ***** *** **** ******** * ** %d", &nom, &denom);
* * ****** * * *** * i<=denom; ++i)
    {
** * * * * *** * ** ** * * * *** * * * ** * * * * * * ***
** ***** * * *** **** ** ** * *** * *** * **** * *** && denom%i==0)
* * * * ** * ** * ** ** ** * *
* ****** ***** * ****** ** ** * ** * *** * ** * ** * ** *** * *** = nom/i;
*** * ** * ** **** ** **** * ** **** **** ******* ** = denom/i;
****** ** *** *** ****** ** * *** * ** * *** * * ** * ** * ****
* * * * ** ** ** * * *** ** * * * ** * ***** * **** *** * ********** *** ****** * * **
** ** *** * * *** *** * * * * *** * * ** ** ** * * * *
***** ** * * * * **** ** ** **** * **** * ****** *** * **** * * ** ** ** * **

* * **** ** ** * * ****** ** ** * * * ** ** *

    }
*** * * * ** * *** *** *** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** * ***** * * * * ** * ***** * * ** * ***
** ** * * ** * * ******
* * *** * ** * ** *** * ** * ** * ****** **** ** * * *
* * ** ******* * * **** *** ** ** *** ** *** *** *
    {
** ** ** ** * * * * * * * *** ***** *** ***** * ** * ******** *
** * ** ***** * * * **** *** ****** ** * ** *
**** ** ** * * ** * *** **** * *** ** * ***** * ** ** * * ** *
* * ** * ** * *** ** ** ** * ** *** * ** * ** * * *** * ***
* **** ** **** *** *** ** * ** *** * * * *** *
    }
**** * ** *** * ** * ** * **** **** ** * ** * *
******* ** * * * * ** * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
* * ** ** ** *** * ** * a, b, rem, n, d;

** ** ** * * * ** * ***** * **** &a, &b);

* * ** * * ** ** * * * ** = a;
* ***** ** * * ** * * * * * = b;

** * ** **** ** *** != 0)
* * **** *** * * ** *
*** ******* * * ** * *** ** *** ** * ** * * ** * * = a % b;
** * * ** * ** ** ****** *** * ** * = b;
*** ** ** *** ** ** *** **** * * ***** *** **** = rem;
** * * * * * ***** *

***** * ***** ** ** % d == 0)
* ** * * * * * ***** * * * ** * ** * *** * ** n/d);
* * ** *** * * ****
*** * ***** * ** * * ** ***** * ** **** ** ** * * ** * ***** * n/a, d/a);

* **** * * * *** ** * ** * 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.247
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.7k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.4k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 11.9k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users