2 like 0 dislike
9.8k views

Write a program that asks the user to enter a fraction, then reduces the fraction to lowest terms.

寫一個程式 輸入一個分數,約分為最簡分數後輸出

Example input:

6/12

Example output:

1/2

Example input 2:

12/6

Example output:

2
[Exercise] Coding (C) - asked in Chapter 6: Loops by (5.2k points)
ID: 31048 - Available when: 2017-11-09 18:00 - Due to: Unlimited

edited by | 9.8k views

67 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>
int a,b,i,j;

int main()
{
* * * ** * * ** * ** * * ** *
for(;;)
* * * * ** ** ***** ***
for(i=1;i<(a+b);i++)
{
**** * * ** ** * * * ** * * **
****** ** * * * *** * ***
* ** ** * * *** ******* *
** * ** *** **** ** * * **
** * * * * *** * ** ** * *** * * * * * * * *** * **
*** * * * **** * * *
}

i=1;
j++;
if(j==10){break;}
** * ***** * * ** * ** **

** * * ***** * ** **** *** * ** * *** * * * * ***
** ** ** ** *** * * **** * * * ** * *


}
answered by (-336 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** ** * * * * * *** * * * **** * ****** * * ***** **
* ** * * *** * ** * * * ****
**** * ** * ** * * * * ********** *** ** * * *** **
** *** *** ** ***** * * * **** * * * *** * **
    {
**** * ***** * * ** * * ** ** ** * **** ** *** * ** *** ** ** ** ***** *
** * * * ** ** *** * * * ***** ** * *** *** * *
* *** *** * **** *** * * * * ** ** * ** ** **** *** * * * * * *** ****
** *** ** ** *** * * * ******* *** ** * * ** * * ***** * *** *** * *
*** * * ** * * * * ** ****** * * * * * ** * * *** **
    }
* * ** *** ** * * *** ***** * * ** * ** * * *
** * * *** * * ** * * * *
    else
** *** ** ** * * ** ***** * * * * * * ** *** * * * ** * *** **
* * * ** * ** * * * * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** ** * * * * ** * nom,denom,i,a;
* ** * * * ** * ** ** * * * %d", &nom, &denom);
* ** ** * ** * ** * ** i<=denom; ++i)
    {
** *** **** *** * *** ** ** *** * * *** * * * * * *** * ** * *
* ***** *** * ** ** * * * * * * *** ** ** && denom%i==0)
*** *** **** * * * ** **** * * * * * * * *
* * * * *** * * * **** * ** * **** * * ** * ** * * *** * = nom/i;
** ** **** * * ** * ** * ** * * * * * * ******* * = denom/i;
* ** * ** * * *** * * *** * ** *** *** * * ***** * *
*** * ** ** ** * **** ** * * ** * ** * * * ******* * ***** * * *** * * ***
** ** ** *** ** *** * * ***** * ******** *** * *
* * *** ** *** * * ** * ** * * *** * * **** * * **** *** *** ** ** * * * * **

* ** ** * ** * *** ***** * * *

    }
* ** ** **** ** * ** * 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
****** * * * * * nom,denom,i,a;
** * ***** * * * ********** %d", &nom, &denom);
** *** ******* * * ** ** i<=denom; ++i)
    {
*** *** * * *** *** ** * * * **** * * ** ** *** * * * **
* ** ** *** ********** * ** ** * * ******* ** && denom%i==0)
**** ** * ** * ********* ***** ****** ** * * ****
*** * * **** ** * * **** * * * * ** * ***** * *** * * ***** ** = nom/i;
* ***** * * * * ** *** *** * *** * * ** ** * ** ***** ** * = denom/i;
* ** * ** * ** * ** * ** **** * * * **** ** **** * * * ***
** * * ** * ****** * * * * ** **** * ** * * *** * * * * * ** ** * ** * *
** * *** ** * * ** * ** ** * ** ** * * *** * * ***
** * ********** ** * ***** * ** ** **** * * * ** * * * ** *** ** **** **** ******* ** *** *

* * * *** ** ** * *** ** * * ** * *** * *** * *** *** *

    }
* * * * * ** ** * ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main()
{
** * *** ** *** **** * ** nom,denom,i,a;
************* * * ** * * * * ** ** %d", &nom, &denom);
** ** * * *** ** * i<=denom; ++i)
    {
* ** ** * ** ** ** * ** ** * * **** *** * * * *
* * **** * * *** ** * ** **** ** * **** * && denom%i==0)
** ** * ** * ** * * ** *** ** * *** **
* * **** * * ** * *** * ** ** **** ***** *** **** **** * * *** * = nom/i;
* * ** * ** ** ********** ** * ** ** ** * ** * * * * *** = denom/i;
** **** ** *** ** ******* **** *** * ****** ******* ** **** **** ** ** * *
*** *** * ** * *** * *** * ** ** * ** * * ** * ** * ** * * **** **
* **** * * * ** * ** ** *** ** ** * **** ** ** *** * * * ******
* **** * * * ** ** * **** *** *** *** *** * ** * ** ** ** ***** * * ** * * ** ***

* ** * * * * **** * *** **** ** * *

    }
* ** * * ** * ** ** 0;
}
answered by (-281 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
    int a,b,count,c,d;
** ** *** **** * ** * * *** * **** ** * * *** ** *
*** * ** *** **** ****
******** ** * ***** ** *** *** * ** *** *** *** *** * * **
** * ** ** * ** * * *** ***** * * ** *** * * *
    {
**** ** ** * ** ** * * ****** * *** * * ** * ** *** * ** ***
* ** * ** **** ** * * * * * * *** * * ** *
*** * *** * *** * * * **** *** **** *** ** * ** * ******* * ******* **
* * * * *** * ** ** * * * ** * * * * * * * * ** * *** ** ** **** *
** *** * * * *** * **** ** **** * * ******
    }
* * ** * ** * * * ***** ** * *** * * * *** * **
* **** ** * *** * * 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Wrong output
Case 2: Correct output
Case 3: Correct output
Case 4: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main()
{
** ** * * * **** ** * * a, b, rem, n, d;

**** * ** *** ** * **** **** * ** * &a, &b);

* *** ** *** * * ** *** = a;
* ** * * **** ** * * * = b;

* ** * * * **** **** ** * != 0)
***** * ** ** **
** * **** * * * ** *** * ***** * * ** *** * * = a % b;
* ** *** * * ** ****** *** *** ** ** * * * = b;
** * ** * **** *** ** * ** * * * * * * * * * * * *** = rem;
* * ** ** * * * ** *

** * ******* * ** * * % d == 0)
* * ** * * * * ** * * *** ** ******** **** ** ** *** ** *** ** n/d);
*** * ** * * **** *****
* ** * *** *** ** ***** *** * * ** ********** * * ** * n/a, d/a);

** * **** * * * * **** *** * *** 0;
}
answered by (5.2k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.174
©2016-2025

Related questions

0 like 0 dislike
71 answers
[Exercise] Coding (C) - asked Nov 9, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 31047 - Available when: 2017-11-09 18:00 - Due to: Unlimited
| 9.8k views
0 like 0 dislike
72 answers
[Exercise] Coding (C) - asked Nov 2, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 29831 - Available when: 2017-11-02 18:00 - Due to: Unlimited
| 9.6k views
1 like 1 dislike
85 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28914 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 12k views
0 like 0 dislike
69 answers
[Exercise] Coding (C) - asked Oct 26, 2017 in Chapter 6: Loops by semicolon (5.2k points)
ID: 28913 - Available when: 2017-10-26 18:00 - Due to: Unlimited
| 9.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users