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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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cout **** * * ****** and sum3 are the * ** *

else cout ** * * * ** and sum3 are not the * * *** * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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cout * * * * *** and sum3 are the * * * *

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}
answered by (-364 points)
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answered by (-367 points)
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** ****** * ** *

using namespace std;

class Adder{
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{

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Adder sum2(x);

Adder sum3(y);

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout *** *** * "sum1 and sum3 are the * * ** ***

else cout ** * * "sum1 and sum3 are not the **** ** ***

}
answered by (-384 points)
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Hidden content!
* ** * * ** *** ***

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class Adder{
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}









int main()

{

int x,y;

cin ***** * x ** * * * ** y;

Adder sum1;

Adder sum2(x); // sum2 is *** to x

Adder sum3(y); // sum1 is initialized to y

cout *** *** ** * *** is " ** * *** * sum1.geta() * ** * '\n'; // prints **** ** is 0"

cout * * * ** is " * ** sum2.geta() * **** * * '\n'; // prints * *** * is x"

cout **** * * * * is " * * * * sum3.geta() * *** * * '\n'; // prints ** * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * * and sum2 are the ** * *

else cout ** * * and sum2 are not the * * *****

if (sum1 == sum3)

cout ***** *** ***** and sum3 are the * ******

else cout * * * * * ** and sum3 are not the * * **

}
answered by (-384 points)
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Hidden content!
* * * ** * * * **

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * *** * ** x * * * * ** y;

Adder * ***
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* * // sum1 is ******** * to y

cout *** ** *** ** * ** is " **** ** ** **** '\n'; // prints ** *** **** is ** ***

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cout ***** *** * * *** * is " * ****** **** *** '\n'; // prints ** ** * is **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** ** * ** *** and sum2 are the * * *

else cout * * ** ** * **** and sum2 are not the **

if (sum1 == sum3)

cout * * **** * * * * * * and sum3 are the ** * ** *

else cout ***** * * *** and sum3 are not the ** * **

}
answered by (-384 points)
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