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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

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cin * *** x * * * **** y;
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sum1 += x; **** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** * * ** * and sum2 are the * * ** ****

else cout * ** **** * * *** * and sum2 are not the ***** ***

if (sum1 == sum3)

cout * * ** ** ** and sum3 are the ****** * *

else cout * * * * * * * * and sum3 are not the ** ** * **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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* ***

{
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answered by (-367 points)
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Hidden content!
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using * std;



class Adder

{
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{

int x,y;

cin ***** * *** x *** ** y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * *** **** * and sum2 are the **

else cout *** * * *** * and sum2 are not the * * ** **

if (sum1 == sum3)

cout ** ** ** * * ** and sum3 are the *** * **

else cout ***** * * * ** and sum3 are not the *** ** *


**** * * * * **** * * *** * 0;

}
answered by (-364 points)
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*

{
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* ** **** ** x * * ** ** y;
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}
answered by (-367 points)
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** ** * * *** * **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * * ** ** x ******* y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout **** * * "sum1 is " ** ** sum1.geta() * *** **** '\n';

cout *** ** *** * "sum2 is " * ** *** * sum2.geta() **** ** * '\n';

cout * ** * "sum3 is " * *** * * sum3.geta() * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * * ** ** "sum1 and sum2 are the * * *

else cout * *** * * "sum1 and sum2 are not the *** *** **

if (sum1 == sum3)

cout * *** "sum1 and sum3 are the ** * **

else cout * *** * * * "sum1 and sum3 are not the ****** ***

}
answered by (-384 points)
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Hidden content!
*** *** *** **** * *

using namespace std;

class Adder{
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};
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**** ** * *** * * ** * ** a;

}









int main()

{

int x,y;

cin ****** ** x * * * y;

Adder sum1;

Adder sum2(x); // sum2 is * * *** to x

Adder sum3(y); // sum1 is initialized to y

cout **** * * *** * is " * * * * * sum1.geta() * * * **** '\n'; // prints *** * is 0"

cout ** ** ** * * * is " ** * * * sum2.geta() * * * '\n'; // prints * ** ** is x"

cout **** *** ** * * ** is " * ** * * * sum3.geta() ** *** '\n'; // prints * * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** * ** and sum2 are the **** ** ***

else cout ***** *** *** ** and sum2 are not the ** *** *

if (sum1 == sum3)

cout *** * ** * and sum3 are the * ** **

else cout *** *** **** ** ** and sum3 are not the ** * *****

}
answered by (-384 points)
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Hidden content!
** ** * * **** *

using namespace std;

class Adder{
** ** ** * * ** *
***** ** * * *** * *** ** ** ** * ** geta();
* * *** * **** * * ** ** ** * ** * * * * * seta(int n1){
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* * * * *** * * * * * ***** ** * * * * a;

};
** *** * *
* *** * * ** * **** ***** a;

}









int main()

{

int x,y;

cin * * * * x * * * ** * y;

Adder *****
** **** *

** *** * * // sum2 is ** *** * to x
**** ** // sum1 is * ** ** to y

cout *** ** * * is " * * *** **** ** * ** * * '\n'; // prints * ** is *

cout * ** ** ** * is " * * * * * ** * '\n'; // prints * * * is ****

cout ** * * ** * * ** is " * ***** * * *** ** * * '\n'; // prints * is * *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * **** * ** * ** and sum2 are the * * * ***

else cout ** * * *** * and sum2 are not the * **

if (sum1 == sum3)

cout ** **** * and sum3 are the * ** **

else cout ** **** ** * * and sum3 are not the **** ***** ** *

}
answered by (-384 points)
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