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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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}



int main()

{

int x,y;

cin *** * x ****** ** y;
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sum1 += x; *** ** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * ** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** **** ** and sum2 are the ****** ***

else cout *** ** **** * * ** and sum2 are not the ** **

if (sum1 == sum3)

cout * * **** * * and sum3 are the **** ****

else cout ** * ** ** and sum3 are not the * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
* *

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answered by (-367 points)
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Hidden content!
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using std;



class Adder

{
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};



int main()

{

int x,y;

cin * * * x ** *** y;
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cout * ** ** * * * * * is * ** *** ****** * * ** * '\n'; // **** * * * is *** ****

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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * *** * and sum2 are the **

else cout * ***** * ** **** and sum2 are not the *** ** **

if (sum1 == sum3)

cout * *** **** * * ** and sum3 are the * * * ** **

else cout * *** **** **** * * * and sum3 are not the * ** **


* *** * **** * ****** * ** 0;

}
answered by (-364 points)
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Hidden content!
** ** **

{
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*** * * ** x * *** * y;
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}
answered by (-367 points)
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Hidden content!
*** * * * ***** ** *

using namespace std;

class Adder{
*** ** * **** **** ** ***
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};

Adder::geta(){
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}

int main()

{

int x,y;

cin * ** ** ** x * * *** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * ***** "sum1 is " * * *** sum1.geta() * *** '\n';

cout * *** "sum2 is " *** * *** sum2.geta() * * * '\n';

cout ** *** "sum3 is " * * * sum3.geta() ** ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout *** * **** "sum1 and sum2 are the ***** ***

else cout * * **** "sum1 and sum2 are not the ** * **

if (sum1 == sum3)

cout * * "sum1 and sum3 are the ** * *

else cout * ** * "sum1 and sum3 are not the ** * ** *

}
answered by (-384 points)
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Hidden content!
** ***** *** *

using namespace std;

class Adder{
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};
** **
****** ** **** *** * a;

}









int main()

{

int x,y;

cin ***** * x ** * ** y;

Adder sum1;

Adder sum2(x); // sum2 is ** *** * to x

Adder sum3(y); // sum1 is initialized to y

cout ***** * ** ** is " * **** ** sum1.geta() ** * '\n'; // prints *** * is 0"

cout *** * * ** * * is " * * **** sum2.geta() * **** '\n'; // prints * *** is x"

cout * * * * * *** * is " * * * ** ** sum3.geta() * * ** * '\n'; // prints ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** * ** * * and sum2 are the **********

else cout ** * *** and sum2 are not the * * **

if (sum1 == sum3)

cout * ** **** and sum3 are the ***** * ** *

else cout * *** * ** * * and sum3 are not the * ** ***

}
answered by (-384 points)
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Hidden content!
*** * * * * *

using namespace std;

class Adder{
* *** **** ** ****** ***
** * * * * * ** * ** * ***** * geta();
* * ** *** ** * * * *** * * ** * **** ** seta(int n1){
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* ** ** * *** * * * ** ** ** * *** ** * ** *** * ** * ** * ** ** **
****** * * * * ** ******* ***** *** ** ** ** ****** * ** ** ** * * ** **** * **** * *** 0;
* * ** * * * * * ** * **** * *** * ***** *
* ** ** * * **** * *
* *** * * **** * * *** *** **** ** * ****** a;

};
** * *
** ** *** * ** * ** a;

}









int main()

{

int x,y;

cin ** **** * x ** y;

Adder *** * *
**** *

* ** ** // sum2 is *** * ** to x
* ** // sum1 is ** * to y

cout *** *** * * * * is " * * * ** *** * * ***** ** * '\n'; // prints * ***** * is **** * *

cout * ***** * ** * * is " * ** * * * *** ** * ****** ** '\n'; // prints ** ***** is * **** *

cout * **** ** * ** * ** is " * ** * ** * * **** '\n'; // prints *** * * ** is ** * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** *** ** * *** and sum2 are the * ***

else cout * * ** ** and sum2 are not the ** *** ** **

if (sum1 == sum3)

cout ***** * ** *** * and sum3 are the ** ** *

else cout * * ** * ** ** and sum3 are not the ***** ** * *

}
answered by (-384 points)
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