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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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}



int main()

{

int x,y;

cin ** *** * * x * * ** y;
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sum1 += x; * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; *** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * * * * * and sum2 are the * * *

else cout ** ** * *** * * and sum2 are not the * * **

if (sum1 == sum3)

cout * ** and sum3 are the ******* *

else cout * **** *** **** * and sum3 are not the ** *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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}
answered by (-134 points)
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Hidden content!
* **

{
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}
answered by (-367 points)
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Hidden content!
* *

{
** **
** ****** * * x ***** y;
* * * * // * is * * * to 0

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}
answered by (-367 points)
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Hidden content!
* * * ** *
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using ** ** std;



class Adder

{
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* * ** * ***** * * *** * ** ** ****** * * a;
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};



int main()

{

int x,y;

cin ** * x ** *** *** y;
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Adder * ** // sum2 is * *** *** to x

Adder *** // sum1 is * * ** to y

cout ** ** * *** is * *** **** *** * * ***** * '\n'; // prints * ******** * is *

cout * ** * * is ** * * *** * ***** * * ** '\n'; // * * * **** * is * * * *

cout ** ** *** * ** ***** * ** is * ** ** ** ** * ** * ** '\n'; // prints * * * * is * * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** * and sum2 are the **

else cout ******** * * * * and sum2 are not the *** *

if (sum1 == sum3)

cout ** *** * ** * ** and sum3 are the * ***

else cout *** **** **** and sum3 are not the **** *


*** *** ** * ** *** * * 0;

}
answered by (-364 points)
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Hidden content!
*

{
*** *
* * ** * * * x *** * ** y;
* * // * is ****** to 0

*** *** // * * ** * x
* * *** * ** *** y

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if ** * == *
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* * ** ** ***** **** ** *** * ** ** * ***
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}
answered by (-367 points)
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Hidden content!
*** **** * *

using namespace std;

class Adder{
****** **** *** *** * * *** *
*** **** * * ** * * * * * *****
* * ** *** * ********* ********* * ** ** * * *
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};

Adder::geta(){
*** ***** ** * * ** ** a;

}

int main()

{

int x,y;

cin * ** *** x *** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout *** * ** "sum1 is " * * ***** sum1.geta() * * * ** '\n';

cout * * **** "sum2 is " * ** * * sum2.geta() * * ** ** * '\n';

cout **** *** * * "sum3 is " ** * sum3.geta() * ** * ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * **** "sum1 and sum2 are the ** * * ** *

else cout * * * ***** "sum1 and sum2 are not the **** **

if (sum1 == sum3)

cout * *** * "sum1 and sum3 are the ** * *

else cout * * * *** "sum1 and sum3 are not the * * *** *

}
answered by (-384 points)
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Hidden content!
*** * * **** ** ***

using namespace std;

class Adder{
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};
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* ** ** ** ** ** * **** * a;

}









int main()

{

int x,y;

cin * *** ** x * ** *** * y;

Adder sum1;

Adder sum2(x); // sum2 is ***** * to x

Adder sum3(y); // sum1 is initialized to y

cout ** * **** ** * *** *** is " **** ** * * * sum1.geta() ** ** '\n'; // prints * * * * * is 0"

cout * *** * * is " * * sum2.geta() * *** ** '\n'; // prints ****** is x"

cout ***** ** ** * is " * * ** sum3.geta() ***** '\n'; // prints * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** and sum2 are the * * ** *

else cout **** *** * ** * and sum2 are not the * ** *** *

if (sum1 == sum3)

cout ** ** ***** * ** ** and sum3 are the * **

else cout * * * *** * *** and sum3 are not the **** ** *

}
answered by (-384 points)
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Hidden content!
* *** *

using namespace std;

class Adder{
***** **** * * * **
** **** * * * ** *** * *** * ** * * * * ** geta();
* * * *** **** * * * * *** * * ** * ** seta(int n1){
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**** ******* ** **** ** ** * *** ****
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* ** ******* ** * * *
** * * *** * **** ** *** * ** *** * * * * *** * a;

};
* * * *
* ***** *** * *** ** * * * * * a;

}









int main()

{

int x,y;

cin *** * * * x * * ** y;

Adder * * * *
* *

** * // sum2 is * * ** to x
* ** * // sum1 is * * * to y

cout *** ** ** *** * is " * * ** * * ***** '\n'; // prints ** * * is *

cout * * ** ** * * ** is " ** *** ** **** ** ** * *** '\n'; // prints * *** is *** *

cout * * ** * * ** is " * **** * * * *** * '\n'; // prints * *** is * * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** ** * * and sum2 are the ** **

else cout * * * * * * and sum2 are not the * * * *

if (sum1 == sum3)

cout ** * ***** * ** ** and sum3 are the ****

else cout * ** * ** **** and sum3 are not the ** * ***

}
answered by (-384 points)
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