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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

int x,y;

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sum1 += x; x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * ** * * and sum2 are the * * *

else cout * *** * * ** * and sum2 are not the * ***** *

if (sum1 == sum3)

cout ** * * ** * and sum3 are the * * *

else cout *** * * ** * * and sum3 are not the * ** **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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* ***

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answered by (-367 points)
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Hidden content!
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using * std;



class Adder

{
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{

int x,y;

cin * ** * x ** * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

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else cout * ** **** ** ** * and sum2 are not the ** ****

if (sum1 == sum3)

cout *** *** * * * and sum3 are the ***

else cout * ** **** ** * and sum3 are not the * * * * *


* ****** * * * ** * * 0;

}
answered by (-364 points)
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Hidden content!
* **

{
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}
answered by (-367 points)
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Hidden content!
**** * ** ** * **

using namespace std;

class Adder{
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}

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{

int x,y;

cin * * * x *** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * ** "sum1 is " * ** * sum1.geta() *** ** * '\n';

cout * * * "sum2 is " * * ** * sum2.geta() * ** ** *** '\n';

cout * * * * "sum3 is " * * *** sum3.geta() * ** * * * '\n';

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sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

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else cout * ** "sum1 and sum2 are not the * *

if (sum1 == sum3)

cout * * **** "sum1 and sum3 are the * ***

else cout * ** ** "sum1 and sum3 are not the **** ***** *

}
answered by (-384 points)
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Hidden content!
* * * ****** **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * *** * x ** * **** * y;

Adder sum1;

Adder sum2(x); // sum2 is ** to x

Adder sum3(y); // sum1 is initialized to y

cout *** *** * * * *** is " ** * sum1.geta() ** * * * '\n'; // prints * is 0"

cout ** * * ** * is " *** * ** sum2.geta() * * * '\n'; // prints * *** *** * is x"

cout * ** * ** *** is " ** **** * sum3.geta() **** * '\n'; // prints *** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * * and sum2 are the *** ** *

else cout * **** * ** * and sum2 are not the ** **

if (sum1 == sum3)

cout ** *** * ** ** and sum3 are the ** * *****

else cout **** *** and sum3 are not the * * **** **

}
answered by (-384 points)
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Hidden content!
* **** * * ***

using namespace std;

class Adder{
****** ** *** * ** * **
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};
*** * ***
** * ** ** ** * **** ** * ** * * a;

}









int main()

{

int x,y;

cin * ** **** x * ****** y;

Adder *** ** *
** *

** * // sum2 is * * * to x
** ** **** // sum1 is * ** to y

cout ** * * * *** is " * * * * * *** * '\n'; // prints * ** is *

cout **** * * * * **** is " * ** * * * * * ****** * '\n'; // prints * ** ** * is ****

cout ** * * **** **** is " * * ** ****** ******* '\n'; // prints ** *** * is * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** * * ** * and sum2 are the ****** *

else cout * * ** * ** *** and sum2 are not the *** *** **

if (sum1 == sum3)

cout ** * * and sum3 are the * *** * **

else cout *** * ** *** and sum3 are not the *** ** **

}
answered by (-384 points)
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