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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

int x,y;

cin ** * * x * ** * ** y;
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sum1 += x; * ** x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; ** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * * * **** **** and sum2 are the *** * *

else cout ** * *** **** **** and sum2 are not the ** * *

if (sum1 == sum3)

cout * ** * ** * * and sum3 are the ** *** ** **

else cout ** * * ***** and sum3 are not the *** *****

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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class Adder

{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

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else cout ****** *** ** * * ** and sum2 are not the * *** ** ***

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cout ** *** * * * ** **** and sum3 are the * ** *

else cout * ** * * * * *** * and sum3 are not the ** **** **


* *** * * ** *** * ** *** 0;

}
answered by (-364 points)
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** *

{
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}
answered by (-367 points)
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Hidden content!
** * ***** **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin * ** * *** * x ***** * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ***** ** "sum1 is " * ** ***** sum1.geta() ** *** *** '\n';

cout ***** * * "sum2 is " *** *** * sum2.geta() * * * '\n';

cout **** ** ** "sum3 is " * * * * * sum3.geta() ** ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ** *** "sum1 and sum2 are the * ***

else cout ** ** ** "sum1 and sum2 are not the **** ** *

if (sum1 == sum3)

cout ** * ** * "sum1 and sum3 are the * * * *

else cout ** * ** * * "sum1 and sum3 are not the * *** * **

}
answered by (-384 points)
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**** ** * * * ** ***

using namespace std;

class Adder{
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};
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* * * ** * * ** * a;

}









int main()

{

int x,y;

cin *** ** x *** *** y;

Adder sum1;

Adder sum2(x); // sum2 is ** ** to x

Adder sum3(y); // sum1 is initialized to y

cout **** *** * ** * * is " * *** * sum1.geta() * *** * '\n'; // prints * * * is 0"

cout * * * * *** * * * is " *** sum2.geta() * * * * '\n'; // prints * * * is x"

cout * * ** * *** * is " ** * sum3.geta() ** * * ** '\n'; // prints * ** ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * *** and sum2 are the * * * **

else cout **** * * *** * and sum2 are not the * *

if (sum1 == sum3)

cout * * ** *** ** and sum3 are the * *******

else cout ** * * * * ** and sum3 are not the * * **

}
answered by (-384 points)
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** * * ** * **

using namespace std;

class Adder{
** * ** * *** * **** * *
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};
***** *
*** ** ** * * *** *** a;

}









int main()

{

int x,y;

cin ****** x * ** y;

Adder ******
* * *** ****

*** * // sum2 is * * *** to x
*** ** // sum1 is * * ** to y

cout * *** **** ** * is " *** ** ** * ***** '\n'; // prints * ** is * *

cout ** * **** * is " **** ** * ** *** ** * * ** * '\n'; // prints ** * ** is * *** * *

cout ***** * * * *** * is " * * * * * * ** ** * * '\n'; // prints * is *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * ** **** and sum2 are the ** *

else cout *** **** * * * * * * and sum2 are not the *** * * *

if (sum1 == sum3)

cout *** * * * * and sum3 are the *** ** *

else cout *** *** * **** and sum3 are not the **** **

}
answered by (-384 points)
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