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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

int x,y;

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sum1 += x; * * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** *** *** * * and sum2 are the * *

else cout * * * * ** ****** and sum2 are not the * * *** **

if (sum1 == sum3)

cout * * * **** and sum3 are the ****** ** **

else cout **** * * *** * and sum3 are not the * * ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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* * *

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answered by (-367 points)
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

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else cout * *** * * * and sum2 are not the * * *** * **

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cout * *** * * ** *** and sum3 are the ** * **

else cout * * ***** ***** * and sum3 are not the *** ***


** * * *** * * * * *** 0;

}
answered by (-364 points)
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}
answered by (-367 points)
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** * * ***** ****

using namespace std;

class Adder{
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{

int x,y;

cin * * x * * * *** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** * * ** "sum1 is " *** * *** sum1.geta() * * **** * '\n';

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cout *** * * ** "sum3 is " *** **** sum3.geta() * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

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else cout * * * ** ** "sum1 and sum2 are not the *** ****

if (sum1 == sum3)

cout *** ** "sum1 and sum3 are the **** ** **

else cout * * ***** "sum1 and sum3 are not the ******* **

}
answered by (-384 points)
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Hidden content!
* ** * ** * * * **

using namespace std;

class Adder{
* * * * ** * * *
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};
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* **** * * * **** ** a;

}









int main()

{

int x,y;

cin * * **** x ** *** * y;

Adder sum1;

Adder sum2(x); // sum2 is * ***** to x

Adder sum3(y); // sum1 is initialized to y

cout * **** * * ** ***** is " * ** * sum1.geta() * ** '\n'; // prints * * is 0"

cout * ** *** * ***** is " ** ** ** sum2.geta() * * * '\n'; // prints ** * ** is x"

cout *** ** * *** ** *** is " * ** * *** ** sum3.geta() * *** * '\n'; // prints * ** ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** ** * * *** * and sum2 are the ******* *

else cout * * *** *** * * and sum2 are not the * * * *

if (sum1 == sum3)

cout *** * * * * ** ****** and sum3 are the ** *

else cout * ** * ** ** * ** * and sum3 are not the ** ** *

}
answered by (-384 points)
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Hidden content!
* * ***** ** *

using namespace std;

class Adder{
** *** *** ** ** * * * * *
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*** * * * * * *** * ** **** * * ** * ** * * * ** * **** **** ** ** ** ***** *** ** 0;
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**** ** * * ** *** * * ***** * *** ** * * *** * * * a;

};
** * * **** **
* **** * ** ** ** ****** ** a;

}









int main()

{

int x,y;

cin * ** x * ** **** y;

Adder * * *
**** **

* * * // sum2 is ** ** * * to x
*** *** // sum1 is * ** to y

cout * * *** ** is " ****** * *** ** ** * * * '\n'; // prints ***** is ** *

cout ***** * * * * is " ** ** ** * * * * '\n'; // prints * * is * ** *

cout ***** * * ** * * ** is " *** * * ** * * * *** '\n'; // prints ** is * * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * * and sum2 are the * *** * *

else cout * * * * * ** and sum2 are not the * **** ** ***

if (sum1 == sum3)

cout * ** *** * ** and sum3 are the ** * * * *

else cout * * ** ** * * and sum3 are not the ** **

}
answered by (-384 points)
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