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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; ** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** ** *** ** * * and sum2 are the * * **

else cout ** ** * * * and sum2 are not the ****

if (sum1 == sum3)

cout *** * ** ** * and sum3 are the ** ** **

else cout *** *** ** * ** and sum3 are not the * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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** ** **

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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * **** * * ** * and sum3 are the ** * ***

else cout *** * *** ****** and sum3 are not the * ********


* *** * * * ** * * ** * 0;

}
answered by (-364 points)
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* * **

{
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}
answered by (-367 points)
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Hidden content!
* * ** * **** *

using namespace std;

class Adder{
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int main()

{

int x,y;

cin ****** ***** x *** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout *** * ** "sum3 is " * * * * ** sum3.geta() * *** * * '\n';

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sum2 += -3;

sum3 += 2;

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else cout *** **** **** "sum1 and sum2 are not the ** * ***

if (sum1 == sum3)

cout * ** "sum1 and sum3 are the ***

else cout * **** * * "sum1 and sum3 are not the **** *

}
answered by (-384 points)
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Hidden content!
** * ** * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * * * x * *** * ** y;

Adder sum1;

Adder sum2(x); // sum2 is *** to x

Adder sum3(y); // sum1 is initialized to y

cout **** ** * ** ** *** * is " * ***** * sum1.geta() * * * * '\n'; // prints ***** ** is 0"

cout *** * * * **** * is " * *** sum2.geta() *** * ** '\n'; // prints ** **** * * is x"

cout * *** * *** is " ** *** ** ** sum3.geta() * * * ** ** '\n'; // prints * ** * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** **** * *** * * and sum2 are the * ** *

else cout * * * * * * * and sum2 are not the ** ** **

if (sum1 == sum3)

cout * *** * * and sum3 are the * ***

else cout **** ****** * ** * ** and sum3 are not the * **

}
answered by (-384 points)
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Hidden content!
*** *** * ******

using namespace std;

class Adder{
* *** * ** ** ** *** ** *
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** ** ** * ** ** ** *** * * ** * a;

};
* * *
* ** *** * **** ** * *** a;

}









int main()

{

int x,y;

cin * *** * ** x ****** y;

Adder * ** *
* **

** * * * // sum2 is *** to x
** ** * // sum1 is **** * to y

cout * ** *** ** is " ***** * * * **** * * '\n'; // prints ** is *****

cout ** **** ** * ** is " ** * * ** **** '\n'; // prints ******* * is * * ***

cout *** * * *** **** ** is " ** * *** * **** ***** * * '\n'; // prints * *** * is *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** * *** and sum2 are the * ** ** *

else cout *** * ** * * * ** and sum2 are not the * *** ***

if (sum1 == sum3)

cout **** * * * and sum3 are the *** **

else cout * * *** * * **** * * and sum3 are not the * ** ***

}
answered by (-384 points)
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