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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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else cout ** ** ** ** * and sum2 are not the * * *

if (sum1 == sum3)

cout ** * * * * * * and sum3 are the ** *

else cout ** ** **** * * and sum3 are not the * *** * ** **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using *** std;



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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * * * ** * * * and sum3 are the *** ** * **

else cout * **** * *** and sum3 are not the ****


* * ** *** * **** * *** ** *** 0;

}
answered by (-364 points)
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*

{
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}
answered by (-367 points)
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Hidden content!
* **** ** * ** ** *

using namespace std;

class Adder{
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}

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{

int x,y;

cin *** * ** x * **** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ***** ** "sum1 is " ** * ** ** sum1.geta() * **** '\n';

cout * *** *** * "sum2 is " * * * *** sum2.geta() *** *** '\n';

cout * * "sum3 is " * * * * sum3.geta() * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ** * * * * "sum1 and sum2 are the *** ***

else cout * * "sum1 and sum2 are not the *** **

if (sum1 == sum3)

cout * * ** "sum1 and sum3 are the *** *

else cout * * "sum1 and sum3 are not the * *****

}
answered by (-384 points)
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Hidden content!
** * * * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * *** x * **** ** y;

Adder sum1;

Adder sum2(x); // sum2 is * ** * to x

Adder sum3(y); // sum1 is initialized to y

cout *** * * * ** is " * **** * sum1.geta() * * *** '\n'; // prints * ** * is 0"

cout **** ** **** * * is " **** ** sum2.geta() * ** '\n'; // prints * ** **** is x"

cout **** * * ** is " ** ** ** sum3.geta() * *** '\n'; // prints * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** *** and sum2 are the ** ***** *

else cout *** * * **** and sum2 are not the * * *** *

if (sum1 == sum3)

cout ** *** ****** * and sum3 are the * ** *

else cout * ** ** ** ** and sum3 are not the * * * *

}
answered by (-384 points)
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Hidden content!
****** * * *

using namespace std;

class Adder{
*** * * ***** **
* ** * * * ** * ** * ** ***** * * * geta();
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**** ** * ** ** ** ** **** *** * * ** ** ***** * a;

};
***** **
* * * * * ** * * a;

}









int main()

{

int x,y;

cin * * * * x * ***** y;

Adder * *** **
* * * *

* ** // sum2 is * * * to x
** *** * // sum1 is * ** to y

cout ******* * * * is " *** ** * ** **** * '\n'; // prints ***** ** is * **

cout ** * ** * is " * *** ** * ** ** * ** * '\n'; // prints * ** is ** * *

cout ** *** * * is " * * ** * * ** * *** ** * '\n'; // prints * ** *** is *** **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * **** * * * and sum2 are the *** *****

else cout **** * * * * *** * and sum2 are not the * * ** *

if (sum1 == sum3)

cout *** *** * *** and sum3 are the * * **** **

else cout * ** * * ***** ** and sum3 are not the ** ******

}
answered by (-384 points)
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