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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

int x,y;

cin ***** x ** ** *** y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum2)

cout * * **** * * *** * and sum2 are the ** * * *

else cout * *** * * ** and sum2 are not the * ******

if (sum1 == sum3)

cout ** * *** *** ** * * and sum3 are the * * ** **

else cout ** * * * * * * ** * * and sum3 are not the * ******

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout * ***** * ** ** and sum3 are the * ** ** * *

else cout ** ** ** and sum3 are not the * ** ** *


** **** ** ** 0;

}
answered by (-364 points)
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Hidden content!
* * *

{
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}
answered by (-367 points)
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Hidden content!
*** * * * * ** *

using namespace std;

class Adder{
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}

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{

int x,y;

cin ** *** * * x ** * ****** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout * *** ** "sum3 is " ** * * ** sum3.geta() * * * ***** '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * **** "sum1 and sum3 are the * ** * **

else cout ** * * * "sum1 and sum3 are not the * * * *

}
answered by (-384 points)
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Hidden content!
***** * * * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * * x *** * * y;

Adder sum1;

Adder sum2(x); // sum2 is ** ** * to x

Adder sum3(y); // sum1 is initialized to y

cout ** *** * * * ** is " ***** *** sum1.geta() ** ** ** '\n'; // prints ** ** * ** is 0"

cout *** * ***** ** * ** is " * * *** sum2.geta() *** ***** '\n'; // prints * * *** is x"

cout ***** * ** *** is " * ** * sum3.geta() * * * '\n'; // prints ** ****** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ******** * ** * ** and sum2 are the * * *

else cout * * ** * * and sum2 are not the ** ** *

if (sum1 == sum3)

cout * *** * ** * and sum3 are the ** * ***

else cout ***** * *** and sum3 are not the * * **

}
answered by (-384 points)
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Hidden content!
** * *** ***

using namespace std;

class Adder{
* * * * *** * * * * *
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* ** * * ** ** * * *** ** ****** **** * * a;

};
* * ***
** * * *** ** * *** a;

}









int main()

{

int x,y;

cin ** ** * x * ** * * y;

Adder * **
* *** *

* **** // sum2 is *** to x
* ** // sum1 is ** ** to y

cout * * * *** * * is " * * *** * * ** ** '\n'; // prints * * is ********

cout * ** * *** *** is " ** ** * * * * ** * * '\n'; // prints * * * is ***

cout **** ** **** ** ** is " ** * ** * ** ** * '\n'; // prints * * **** is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** ** *** and sum2 are the * ** *

else cout ** ****** *** * and sum2 are not the *** ****

if (sum1 == sum3)

cout * **** * * * ** * and sum3 are the ** * * * **

else cout * **** ** * and sum3 are not the * ** * ***

}
answered by (-384 points)
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