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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; *** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** ** * * * and sum2 are the ***

else cout ****** * * ** * and sum2 are not the **** * **** *

if (sum1 == sum3)

cout * * * * ** * ** and sum3 are the * * ** *

else cout ******* * *** and sum3 are not the *** * **

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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using ** * std;



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cout *** * * * ** *** and sum3 are the * **

else cout ** *** * * and sum3 are not the * * ** *


*** ** ** * * * ** *** *** 0;

}
answered by (-364 points)
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* **

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}
answered by (-367 points)
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Hidden content!
* ** *** ***** * * *

using namespace std;

class Adder{
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{

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cin * x ** *** * ** y;

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Adder sum2(x);

Adder sum3(y);

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cout *** "sum3 is " ** ** sum3.geta() **** ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout ** ** * ** "sum1 and sum3 are the **** * *

else cout * **** "sum1 and sum3 are not the ****** *

}
answered by (-384 points)
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Hidden content!
* * * * * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ** * * * * x * *** y;

Adder sum1;

Adder sum2(x); // sum2 is * ***** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * ** * * is " * ** sum1.geta() *** *** ** '\n'; // prints ** * * is 0"

cout *** * *** *** * ** is " ** * * * sum2.geta() ***** * *** '\n'; // prints * ** * is x"

cout ** * ** * ** * is " * **** sum3.geta() ***** * * '\n'; // prints * *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout **** ** ** ** * * and sum2 are the * *****

else cout **** * * ** * and sum2 are not the *** * *

if (sum1 == sum3)

cout * ** ** * *** and sum3 are the * ** * **

else cout * *** ** * *** and sum3 are not the * ** *

}
answered by (-384 points)
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Hidden content!
* * **** ** **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * **** x * * **** y;

Adder *** **
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* *** // sum2 is ** ** to x
* * // sum1 is ** to y

cout ***** * ***** *** is " **** * ** * ** * ** *** '\n'; // prints ** ** ** is ** **

cout ** ** * * **** is " * ** * **** ** ** '\n'; // prints * *** * ** is * ***

cout ** * ** * ** is " * *** * * *** * * * ** '\n'; // prints * * *** is ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** *** ** * * ** *** and sum2 are the ** *

else cout * ** * ***** * * and sum2 are not the ** * * *

if (sum1 == sum3)

cout **** *** * * ** * and sum3 are the *** * * *

else cout ***** * * * and sum3 are not the * * * **

}
answered by (-384 points)
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