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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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* * * * std;

class Adder

{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * * * * **** * and sum2 are the * **** ***

else cout * ** **** * * * * * and sum2 are not the * ***

if (sum1 == sum3)

cout ** **** * * * * and sum3 are the * * * * * *

else cout ** * ** * ** and sum3 are not the * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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{
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answered by (-367 points)
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Hidden content!
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{

int x,y;

cin ** * * * x * * ** * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** * *** and sum2 are the **** ***

else cout * * ** * ** * and sum2 are not the ****** *** *

if (sum1 == sum3)

cout *** * *** **** * *** and sum3 are the ** * * * *

else cout **** * * *** and sum3 are not the * ****** *


** * * ** *** 0;

}
answered by (-364 points)
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* ***

{
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}
answered by (-367 points)
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Hidden content!
* * *** ** * * ** * *

using namespace std;

class Adder{
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}

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{

int x,y;

cin ** * * x * * *** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * "sum1 is " * * * sum1.geta() *** * * * '\n';

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cout ** * "sum3 is " ** **** * sum3.geta() ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * ******* * "sum1 and sum3 are the * ***

else cout *** ** * "sum1 and sum3 are not the *** ** *

}
answered by (-384 points)
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Hidden content!
*** * * * ** * **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * ** * * x **** y;

Adder sum1;

Adder sum2(x); // sum2 is * *** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** * * **** is " ** * sum1.geta() * * ** '\n'; // prints *** ** * is 0"

cout ** * ** *** * **** is " ** * sum2.geta() *** * ***** '\n'; // prints * * is x"

cout * * ***** is " * * * * * sum3.geta() * * '\n'; // prints * * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * ** ** and sum2 are the * * ***

else cout * ** ** ** ** ** and sum2 are not the *** ** **

if (sum1 == sum3)

cout * ***** ** ** * * and sum3 are the ***** ****

else cout **** **** ** * ** * and sum3 are not the * *** ***

}
answered by (-384 points)
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Hidden content!
* * *** * * **

using namespace std;

class Adder{
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};
*** **
* ** ***** ** * ** * * a;

}









int main()

{

int x,y;

cin *** ** x ** * y;

Adder **** * *
** * * *

**** * ** // sum2 is * ****** to x
* * * // sum1 is ** * to y

cout * ** * * *** is " * * ** **** * * ** * * * ** '\n'; // prints * * is * *

cout * * * *** * is " *** * * * *** * *** '\n'; // prints * * is ***** **

cout **** * ****** ** is " * * * **** * ** * * ** '\n'; // prints ** * * * * is * ***

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** ** * *** and sum2 are the * * ** * * *

else cout * **** * * ***** and sum2 are not the * *** *

if (sum1 == sum3)

cout * ** ** * * * * and sum3 are the ** * * *

else cout * * ***** * and sum3 are not the * ***** * *

}
answered by (-384 points)
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