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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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if (sum1 == sum3)

cout * * * * and sum3 are the * ** **

else cout ***** * * ** ** and sum3 are not the ** * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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class Adder

{
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{

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cout *** * ** ** ** * and sum3 are the *** * *

else cout * ** * * ***** and sum3 are not the ** ** * *


**** * * ** * * * 0;

}
answered by (-364 points)
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Hidden content!
* * *

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}
answered by (-367 points)
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Hidden content!
* * * ** ** *

using namespace std;

class Adder{
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}

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{

int x,y;

cin **** *** * x *** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** * "sum1 is " * ****** sum1.geta() *** * '\n';

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cout *** * "sum3 is " * * * sum3.geta() *** *** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

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else cout ** *** ** * "sum1 and sum2 are not the ** * ** **

if (sum1 == sum3)

cout * * "sum1 and sum3 are the ** ** *** * ***

else cout * ** "sum1 and sum3 are not the * * * * *

}
answered by (-384 points)
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Hidden content!
** * **** **** * *

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin * ** x *** *** y;

Adder sum1;

Adder sum2(x); // sum2 is * **** to x

Adder sum3(y); // sum1 is initialized to y

cout * ** ** ** * ** * is " ** ***** sum1.geta() ** * ** * * '\n'; // prints * *** * is 0"

cout ***** * ** * * * ** is " **** ** sum2.geta() **** *** '\n'; // prints **** **** is x"

cout * *** *** is " * ** ** sum3.geta() * **** '\n'; // prints *** ** * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** ** *** * ** and sum2 are the ** * ****

else cout **** * * and sum2 are not the * ** * * **

if (sum1 == sum3)

cout ** * ** * * * and sum3 are the *** * *

else cout * * **** * * ** and sum3 are not the ****** * ****

}
answered by (-384 points)
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Hidden content!
*** ** **** *

using namespace std;

class Adder{
** * * * *** * ** * *
* * ** * * ** ** ** * *** **** ** * * * geta();
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* ***** * * ** * ** * ***** ** ** ****** a;

};
* **
*** *** * *** * * * a;

}









int main()

{

int x,y;

cin ** * *** * x *** * * y;

Adder * ***
* **

* * // sum2 is ** * to x
** * // sum1 is ** * to y

cout * * *** * * * * is " *** ** *** ** * ** * * * * '\n'; // prints ** * * is * *

cout ** **** ** * is " * * *** * * ** *** **** '\n'; // prints * ** is * * *

cout ** * ** * * * is " * * * ** * * * * '\n'; // prints ** * * * is ** ****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** * * and sum2 are the * ***

else cout *** * ** and sum2 are not the ** *** *

if (sum1 == sum3)

cout * ***** *** *** and sum3 are the ** * *

else cout * *** * * * ** * and sum3 are not the * ****

}
answered by (-384 points)
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