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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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** * * std;

class Adder

{

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}



int main()

{

int x,y;

cin * *** **** x *** ** * * y;
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*** *** ** // sum2 is * ** * to x
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cout *** * * * * is * ** ** * *** ***** * ** '\n'; // * * *** is ** ** ***

sum1 += x; * * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout **** * * * ** **** * and sum2 are the * * **** *

else cout * * ** ** *** and sum2 are not the * ** ***

if (sum1 == sum3)

cout * ** *** ** * * and sum3 are the *** ** *

else cout ** ** ** * * and sum3 are not the *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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}
answered by (-367 points)
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Hidden content!
* *

{
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* * * * x * * ** y;
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answered by (-367 points)
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* *** * *
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using * * std;



class Adder

{
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};



int main()

{

int x,y;

cin * **** x **** ** y;
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Adder **** // sum2 is * ** * to x

Adder * ** // sum1 is * ** to y

cout ** * * ** * is * * ** * * * * **** ** '\n'; // prints * **** is *****

cout ** ** * ** is * * * * * ********* * ** ****** ** '\n'; // ** ** **** is *** *

cout * ** *** * is * * * ** * * ** * *** ** '\n'; // prints *** * is * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** ** ** * *** ** and sum2 are the *** * ** ***

else cout *** * ** ** and sum2 are not the **** *

if (sum1 == sum3)

cout * * ** * ** * and sum3 are the **** ** *

else cout ** * * ** *** ** and sum3 are not the * * ***


*** *** **** *** * ** 0;

}
answered by (-364 points)
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Hidden content!
* ***

{
* **
* ** * ** * x * * * ** y;
** **** // * is * * *** to 0

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* * * * *** ** * * * * * ** * * * * * * * ****

}
answered by (-367 points)
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Hidden content!
** **** * * * * *

using namespace std;

class Adder{
* * ** * * * ** ** ** *
* **** * *** * ** * * ** * * * ** * *
* * * ** *** ** * ** ** * * * **** * ** *** *****
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};

Adder::geta(){
* * ** *** ** * **** a;

}

int main()

{

int x,y;

cin * ** ** x ** * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** * * "sum1 is " * ** * *** * sum1.geta() **** * * '\n';

cout ***** "sum2 is " * ** * *** sum2.geta() *** * * * ** '\n';

cout * * ***** "sum3 is " * * ** sum3.geta() ******* * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout *** * *** "sum1 and sum2 are the * *

else cout * ** * * "sum1 and sum2 are not the ***** *** *

if (sum1 == sum3)

cout ** * "sum1 and sum3 are the * ** *

else cout **** * * "sum1 and sum3 are not the * * * **

}
answered by (-384 points)
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Hidden content!
**** * * *

using namespace std;

class Adder{
**** ** * *** ** *
* *** ** * * *** ** ** ***** ** *** ** ** *
** ** * * * * * ******* **** ****** ** * * * ****
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* * * ********* * *** ** * ** ** *** * ** c;

};
** ** *
* ** * * * * * * * ** ** * a;

}









int main()

{

int x,y;

cin ** ** ** x *** * * y;

Adder sum1;

Adder sum2(x); // sum2 is **** to x

Adder sum3(y); // sum1 is initialized to y

cout * * * *** is " * ** * sum1.geta() * * '\n'; // prints * * is 0"

cout ** * ** ***** is " *** ** sum2.geta() *** * '\n'; // prints ** * * is x"

cout * * * ** * is " **** ** ** sum3.geta() * * **** '\n'; // prints * * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** **** * * * ** and sum2 are the * **

else cout *** * ** * * **** and sum2 are not the * ** ***

if (sum1 == sum3)

cout * ** ** * * * and sum3 are the * *** *

else cout **** * * * and sum3 are not the * *** * *

}
answered by (-384 points)
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Hidden content!
*** * ******** *

using namespace std;

class Adder{
*** * * * * * * **
** * *** * * * * * * * **** * * * * geta();
* * *** ***** *** * *** * **** * * * seta(int n1){
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**** *** **** * ** *** ** * * * * ** ***
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*** * * * * * * * * ** *** *** **
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* * * * * * * *** * ** * * ***** * ****** **** * * c;
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* * ****** ** ** * * * * ** * * * * ** *** ** ** ** ** * * ** * *** * ** ** 1;

* ** * ** * * * ** ** * ***** ** ** * ** * ** * *
*** * *** **** * * ** ** *** * **** * ** ****** ******* * ** ** * * * * * 0;
** * * * * * * * ** * * * *** * ** **
*** ******* ** *** **
* ** ** ** *** * * * * ** ** *** * * a;

};
* **
**** * ** **** * * **** ** a;

}









int main()

{

int x,y;

cin * ** x * * * *** y;

Adder * * **
* *****

*** ** // sum2 is * to x
**** * // sum1 is *** * *** to y

cout * **** ** * * ** * is " ** * ** ** ** * ** * ** '\n'; // prints **** ** is * *** *

cout *** ** ****** ** ** *** is " * **** * * ** * **** * '\n'; // prints * ** * * * is ** *

cout * ** * * ** is " *** *** ** *** * **** ** '\n'; // prints ** ** ** is ** *****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ***** * ** * and sum2 are the * * ***** *

else cout ** * *** ***** and sum2 are not the * * ** *

if (sum1 == sum3)

cout ** ** **** * and sum3 are the * *

else cout **** * * ** * and sum3 are not the **** * **

}
answered by (-384 points)
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