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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * and sum2 are the * ** *

else cout * ** ** * * and sum2 are not the ** * *

if (sum1 == sum3)

cout **** ** * ** * and sum3 are the *** * * **

else cout *** **** * ** and sum3 are not the * * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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{
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{

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cout ** * ***** * * ** and sum3 are the **** * * *

else cout ** ** * * ** and sum3 are not the * ** * ***


*** ********* * ** *** * * 0;

}
answered by (-364 points)
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*** *

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}
answered by (-367 points)
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class Adder{
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}

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{

int x,y;

cin **** ****** x * * * * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout * ****** * "sum3 is " * ** * *** sum3.geta() ** *** ** '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout ** *** * "sum1 and sum3 are the * * *

else cout * ** * * "sum1 and sum3 are not the *** *** *

}
answered by (-384 points)
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Hidden content!
**** ** * * **

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin **** * * x *** * y;

Adder sum1;

Adder sum2(x); // sum2 is * * **** to x

Adder sum3(y); // sum1 is initialized to y

cout ** * *** ** * * ** * * is " ** ** sum1.geta() * ** ** '\n'; // prints * **** ** * is 0"

cout * *** ***** ***** is " **** * sum2.geta() ** **** '\n'; // prints * ** ** ** is x"

cout * *** * * * * ** is " * ** sum3.geta() ** * * ** * '\n'; // prints ** *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * ** ** and sum2 are the * *** * *

else cout * ** * *** **** and sum2 are not the * * * *

if (sum1 == sum3)

cout ********* ** *** and sum3 are the * * ** **

else cout ***** ** *** and sum3 are not the * * **

}
answered by (-384 points)
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Hidden content!
** * **** * *

using namespace std;

class Adder{
** **** ******* * * * *
* * * * * * *** * ** ** * ** ** ** * geta();
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**** **** **** ** * * ** * * * ** ** *** ** * * ** ** * *** *** * ** * * * *** * 0;
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};
* *
* * * ***** * * * * * ** a;

}









int main()

{

int x,y;

cin *** * * x ******* y;

Adder *
* * *

* **** // sum2 is *** to x
* ** ** // sum1 is ** * * to y

cout * ** * ** * is " *** *** ** **** * ** * ** ** '\n'; // prints **** ** * is * **

cout ** * * * ** * ** is " ***** ** * * *** * ** * '\n'; // prints * * is *** *

cout ** ** * *** * *** * is " * ** ** * ** *** * **** * ** '\n'; // prints * is * ****

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** *** * ** * and sum2 are the * * *

else cout * ** ** * *** **** ** and sum2 are not the ** * **

if (sum1 == sum3)

cout *** *** ** * ** and sum3 are the ** *

else cout * ** * ***** * and sum3 are not the * * *

}
answered by (-384 points)
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