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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

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cout ** * *** ** * and sum2 are the * *****

else cout ** ** * * **** ** and sum2 are not the * * * *

if (sum1 == sum3)

cout * *** * *** * and sum3 are the ** * *

else cout * ** * * *** **** and sum3 are not the * * *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * ** ** * **** and sum3 are the * ******** *

else cout * * * * * and sum3 are not the * * *


**** * *** * ***** * * * ** 0;

}
answered by (-364 points)
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Hidden content!
* *

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answered by (-367 points)
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Hidden content!
* * * * ** * *** *

using namespace std;

class Adder{
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int main()

{

int x,y;

cin * * * x y;

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Adder sum2(x);

Adder sum3(y);

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cout *** ** "sum3 is " ** * ** sum3.geta() * * ** '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

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else cout ** **** "sum1 and sum2 are not the ** * *

if (sum1 == sum3)

cout * **** * "sum1 and sum3 are the * * * ** *

else cout *** ** ***** "sum1 and sum3 are not the * * ***

}
answered by (-384 points)
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Hidden content!
* * ** ***

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin ***** * * x * * * * y;

Adder sum1;

Adder sum2(x); // sum2 is ** *** to x

Adder sum3(y); // sum1 is initialized to y

cout *** ** * * * is " *** * * sum1.geta() * * ** '\n'; // prints * ** is 0"

cout * * ****** ** is " ** * sum2.geta() * * **** * * '\n'; // prints ** * is x"

cout *** ** * * is " *** **** sum3.geta() ** * ** '\n'; // prints * * ******* is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * ** * ** and sum2 are the * ** *

else cout ** ** ** and sum2 are not the *** *** **

if (sum1 == sum3)

cout ** ******** ** * and sum3 are the * * * * **

else cout * *** *** and sum3 are not the * * ** * *

}
answered by (-384 points)
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Hidden content!
** * * ** * * ****

using namespace std;

class Adder{
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};
***
***** ** * ** **** * a;

}









int main()

{

int x,y;

cin * * * ** x * * ** * y;

Adder *** **
** **

** ** // sum2 is * * * to x
***** // sum1 is * * to y

cout * *** * * ** * is " * ** * * * ** ** * '\n'; // prints ** **** * is ** *

cout ** * ** * ** * * is " * ** * ** ** * ** ** * '\n'; // prints ** ** * is * *****

cout **** * ** ** ** * is " * **** * * ** ******** '\n'; // prints * * ** is **** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ***** and sum2 are the ** * *

else cout ****** * * ** * and sum2 are not the *** ****** *

if (sum1 == sum3)

cout * * * ** * and sum3 are the **** *

else cout * * * * * * and sum3 are not the * ** * *

}
answered by (-384 points)
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