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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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* *** * std;

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{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * * **** * * ** and sum2 are the ** * * * **

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if (sum1 == sum3)

cout * ** *** ** * and sum3 are the ** * ** *** *

else cout * * *** ** ** *** and sum3 are not the * *

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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{

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cout * * * ** ** and sum3 are the ** * ***

else cout **** * * * * **** * and sum3 are not the * * *


* ** ** ** * * * * ** 0;

}
answered by (-364 points)
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Hidden content!
* *

{

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}
answered by (-367 points)
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Hidden content!
*** ** * ** *

using namespace std;

class Adder{
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{

int x,y;

cin *** * *** x * * * ** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

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cout ** * * * "sum2 is " * * * sum2.geta() * ** * * '\n';

cout ** ** ** "sum3 is " ** * ** sum3.geta() ** * * * '\n';

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sum2 += -3;

sum3 += 2;

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else cout ** ***** * "sum1 and sum2 are not the * * *

if (sum1 == sum3)

cout * * "sum1 and sum3 are the ** *** *

else cout *** * ** * "sum1 and sum3 are not the ** **** * *

}
answered by (-384 points)
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Hidden content!
** * *** ** ** **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin *** * * ** x * * y;

Adder sum1;

Adder sum2(x); // sum2 is ** * * to x

Adder sum3(y); // sum1 is initialized to y

cout *** * ** * * * * is " ** *** * * sum1.geta() *** ** ** '\n'; // prints * is 0"

cout ** *** * * * is " ** sum2.geta() **** *** ** '\n'; // prints * *** * is x"

cout * * ** * ** ** is " ** * ** sum3.geta() ** * ** '\n'; // prints * ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** ** * * ** ** and sum2 are the **** * **

else cout * *** * * ***** and sum2 are not the *** ** *

if (sum1 == sum3)

cout ****** * * * * * ** and sum3 are the *****

else cout ** ** ** ***** and sum3 are not the * ****** *

}
answered by (-384 points)
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Hidden content!
* *** * ****

using namespace std;

class Adder{
* * *** *** * *** * * * ** ***
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*** * * ** * **** * * **
* * * * ** * ***** * ** ** * * a;

};
* *****
* * ** * * * *** ***** a;

}









int main()

{

int x,y;

cin ** ** ** * x * **** * y;

Adder * ** *
* * *

** ** * // sum2 is **** to x
** **** // sum1 is ** * ** to y

cout * * * ** * ** is " * **** ** * ***** * * *** * * '\n'; // prints ** * is **** **

cout **** * * * ** * * is " ** * * ** ** *** * * ** '\n'; // prints * ** * * * is *

cout ** * ** *** * **** is " * ** * **** * ***** '\n'; // prints * * is * ** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout **** * and sum2 are the ** * *****

else cout ** ** * ** ** and sum2 are not the * *

if (sum1 == sum3)

cout * ** * * * * and sum3 are the * ****

else cout * * * ** * * * * and sum3 are not the ** * **** * *

}
answered by (-384 points)
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