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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum3)

cout * * ** ****** and sum3 are the ** ******

else cout * * * * ** * and sum3 are not the * ** *

}
answered by (-367 points)
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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answered by (-367 points)
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{
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{

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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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cout * * ** *** ** and sum3 are the ** *

else cout * * ** * * * *** *** and sum3 are not the ** * **


* * * ** ** * * ***** * 0;

}
answered by (-364 points)
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** **

{
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}
answered by (-367 points)
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Hidden content!
**** * *** ***** **

using namespace std;

class Adder{
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}

int main()

{

int x,y;

cin **** * x * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * ** "sum1 is " **** * * sum1.geta() ****** *** '\n';

cout * * * ** ** "sum2 is " ** * sum2.geta() **** *** ** '\n';

cout ** *** * "sum3 is " * ** * sum3.geta() * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ** **** ** "sum1 and sum2 are the * ****

else cout *** *** "sum1 and sum2 are not the ** ** *

if (sum1 == sum3)

cout ** *** ** "sum1 and sum3 are the *******

else cout *** * "sum1 and sum3 are not the * ** *

}
answered by (-384 points)
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Hidden content!
******** * *

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * * * **** x * **** * y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout * *** ** ** * is " *** * * sum1.geta() ** * '\n'; // prints * * is 0"

cout * **** ** * * is " * * sum2.geta() ** * ** '\n'; // prints ** ** is x"

cout **** * *** * * * is " * * sum3.geta() ** ** *** * '\n'; // prints *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** * *** *** and sum2 are the ** * ** ** *

else cout *** *** * ** * *** and sum2 are not the * * ****

if (sum1 == sum3)

cout ***** * * * ** and sum3 are the ** * ****

else cout * * * * **** * and sum3 are not the * * * * *

}
answered by (-384 points)
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Hidden content!
*** * * *** **** *

using namespace std;

class Adder{
** ** **** * * * *
** * * * * *** ** ** * ***** * * ** * ** geta();
* * * * ** * **** * * * * ** *** ** * ***** * seta(int n1){
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****** ** *** * * * * * * * *** *** **** ** * * * * ***
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* * ** * * ** * * ** *** ** ***** * * * **
** *** * * * * * ** ** *
* *** * ***** * * ** ** ** * * * a;

};
* * * *****
***** ** * * ** ** * * * a;

}









int main()

{

int x,y;

cin ** * x * **** ** y;

Adder * *
** * *****

* * * // sum2 is * to x
* *** // sum1 is **** to y

cout ** * ** * *** * is " * * * ** **** ***** '\n'; // prints * * * is *****

cout * ** *** ** * ** * is " * ** * * ** ** * **** * '\n'; // prints * *** is ** * *

cout ** *** **** ***** is " * ** * * *** * '\n'; // prints * ** is *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * **** *** * and sum2 are the *** ** ** *

else cout * ** * ** ** ** * and sum2 are not the **** *

if (sum1 == sum3)

cout ** * * * * * * * * and sum3 are the * * *

else cout * *** * *** * and sum3 are not the * ** ****

}
answered by (-384 points)
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