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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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class Adder

{
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{

int x,y;

cin * * *** x *** ** * y;
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sum1 += x; * * x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** *** * * and sum2 are the * * *** **

else cout * *** ** * * * * and sum2 are not the * * * * *

if (sum1 == sum3)

cout * * ** * * * * * and sum3 are the ** * *

else cout *** * ** *** * * and sum3 are not the * * * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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** ***

{
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answered by (-367 points)
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{
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{

int x,y;

cin * *** x *** ** y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * * * * and sum2 are the ** * ****

else cout ***** * * * ** * and sum2 are not the *** ****

if (sum1 == sum3)

cout ** *** * and sum3 are the * ** *

else cout * * *** * ***** * and sum3 are not the * ** ** *


*** ** * * * **** ** 0;

}
answered by (-364 points)
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* * **

{
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}
answered by (-367 points)
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Hidden content!
** *** * ** ** * **

using namespace std;

class Adder{
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};

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}

int main()

{

int x,y;

cin * * ** x **** *** ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * *** "sum1 is " ** ****** * ** sum1.geta() *** * ** ** '\n';

cout ** * * "sum2 is " ** ** * *** sum2.geta() ** * '\n';

cout * **** * * * "sum3 is " * * sum3.geta() *** * * * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout ** "sum1 and sum2 are the ** * * *

else cout * ** * * "sum1 and sum2 are not the * * *** ****

if (sum1 == sum3)

cout ***** ** "sum1 and sum3 are the ** **

else cout * **** "sum1 and sum3 are not the ** *** * **

}
answered by (-384 points)
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Hidden content!
***** * * ** **

using namespace std;

class Adder{
* * ****** ** ** *
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** *** *** * * *** * * ** ** *** * * * *
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**** *** ** * *** * * *** * *** * ** * ** ** c;

};
* *** ****
* * * * * *** *** * ** a;

}









int main()

{

int x,y;

cin * ** x * *** * y;

Adder sum1;

Adder sum2(x); // sum2 is * * to x

Adder sum3(y); // sum1 is initialized to y

cout * * * ** * ** is " * * ****** sum1.geta() ***** ** '\n'; // prints * ** is 0"

cout *** ** * ** * * is " **** * * sum2.geta() * **** '\n'; // prints ** * is x"

cout * * ** * ** is " * **** ** sum3.geta() * ** ***** '\n'; // prints **** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * ** * * ****** and sum2 are the *** ****

else cout * * * * * ** and sum2 are not the ** ***** *

if (sum1 == sum3)

cout * * * and sum3 are the *** * ** *

else cout ** * * * ** and sum3 are not the *** *

}
answered by (-384 points)
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Hidden content!
** * * * *

using namespace std;

class Adder{
****** * * ** *** *** ***
** ** ** ** * * * ** * * * * ** ** ** * geta();
** ** ** *** * **** ** * ** ** * ** * seta(int n1){
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**** * ** ** * *** ** ** * * *** ** * *********** *
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** *** * ** * * * * * ** *** ******* * * ** * *** ** ** * * ** * * c;
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* ****** * * * **** * **** *** * ***** ** * ** *** ** * *** ** * * *
* * * * * * *** *** ***** * * ** ** * *** **** **** * ** **** ** * *** * **** * * * **** * 0;
* * * * ** * ***** ** *** * ** * **
* * ** ** * * ** * ** ****
** * ** * ** ** * ** * ** ***** * ***** * a;

};
* ** *
** * * * ** * * ** * **** *** a;

}









int main()

{

int x,y;

cin *** * **** x * ** *** * y;

Adder ** ** ** **
*

* ** * // sum2 is * * to x
** * // sum1 is * *** to y

cout * * * ** **** is " ** *** ** ** ** ** * * ****** '\n'; // prints * * * ** is * *** *

cout *** * is " ** * * ** * **** **** *** '\n'; // prints * ** * is *** *

cout * * * * * * is " ***** ** ** **** ****** '\n'; // prints * ** * is **** * *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** * ** * * *** and sum2 are the * ** * * **

else cout ** ** * ** **** * and sum2 are not the ** *** *

if (sum1 == sum3)

cout * * * ** * ** * and sum3 are the ** ** **

else cout *** *** * * * ** and sum3 are not the * * ** **

}
answered by (-384 points)
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