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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{
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{

int x,y;

cin ***** x ** * ** ** y;
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sum3 += 2; *** 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * *** * *** * and sum2 are the *

else cout *** * * ** and sum2 are not the ** *** ***

if (sum1 == sum3)

cout *** ** * * ** and sum3 are the *** ** *

else cout * * ** ** and sum3 are not the * * * * *

}
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answered by (-367 points)
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answered by (-134 points)
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answered by (-367 points)
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** *

{
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answered by (-367 points)
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*** *
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using * std;



class Adder

{
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{

int x,y;

cin **** *** x *** ** ** ** y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** and sum2 are the * * *

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if (sum1 == sum3)

cout ***** ** * * **** * and sum3 are the *******

else cout * ** * * * and sum3 are not the * *** ***


* **** * *** * * * ** 0;

}
answered by (-364 points)
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** **

{
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* * ** *** * x * ***** y;
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}
answered by (-367 points)
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* * * * **

using namespace std;

class Adder{
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};

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}

int main()

{

int x,y;

cin * * **** x * * ** y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * ** * "sum1 is " * * sum1.geta() * * * * '\n';

cout **** *** "sum2 is " * ***** sum2.geta() * * * * *** '\n';

cout ** * ** "sum3 is " ** ** **** * sum3.geta() ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * * * ** * * "sum1 and sum2 are the ** *

else cout * ***** * "sum1 and sum2 are not the * *** *

if (sum1 == sum3)

cout *** ** "sum1 and sum3 are the * ** ** * *

else cout * * * "sum1 and sum3 are not the * * *****

}
answered by (-384 points)
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******* * * *

using namespace std;

class Adder{
* **** * * * ** ** * * **
** ** ***** * ** * *** * * ** ** * ***
* ****** ** *** * *** ******* * ** * * *
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* * * * * * * * ***** * * ** * * * * * ** * c;

};
* * **
****** ** *** ****** *** a;

}









int main()

{

int x,y;

cin * * x *** * * y;

Adder sum1;

Adder sum2(x); // sum2 is **** to x

Adder sum3(y); // sum1 is initialized to y

cout * * * * **** is " **** ** * sum1.geta() * * *** * '\n'; // prints **** ** is 0"

cout * ***** * * * is " ***** * * sum2.geta() * * * '\n'; // prints *** ** is x"

cout ***** * * ** * * * is " * * ** ** sum3.geta() * * * *** '\n'; // prints ** * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** ** *** * and sum2 are the * * **

else cout ** * * * * * * * and sum2 are not the * **

if (sum1 == sum3)

cout ***** **** * ** *** and sum3 are the ** * *

else cout * * * ** * * ** and sum3 are not the ** * **

}
answered by (-384 points)
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Hidden content!
** * * * * ******* *

using namespace std;

class Adder{
** * * * ** * * *****
* * * * * ** * ** **** * ** * *** geta();
****** ** * * * ** ** * ** * *** * * * *** * ** seta(int n1){
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*** ***** * ** * *** * * ***** ** * * * * * * ** * ** x){
* * * **** * * ** ** * * * * ***** ** ** * c;
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* * * **** ******* ***** * * *** ** ** ** c;
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**** * ** **** *** * **** * * * * * * **** * * **** * * * ** c;
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* ** * *** * **** * * ** ** * * ** * * * ** * ** * * ** * * ** * * ** 1;

******* * ***** * ** ** ** * * ***** * ******* * *** ** * *** ***** * ***
* ** * ** ** * **** * * ** * * **** ****** * *** *** * * ** * * ** ** ** * * * ** 0;
*** * * ** * * ***** * * * * **
** ****** ** **** ** * *
* * * *** * * * ** ** * * ** ** * * * *** a;

};
**** ** **
** ** **** ******* a;

}









int main()

{

int x,y;

cin * ** * * x * * * y;

Adder * *
*** * *

* * * * // sum2 is *** * to x
**** * // sum1 is ** ** to y

cout * * * * ** ** ** is " * *** * * * *** * ** '\n'; // prints ** * ** is * **

cout *** ** * * * **** is " ** * * *** ** ** ** '\n'; // prints * * ** * is ** *

cout * * ** ** **** is " * * *** *** * * **** * '\n'; // prints **** is ******

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * ** * *** * and sum2 are the * * * ** **

else cout * * ** * **** * and sum2 are not the ** * ** ***

if (sum1 == sum3)

cout ** * ** ** * * **** and sum3 are the * ******* * *

else cout ** ** *** * * **** * and sum3 are not the *** ** * *

}
answered by (-384 points)
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