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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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cout ** * * ** * *** ** * and sum3 are the ** **** * * *

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}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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answered by (-367 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
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using * * std;



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{

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cout * * * ** * * * and sum3 are the *****

else cout *** ** ** *** * * * ** and sum3 are not the ** * * ****


** ********* * * *** * 0;

}
answered by (-364 points)
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Hidden content!
* *

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}
answered by (-367 points)
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Hidden content!
** * * ** *

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class Adder{
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{

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Adder sum2(x);

Adder sum3(y);

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if (sum1 == sum3)

cout * * "sum1 and sum3 are the * * ** **

else cout *** * * "sum1 and sum3 are not the * * *

}
answered by (-384 points)
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Hidden content!
** ******* * *** ***

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class Adder{
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}









int main()

{

int x,y;

cin *** ***** x * ** * y;

Adder sum1;

Adder sum2(x); // sum2 is *** to x

Adder sum3(y); // sum1 is initialized to y

cout **** ** ** * ** * is " **** ** sum1.geta() * *** '\n'; // prints ** * * is 0"

cout * * * ** *** * is " *** * * * * sum2.geta() *** *** '\n'; // prints * **** ** is x"

cout ** ** *** *** ** is " * **** ** sum3.geta() ** * * ** * '\n'; // prints * *** * *** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * **** * ** ** and sum2 are the * *** * *

else cout ***** * * * ** ** and sum2 are not the * ****

if (sum1 == sum3)

cout * * ** * * * * and sum3 are the * **

else cout * * * * * * ** * * and sum3 are not the ** ** * *

}
answered by (-384 points)
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Hidden content!
**** * * ** ***

using namespace std;

class Adder{
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};
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}









int main()

{

int x,y;

cin **** * x ***** ** y;

Adder * *******
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**** * ** // sum1 is * ** * to y

cout ** * * **** * is " ** * * * * ** * '\n'; // prints * ** **** is * * *

cout *** ***** ** ** ** is " * ** **** ** ** ** * **** * '\n'; // prints ** ** * is ** *

cout ** *** * * * is " * ** **** * * * ** * * * '\n'; // prints * * * is * * * **

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout *** *** *** * * *** and sum2 are the *** ** ***

else cout *** * * ** * ** and sum2 are not the ** * **

if (sum1 == sum3)

cout ** * ** *** * and sum3 are the ******

else cout * ** * * ** ** and sum3 are not the * **

}
answered by (-384 points)
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