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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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*** * * **
* * *** ** ***
** * *** std;

class Adder

{
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int main()

{

int x,y;

cin * x * * * * y;
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sum1 += x; x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; * * 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * * * ** * and sum2 are the * * * *

else cout **** * * * ** and sum2 are not the * ***

if (sum1 == sum3)

cout *** ***** *** * and sum3 are the ** * ***

else cout *** **** * * * and sum3 are not the ** *

}
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answered by (-367 points)
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}
answered by (-134 points)
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** *

{
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}
answered by (-367 points)
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** * * *

{
* * *
** * * *** x * * * y;
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* * * * * * ** *** * * y

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answered by (-367 points)
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* ** ** * * * * *
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using ** *** std;



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{
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};



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{

int x,y;

cin * * * * x * * y;
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sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ***** ** * ** * and sum2 are the *** ** *

else cout ** ** ** *** ** and sum2 are not the * ***

if (sum1 == sum3)

cout * **** * ** * * and sum3 are the ** **** **

else cout ********** * * ***** and sum3 are not the * *****


*** * * **** * ** * ** * 0;

}
answered by (-364 points)
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* * *

{
**
* * * * x y;
* * **** // *** is * * * * ** to 0

*** * * // * * ** * x
*** ** * * * * * * y

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* * *
** ** ****** *** * ** * * ** *** ***
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}
answered by (-367 points)
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**** ** * **

using namespace std;

class Adder{
** * ** * **** * * ** *
* ** ** ** * **** ** * * * * * * * * ** *
* **** **** ** *** * * **** * * *** ** ** * * *
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};

Adder::geta(){
* * * *** * * ********* * a;

}

int main()

{

int x,y;

cin ******** x * ** * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout ** "sum1 is " ** * * * ** sum1.geta() * ** * '\n';

cout * ** "sum2 is " *** * sum2.geta() ** '\n';

cout ** * * "sum3 is " * ** * * sum3.geta() *** ** * '\n';

sum1 += x;

sum2 += -3;

sum3 += 2;

if (sum1 == sum2)

cout * ** "sum1 and sum2 are the * * ***

else cout ** * "sum1 and sum2 are not the ** ** *** *

if (sum1 == sum3)

cout ** ** ** "sum1 and sum3 are the *** *****

else cout * ** * * ** "sum1 and sum3 are not the * * ****

}
answered by (-384 points)
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** * ** ** * * *

using namespace std;

class Adder{
** * ** ** * ***
** ** * *** * *** * * ** **** ** *
***** * * *** * ** ** * *** ** * ** ** ** * * *
** * ** * *** * * * ** ** ** *** * * * * ******** ** ****** *
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* * ** * * ***** ** * * ** * * *** * c;
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* *** ** * * *** * * ** ** * *** * * * * * * * ***** * * *** * * * * * * * ** * * **** * * * ** 0;
**** ** * ******* **** ** * ** ****** * **
* ** * *** * ** * ** *****
** ** * ** ** ****** * * *** ** ** * a;
* * *** * ** ******** * ** * ** *** * c;

};
*** ***
* ** ** * * ****** a;

}









int main()

{

int x,y;

cin * ** * x ** ***** * y;

Adder sum1;

Adder sum2(x); // sum2 is *** ** to x

Adder sum3(y); // sum1 is initialized to y

cout * * ** * ******* is " *** ** * sum1.geta() *** * *** '\n'; // prints * * * is 0"

cout * * * * ** * *** is " * * ** * sum2.geta() * ** * '\n'; // prints ***** * is x"

cout * **** ******** is " * *** *** sum3.geta() ** **** '\n'; // prints * ** * * is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** ** ** ** and sum2 are the ** * * ** **** *

else cout * * * * *** ** * and sum2 are not the ** * ** *

if (sum1 == sum3)

cout ****** * * ** ** and sum3 are the ** * ** **

else cout * **** * *** and sum3 are not the * ****

}
answered by (-384 points)
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Hidden content!
* ** * * ** * ****

using namespace std;

class Adder{
* * ****** **** *
*** *** ***** * * * ** *** ** *** **** * **** geta();
* ***** ** ******* *** * ******* *** * ** seta(int n1){
*** * * *** * *** **** * *** * ****** ** * * * * * *
** * **** * * * * * * ** *** * **** * *
** ** * * ***** * * * * *** ** *** **** * * * * *** * * * * * * *** x){
** ** ** ** * ******* * * ** ** ** *** ** ******* **** *** c;
* * * * * * * * ** ** *** * *** *** * **** * * ** * ** *
* ** **** * ** * * * * *** * *** ****** ** *** * * c;
** ** * * ** ***** ** * ** * *** ** *
* *** **** * * * * * ****** * * * **** * ** * * * * * b){
**** * ***** * * ***** *** * *** * * * *** * * **** * **** ** c;
** * ***** *** ** ** * * * * ** * *** * * * ** ** **** *** * ** *** * ******* ***
** ** ** * *** * *** *** * *** * * * * * ** * * ** ** ** *** * ** * * ** ** * * *** **** 1;

** * * * ** * * * **** ** * ******* * * * *** ** ** * **** *
** * * **** *** * * **** * ** * * ****** ** ** ** * * *** * ***** * * *** ** * **** * **** ** * 0;
*** **** ** * ** * * * ** *** * ** **
*** ** * * * * *
* * * * ** ** *** * * * * *** ** * ** *** *** a;

};
** * * *
** *** * *** ****** **** * a;

}









int main()

{

int x,y;

cin * ** * * x * * **** * y;

Adder * * * ***
** *

* *** * // sum2 is * *** ** to x
* * ** // sum1 is * to y

cout ** * ** * **** * is " ** * * * * ** '\n'; // prints * * * is ** **

cout * ** * *** * ** * is " **** * * ** *** * ** * '\n'; // prints ** ** is *

cout **** * * * *** ** is " * ****** * **** *** * **** '\n'; // prints * * * ** is *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout ** * * ** * ** and sum2 are the * ** * *

else cout * *** * ** * and sum2 are not the *** *

if (sum1 == sum3)

cout * * *** ***** and sum3 are the *** ****

else cout ** * ** * * *** * and sum3 are not the ** **** *

}
answered by (-384 points)
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