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Write a class called Adder that stores the sum of all the ints given to it. Your Adder class should allow you to write the following main function (and code like it):

int main()
{
int x,y;
cin >> x >> y;
Adder sum1; // sum1 is initialized to 0 
Adder sum2(x); // sum2 is initialized to x
Adder sum3(y); // sum1 is initialized to y 
cout << "sum1 is " << sum1 << '\n'; // prints "sum1 is 0" 
cout << "sum2 is " << sum2 << '\n'; // prints "sum2 is x"
cout << "sum3 is " << sum3 << '\n'; // prints "sum3 is y" 
sum1 += x; //adds x to sum1; now sum1 is x 
sum2 += -3; // adds -3 to sum2; now sum2 is x-3
sum3 += 2; //adds 2 to sum3; now sum3 is y+2 
if (sum1 == sum2)
cout << "sum1 and sum2 are the same\n";
else cout << "sum1 and sum2 are not the same\n";
if (sum1 == sum3)
cout << "sum1 and sum3 are the same\n";
else cout << "sum1 and sum3 are not the same\n";
}

You should write the functions that are necessary for Adder to be used as in the above program. Combine them all together in your answer to make a perfect program. Use const wherever appropriate, and do not write or use a cast operator. Make sure to include any necessary header files.

Example input:

3 5

Example output:

sum1 is 0
sum2 is 3
sum3 is 5
sum1 and sum2 are not the same
sum1 and sum3 are not the same

 

[Exercise] Coding (C) - asked in C++
ID: 24588 - Available when: Unlimited - Due to: Unlimited

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{

int x,y;

cin **** * x * * * * y;
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sum2 += -3; // adds -3 to sum2; now sum2 is x-3

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if (sum1 == sum2)

cout ** * ** ** ** and sum2 are the * ** *

else cout ****** *** * * * and sum2 are not the ** * ** *

if (sum1 == sum3)

cout * * * ** * ** and sum3 are the * * * * **

else cout ***** * ** * * and sum3 are not the * **

}
answered by (-367 points)
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answered by (-367 points)
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Hidden content!
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answered by (-134 points)
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Hidden content!
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answered by (-367 points)
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Hidden content!
* * **

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answered by (-367 points)
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Hidden content!
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using * * * std;



class Adder

{
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{

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cout ** **** * * ** ****** and sum3 are the * * ** * * *

else cout ** *** and sum3 are not the * **


* * *** * * * ** ***** *** **** 0;

}
answered by (-364 points)
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* * **

{
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}
answered by (-367 points)
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Hidden content!
**** ** * * **

using namespace std;

class Adder{
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}

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{

int x,y;

cin * ** * x * * y;

Adder sum1;

Adder sum2(x);

Adder sum3(y);

cout * * * * "sum1 is " * * * sum1.geta() * ** '\n';

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sum2 += -3;

sum3 += 2;

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if (sum1 == sum3)

cout * ** * "sum1 and sum3 are the * ** *

else cout ** * ** *** "sum1 and sum3 are not the * * **

}
answered by (-384 points)
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Hidden content!
* * * ** **

using namespace std;

class Adder{
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}









int main()

{

int x,y;

cin * x * * * * * y;

Adder sum1;

Adder sum2(x); // sum2 is * *** * to x

Adder sum3(y); // sum1 is initialized to y

cout * * ** * is " **** * * sum1.geta() ** '\n'; // prints ** * is 0"

cout ** ** ** * * ** * is " * * ** * sum2.geta() * ** ** '\n'; // prints * * ** is x"

cout *** * * * ****** is " *** sum3.geta() * ** * '\n'; // prints *** ** is y"

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * * * ** * ** ** * and sum2 are the *** * **

else cout * * * **** ** * and sum2 are not the ** * **

if (sum1 == sum3)

cout * **** * **** and sum3 are the * * *

else cout *** ** * ** * * and sum3 are not the * ** **

}
answered by (-384 points)
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Hidden content!
*** ****** * ** *

using namespace std;

class Adder{
******* * ** ** **** ****
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};
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**** *** ** ** * ** *** a;

}









int main()

{

int x,y;

cin * * *** x *** * **** y;

Adder * ***** **
* *

*** ** // sum2 is **** * to x
* * *** // sum1 is * * ** to y

cout * * * * ** ** * is " * * **** * ** '\n'; // prints * **** is ** *

cout * ** * ** * ** is " * * * ** * ** * ** ** '\n'; // prints * ** is ** * ***

cout ***** * * *** ** is " ***** * * ** * * * '\n'; // prints * ** ** is *** *

sum1 += x; //adds x to sum1; now sum1 is x

sum2 += -3; // adds -3 to sum2; now sum2 is x-3

sum3 += 2; //adds 2 to sum3; now sum3 is y+2

if (sum1 == sum2)

cout * *** * ** * * *** **** and sum2 are the * * **

else cout **** * * * *** and sum2 are not the ** *** *

if (sum1 == sum3)

cout * **** ** * ** ** *** and sum3 are the *** * ***

else cout **** * * * * ** and sum3 are not the * * * *

}
answered by (-384 points)
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