0 like 0 dislike
9.2k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 9.2k views

46 Answers

0 like 0 dislike
Hidden content!
#include * *** * * *

int main(){
** * * * number[5]; // Do not change
* * ** size = 5, * * ** // Do not change

**** * * *** ** ** * // Do not change
* * **** * * * ** * ***** ***** * *** * // Do not change
* * * // Do not change

**** **** * *** * * * {
* ** * ****** * *
* * * * * * * * * * ************* * {
** * ** * ** ** ** * *** ** * **
* ** *** ** ** * **** * ** **
* * * * ** * * ***** **** **** ** * **
*** * *
* *** *
* *****
**** *** ** * ** * * * {
** **** ** **** ** **** *** * **** ** ** * *
* * **

* * * 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * * * ** *** *** ***** number[5];
*** * *** * * ** size = 5, temporary;
    
* *** * * ** * * * ** *** * i=0;i<size;i++){
******* * ** ** ** * *** * ** ** * * **** ** * **** *** ******** *
**** * * ** * * * ****

** ***** *** ** * * j = 0; j < size; j++){
** ** * ***** * * ***** *** * *** * i = 0; i < size-1; i++){
* *** **** *** * ** * * * ** ** * *** ** * *** **** ***** ** * * * * * ** > number[i+1]){
* * ***** *** * *** * * ** ** ** * * * * * **** * ** * ***** ** * ** * * * **** * * temporary; ** * * * * *** ** * * ** *
* ** *** **** * *** **** * * ** *** * * * * * * * **** *** * * * ** * ***** * * *** * * = number[i];
* *** ***** * *** **** *** * * *** ** * * ** * * ** ** * ** *** * * * * * * ** * * **** * * = number[i+1];
* ******** * * ***** ** ** * * ** * * * ** ** * * * * * * *** * * * * ***** * *** *** * * **** *** * = temporary;
*** * ** ****** * ** *** ***** ** *** ** ****** * * * * ** ** * ******* * **
*** ** * ** * ***** * *** * **** ** ** *** ***
** ** * * *** **
* * **** * **** ** * ** i = 0; i < size; i++){
**** * ***** ***** * * * * * **** * ** *** ** **** ** ** * ** ", number[i]); * ** * ** * * ** * * **** *
*** *** * * * *** * ** * ** *
    
* * * * ***** ** * * ** ** **** 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ****** * ***

int main(){
** *   int number[5]; // Do not change
*******   int size = 5, temporary; // Do not change
* **  
    for(int ***** ** ** // Do not change
** * * *** * * ** * * ** *** ** ** ** *** **** // Do not change
* * * * ** ** } // Do not change

** *   // Your conditions start from here
*** * * ** * ** * * *** * j = 0; j < size; j++){
* * **** ** *** * **** ** * *** ** * i = 0; i < size-1; i++){
*** *** *** * * ** *** **** * ***** ** ** * * ** ** **** * ** ** > * * **
*** ***** * ** * *** * * ** * ** ** * * * * * * * * ** ** ** ** * * temporary; * * * *** ** *** ***** *** ***** *
** * ****** *** * * * * **** ******* *** ******* * **** ** ** *** * * **** * * *** * * * * * = * *
* * ** *** *** *** ** ** ** ** * **** * * * ** * ** ** ** * ***** ** ****** ** * *** **** = ***
**** * * *** * * * **** ***** ****** * * * * **** *** **** *** ** ** ** * **** ** * * * * = temporary;
* * * ** * *** *** * * **** * * * * * ****** **** * **** *
**** ***** * * *** * * ** ** ** *** * * **
* * * ******** *
**** *** **** * **** i = 0; i < size; i++){
*** ** * *** ** **** ** * * ** **** ** * * *** ** * * * * * *** ** ** * ****** * * **** ** ****
***** ** * ** * * ** *****
****  
* ** * * * * * * 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * ** * ***

int main(){
*** *   int number[5];
    int size = 5, temporary;
   
    for(int ** * *
        *** * ** ** *** * * ***
** **   }
* ****** ** ** ** * j = 0; j < size; j++){
** * ******** * ** * ** ** *** ******* * * * from left to right */
* ** *** ** ** * ** **** *** * * * * **** * *** * i = 0; i < size-1; i++){
* * ** * * * ** ** **** ***** ** ****** *** ** * ** * * **** * ** ** * i-th element with its neighbor to check if they are in order */
* * **** ** * **** * * * ** * * ** * * ** ** ** ***** ** * * > ** * *
**** * * * * * **** * * * *** * ***** * *** ** * * ** * **** ****** ** *** exchange the values of x[i] and x[i+1] */
* * * *** * * ** * * * **** ***** * **** * * *** ** * * * * ***** **** * * * ******* * * * * * ** temporary; ** * ** *** *** *** ** * *** *
** * * ** * * * * *** ** * * * * ** * * *** * * * * * * * ** ** * * = *
* * ** * * *** * * * ** ** * ** ** * *** **** ** ** * * *** * *** ** ** = **
* * * ** * ** * ***** ****** ** ** **** *** * * * * ** * ** *** ** * *** ** **** *** ** * ** * * * = temporary;
* ** * ** *** ** * * *** * *** * * * ** *** ** * ** *** *
*** **** ** * * ** * *** * ** * * *
* * *** * * *** ** *
* *** * *** ** * ***
* * **** * * **** ** * print the array */
* * ****** ** *** *** ***** * i = 0; i < size; i++){
**** * * * * * * ** ** * ******* ** * * *** **** ** * * * ** * * ***** * * * **** *** * * *
* * * *** ** *** *
*** ***  
* * ** * * ** 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** ** ** ** **** x[] = {77,22,88,11,22};
* * * ** * * ** * * * ** size = 5;
    
* *** * *** ** ** ** ** print the array */
** ** * **** * *** * * **** i = 0; i < size; i++){
** * ** * * ** * *** ** * ******* **** ** * * *** * ", x[i]); * * * * * ********* ****** * **** *
* ***** * ** *** * **
* ***** ** ** * * ** * ** ** *
* * * ** * ****** * * * **
* **** * ** * ** I need this to happen size-times */
* * * * ** ** ** *** **** ** j = 0; j < size; j++){
* *** * * ** * ** * * ** * ** ** * **** from left to right */
* * ****** * * *** **** ***** ** *** * i = 0; i < size-1; i++){
** *** * *** * *** * ** * * *** * ** * *** *** * * * **** **** * i-th element with its neighbor to check if they are in order */
* ** * * ******* ** * *** * * ** * * * ** ** * **** * * > x[i+1]){
*** * * * * * * * * *** * ****** * * **** * ** * ** **** **** ** * ** * * * * * exchange the values of x[i] and x[i+1] */
****** * ** *** ******* * * * ** * ** ***** * *** * * *** *** ******* * * ** * * * temporary; *** ** * * * * * * ** *****
*** * ** * ** **** ******** * **** ** ** ** ***** * * ** ** ** ** * ** * ***** * *** * = x[i];
*** *** ** ** * ** * * * ** * * * * ** ** * ** ** * ******* ** *** ** * * * ** * * = x[i+1];
* ** * * * ** * ** * * *** * ***** ** **** ***** * * ** * *** ** * ** ** * * * * * = temporary;
* * *** * **** ** **** * ** * ** *** * *** ******** * *** * * *
** ** ** *** * ** ********* ** ***** * * *** **
* **** ** ** ** * *
** * * ** ******** ***** **
* ** *** *** ** * print the array */
*** * * **** * ** * **** * ** * sorting: \n");
* ** ** **** ** ** ** *** i = 0; i < size; i++){
* ** * * ** * ** * * ** * **** ** ** * ", x[i]); * * * ** ** *** ***** * * * * * *
* ***** * * * * * * *
* *** ** ***** ** * ** ** * **** *
* * * ** **** ** ** * *
**** *** * * *
*** * *** ** * * ****** *** * * * * ***
** * ** ** * * * *** ** ***** *** ** *** * * * *  
* ** ** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * **** * ** ** x[] = {77,22,88,11,22};
** ** ** * ** * * size = 5;
    
* *** *** ** * **** * print the array */
* * **** ** * * ******* *** i = 0; i < size; i++){
* ** * ** *** *** *** ** * * ***** ***** * ", x[i]); * * *** * * ** * *** *
* *** * ******* *** * *
* *** ** *** * ** * ** ******* ** ** *
*** * ** * ** * ***
* *** * ** **** ** * I need this to happen size-times */
** * * * ** ** j = 0; j < size; j++){
** * * * ** * * *** * ** * * * * * ** * from left to right */
* * * * * * * *** * * * * * *** * *** ***** * i = 0; i < size-1; i++){
***** * * * * **** * * * * * ** * * * *** * *** ** * ** ** * * * ** * i-th element with its neighbor to check if they are in order */
*** * ** ** ** ** ** * * * ***** ** * ** * *** ** * * * * ** > x[i+1]){
* *** **** ** *** ******* * * * * ** * * ** ** ***** * * ** * * ** **** * ** * ****** * exchange the values of x[i] and x[i+1] */
* * **** ** * *** ** ** ** *** * *** ** ** ** *** * ** ** ** ** *** ** ** * ** ** * * temporary; * * * ** * *** ** * * * ** ** *
* *** * ** * * * * * ******** * * *** * ****** *** * ** * ** ** ** * * * * * * * * *** = x[i];
* ** ** ***** ** * * * ** *** *** ** * * *** * ** * * ** ** * * * * ** *** * * * = x[i+1];
***** **** * * ** * **** ** **** ** * * ** ** * *** * * ** ** *** ** ***** **** * * ** = temporary;
** ** ** * * *** * ** * ** ** * ****** * ** * ** ****
* * ** * * **** ** * * ** * * ** ** * ** ****
*** *** ** * * * * ** *
**** *** **** **** * ***
* * **** ** *** ** * * print the array */
* ***** ** ** ** ** * ** * * ** sorting: \n");
* * * **** * ** * * * * i = 0; i < size; i++){
* * *** ** **** * * **** ** *** ** * ****** *** *** * *** ", x[i]); * * * ** **** ** ** ** ** *
* *** *** * ****
* ** * ** *** ** * *** ***** ** *
* ** **** ** ***
*** * * ** ** * **** **
* ********** * *** ** ** ** ** *** * * *
* ** * ** * ** *** * ** * ** ** * ** ***  
* * ** ***** * ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** * **** * * * * * x[] = {77,22,88,11,22};
* * * * ** * * * **** ****** size = 5;
    
* * * *** **** ** * *** print the array */
****** ***** *** ** ** * i = 0; i < size; i++){
* ** * ** * **** * * **** * * * * * ** * ** * ", x[i]); ** * * ** **** ** * ******* * *
** ** * **** * * **
* *** * ** * * * * ** * * **
* ** * ** * * ** * *
* *** ** *** * * ** * * ** I need this to happen size-times */
** *** * * ** * ** * * * * j = 0; j < size; j++){
* *** * * * * * * ** * ** ** ** * *** ** from left to right */
* * * * * *** * * * *** ** ** * ***** ** * * i = 0; i < size-1; i++){
* *** * *** * * * * *** ***** * * * ***** ******** **** * * *** *** **** i-th element with its neighbor to check if they are in order */
** * ** ** ******* *** * * **** *** * ** ** * * * * * > x[i+1]){
* * * ** * * *** * *** ** ** *** ** *** *** * ****** ***** ** *** ** ** *** ** exchange the values of x[i] and x[i+1] */
** * *** * * * * * ** * * * * * * *** *** ** * ** * *** * *** ** ** * ** * *** ** **** * temporary; * * ******* **** * ** *** * *
*** ** * ** *** *** **** ** ** * * * *** * * ** ***** ** * * * ***** ** *** * ** ** ** = x[i];
***** ****** ** ** * * ** ** * * * * *** ** * * ** * * * * *** * ** * * * * = x[i+1];
** ** *** * ** ** * *** * *** *** *** * * * *** * * **** * * ** * ***** * *** * ** ** = temporary;
** ** ** ** ***** * ** *** * *** * ** *** * * *** * * ***
** *** ** * ******* ** ** ***** **** ***
* * ** *** ******** * *
* * ** ** * *
* * * ** ** ****** * * print the array */
* * * * *** * ** ** **** ** * **** sorting: \n");
* **** ***** ** *** *** * i = 0; i < size; i++){
* ** * * *** ** * * * * ****** ***** ** * * * * ", x[i]); * *** ***** ** ** ** ** * **** *
** * * * ** *** **
** * *** * ** **** **** * ** *
**** * * ** * *** *
** ** *** * ** **
*** ***** ******** *** * ** * * *
*** * ** * ** ******* * *** ** * ** * ** *  
*** * * * * * * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * ****** * x[] = {77,22,88,11,22};
**** * * * * ** **** * size = 5;
    
*** * ** * * * *** print the array */
* *** ** ** * * ****** * ** i = 0; i < size; i++){
* * * **** * ***** * *** * ** ** * ** * ** * * * ", x[i]); ** ** ** * **** * *** ** * ****
*** ** *** ** *** ** *
*** ** * ** ****** ******* * * ** *** **** *
* * ** * ** * * **
** * * ** *** *** I need this to happen size-times */
** * * ** * ** *** * ** ** * ** j = 0; j < size; j++){
*** * **** ** * * **** ** * ** * *** ** * from left to right */
** * ** * * * ** *** *** * * ** ** *** *** * i = 0; i < size-1; i++){
* ** ** * * * * * * * * * *** * * * * **** *** ** * * * * i-th element with its neighbor to check if they are in order */
* * **** * * * * * * * * ** * ** *** * * * * * ** * * * * > x[i+1]){
* ** * ***** * * * * *** * ** ******** * * * * *** * * *** *** ** * * ** * * * exchange the values of x[i] and x[i+1] */
* * ** * ** * *** * * ** * ** ** * * *** **** ***** ** * * ** ** *** * ** ** * temporary; * * * ** ** *** ** ** **** ***
* ** ** * * **** * * * ** ** ** ***** ** * *** * * *** * **** * *** * *** * * ** * ** * * = x[i];
* * ** **** ** * * *** ** ** ** *** ** * *** **** * * * ***** **** * *** *** * * = x[i+1];
* * * ** * * * * **** * *** * **** *** ******* * * *** * ** **** = temporary;
* * ** ** * * ** **** *** * * * * * * *** ** ****** * *
*** ** ** * ** ******* * ** * ** *** * ** * * * *
* *** ** * *
** ** * * * * * *
*** * *** *** ** * print the array */
* * ** ** ** * *** * ** ** ** * ** sorting: \n");
** ** ** * ** * * *** * ** i = 0; i < size; i++){
** * **** *** **** ** * * **** ** ** * * *** * * * * ** ", x[i]); * * ** * **** ***** **** ***** *
***** * *** * * * *
*** *** **** * * * ** * * * **
** * * ** ******* * * ** *
** ** * * * * ** * * *
* **** ** **** * *** * * *** ** * * **** ** *
*** * ***** *** * * * * ** * * ** ** ** *  
* *** * ** ** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
***** * * * * ** ** * x[] = {77,22,88,11,22};
* * * * ******* ** * * ** * size = 5;
    
* * * * * *** *** * print the array */
** ** **** * * * ** * i = 0; i < size; i++){
*** * * *** ***** * * * * *** ** **** * * * *** ", x[i]); ** ** * *** ***** ** * * ** *
* * * * *** * * * ***
* ***** *** *** * * *** * * ** * * * * ****
* ** ****** ** ****
* **** * **** ** * ** I need this to happen size-times */
** * * * * * ***** * j = 0; j < size; j++){
*** ** ** * **** * * ** ** ** * * ** ** ** * from left to right */
* *** ** * * ** *** *** * ******* ** ** ** ** i = 0; i < size-1; i++){
* * *** * ** * * *** * * *** * * ** *** * * * * ** ** *** * i-th element with its neighbor to check if they are in order */
* ** ** *** * * ** * ** **** *** ** **** * * ***** * ** ** > x[i+1]){
* ***** ** * ** ******** **** ** * * * **** ** ** * ***** * * **** ** * * * *** * exchange the values of x[i] and x[i+1] */
** * **** * ** *** ** * ** ** * * * * *** * ******** * **** * * * *** ** * ***** ** * ** temporary; ***** * *** * **** ****** * ** * **
* *** * ** * * ** * * * ** *** * *** *** * ** * *** *** *** * * **** *** ** ** ** ** * * = x[i];
* * ** * ** * ***** * **** * * ** ** * * ** * ***** * ** * *** * * * ** * *** = x[i+1];
* ***** * ** ** ****** * * ** ** * *********** * **** * * **** * ** *** = temporary;
** ** ** * *** * * * *** * ******* * ** ** ***** * **
** * * *** * ** ** ****** ** * ** ** ** ** ** *
* * * * *****
***** ** * ** **** ***** **
****** *** *** * **** *** * * print the array */
** *** ** * * * * * * *** * ** * sorting: \n");
** * **** **** i = 0; i < size; i++){
**** ** ** * ** ** * * * * * ***** ** ** ** *** *** ", x[i]); * ***** *** ******* * ***** * * *
* * * ** ** ** * * *
* * * ******* **** ** * ** ******* *** *
* * * * * * * *****
* * ** * * * ******* ****
* * ** *** * *** * * * *** ** ***** * ***
*** * * * * **** * * ** * ** *** ** * ** * * * *  
* ****** *** * * ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** * * * *** * ***** * x[] = {77,22,88,11,22};
******* * * * * * size = 5;
    
**** ****** *** * print the array */
* * ** ** * **** *** i = 0; i < size; i++){
* * * ***** * * ***** * ** ** *** * *** *** ", x[i]); * * * * * * * **** *** ***
* ** *** * * **** * *
*** * ******* ** *** ***** ** *** * * * **
** ** ** *** **** * ***
* ** ** * * **** ** * **** I need this to happen size-times */
*** *** * * * * ** ** j = 0; j < size; j++){
* * ******* ** ** *** ***** *** ****** *** from left to right */
* * ** * * ** ** ******* * ** ** * ** * * i = 0; i < size-1; i++){
* * ** ** * * * **** *** ** * * ** * ** * **** ******* ***** * *** i-th element with its neighbor to check if they are in order */
** * ** ** * ** * * **** ** ** * * ** **** * * * * * ** *** ******* ** * > x[i+1]){
*** ****** * * * ** *** * * *** **** ** * * ** *** * * * * *** * ** * * * * * ** exchange the values of x[i] and x[i+1] */
**** *** * **** ** ***** ** *** ** * * *** * ** ****** *** ** * * *** ***** * ** * temporary; **** * *** ** * * *** **** ** *** * *
*** * * * ** * ** * ** *** * * *** * ** * *** ** ** * ** * ** *** * ******* * ** *** ** * = x[i];
* ******* *** *** ** ** * *** * ** * ** * * * * ***** ** *** * * * * * ** * ** ** * * * * * = x[i+1];
**** * ** * * * *** ****** * * *** ** * ** ** * **** * *** *** **** *** **** = temporary;
** ** * **** * * ** * * * ** * * * *** ** *** *****
** ** * * * ** **** ** **** * *
* * ** * * * **
* * * * * *** *
* ** * * * * * * ** ** print the array */
** ** * * ********* ** * * sorting: \n");
* *** * * ** *** ** * i = 0; i < size; i++){
*** * ** * ** *** ** * ** ** * ****** * ", x[i]); ** * *** * * **** * ** * * ** *******
* * ** ** ** **
** * *** *** * ******** ** ** * * *
*** ** **** * *****
* ** ********* ** * *
* * ** * * * ** ** ** * *** * *
* * * *** ***** * * * * *** ** ****** * * *** * ** *  
** * ** ** *** * * **** * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.50.27
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 6k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.8k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.5k views
12,783 questions
183,442 answers
172,219 comments
4,824 users