0 like 0 dislike
8.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include * ** ** *** ** *

int main(){
** * ** number[5]; // Do not change
* **** * size = 5, ** * // Do not change

* * **** * * *** *** * // Do not change
***** **** * ** ** * *** * **** * * *** * // Do not change
* **** // Do not change

** * ****** * * * * {
* * *** ** * * *
* *** ** * *** *** ** {
* * * * ** ***** * * * * ** * ** *
* * * ** ****** * * * ** *** **** *****
***** *** **** *** ** **** *** ***
*** * * **
**
** * **
** * ** * * * * {
** * * ********** ** * * **** ** * ** * ***** ******
**

*** *** 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * * ** * ** * * number[5];
*** ** *** *** ** size = 5, temporary;
    
******* ** * ** i=0;i<size;i++){
* * * * * * **** * * * ** * ** * **** * * * * ** * ***** * ** ***** * * ***
* * ****** *** * **** *** *

* * ** * * * * * ** **** * * j = 0; j < size; j++){
*** ** * * * * ** * *** **** *** **** i = 0; i < size-1; i++){
*** * * * *** * * * *** * ** * *** ******* ** * ** * *** ** *** > number[i+1]){
*** * ** ** * * * **** * ** * ** * * * * * *** ** * * * * * ** ** * * * * ** temporary; ** ** * ** *** * *** * * *** *
* ** ** ** *** * * * ** **** * **** * * * * * *** * * * * **** * ** * * * * * ** * * * * = number[i];
** * * * * * ***** ** *** ******* ** * * *** **** * * * ** * * * ** * * * * ** *** = number[i+1];
*** * ** * *** * * * * * * * ** * ***** * ** *** ****** *** * ****** * ** * * * *** * ** * ** ** = temporary;
** *** * * ** * *** * * ** * ** * * * * * **** * * ****
***** **** * **** * * * * *** *** * **
*** ***** **** ** **** *
* * ** * ** * * * i = 0; i < size; i++){
* ** * * ** * * ** ** * ** ** * ** * * ** **** ** ", number[i]); * ** **** * **** **** * ** *
* ** * **** * * ***
    
* * * * * * * ***** * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** ** *** ** *

int main(){
**   int number[5]; // Do not change
* *   int size = 5, temporary; // Do not change
* *  
    for(int ** ** * * ** * // Do not change
* *** ***** ** * * ** * **** ** * * ** * * ** **** // Do not change
** ** ** * } // Do not change

* ****   // Your conditions start from here
* * *** * ** * **** * * ** * * j = 0; j < size; j++){
*** *** * * *** * * * * ** **** * * * ** * i = 0; i < size-1; i++){
* * * **** ** **** ** * ***** * ** ** ** * ** * * * ** *** > * * * *
** * * * ** *** ** ** * * * ***** * ** *** ** *** **** * * ** ** * * **** * temporary; ****** * * * * * * ** ****** ***
* **** ** * * ** * **** ** * ** ***** * * * * * * * ****** * * *** * ** **** ** * * ** * = * ****
* * ***** ** * ******* * * *** ** ** **** * **** * **** * ***** **** * **** * * * ** * * = * * ***
* ** * ** ****** * * **** * * * * ** *** * ** ** *** ** ** **** * * * * * * * *** = temporary;
** * ** ** *** ***** * * ** * *** * ** ** * ** * * * **
** ** ** ******* ** * **** * * * * **
** *** * * ** * *
** ** ** ** * * * *** i = 0; i < size; i++){
** ** *** * *** **** * ** * ** *** ** * ** * * * ** * ** ***** * * *** **** ** * * *
* * ***** * ** * ****
* * * *  
* * ** ** * * * * 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include *** ***

int main(){
** ****   int number[5];
    int size = 5, temporary;
   
    for(int ** * * * * *
        * *** * * *** * * * **
* *   }
* ** * * ** ** *** * ** j = 0; j < size; j++){
** ** * * * ***** ***** * * ** * * *** ********* * * ** from left to right */
* * * *** ***** ** ** * * *** * * i = 0; i < size-1; i++){
*** ** * ** *** ** * **** * * ** ** ******* *** * ********* ** ** *** *** i-th element with its neighbor to check if they are in order */
* ** ** * ** * *** * ******* ** ** ***** * * * * *** * ** * ** ** * > *** *
* ** *** * * * * ***** ******* *** **** *** * *** **** ** * * * * ** **** * * * ****** exchange the values of x[i] and x[i+1] */
* *** * ** ***** **** ** ** * ** * * *** * * * * *** ** **** * **** *** * * ** ** temporary; ** ** * * ******* * **
*** ** ***** * *** * ** * * ****** * *** ** * *** ** * * * *** * ** * ** * * * * *** = * **
*** * * *** * ** *** * *** * ** * * * ** * **** * ** * * ** ** * * * * * * * * = *
* * * **** ** *** ***** ** * *** * * * * * * * * ** * ** ** * * * *** * * ** *** * * = temporary;
** * * ** ** * * * ***** * ** *** *** ** ** * *** * * * ** **
** * * * * ***** **** *** * ** * * * *** **
* ** ***** ** ** * *
* **** * **** * ** *
* * * * * *** print the array */
**** *** *** * ******* * i = 0; i < size; i++){
* ** * * * ** ** * ** **** ** *** ** * * * * * ** *** * *** * ** * ** * * * * * **** * ** * *
* * * ***** *** *
* *  
** * *** * * * ****** ****** ** 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** *** *** * **** * * x[] = {77,22,88,11,22};
** ** * * ** ** *** ** size = 5;
    
*** ****** * ** * * * * print the array */
* * * ***** * * * ** ** * i = 0; i < size; i++){
******* * * *** * ** * *** ******** *** * * ** ** ** *** * ", x[i]); * * * * * * *** * * * *
* ***** * *** *****
** ** ** * * * ** * * * ****** ** * ****
***** * *** * * *** *
* * * *** *** ** * * I need this to happen size-times */
* **** *** * * * * *** * ** j = 0; j < size; j++){
* ** * * *** * * ****** * ** * * * * * ** ** ** from left to right */
*** *** * * ****** * * *** ** * * *** * ** i = 0; i < size-1; i++){
* *** *** * ******* ** * **** * * * ** ** * * * ****** ** * ** * * * * i-th element with its neighbor to check if they are in order */
* ******** *** * * * * * ** * * **** * * * ** ** ** * ** *** ** ** ** * * > x[i+1]){
**** * * * * * * * * *** ** ** ** * ** * ** ******** ** * ** ** * ** * ** exchange the values of x[i] and x[i+1] */
* ** * ** ** * * ***** * ** ** * * * ** * * ***** * ** ** **** * * * ** * * * temporary; * * ** ** * *** * * ******
* **** ** * * ** * ** **** * * ** * ** * ** * * ** * * * ** *** **** * **** * = x[i];
* ***** * * * * ** *** ** ** ***** * * * *** ** ** *** * * ******** * * *** ******* * * = x[i+1];
* * * * * *** * * * * * **** ** ** ****** * * * *** * ** *** ** ** * * ** *** ** = temporary;
* ** *** **** * * ** ** *** * ** * * * ** ** ** * *** * * ****
** * * * **** ** ** ** ** * ** * * * ** *** ****
* *** * ***** * * *
** *** *** *** ****
* ** **** * ***** **** print the array */
* ***** * **** *** * * * sorting: \n");
** * * * ***** * * * i = 0; i < size; i++){
* ******* * * * * * * * *** * * **** ** * * ** * ", x[i]); ****** * * * * * * * ** *
* ** ***** * * * * *
* * *** **** ***** * ** * * * * * *
* ** * * * * *
* ** ** *
* * ** *** * ** * ** **** **** ** *
** * * ** * ** *** ** * *** *** ** * * ** * * *** *  
*** * * *** * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * *** * * * x[] = {77,22,88,11,22};
*** ** * * ***** * ** size = 5;
    
* * * *** ** * ***** print the array */
*** *** * ** * **** ** * i = 0; i < size; i++){
* * *** **** * ** * ** ** *** *** * * ** ** ** * ", x[i]); * *** ** ** ***** * * * * * ** *
***** * ** ** * ** * *
* * ** * * ** ** *** **** ** * * * *
* *** ****** *
** * * **** ** * I need this to happen size-times */
**** * * ** ****** **** * ** j = 0; j < size; j++){
* ** *** ** ** ** * * * ** * ** ** ** * from left to right */
* * *** *** ** ** * ** * ** * *** ** ** i = 0; i < size-1; i++){
* *** **** * * * ** *** * *** * **** *** i-th element with its neighbor to check if they are in order */
* * *** **** *** ** * * ** * * ** *** ***** **** * * ** * *** * ** ***** > x[i+1]){
*** ** *** **** **** ** *** ** ** *** ** * ***** * * ***** * ** ** ** * *** ***** ** * exchange the values of x[i] and x[i+1] */
** * * ** * ** * ** *** * * *** * * * **** * *** ** **** * * * ** ******* ** temporary; * **** * ***** ** ** ** ** *** *
**** * * ** ** *** * * * * * *** * ** ** ***** ** * * * * **** * *** = x[i];
**** ** * *** ** ** ** * * * ** ** * * ****** ** * * ** ** * * ** * ** * ** * = x[i+1];
****** * *** * * * ** * * * * * ** * * *** **** *** * ** ** * * * ** ** * **** ** ***** = temporary;
* **** ** * * * ** ** * ** ***** * * * *** * * ** * ** ****
*** *** *** * * ** ** * *** * *
* *** * ****** *** * **
*** * ** * ** * * *** **
* *** * * * * ** * * print the array */
** * * * *** * ****** *** * **** sorting: \n");
* **** * * ** * * * * i = 0; i < size; i++){
* ** *** ** * ** *** * ** * ***** * ** * ****** *** ", x[i]); *** * **** * *** * * ** **** *
** *** * * * *
*** **** * ** * * * *** *
* * * ** * * ** ** *
* *** * ** ** ** **
* * ***** * * * * ** * * ** * *
* * *** * ** ** * **** *** ** * *** *** **  
* * * * * * * *** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * ***** **** x[] = {77,22,88,11,22};
* * * ** ** * * * ** size = 5;
    
******* ** * ** *** * print the array */
** * **** * * ** * * *** * * i = 0; i < size; i++){
* *** * * ***** ***** * * * ** * * * * ****** * * *** ", x[i]); ** * * * ** *** *** *****
*** * * * * ** ****
* * ** * * *** * *** ** *** * ** * *
* * **** * * ** * * *
* * * ****** * * * ** I need this to happen size-times */
* * * * * * * ** *** * j = 0; j < size; j++){
* * * * * * * * ****** * * * * * * * * from left to right */
* ** * ** * ** * ** * ** *** ** ***** * *** * * i = 0; i < size-1; i++){
* ** ******* ** *** * * * * * ** ***** ** * *** * *** ** ***** i-th element with its neighbor to check if they are in order */
* ** * *** ** *** * * * ** ***** * * *** ** ** ***** * > x[i+1]){
** * *** ***** *** * * * *** * ***** ** **** ** **** * * ** *** ** * * ***** *** ** exchange the values of x[i] and x[i+1] */
* * * * * * *** * ****** ** * *** ** *** * * * ** ***** * ** ** * ** * temporary; * ** * * **** ** * * ** * *
*** * ** * *** * *** * *** ** * *** ** * *** * * * * * * ** ** *** ** * **** ** * * = x[i];
* ** ** * ** *** * * ** * * *** * * ***** * * ** * * * * * * ** * * * ** ** *** * **** * * = x[i+1];
**** ****** ** * * * *** ** * * * * * ****** * * *** **** ** **** ** ** * * **** ***** ** = temporary;
******* *** **** *** * *** * ***** ****** *** * * * * ***
** * * ** * *** ***** * **** ******* * *** *** **
* * ** * ** * * ***
* *** * **** * ** *
* * * * * * * * print the array */
** * * ** ** * * * *** * ** * * **** sorting: \n");
* * ** * ** * ** ** * i = 0; i < size; i++){
*** * *** *** * * ** * * ** * * ** * ** * * ** ", x[i]); ** ** ** * * ** ***** * * * *
******* * ****** ** ***
* ******* ** * * * * * **** *
* *** * ***** * *
** * * * *****
** ***** ** * ** * ** * *** * ** * * * *
** * ***** ** ** *** **** ** * * ** *  
* * * * * *** ***** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * *** * * * x[] = {77,22,88,11,22};
* * ** ** **** * * * size = 5;
    
* * **** * ** ** *** print the array */
** ** * *** * * ** * ** i = 0; i < size; i++){
*** *** * ** * * ****** ** **** ** * ** * ** ** * * * * ", x[i]); *** ** ********* * ****** * * **** * *
* *** * ***** ** * *
** *** * * * ***** *** *** ** * **
* * ** * **** ****
** * ** *** ** *** * * I need this to happen size-times */
*** ** * * * ** ***** *** j = 0; j < size; j++){
*** ***** * ** *** *** * ** * ******* ***** * from left to right */
*** * * *** * *** ******** * ** *** * * * * ***** i = 0; i < size-1; i++){
*** **** ** * * ***** * ******* ** *** * * *** ** ** * * *** ***** ***** i-th element with its neighbor to check if they are in order */
******* *** * ** ** * * ** * * * ** *** **** * * ** * **** * ** * * * * * > x[i+1]){
*** ** ***** **** ***** **** *** * ** * *** * ** ** ** ***** ** * * *** * *** * * * ** *** exchange the values of x[i] and x[i+1] */
** * * *** * *** ** * ** ** * * ** **** * * ** ** *** ****** * ** * ****** ****** * temporary; * * ** **** *** *** * ** * *
* ** ** ** * * ** * * ** ** *** ****** * * * ** ** *** * * *** * * * * * = x[i];
**** ** ** *** *** ** * * * *** * ** * * **** * * *** **** * * * * * *** * **** ********* = x[i+1];
* *** * ** ** ** * * * ** ** * * * ** ** * ** * * *** ** ** * ** = temporary;
*** *** * ** ****** *** ** ** **** ****** ** * * ** * * * *
**** **** * ** ** ** ** * **** ** * **
* **** * * * * **
* * ******* * ** * *
* *** * * ** * print the array */
* ** * * * ***** * **** * * **** * ** sorting: \n");
* * * **** **** *** * ** i = 0; i < size; i++){
* ** *** ** ** ** *** * * * * * * * *** ** * ", x[i]); * ********** ** * * ***
** ** * *** * * * *
* * *** ** * ** ** ******** * ** *** ** *
* ***** ** *** * *
*** *** * * * * *
* *** * ** *** **** ** **** * *
*** * * ** ** ****** *** ** * *  
*** * *** *** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** **** ** * * * x[] = {77,22,88,11,22};
* ** * * * * * * ** size = 5;
    
* ***** ****** * * * print the array */
*** * * *** ** ** * i = 0; i < size; i++){
** ** * * * **** * ** **** ***** ** * * ", x[i]); ** ** ** * * * ** * *******
** * *** * * ** *
**** *** *** * *** * * ** ** * * * ** * *
** * *** * *** *
******** * ** ** * I need this to happen size-times */
* * ** * * * ** ** *** ** j = 0; j < size; j++){
* * *** * * * * *** * * * *** ** from left to right */
** ****** * ** ** * ** * ** * * * * ** ** * *** i = 0; i < size-1; i++){
* * ****** * * ** ** *** ** * **** * *** * *** * * * * * ** *** *** * * * i-th element with its neighbor to check if they are in order */
*** * ** * **** *** * **** * *** * ********** ** * * *** **** ** > x[i+1]){
**** * ***** * * * * * ***** ** * * ** * * ** ******* * ** * * * ** * ** *** * ** exchange the values of x[i] and x[i+1] */
* ** * *** * * * ** * *** * ** ** * * *** ** * ** ** ** ** * * ** temporary; * * **** **** ** ** * **
** * * * *** * ***** * * *** * * **** **** * * * ** *** *** **** * * * ** * * = x[i];
* * * * * * *** *** **** ** ** * * ** ****** * ** * ** * *** * * ** = x[i+1];
* * ** **** * * ***** * *** **** * *** **** * *** * **** ** * *** ** ** * * * **** * * *** * * = temporary;
* * * ** * *** ** * * * * * * * ** ** * * *** * * * *** *** ** * **
** ** * * * * * * *** ** **** ** *** * *****
* *** * * *** * * **
* * ** * ******* * ****
* ** ***** * * ** print the array */
**** * ** ** * ** ** ** * * * sorting: \n");
* **** ** * * * ** ** i = 0; i < size; i++){
* * *** ** ** *** *** **** *** **** * **** *** * * ", x[i]); * * ** *** * * ***** * *** *
* * * ** ****** * ** *
* * * * ** ** * * ***** *** *** * *
** ** * * ***
****** * ** ** * *
* ** *** ** *** ** * ***** ** * ***
* * * *** * ** ** * *** **** *** ** * *  
* * ** * * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * ** ***** ** x[] = {77,22,88,11,22};
* * * * * ** * * * size = 5;
    
* * ** *** ****** print the array */
* * * * ** * * ** ** * i = 0; i < size; i++){
*** ** * ****** ** *** * ** ** ** * *** * * ** ** ", x[i]); * ** * * ** *
******* * * *** * ** **
* ** * *** * ** * * * ** *
* ** *** *** ** * * **
** * * ** ** ** * * **** **** I need this to happen size-times */
* * ** ** * * * ** *** * j = 0; j < size; j++){
* ******* ** * ** ** * *** * * * * * *** ** from left to right */
** **** ** * * *** * * ***** * * * **** * i = 0; i < size-1; i++){
**** ** * * * **** ** *** * ** * ** *** ** ****** * * * * ** * i-th element with its neighbor to check if they are in order */
* ** * * * * * * ***** ** ** * *** * * * * * * * * * * ** > x[i+1]){
* * ** *** * * * * * ** * ** ** * **** * * * **** * ** ** * ******* * * **** ** * exchange the values of x[i] and x[i+1] */
* ** ** ** **** * ** * ** * * ****** ** **** * * ***** ** * ** ** * * * ** * *** temporary; ** * * ***** *** ** * ** ***
* * ** * * * ** ** ** * * ***** * *** *** * * * ** **** * ** * **** **** * *** = x[i];
** *** * * ** ******* ** * * *** ** * * ** * ** ** * * * * *** ** ** * * * ** * * = x[i+1];
* ** ****** * ** ***** * ** * ** ** ****** ** * ****** * ** ** * ***** * **** ** * = temporary;
* * * * * *** *** ** * ** *** **** ** *** *** *** * ** **
* ** * * * * * ** * * ** *** * *** ***
* *** *** * * **
** * * * * * *** ******** *
** ** * *** ** * ** * print the array */
* * * * * ***** * ** * * * ** * sorting: \n");
*** ****** ** ** ** * i = 0; i < size; i++){
*** **** * * ** *** *** * * * * * * ** * * * * ******** ", x[i]); * ** ** * ** ** * * * ** ** *** ******
** * * * *
* * * ** *** ** * * ** * *** * * * *
* ****** * ***** *
* **** *** **** ***
* ** *** * * * *** * * * ** * ** * * *
* ** ** ** * * ** * *** * ** * * * ** *** **** **  
* *** ** *** * * **** * * * ****** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.194.139
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.6k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.6k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users