0 like 0 dislike
6.9k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.9k views

46 Answers

0 like 0 dislike
Hidden content!
#include * *** *** * ****

int main(){
*** * ** number[5]; // Do not change
* ******** size = 5, ** *** // Do not change

** *** ** * *** *** * * * // Do not change
*** *** ** ** * ** ** ** **** *** * // Do not change
// Do not change

* * ** * * * * ** {
* * * ******* * * ***
*** ** ***** ** * ***** * ***** {
****** * ** * *** **** * * * * * * **
**** *** * ** ** ** * * * **** *
****** * * * ** ***** ********
* *** ** * *
* ** *
* *** *
** *** * ****** *** {
* ** * ** * * * *** * *** * **** * * *** ***
** *

* ***** ** 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * **** * **** * ** * number[5];
****** **** *** ** * *** size = 5, temporary;
    
*** * ** *** * * **** * i=0;i<size;i++){
* **** * *** * * ** * ** * * * * * * * * *** * * ***** * *
***** *** * * *** *

** ** * **** * * ** *** * * * j = 0; j < size; j++){
** *** **** * ** * * * *** * **** ** * **** *** * i = 0; i < size-1; i++){
*** ** * * * ** ** * * *** ** ** ***** * * *** * ** ** * * ** * * ** > number[i+1]){
****** * *** * * *** ** ** * *** **** ** **** * * * * ****** **** **** * ** temporary; **** ** * ** *** *** * * *** *
* **** * * * *** ***** *** * * *** ********* * * * * * * * ** **** ** *** * = number[i];
** *** **** * * * * * * * * * ** * * *** *** ** ** ** *** ** * ** ** * * **** **** ** = number[i+1];
** * ** ** * *** ** *** * * * *** * ***** * * * ** **** *** * *** *** * ** * *** ** = temporary;
******* * ** *** ******* **** ******* * **** * * **** * ** * *
**** ** * * ** ** * ** * * * ** * ** ** * * *
** *** ** * * * *
*** **** ** * ***** * * * * * ** * i = 0; i < size; i++){
* ** * **** * ** ** * * ** *** ** * ** * ** * ** ", number[i]); * ** * ** ** * * *** * * * * *
* * * * * ** ** *
    
* * * * * * ** *** * * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** * * *

int main(){
**   int number[5]; // Do not change
***   int size = 5, temporary; // Do not change
* **  
    for(int * **** // Do not change
* * * * * ** ** ** *** * ** * ** ** ** **** // Do not change
** * * * } // Do not change

* *   // Your conditions start from here
** *** ** *** ** *** ** * * ** j = 0; j < size; j++){
* * * **** * * ** * ** * ** * * * * * i = 0; i < size-1; i++){
** * *** * ** **** * * * * *** ** ** ** *** ** ** ** * > * *
** * * * ** * * **** * ** * *** ** ** **** ** **** *** **** ***** * ***** * * temporary; * * * ** ***** * ** ***** * ** *
******* * * * ***** * * *** * *** * ** ***** * *** * *** * ** ***** ** * ** * ** = ** **
* ** * * * * *** * ** * **** **** ** *** * * * * ** * * *** ** * *** * = * * **
* * * * *** ** *** **** ** **** * * ** ***** * * * * *** * * ** ** * * ** **** * ** = temporary;
* *** * **** ** ****** **** *** * * * * *** * * ** **** ***** **
* ***** ** * * * ** *** **** * * * * * ** * **
***** ** * **
*** *** *** * * * i = 0; i < size; i++){
* * * ****** ****** ****** * ** * * *** ** * **** ****** **** *** *** *** * * * * ***** **** ** ** * * * *** *
* *** * * * * *
** * **  
** * * ** *** * * * * * *** 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * ***

int main(){
* * *   int number[5];
    int size = 5, temporary;
   
    for(int * ** ****** * *
        ** * * * * * * **** * * *
** *   }
***** ****** * * * j = 0; j < size; j++){
* ** *** ** * *** * ***** * * * ** ** * * ***** from left to right */
* **** ** ** ** * *** * ** **** * *** * **** ** * i = 0; i < size-1; i++){
* ** ** * ** * * * ** *** * *** ** * * * * * ********* * *** i-th element with its neighbor to check if they are in order */
** * * ** ** * * * ** ** ****** * ** * * ** * ** * * ******* *** * * * * *** * **** *** > **** * *
**** * ***** ** **** * ***** ** ** * * * *** **** * * ** ******* * * * *** exchange the values of x[i] and x[i+1] */
* * ** * ** *** * * * * *** * * ** * * *** ** ****** * **** * *** *** * * temporary; ** ** * ***** * * **** * *
** * * **** * * *** * * * ** ** *** * *** * *** ***** ** * ** * * * ** = **
* ***** **** **** *** * * *** * ** * * *** * * ** ** ** ** *** ** * ** * **** * ** = * ***
* * ** * ** **** ** ** ** * * ** * **** * ** * * * * * * ** ***** * ** * * *** ** * = temporary;
* ** ** * ** * * * *** ** * * ** ** *** * ** ****
** ** *** * *** * * *** ****** * ***** *
** * **** *** * ** **** *
* * * ** * ** ** * *
* * * **** *** *** print the array */
* *** ** * ** * i = 0; i < size; i++){
***** * * * * * *** ** * * ** * * * *** **** ** * *** * * * * * * ** * * * *** *** * ***** ** *
*** ** * **
** ***  
** **** *** ** * * * * 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * * * *** * x[] = {77,22,88,11,22};
* ***** * * * * * *** size = 5;
    
* * * * **** * ***** print the array */
**** *** ** * * * *** * *** i = 0; i < size; i++){
* * ** **** * *** ** **** ** * ** ** * * * * * ", x[i]); * *** * ** ** *** * * * * **** ***
*** * * * ** * *****
***** * **** *** ** * ** ** * *
* * ** **** * ****
**** ** ** * * * * ** I need this to happen size-times */
* ** * * *** * * ** j = 0; j < size; j++){
** ** * * * ** ** * * ** **** * *** * from left to right */
** * ** * * ****** ***** * * ** * *** *** * **** i = 0; i < size-1; i++){
*** *** * * * ** *** ** * * * * ** ** ** ** * * *** * * * i-th element with its neighbor to check if they are in order */
* * * * *** * * ** * ******** ** * * * * * * * * * * *** * ** *** > x[i+1]){
*** ** *** ** ** * **** * **** ** * ** ** * * *** * ** * ** ** ** *** * * * ***** ** * *** exchange the values of x[i] and x[i+1] */
*** * ****** * * ********* **** * * *** ** *** * ***** ** * ** * ** *** ** ***** temporary; * ** * ** ** *** * *** * ** *** ***
** * * ***** * *** * * * *** ***** *** * * ** * * * * ** * **** ** * * * **** = x[i];
**** *** * *** ** *** *** * *** * * *** * ** *** * * * * *** **** *** ** ** * ********* = x[i+1];
* ** ******* * * * ** * **** * * *** ******* * * ***** * ** ** **** * * ** ** * * = temporary;
** ** * * ** ** **** **** * * *** *** * * * * * *** **** ******
*** ** ** ** * **** ***** *** * ** * * * * *
* * ** * * **
* *** * * * * ***
* ** *** * ** * ***** print the array */
** * * * *** ****** * *** * *** * * * * sorting: \n");
** * ** ***** * * * i = 0; i < size; i++){
**** * * ** * ** * * ** * * ****** **** ** * * ** ", x[i]); * *** * * * ** * ***
* **** * *** * ** ****
** * ** * * * *** * * * ** * ***
*** * * ** ** * * **
**** ** ** * * * **
* * *** ***** ** * ** ** * ** * *
*** ** ** * ***** * * * **** ***** *  
** ** * ********* * * * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * * * * ** * ** x[] = {77,22,88,11,22};
** * * * * ** ** ** size = 5;
    
** * ** ** **** * *** * print the array */
** *** * ** * * **** * i = 0; i < size; i++){
* ** * ** *** ** *** ** *** * * * * * * * * *** * ", x[i]); *** ********* * * * ** * * **
* * * ** * *** * *
* *** * * * * * ** ** * ** * ****
***** * *** ***
**** * ** * ** *** ** I need this to happen size-times */
***** * * * *** ** *** *** j = 0; j < size; j++){
** * ** ** * * ** ** ***** * * * *** * from left to right */
** * * * *** ** ** * * * * ** * * * **** i = 0; i < size-1; i++){
* *** * **** ***** * * * ** ***** ** * ** ** * ** *** ** * ***** i-th element with its neighbor to check if they are in order */
**** *** * ** ** * * * ** ** ***** ** * * **** * **** > x[i+1]){
*** * * *** * ** ***** * ** * * ** * ** ***** *** *** * ** ** ** * * * ** **** exchange the values of x[i] and x[i+1] */
* ** * **** * **** * * * * ** **** * * * ** **** * * * ** * * ** * * ****** **** ***** ** * temporary; ** * * ** **** ** * *
** * ** * * * * * ** * ** ** ****** ** ** * **** * *** * * * *********** * ** * ** **** * = x[i];
* * * * * *** *** ***** *** *** ****** * **** *** **** ** * * * * * *** **** * = x[i+1];
* * ** * * *** * **** * *** **** *** ** * *** ** * * ***** **** *** * ***** ** * * ** *** = temporary;
** *** * * ** * * * ******* ** * * ***** ** * *** * *** **
* ** *** ** * ** ** * ** **** **** *
**** *** * ** ** * ** ** * *
*** **** * ** * * *
* ** *** * ***** * ***** print the array */
** * * * ** ** ** *** **** * sorting: \n");
* *** ** * ** ** *** * i = 0; i < size; i++){
** ** * **** ** ** * *** * * *** ** * *** * ", x[i]); ***** *** **** ** ** ** ****** ** * **
** * ***** * * ** *
* * * *** * * ** * *** *******
* **** * **** * *
* ** ** * ** *****
** *** ** * * *** ********* * * ** *
* ** * * * * *** * ** * * ** ****** * ***  
* * ** **** * * * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ** * * **** * **** * * x[] = {77,22,88,11,22};
*** * **** ****** ** * size = 5;
    
* ***** * * print the array */
* **** **** * ** * * i = 0; i < size; i++){
***** * ** ** ** * ** * * * * * ** * * ** * * ** ", x[i]); * ** ***** ** * * **** * ****
** * * ** * * *** * * ** *** *
* ** ** * * * *** * * * ** *** * * ** *
* ** ** * * * * *** *
* **** ** * * * * * * I need this to happen size-times */
*** ** ** ** ** ** ** * ** j = 0; j < size; j++){
* *** ** ***** * ******* * * * ** ****** * from left to right */
** *** * * * ** ** **** ** * * ** * i = 0; i < size-1; i++){
*** * * ** * * * *** ** * **** ** ** * ** *** *** * * * i-th element with its neighbor to check if they are in order */
**** * * **** * ** ** * * ***** ** ** ** * * * ** ** * ***** * > x[i+1]){
** ** * * ***** * ****** ** * ** * ** * *** ** * * * ** *** * **** * * **** exchange the values of x[i] and x[i+1] */
* * * ** ** ** * * * * * * ** ****** * * * * * ** * * * *** *** * ** * * ** temporary; ** * * ** * * *** ** *** * ****
* ** *** ** **** ** * ** * ***** * * * * ** * * **** * * ** * ** * * *** * * * * ** *** = x[i];
* * *** ** * * ** * * * * *** ** **** * * ** *** **** * ** * * * *** ** = x[i+1];
**** * ** * *** * * * * ** ******* ** *** * * * ** * ** * ** ***** * ** ** * *** = temporary;
*** * * * * * * ** * **** ** * * *** * *** * *** *
****** * ** ***** ** ** * **** * * ** ** *
* * * **** * * ** ** *
*** * ** * * ** *
* ***** * * ** * ** print the array */
*** *** * * ** **** * * *** * sorting: \n");
** * * ** ** ** i = 0; i < size; i++){
** ** ** ** ** ****** * * ** * **** * * * * ** * *** * * ", x[i]); * * * * ** * * * * *
* * ** * * ***** *
* * * ** * * ** * * *** ** ** * * *** *
* * *** *** ** * *
***** * * ** ** * ****
* ********** *** ** * *** ** * * ** ****
** ** * ** * ** *** ** *** ** * * ** ** *  
* * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ****** *** * * * ** * x[] = {77,22,88,11,22};
* * **** ** * * * * * ** size = 5;
    
* ** ** ** ** * ** print the array */
* * * ** * * * * * i = 0; i < size; i++){
*** ** **** *** * * ** * *** * * * * * * ** ****** ", x[i]); * * * ** ** * * * *** ***
*** * * ** * * ***** ***
** ** ** * * ** * * **** * ** * ***** *
**** * * ** ** ** ** *
*** * * * * ******** I need this to happen size-times */
* * * ** ** *** * * j = 0; j < size; j++){
**** **** * *** *** ** ** ***** * * * * ** from left to right */
* ** * ** ** **** ** ****** * ** * * * i = 0; i < size-1; i++){
* * * * ** * * **** ** ** *** *** * * **** * * * ** ** * * * * * * ** i-th element with its neighbor to check if they are in order */
*********** *** *** * * * ** * * * * ** * **** * * * * * ** > x[i+1]){
*** * * * * ** *** ** ** * ** ** * ** ** ************ **** ** * ***** *** **** exchange the values of x[i] and x[i+1] */
* * * * **** ** ** **** * * *** ** * ****** *** * * ***** *** ** ** * * ****** * * temporary; * * * **** * * ** * * * * *
** * * * **** ** **** * * *** ** * * * ** ** * * *** *** **** * * * **** ** ** *** = x[i];
* ** * * *** ** * ** * * * *** * ** * *** ** * *** ***** ** * * ** * ** * * *** = x[i+1];
* * ** ** ** ** ***** ** * * *** ** * * **** * * ** * * * * * ** * *** ** ***** * * = temporary;
** ** * * * *** * *** * * * * *** * * * ** ****** * *
* * * ** * **** ***** ***** **** * **** ***
******* * *
* *** **** ** **** *
** * *** * *** * * ** print the array */
* ******* ** * ** ** ** * * * * sorting: \n");
*** * ** * ** * * * i = 0; i < size; i++){
*** * ** ** * ** * * *** * * * * * * *** **** ", x[i]); ** ** * ** **** * **** * *
*** *** * *** ** ** ** *
* *** ** ** * * * **** ** **** * *
***** ** * * * * ****
**** ** *** * **
*** ** * * ** * * ** ** *
* * *** * **** ** * ** * ** * ** ** * * *** * * * * ***  
** ** * ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** **** *** * * *** *** * ** * x[] = {77,22,88,11,22};
* *** ** * ** * * ** size = 5;
    
* * * ** ** ** ** print the array */
* ** * *** ** **** i = 0; i < size; i++){
* *** * ** * ** * *** ** * * * *** ", x[i]); *** * ** * *** * ** * * *
* * * ** * **
*** * **** * * ** *** *** * ** * * *
******** * ** ** * **
** *** ** ****** *** * I need this to happen size-times */
* ** ** * ** * * ** j = 0; j < size; j++){
** ** ** ** ** * * * **** * * ** * * * *** from left to right */
* * * **** ** * * * * * * * * * * ** * ** ** i = 0; i < size-1; i++){
* * * * * * ** ** ***** * * ** * * * * ** * * **** ** * ** i-th element with its neighbor to check if they are in order */
** **** ** * * * * * * * * *** **** * ** * * * * *** * * * * > x[i+1]){
** * * * * * * ** ** *** **** *** ** ***** * ** ** ** ******* * * ** exchange the values of x[i] and x[i+1] */
*** ** * * ***** ** * ****** ** ** * * ***** ** ** * * *** * **** ***** ***** * * ***** **** * temporary; *** *** * *** *** * * * ** * * **
** * *** *** * * ** * * * ** * * ****** * ** **** * *** * * * ** ** * ** **** * * * = x[i];
** * ******* ****** * * * * *** *** ** * * ** * **** *** *** ** ** ** * * ** *** * * ** **** = x[i+1];
* * * * ** ** * *** *** ** ***** * * * * *** ** * * * ** ** * * * * ** ** * = temporary;
** ****** ** ** *** * * ** * ***** * * ****** ** * ** * ** **
* ** * ***** ** ** * ** * * * ***
****** * * ** * * ** * *
** * *** * * * * ***
* * ** ** * ***** * print the array */
* * * * *** **** *** *** **** ** * * sorting: \n");
** *** ** ** *** * ** **** **** i = 0; i < size; i++){
**** * ** * *** * * * ***** * *** ** *** * * * ** *** ", x[i]); * ***** * * * *** * *** ** * * *
*** ** * * * *****
** **** ** * * **** **** ****
* ** * **** * * * * **
* *** * *** **
** * *** * * ** * * ** * * **
*** ***** ** **** * * * *** * *** * *  
*** ** * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
******* ** * ** ** x[] = {77,22,88,11,22};
* * ** * ** *** * * **** size = 5;
    
*** * **** * * **** ** * print the array */
* * * * * ** * * * ** *** i = 0; i < size; i++){
***** * ***** **** ** ** * ** * * * ** *** **** ", x[i]); ** * * **** * *** ** * *** * ****
* *** *** ** ** * **
*** ** * *** ** * ** ****** * * *
** * *** ****** * * * * **
** * * * * **** **** I need this to happen size-times */
* ****** *** * ** *** ** *** j = 0; j < size; j++){
**** *** ** * *** ** ** ** ****** * *** **** from left to right */
* * *** ** ** ** * *** ** * **** * * * *** ** i = 0; i < size-1; i++){
** ** ** * * * ** **** * * * **** ****** ** * * ** * *** *** ** i-th element with its neighbor to check if they are in order */
** **** ** *** *** * * ** * * * ** *** ** **** *** * ** ** * * *** ** > x[i+1]){
* * ** * ** ****** *** **** *** ** * **** ** * ** * ** * * *** * ** * ** * * * * * exchange the values of x[i] and x[i+1] */
* * **** *** * * *** **** ** ** * * *** ** **** * * **** ** **** ** ***** *** ***** * temporary; ******* * * ** ** ** ** *****
** *** * * ** ***** ** ******* ** **** * * ** * * ** ** *** * * ** ** * ** * **** = x[i];
** ** *** * * ** * * * * * ****** ** ** * ** * ** * * * *** ** *** * * **** * * * * = x[i+1];
* * * * * **** * * ** * * ** * * ************ * ** *** * * ** ** * * * ** ** * * *** **** = temporary;
** * ** ** **** * ** * ** *** * * * **** * ** * * ** **** * *
* ** * * * * ** * ** * ** * ** * * * *
** * * * ** ** ** * *
* * * * *** ** ** *
** * ** ** * * ** print the array */
** ** ***** * * ** ** ** ** *** * * * sorting: \n");
** ** ** ** i = 0; i < size; i++){
* * ** * * * * * *** *** ** * * * * * ** * ", x[i]); *** ***** *** ** * * *** * *** *
** *** * * ***
* * **** * ** * * ** * * * **
* * * ** * ** * *
*** * *** * ** *
* *** ** * ** * *** *** **** ** *** *
**** ** ******* **** *** * * * ** ** ** *  
***** * **** * **** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.127.131
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.3k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.2k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.6k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.9k views
12,783 questions
183,442 answers
172,219 comments
4,824 users