0 like 0 dislike
8.7k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 8.7k views

46 Answers

0 like 0 dislike
Hidden content!
#include ** *** * ** **

int main(){
* * ** number[5]; // Do not change
* ** size = 5, ** // Do not change

* * * *** * ** * // Do not change
***** * * **** ** * * ** * *** ** * // Do not change
** * * // Do not change

**** ****** **** {
* * * * * * * * * ** *
* ** ********** * *** *** * {
* ** ** * **** * * * * ***** * *
* ** ** *** *** ***** **** * ** * * *
**** ** * ***** ** *** *** ** *
** * ******
*** ** *
* * *
** * ** ***** ** * {
**** * * * * *** ** *** * ** ** ** ****
* *

* * *** 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * ** * ***** * ** number[5];
** * * * *** * * *** size = 5, temporary;
    
* * * * ** * **** * * i=0;i<size;i++){
** * * *** ** ** * ** * * * ** ** ** ***** * * * *** ** * **
* * ** * * * * *

* ** * * *** *** ** * * * j = 0; j < size; j++){
** * * *** * ** ** * * ** * ***** * i = 0; i < size-1; i++){
* ** ** *** * * * * **** * * * * ** * * * * * **** ***** *** *** > number[i+1]){
* * * ** * ** * * * * * * ** * * * ** *** *** * * * * * ** * * * * * * **** * * ** temporary; ****** *** * ***** * *** * **
***** *** ** **** * ** * * ** * * * * ** ** * * * * * *** ** * ** **** *** * ******* ** = number[i];
** ** * * ** **** ** ** ***** *** *** * ***** * *** ** * ** * * * ** * *** * **** = number[i+1];
* ** * ** * * * * ** ** * * * * * ** **** ******** * * ** ***** ** * * ** *** ** * *** = temporary;
** * * * * **** * * * **** ** **** *** ** **** *******
* ** ** ** * *** **** ** * * * ** *
* * *** * * * * * *
* ** * *** *** ******* i = 0; i < size; i++){
* *** * ** * * ***** *** * **** ** * ***** * ** ", number[i]); * ** ** ******* *** ** **
* ** **** *** *
    
****** * * ** *** * * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * *** ** *****

int main(){
**   int number[5]; // Do not change
*** **   int size = 5, temporary; // Do not change
** * **  
    for(int * * **** * ** * // Do not change
* * ** * * * * ** ** * * * * ** // Do not change
* * *** *** } // Do not change

****   // Your conditions start from here
* * ** * ** *** * *** * j = 0; j < size; j++){
** * * * ** *** *** * * ** *** ** ** * *** ***** ** i = 0; i < size-1; i++){
* ** ****** * * *** * ** * ** *** * **** ** * * ** * *** ** **** ** * * * ** * > * *
** ** **** * ** * * * * * * * ** ***** * * * ** *** **** **** * * * * ** temporary; * * * ** * *** * **** * ***
** * *** * * ** * * ** *** *** * **** ** ** ** ** * * * * * * * **** * ** *** * ** = ** *
* * * ******** *** ** * ** ** * *** * * ***** * ** *** *** ***** ***** * * = ** *
*** **** ** ** **** ***** * * * * ** * *** * *** * * * * * * ** * * * ** ** * ** * = temporary;
******** ** * * * * * * ** *** ** * *** * * * * ***** ** *
* ** * * ** ******* *** ** * **** **
** *** * * * * *** * *
** * * ** **** **** i = 0; i < size; i++){
* * ** ** * * * *** ** * * **** **** *** ** ***** * * ** ** * * * ** *** * ** ** ** * * * * ** ** ******
* * *** ************ ***
***  
***** * **** **** * * ** * 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * ***** * *

int main(){
* ** **   int number[5];
    int size = 5, temporary;
   
    for(int * ****** **
        * ** * * * * * * ***
* *   }
* * * * ** *** * * * **** * j = 0; j < size; j++){
** ** * *** * ****** * ** *** ** from left to right */
* **** * ** * * ** * ** **** ** * * * ** *** ** ** * i = 0; i < size-1; i++){
** * * ** * * * * ** ** **** * ****** * *** ** * **** * * * *** * i-th element with its neighbor to check if they are in order */
* * ***** *** ** ** ********** **** ** * * *** * * *** ** * ** ************* > * * * *
**** * ***** *** ** * * * * * * **** * * *** *** ** ** *** * * * *** * * ** ** * exchange the values of x[i] and x[i+1] */
** * ** * * * *** **** * * * ** ** ** * * ******* * * *** * * * **** * ** ** * *** * *** * *** ** * temporary; ** ** *** * ** ** * ** *
* **** **** ******* ** ** ** * ****** * * ****** *** * ***** *** ** * ** * *** * * ** = *
* ** ** ****** * ** * ** * *** * ** ** **** ** ** ** * * ** ** ***** * *** *** * * = * ** *
** ** *** *** **** * * * *** ***** ** ** * *** ** ** ** * **** * **** ** ** * * ** * *** ** = temporary;
* * * * ** * * * * *** * * * * * * ** ** ** * * **** ** ** ** **
*** * * ** * * * * * * * *** * ** ***
* ** * * *** *** ** *
* * * ** *** * ***** * *
***** * ** * * * ** print the array */
** * *** *** *** ** ** i = 0; i < size; i++){
*** * *** **** ** * * ** * * *** ** **** **** * * * **** ** ** ***** *** * * * * ** *** * * *
* ** **** ****** ******
** *  
** * * ** * * * ** * 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ***** ***** * x[] = {77,22,88,11,22};
**** *** ** **** ** ** size = 5;
    
* * ***** ** * ** ** * print the array */
* **** * ** * ** * * * * i = 0; i < size; i++){
* ** ** * * **** * * * * * ** *** * * ** * ", x[i]); * * * *** * * ** ** ** **
***** * * * * * ***
* ****** ** ** ** * ****** * * *
** ** * ** *** ** ** **
*** * *** ***** I need this to happen size-times */
* ** **** *** * * ** j = 0; j < size; j++){
** * ****** ** *** ** ** ** * *** ** ** ** * * from left to right */
** * ** **** ****** *** ** ** * **** *** *** * ** i = 0; i < size-1; i++){
** ****** *** ** * *** * ** * ** * *** * ** ** ****** *** ** **** * * * i-th element with its neighbor to check if they are in order */
**** * * *** * * *** * ** * * ** * * * **** ** * * * ** * * > x[i+1]){
*** * * * **** ** * * * * ** * ** * ** *** * * *** ***** ** * ** *** *** * * * *** exchange the values of x[i] and x[i+1] */
** * * ** * *** * ** **** *** ** * * ** * * * ** * * * *** * * * * * * * * * *** * ** temporary; * * *** **** * * ** ** * ** * **
** * *** * * *** * ** ** ***** ** * * * ** * ** * *** * **** ** ** ** *** ** * ******* ** ** ** = x[i];
* * * ** * ** * * * ** * *** * * * **** * * *** ** ** ** *** ***** * * **** *** *** * = x[i+1];
** * ** * ***** * * * ** * * *** * *** *** * *** * * ** * * * *** *** * ** ****** ** * = temporary;
** * **** ** * * * * *** * * * * *** **** ** ** **** * ** **
* ** ** ** ** * ** ** * * * ** ** ** **** ** * *
* ** * * * ** ** ** *
*** * * * *
* *** * * **** *** * * print the array */
* * ** *** ** * ** * * *** ** ** sorting: \n");
****** * ** ** ** * ** * * i = 0; i < size; i++){
***** * * * ** **** * **** **** ** * ** *** * * * ** **** * ", x[i]); ** * * * * **** ** ** * * * * *
* ** * * ** ** * **
* * ** * *** * * * * ******* ** *** *
* * * * ** **** *
* * ** ** * ** * ***
**** * ** *** *** * * *** **** ** *****
**** * ** **** * ** * * * * **** ** ***  
* * * * * * * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * ** * * ****** x[] = {77,22,88,11,22};
* * ** ****** *** * ** size = 5;
    
** **** *** ** * ** * print the array */
* * * **** * *** *** i = 0; i < size; i++){
** * * ** * * *** ** * * * * ** * * * * ***** * ** * ****** ", x[i]); ** * * ** *** *** * ****** *
***** * ** * ** * ***
* * * ** ** * * * ***** * * ** ***** * * **
*** ** ** *** *** **** *
** * * ****** ** * ***** I need this to happen size-times */
* ** **** ** ** * * ***** j = 0; j < size; j++){
** ** * ** * ** * * * ** **** * ** **** *** from left to right */
***** ** * ** * ******* ** ** *** * * * * * ** * i = 0; i < size-1; i++){
* ** * *** *** * * * * *** * ** * * * * *** ** **** * **** ** * i-th element with its neighbor to check if they are in order */
*** *** * * ** ***** * * * *** * *** *** ****** ** ***** ** * *** * * * > x[i+1]){
* * * ** * * ** ** * * *** * ***** * ** * * * ** *** *** ** ** * ** ****** ** * exchange the values of x[i] and x[i+1] */
**** *** ** * *** ** ** * * ** ***** ** * ** * * ** ** * ** * * * ** * ** ** temporary; * *** * ** * ** **** * ** ***
*** **** * *** * * * * * * * *** ** * ** * * * ** ** ** * * * * *** * ** * *** * ** ** * * = x[i];
**** * * ** ******** * ** * ** * * ** * ** ** * * * *** ** * ** * ** ** **** * **** = x[i+1];
*** ** * ** * * *** * ** * ** **** ** ** *** *** * * * ** * * ** * * * ** ****** ** *** * ** * ** = temporary;
*** * * * * * ***** * * * ** * ******* **
* *** *** ** * * * * ** * ***** *** * * ***
** * ** * ** * * * ** * * * * *
* * * *** ** **
* * * * * ****** * * * print the array */
** ** *** * * * ** * * ** **** sorting: \n");
** **** * ** * * ** ** i = 0; i < size; i++){
* * *** ** *** * ** * ** ** **** * **** ", x[i]); * * ** * ** * ** ** ***** * * **
* * * ** ** * ** * ***
* ******* * * ** ** * * * * ** * * * *
*** * * ** *** ** ** ***
* ** * ** * * ** *
** ** * ** * * * * * *** *******
* * * ***** ******** * ** * * * *  
**** ** ** * ** ** * ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * ** * x[] = {77,22,88,11,22};
**** * * * *** * size = 5;
    
*** *** ***** * **** *** print the array */
* * * *** ** * *** * * * i = 0; i < size; i++){
* * * ****** *** * * ** * **** ** * * * * * ***** **** * ", x[i]); ** ** * * * * **** * ** * *
* * ** * * * ** * **
* * ******** ** *** * * * ** * *
* *** * ** *** * **** *
* ******* ** ** ** ** ** ** I need this to happen size-times */
* * * ** * ** ** j = 0; j < size; j++){
* *** *** ** * * * * ** * ** * * ** from left to right */
* * ** **** ******** ** * ** ****** * * i = 0; i < size-1; i++){
* * ** ******* *** * * * * ** * ** ** ***** ** ** * ** * ** * * i-th element with its neighbor to check if they are in order */
** ** * * ** * * * * * * * * * ** ** ** *** * * ********* * ** *** * ***** > x[i+1]){
* *** * * ***** *** * * ** *** ** ** * * ** * * * * ** * ** ** *** * ** ***** exchange the values of x[i] and x[i+1] */
** * * * ** *** * * * ** ** ** ** * ** * *** * ** ** * ** * ** ** * * * * ** * * temporary; ** *** ** * * * * ** *** * ** **** * *
* * * **** ** * *** *** * **** **** ** * *** * ** ** * * ** ** * * * **** *** * * ** * = x[i];
* * *** * ******** ** ** * * ** **** ** * ** * *** * *** * ** * * * **** * * ****** * ** ** *** = x[i+1];
* ** ** * * * * * * ******** *** * ****** *** ****** * * ****** * * * * ***** *** * = temporary;
* ** **** * * * *** ** ** * * *** * ****** **** * * * * * * * * * **
* * * * * * * * * * ** ** ***** ** * * **
* ****** * ** * *** *
** * * ***** ********
**** * * ** * * ** ** ** print the array */
* * *** **** ** * *** ** * * *** sorting: \n");
** *** * * * * * i = 0; i < size; i++){
* * * * ** *** * ** ** * ** ** * ** ******* ", x[i]); *** **** **** *** ** * ***
** * * ********* ** ****
***** * * *** ** * **** ** *
*** * * * **** *** *
** ** * * ** ** * * ****
* * * ** **** ** * * *** * * **
* * *** * * ** ******* *** * *** ** *** **  
** * *** **** **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* *** ** ** ** ** x[] = {77,22,88,11,22};
**** * ** * **** * * size = 5;
    
** * * *** ** *** ** print the array */
***** * * * **** * ** i = 0; i < size; i++){
** * * * * ** * *** ** *** ** * ** ** * * ** *** ** * ", x[i]); ** *** *** * ** * * **** * ** *
* * ** ** *** **** ***
* * ** * * ** * ** * *** *** * * ******
* * **** ***** * **** *
* * ** * ** **** ** I need this to happen size-times */
******* * *** * ******* *** j = 0; j < size; j++){
**** * *** *** * * ** * ** ** * * ** from left to right */
* * ****** * ** * * ** * * ***** ** * ** i = 0; i < size-1; i++){
* ** * * * *** * *** **** *** * ***** * * * ** ** ** * ** ***** * * i-th element with its neighbor to check if they are in order */
** * **** ** *** * *** ** **** ****** * ** * *** * **** ** * *** * > x[i+1]){
* ***** * ***** * * * **** ** * * ** * * *** * *** * * * ** * * * exchange the values of x[i] and x[i+1] */
* * * ***** *** ** * * *** **** ** ** * * * *** * * * * ** * ** ** * * * * * temporary; * **** ** ** *** * * *** ***
* * * ********* * ** * ** ** ** ***** ** * * ** *** ** ** ** *** ** ** ** *** * ****** = x[i];
**** * * ** * ** ** * *** ** * ** * * * ** **** ** *** * ** ** *** * = x[i+1];
* * * * * * * ** ** * ** **** * ** * * * ******* ****** ** ** * ** * * ** ** * *** = temporary;
** *** * * **** ** * *** ***** * * ** * * * * ** ** ** ** **
* * * * * ***** * * ** * ***** *** ***** ** * **
** ** * ** * * * ** ** *
* ** ******* * ****** *
* * **** * * **** ** ** * * print the array */
**** ** * **** ******** * ** *** sorting: \n");
**** ** * ** **** * *** i = 0; i < size; i++){
***** * * * ** ** **** ** *** * ** * * * * * ", x[i]); ** *** *** *** ***** *** *
* * *** ** ** * * *** *
** * *** *** *** * * * * * ***
* * * ** **** ** *** *
** ************ *** ***
** * ********* * * * ** * * ** *** ****
**** *** ***** * *** * * *** ** ** ** * ******  
*** * ****** ** **** * ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** ** * * * *** *** x[] = {77,22,88,11,22};
** * ***** * ***** size = 5;
    
** * ** ** *** * * *** print the array */
* *** * ****** * * * * i = 0; i < size; i++){
** * ** * * ** * * * * ***** *** ** * **** * **** * ", x[i]); *** * * * ** ******* * ***** * **
* ** ** * ** ** *** ** *
**** * ** * **** *** * *** ** ***
** * ** ** ** ** ** *
* * * * *** **** **** I need this to happen size-times */
*** ****** ** * ** j = 0; j < size; j++){
* * * ***** * ** **** * * * ** * * * ** * *** from left to right */
* ******* ** * * * * ** * ** ****** ** i = 0; i < size-1; i++){
**** **** * *** ***** ** ******* **** ** *** * * ****** ** * **** ******* * i-th element with its neighbor to check if they are in order */
* **** * *** ** * * * * ** * ***** **** *** ** * ** * ** * * * > x[i+1]){
******** *** * * ** ** ** ** * * ** * *** * **** * *** *** * * *** * * * * * * * ***** * ** * exchange the values of x[i] and x[i+1] */
* ** ** * * * * ** * * * * * ******* * *** *** * ** * * * *** * ** *** ********** temporary; **** ** ** ** * **** * * ** ** ***
** * * * * * * * ** ** ***** * * * * * ** ** * * ****** ** ** ** * *** *** ** = x[i];
** ** **** **** ** ** ** *** ** * * ** ** *********** ** ** * * * ** * *** **** ** * *** = x[i+1];
** *** * ** * * * ** * * * * ** ** * * ** *** ** ** * * ** *** * ** *** ** * ** = temporary;
*** * ** ** **** ** * ** ****** * ** ** ** ** * * ** **** ** * * *
*** ** ** * ** * * * ** ** ** *** ***** **
** * * * * *** ****
* * *** * ** * * *****
* ** * * * *** ****** print the array */
* * ** * ** * *** * * * * * ** * sorting: \n");
* * ** ** *** *** * *** i = 0; i < size; i++){
**** * * * * ** * ** ** * * * * * *** ** * ** * ", x[i]); ** ******** * * ** * **** ** ** ** ***
*** * * * * * *** **
* * *** ** * * *** * * * * * * * *** *
*** * * * * * *
***** ** ** ** * *
* **** * ** ** ** * * *** *******
* *** *** * * * * * * ** * ***** ** ** * * *  
* * ****** * * * *** * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * *** * ******* * * ** ** x[] = {77,22,88,11,22};
*** * ***** ** *** * * size = 5;
    
* ** ** **** ** * * print the array */
**** ** ** * * *** ****** i = 0; i < size; i++){
* **** * **** ** * *** *** * * *** *** * * ", x[i]); * * *** *** * ** * ** ** ****
* **** ** * * * * **
****** ** *** ** * ** ****** * ** * * *
*** **** * ** * *** *
****** * * * * * * * I need this to happen size-times */
** * *** * ** * * ** * j = 0; j < size; j++){
* * **** *** * * ** * * ***** *** * * ** * from left to right */
**** * * * * * *** * ** * * ***** ** ******* ** * i = 0; i < size-1; i++){
****** * *** * * *** ** * ** * ** * * *** *** * *** * **** * * i-th element with its neighbor to check if they are in order */
** *** ** ** * * *** ** * ***** *** **** ******* * ** ** * * *** * * * * * > x[i+1]){
* * * *** **** * * * * * ** ** ** * ****** * * * ** * ** * *** ** * *** ** * * *** ** exchange the values of x[i] and x[i+1] */
** **** *** ** * ****** ** ** * * ** * ** ** * * * * * * ** ** * * * * * * ** * ******* temporary; *** * ** **** * ****** ***
* **** * * *** ** * * ** * * * * ** * * * * ***** **** ** * * *** * * * **** * * *** * ** = x[i];
* * ** * ** * **** * * ** ********* * * * * ** *** * *** * ** * **** * **** * ** ** = x[i+1];
* ** ** ** *** * * **** * ** * * * *** * **** *** *** * * * ** ***** *** = temporary;
** ** ** * * * * ** **** * ****** **** **** * ** *
* ** ** ** * * * ** *** ** * * * * * ****
** ** * *** * * * *
* * ******* * ** *****
**** * * *** ** ** * * * print the array */
** * ** **** *** * *** ** * * * ** sorting: \n");
*** ** * * * * *** * * * i = 0; i < size; i++){
* * * * * * ** * * * ** * *** *** * **** **** ** ", x[i]); * ** * * *** * ** ** ** * ** * **
** ** * * *** **** ** *
* ****** *** ** ** ** * ** ** ** * *
** * * ** * * *** *****
* *** * * * *** * ** **
* **** ** * * * ***** ** * **** * **
*** ***** * * ** ** * ** ** *** * ** * *  
* * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.33
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 5.5k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.7k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 4.7k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 2.4k views
12,783 questions
183,442 answers
172,219 comments
4,824 users