0 like 0 dislike
6.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include * ****** ** *

int main(){
* ** ** ** number[5]; // Do not change
* * size = 5, * ** // Do not change

* * * ** * ****** // Do not change
***** **** ** ** * ***** * * *** ** * // Do not change
* ** // Do not change

***** * * ** ** {
* **** * ** * ** * * * * *
* ** * * ** * ** * * ** **** {
* * * ****** * * * * **** **
*** ** * ***** ******* *** *
* * * * *** *** * * ** * *** * *
******** **
* **
* * *
* ** ** * **** ****** * {
* ***** * *** **** * ** * * * * * ** ***
* * ** *

* * ** * * 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ******* * ***** * ** number[5];
*** **** * ******* size = 5, temporary;
    
* ***** * * *** *** i=0;i<size;i++){
** * * ** *** * * *** * ** ** * * * * * *** ** ** * *** ****
***** ***** ** * *

* * *** * *** ** ** *** **** j = 0; j < size; j++){
** * * * * * * * * ** ** *** ** * ** * i = 0; i < size-1; i++){
** ** ** * * *** * ** *** * **** ** ** * *** * * * ** * * * **** * > number[i+1]){
** *** * *** * * ***** * * ** **** ** ****** * ** * ** * ** ** * * * **** ** ** ** * * * *** temporary; * * *** * * **** **** * ** *
**** * * ******** * ** *** ** *** * * ** * **** ** * * ** ** * ** ** * **** **** * *** *** * = number[i];
* * * ** * * ****** ** **** ** *** * * * * ** ** ** * * ***** *** *** ****** *** = number[i+1];
***** *** * * ** *** *** ****** * * *** * * * * *** ** **** ** *** * ** ****** * * * ** ** = temporary;
* **** * *** ** *** * ***** ** ** *** * * * * * ***** *** **** *
*** * * * *** * * * ** *** * * *** ** **
*** * * * * *** *** *
* * * * * * ** **** * i = 0; i < size; i++){
** * *** * ** * * ** * ** * * ** * * * * * ***** ", number[i]); * *** * * * * * * * *
* * * **** *** ***
    
* *** * * * * ** ***** * 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * *** ***

int main(){
****   int number[5]; // Do not change
*** ***   int size = 5, temporary; // Do not change
*** * **  
    for(int * ** ** * * ** // Do not change
* *** * ** * ** *** **** * *** * ***** ** * // Do not change
** * * ** } // Do not change

* * *   // Your conditions start from here
* * **** * *** * * * ***** * j = 0; j < size; j++){
* * * *** *** ***** * * * * ** *** i = 0; i < size-1; i++){
* * * *** * *** ** *** ** * * * * ** * ** * *** ** ** **** * ** > ** ** **
***** ***** ** ** * ***** **** ** * * ** ** *** *** ** * * * * * * ******* * ** temporary; ** ** * * ***** * *** **
** * * * ***** ********* * ** ** * * * * * ** **** * *** ** **** * ** * *** * * **** * = * *
** **** * * ** ** * * ** * * ******* ** * ** * **** ** * *** * **** ** * * * * *** * * * ** * = ** *
* ***** * * * * ** *** * * * * ** * * ** * *** * ** * ** **** *** ** * ****** *** * = temporary;
* * *** *** * * * * * ** * ****** * * * * *** **** *** ** *
** **** ****** ** * *** * *** ******** * **
*** * ***** ** * **
* ** *** * * * *** * i = 0; i < size; i++){
* ***** * * ** ** * ** * ** ** * ** * ***** **** * *** * ** * ** * * * * * * ** * ** *
* ** **** ** * * *** *
 
**** ***** ** *** * * * *** 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include ** * **** **

int main(){
** ****   int number[5];
    int size = 5, temporary;
   
    for(int *** * **
        ** * ** * * ** * * * ****
* * ***   }
* * * * * ** * * j = 0; j < size; j++){
** ** ****** * * ***** ** * * ** * * ** * ** from left to right */
* ** * * * * * ** ** *** * * * * *** * i = 0; i < size-1; i++){
* ** ** ** **** *** ** ** ** ** *** * ** ** * * * * * * * * ***** i-th element with its neighbor to check if they are in order */
* * *** ** * * **** * * *** *** * * *** * *** * ** ** ** > ******** *
* ** * ***** * ** * ** **** *** * **** * * * * * * *** * * ** * ** ** exchange the values of x[i] and x[i+1] */
**** * * ** ** ** * *** * * * ** ** * * ** *** * * * ** *** ** **** ** * ** * * temporary; ** ****** * * **** ** ** * *** * * *
* ** ** * ** * ** *** ** * *** ** * *** * * * * * * *** * ** ** * *** = **
** **** * ** ** *** * * * * * ***** * ** **** **** ** * * * * ** = ***
* * * * ** * ** * * * ** **** * ** * * * ** * * ** * ** * * = temporary;
* * **** * * ** ** ***** * * * * *** *** ** ** *
** * * * * ****** * ** * **** * ** ** ** * * ****
* * * **** ****** **
**** ******* * * **** *
** * ** ** *** * * * * * print the array */
* * ** * * **** * ** *** i = 0; i < size; i++){
* *** ** * * * ***** *** * ** * ** * *** * *** ******* * * * *** *** * ** * *********** ** ****
* ******* * * * * ***
** ****  
* **** * * ** * ***** * 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * **** ****** * * x[] = {77,22,88,11,22};
* ** * * **** * * * * * * size = 5;
    
* ** * * * * ** print the array */
* * * * * ** * ** * i = 0; i < size; i++){
* ** **** ****** **** ** *** ** ** * ** * * * ", x[i]); * * * ** **** * * **** ** * ** *
* ** * ** ** * ** **
* ** *** ** * ** ***** * ******** * * * *
*** * * **
* * *** ** ****** ***** * * I need this to happen size-times */
***** * * * **** j = 0; j < size; j++){
** * ** * * * ** * * *** * * * ** from left to right */
** *** * * * * * ** ** ** **** ** * ** *** i = 0; i < size-1; i++){
* ** * * **** ** * * * * * ** ***** ** ** ***** * * * ** **** * *** i-th element with its neighbor to check if they are in order */
* * ** ****** * * * ****** * * * ** ****** * * ** * * ******** * * **** > x[i+1]){
*** * ** * * * * ** * *** **** ** **** * *** ** * ** ** ** ** * * * * * * **** *** exchange the values of x[i] and x[i+1] */
** * *** * ** ******* **** * * *** * * *** ** ** ** ****** * * ** ** * * * * * * * * * * temporary; * ****** *** *** ****** * ** * * **
*** ** *** ******* * *** * ** **** * ** **** ** *** * * ** *** *** **** *** * *** * * = x[i];
* * * ** *** **** ***** * ** ** * *** * **** * * * * * * **** * * ** * ** * **** ** ** = x[i+1];
* ** * * **** * ** ** **** *** * * **** ** * ** **** * *** * * *** * * * * * ****** ** * = temporary;
** *** * ** * ** ** * ***** * * ** * ****** * * ***** *
*** *** * * * * ** * * * ***** **** **** ** **
* * * ** *** ****
* * * * * * *
* **** * * ** ** ** print the array */
* *** * ** *** ** **** **** sorting: \n");
* * * ** * * * * ** i = 0; i < size; i++){
*** *** ******* ** * ** ** ** * ** * ****** * * * * * ** **** ", x[i]); ** ** **** *** * * *** *** ****
*** ** * ** ****** * **
* ** * * * ** ** *** ** *** *
** ** * * ** *
****** *** ** * ** * *****
* * ***** *** **** * * ** ** ** *** ** **
* **** **** * * *** **** *** * * * ** * ** **  
*** ** * ***** ** * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * ** ***** * x[] = {77,22,88,11,22};
** ** * * ** ******* * ** size = 5;
    
** ** * **** ** ** ** print the array */
* * ** * * ** ** * * i = 0; i < size; i++){
* *** * *** ******* ** * ** * * ****** *** * ** ***** ", x[i]); *** * * * * ** * * * * * * ** * **
* * * * ** ** **** * *
* ** *** * *** *** * ** * *** * ***
* * ****** * * * *
* * ** * *** * *** ** * ** * * I need this to happen size-times */
* ** ** ** ** ** *** j = 0; j < size; j++){
* *** * * *** * * * * * * ***** ** ** ** * *** from left to right */
* * * * * ** ** ** **** **** **** * * * i = 0; i < size-1; i++){
**** * * ******* * ** *** ** * ***** * * ***** *** ******** * **** ** * i-th element with its neighbor to check if they are in order */
** ** **** * * * * *** * ** * * * * ** ** * * *** * *** * > x[i+1]){
** *** * ***** ****** ** ** *** * ** * ***** ** * ** * * * * ** * * * * ** *** * exchange the values of x[i] and x[i+1] */
* ** *** * * ***** ** * * **** * ** * * * *** * * ** * *** * * * * * * ** ** temporary; *** ******** ****** *** ** * *
** ** * ** * ** ** * * ** ******** * * * * ******** * ** * ** * * * * * ****** = x[i];
********* * * ****** ***** * * * **** **** ** * * * * ******** * * ***** * ****** = x[i+1];
* ***** ***** *** ** * * *** * ** ****** * *** ***** *** **** * *** *** **** **** = temporary;
** * * ** * ********* * * ** * * ** *** * * ** * **** ** * ***
** ** * * * * ** ** **** ** * ** * **** * **
* * ** **** * **** *
* * *** * * ** ** *
**** * * *** ** * * print the array */
* ** ****** ***** * * * * sorting: \n");
* **** ** * ** * * i = 0; i < size; i++){
*** ** * ** * ** ** ** * ** * ***** * **** ** **** * *** ", x[i]); * ** ** ***** ** ***** *** *** * **
*** *** * ** ***
** * *** * *** * * ** * *** * * *** * ****
* **** ** * * ** * * *
** *** * ** ** * **
* *** ** *** **** * * ******** ******* * **
** *** **** **** ** ** *** * * * * ***  
* * ** * * ** ** ** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* **** * ** ** * * * * x[] = {77,22,88,11,22};
*** ** * ** * * ** ** size = 5;
    
** ** * * * * *** * * print the array */
* ** ** * *** **** ***** * i = 0; i < size; i++){
* * ** *** * * *** ** * ***** *** *** ** * * * * * ", x[i]); * *** * **** * ** * ** * * **
**** *** ** ** * ******* *
** **** * * * * ** ***** ** * *** *****
*** ** * ** *** ** * *
* *** *** * * ** ** * * * I need this to happen size-times */
* * *** *** * * *** * * ** j = 0; j < size; j++){
* * ** * ** * ***** * *** * ** ** *** * from left to right */
** ** ** ** *** * ** * ***** i = 0; i < size-1; i++){
* ** * * ** * * *** ** **** **** * * *** * ** * * * *** * * ******* i-th element with its neighbor to check if they are in order */
** * *** **** ** * ***** * * ** * * * * **** *** *** * ******** ** * **** > x[i+1]){
*** ** * ** *** ** * * * ** * ** ** * *** * ***** ** * * * * ** * * ** * ** * ** * exchange the values of x[i] and x[i+1] */
* *** ** * * *** * ** * * **** * ** * * * * *** * *** **** *** *** ** * * temporary; *** ** ** ** *** ** ** * ** **
**** * * * ** * ** ** ** * * **** * * * * * * * * ***** **** *** * **** ** ***** * = x[i];
**** * * * ** *** **** * ****** ** ** * ** * * ** * ** * * ** * ** ***** * ** * * * * = x[i+1];
* ** ** **** * ** ** * ** * * * * *** * * ** ** * ***** * ** * * * *** ** * = temporary;
*** * *** * *** * ** * * ** *** * ** * **** * *** * * * *****
* * * ** ** * ** * *** ** ** ** ********
** ** * * ** *
********* ** *********
* * * * * * *** ***** print the array */
** *** *** ****** **** * * *** *** sorting: \n");
** * * ** ** * * * * * i = 0; i < size; i++){
* ** *** * * * ** ******** * * * ** ** * * *** ", x[i]); * * * *** * * ******** ** * *
*** * * *** ** * *
** ** ** **** * *** * * * * *** * *
**** **** * ** * ** *
** ** * * * ******
**** * ********** ** * **** *** ** *
*** * * ** *** * ** * * * *  
** ** * ** ** ** * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * ** **** ****** ** x[] = {77,22,88,11,22};
*** ** * ** * * ** * size = 5;
    
* * * * * ** * *** print the array */
* ** **** ** ******* * i = 0; i < size; i++){
** * * * ** * ** **** * ** ** * ** * ** * * ** * ", x[i]); * * * ** ** * * *** ** *
** * ** * ** ** *** ** *
** * * ** ** **** * * * * * ***
* * * * ****** ***
* ** * * * * ** I need this to happen size-times */
* * * * **** ******** *** j = 0; j < size; j++){
* *** * * ** * ** ***** * ** * ** ** from left to right */
* * *** *** * * *** *** * **** * * * ** *** i = 0; i < size-1; i++){
* *** ** ******** *** ** * ** * ** * *** * *** *** ** * ** ** * * * i-th element with its neighbor to check if they are in order */
* *** ** ** **** * * ** * * ** * ** ** * ** ** *** ** *** * * ** *** * > x[i+1]){
* *** * ******* * * * * * * * ** * * * ** * * * ** * ** ** * * * * * * * * **** * exchange the values of x[i] and x[i+1] */
*** ** ** ** ***** ******* * *** * * * ** *** * * **** ** *** * ** * *** temporary; ***** ** * * **** **** * ***** * *
*** * * * *** **** ** * ***** ** * ** ** ** *** *** * * ** * **** * ** ** *** = x[i];
* * ** ** * * * * ** ***** * ** * ** **** ** ** * * **** * * * ***** * * **** * * ** *** = x[i+1];
* ** *** **** ** * ************* **** ** * ** * ** * * * * * **** *** ******* * * = temporary;
*** ** ***** * * * ****** * ** * *
** * * * ***** * *** * * ** *** * ** **** **
* * * **** ** ** **
* * ******** * *
* *** * **** ***** * * ** print the array */
* * ** ** ** * * * * **** ** * sorting: \n");
** ** * * ** ** ** ** ****** i = 0; i < size; i++){
** * **** ** *** *** * ** **** ** * *** *** *** * ** ", x[i]); ** *** *** * ** * * * ** ***** *
*** ** ** *** **** ****** *
*** * * * * * * * ****
* ** * ** ** * * ****
*** * **** * ** ***
* ** ** **** * * * * ** ***** *
** * * * * *** * * *** * ***** * * ** ******  
*** * * ** *** **** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** *** * * *** ** *** ** x[] = {77,22,88,11,22};
* * ** ** * *** *** size = 5;
    
*** *** * * * **** * * * print the array */
* *** * * * * * ** *** ** i = 0; i < size; i++){
*** ***** * * ** * * * * * * * * * * ***** ", x[i]); * ** *** ***** * *** * *** ** *
* ** * ** * *** **
**** *** ** * * * * *** ***** ****** *
***** * * ** *
* * ** * * ** * *** I need this to happen size-times */
* **** * ** ***** ** * * j = 0; j < size; j++){
** ** * * ** ****** * ** * * * * * **** * ** from left to right */
** * *** ** * ** * **** * * * ** * * i = 0; i < size-1; i++){
* ** *** ** * * * * * * * * *** **** ******** * *** * ** ** * * *** i-th element with its neighbor to check if they are in order */
* * **** *** * * ** ** *** * ** * ******** **** *** * * *** *** > x[i+1]){
** ** **** * * * ** **** *** ********** ** * * * ** *** * * ** **** * *** ** exchange the values of x[i] and x[i+1] */
* **** * ** ** * ** ** ** *** ** *** * * ** ** * * ** * * * ** ** ** ** *** * temporary; **** * *** * ** ** * ** ** **** * ** *
** * *** * * ** * ***** ****** * * ******* * * * * *** **** * ** **** *** ** = x[i];
* ** *** *** * ** ** * * ** * * * * *** ***** * * * * ** ** * ** ** ** = x[i+1];
* ** * **** * ** **** * ** * *** ** * *** ******** * ** **** * ** ** ****** * ** * = temporary;
* ** * * ** * * ** ** * *** * * ***** * ** * * * ** * **
***** ** **** **** *** *** * * * **
* ** **** *** * ** * **
* ** ** *** * ****** **
* * * ** * * * * * print the array */
****** * * * **** * ***** ** * * ** sorting: \n");
* ** * * * * ** ** * i = 0; i < size; i++){
* ** * * **** *** * **** *** * **** ** * * ** * ** ", x[i]); ** * * * * * **** * **** ****
* * * * * * * **
* * * ** * **** * *** ***** * ** * *
* *** *** * *** ** * **
* * * * ****
** * * ** * * * ****** *** ** ** **
** * ** * * ** *** ****** ***** * * ** * ******  
* * * *** ** * * * **** ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* ***** *** * ** * * x[] = {77,22,88,11,22};
* ** * ** * * * * **** size = 5;
    
** ** * * ****** ** * print the array */
** ** * * ** * * ** **** ****** i = 0; i < size; i++){
** * ** *** * * ** ** * * * ** * ** * ** **** ** *** * ", x[i]); * *** * ** * *** * * * *
* ** ** * **** ***
* * * ** ** ** * * * ******** *** *
* * ** ** * ** * **
***** * * ***** * * * * I need this to happen size-times */
***** **** * * * * * j = 0; j < size; j++){
** ** ***** * * * * * * ***** * * * * * *** * from left to right */
** * * * * *** * *** * ** ** * *** *** **** i = 0; i < size-1; i++){
** * * ** * *** * * **** ** * * * *** ** * * * * ******* * ** * * i-th element with its neighbor to check if they are in order */
* **** ** * * * * ***** ** ** *** * ** * * ** *** ** ***** *** * * * ** * > x[i+1]){
** ** * **** **** ** * * * *** ** * ****** ** * * * * ** ****** * * * * * exchange the values of x[i] and x[i+1] */
* * * * ** ******* *** ** * *** * *** ** * ** *** ** * * * * ** * ***** * ******** * * ** * * temporary; *** ***** * * * * **** ** * **
* * * *** **** * * *** * * * * * * ******** * ** ******* * * *** **** * = x[i];
* ** * ** *** ** ******* * * * ******* ********* ** ** ******* ** * *** * * ** ** ** *** * = x[i+1];
* *** ** * * * ** * * * * *** ******* ** ** *** ** ***** * * * * ** * * *** * * * * *** ***** ** = temporary;
** *** ** ** ** ** * * *** * * *** ***** * ***** * * ** **
**** * **** ** ******** ** ** * * ***
* ** ********* ** *
*** * * ***** * *** * *
** * * ***** * *** **** * * print the array */
* * ***** * * * ** *** *** * * *** sorting: \n");
* **** **** * ** ***** * i = 0; i < size; i++){
** ***** **** ** ** * * * ** * ** *** * ** *** **** ", x[i]); * * * * * *** ** *** ** * ** ****
* * * ** * ** ***
*** * ***** ** * ** * *** * * ** **
* *** * * *** ** *******
* * * * ** ** * * ** **
*** ** * *** * * * ***** * **** ***
* **** * ** * ** ** * * *** * * ******* ***  
*** * **** * ** * * **** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.59
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users