0 like 0 dislike
6.6k views

Please write a program that receives 5 numbers in an array, then makes those numbers in ascending order by using bubble-sort.

**Use the template given below**

Code (Template)

#include <stdio.h>

int main(){
	int number[5]; // Do not change
	int size = 5, temporary; // Do not change
	
	for(int i=0;i<size;i++){ // Do not change
		scanf("%d",&number[i]); // Do not change
	} // Do not change

	// Your conditions start from here

	return 0;
}

 

Input 1

77 22 88 11 22

Output 1

11 22 22 77 88

 

Input 2

34 32 12 64 2

Output 2

2 12 32 34 64
[Exercise] Coding (C) - asked in Chapter 4: Arrays by (5.9k points)
ID: 37580 - Available when: Unlimited - Due to: Unlimited
| 6.6k views

46 Answers

0 like 0 dislike
Hidden content!
#include ** ** * * *

int main(){
* ** **** number[5]; // Do not change
*** * size = 5, ** * * // Do not change

* * ******* *** ** ** ** * // Do not change
**** ***** * * * * * * * *** * * * ** ** // Do not change
**** *** // Do not change

*** ** * * *** ** {
* * * * * ** *** *** **
**** ** ** **** ** ** ** * ** ** {
* ** *** * *** * * * * *
* ** * * **** *** * **** * **** ** *
** ** * * * ***** ** ** * **** * *
** * * * *
* **
* * ****
** ** * ** ** *** {
***** **** ** ** * ** * * * * ** ***** * *
*

* * * * * * 0;
}
100/100 answered by (273 points)
0 0
prog.c: In function 'main':
prog.c:11:6: error: 'i' undeclared (first use in this function)
  for(i=0;i<5;i++) {
      ^
prog.c:11:6: note: each undeclared identifier is reported only once for each function it appears in
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ** ** ** * * number[5];
** * * * * * *** * * size = 5, temporary;
    
* * ** ** *** ** *** i=0;i<size;i++){
**** * ** * ** ** ** * *** * *** **** ** **** * * ** * * * * ** **
** ** * ***** * * ** ***

*** **** *** *** * * *** * * j = 0; j < size; j++){
* * *** ** * * * ******* *** * **** * * i = 0; i < size-1; i++){
* ** * **** *** ** **** *** *** *** * ** * ** * * ** * *** * *** > number[i+1]){
* ** * ** ****** **** ******** ***** **** * * ** * *** * ** * *** ** *** *** **** *** temporary; * * * **** * * *** * **** **
* ******** ***** * * * * * * * ** * **** ** ** * *** * ******* **** ** * * *** ** * *** * = number[i];
* ** ** ** ** * * * *** *** ******* *** * * *** * * * * ** * * ** ** ** * ** * = number[i+1];
* * * **** ** * ** * * * * **** *** * ******* ** ** ** **** * ** * * *** ** * * ** ****** = temporary;
** *** **** ***** * * * ** * * ** * * *** * * * * ****
** * * * * **** ** ** * ** ** ****** * ***
****** * ****** * **
* ** * * ****** * *** * * i = 0; i < size; i++){
* * ***** ** * * * ** ******* ** * * * * * ** ", number[i]); * *** * * * * * * ** * *
*** * * * *** ** * ** * **
    
** ** *** ** ** *** *** 0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include * * * *

int main(){
*** ***   int number[5]; // Do not change
  int size = 5, temporary; // Do not change
*** **  
    for(int *** ** * *** // Do not change
* *** ** * * **** * * * ** * **** * ** // Do not change
* * * * * * * } // Do not change

*   // Your conditions start from here
** * ** ** * *** * *** ** * ** ** ** j = 0; j < size; j++){
** * * *** **** * ** **** * ** *** *** ** i = 0; i < size-1; i++){
* * * ** ***** * ** ** ** * * * * * **** * **** **** * > ** *
** ** * * * *** ** **** *** * * * * ** * **** * ** ** * ***** ** * * * ** * temporary; * * ** * ** * * *** * *** * *** *
* * ** * * * * ** * * * ** * *** ** ** ** **** * *** * * ***** ** ** *** ** * ** * *** * * = *
** ****** *** * * * * ** **** ** * ******* * **** ** * * * **** * * * * ***** * * ****** * = ** **
* * * **** ***** ** * ****** * * * ** ***** ** * * * * * * ***** **** * **** = temporary;
**** ** *** *** *** *** * * ***** * ** * * *** * ** * ** * * ** **
* *** * * * * * * ** ** ** ****
* ** **** * * * *******
* *** * ** * * * * ** * i = 0; i < size; i++){
** ** ** * * ** * * ******* * * ** * * * **** ** * * * * * * * **** *** * * *** * * * * ***
* * ****** * ** **
** **  
* * * ***** ** 0;
}
100/100 answered by (283 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include **** *** *

int main(){
* *   int number[5];
    int size = 5, temporary;
   
    for(int *** *** ** *
        * **** * * * * ***
*** ***   }
** * ** * ** ** ** j = 0; j < size; j++){
**** * ** * * * ** * ****** * ********* from left to right */
** * * ** ** *** ** ** ** * ** *** ** ** *** * * i = 0; i < size-1; i++){
*** ** * * ** ** *** ** * ***** * ** *** ********* * * * ** ** ** i-th element with its neighbor to check if they are in order */
* ** * * ** * ** * * * ** ** ***** * * ** ** ** * * * **** *** > * *
* ** **** ***** * *** ** ****** ** * ** * ** **** * * ***** * ***** * *** ***** ** ** * * exchange the values of x[i] and x[i+1] */
*** * ** *** * *** * ***** * * * * ** * * * **** * ** *** * * * * * temporary; ** ** * ** ** * * * * * ** * * **
* * *** **** * * * * * * ** * ** ***** * * * * *** ** *** * ** ** ** *** * = ** * *
** ** ** ***** * * ******* * * * ** * * * * ** ***** * ** * ** * ** *** ******* = * *
* * ** ** * ** * ****** * ******** ** ** * * * * ** * * * * * **** ** * ***** ** * *** * = temporary;
* **** * ** * * * ** * * * * ** * * ** *** * ** ** ** * *** **
** * * **** * *** * * ***** * *********** ** *
* **** ** * * ** *
***** * * * * ** *
*** **** ** * *** ** * * * * ** print the array */
*** *** *** * * ** * i = 0; i < size; i++){
*** ** * *** ** ** *** *** * * * ** *** * ** *** ** * *** * ** * * * * * * * *** ** * * **
** ** *** * * ** * *
**** *  
*** **** * * *** ***** 0;
}
100/100 answered by (153 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
prog.c: In function 'main':
prog.c:30:5: warning: implicit declaration of function 'system' [-Wimplicit-function-declaration]
     system("PAUSE");
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Correct output
Case 2: Wrong output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** ** ** * ** * * **** ** * * x[] = {77,22,88,11,22};
** ** * * ** * size = 5;
    
** **** * * ** * *** * print the array */
* ** * ** *** * * * ***** i = 0; i < size; i++){
** **** * * **** * **** *** **** *** * ", x[i]); * * **** *** * * **** * ** *
* ***** * ** *
** * ****** *** * **** ** ** *** * * *
* ** * * * * ** *** * *
* * ** ***** ** * *** * I need this to happen size-times */
* ** ** *** ** * ****** * * * j = 0; j < size; j++){
*** * * ** * ** ** *** *** * * ****** **** * ** from left to right */
** * * * * ** ** * **** **** * ******* * * ** * i = 0; i < size-1; i++){
** * ** * *** ***** **** ** * *** * ** ** * * * ****** * * ****** ** * * * i-th element with its neighbor to check if they are in order */
** **** ** * ** * * ** * * * ** ** ******** * * * * * ** > x[i+1]){
***** ** * ** ** * ** ** **** * ** * * *** * * * * ** *** * * **** ** ** * * exchange the values of x[i] and x[i+1] */
* * * ************ ** * * * * ** * * * ** ** ** ** * **** ** * * ** * * * temporary; ** * * * * * ** * ** * **
* ** ** * ******* *** * * * * ** * * * * **** * * * ****** * ** ** * ** ** * *** * **** = x[i];
** * ******** * ** * **** ****** ** * ** * * * ** * ** * * * ** ** ***** ***** ** = x[i+1];
* ***** *** ** * * * ** * * * * ** ** * ** * * *** *** *** * ** ** **** *** ** ** * * = temporary;
***** * * * *** ***** * * *** * *** **** ** * ** * * ** * ** ***
** * ***** * * * * ** * *** ****
* ** * ***** ** ** ** *** *
** *** * ****
** ** ** *** ****** ** * print the array */
** * ** ** * ** **** * * *** sorting: \n");
*** * * ** * ** * * ** i = 0; i < size; i++){
*** * * ** * * * * * * * ** * * ** **** * * ** ", x[i]); * * * * * * * * *** * ** *
* * *** ** * * ** **** *
* * * **** * * * *** *** * * * **
* * ** * ** * *
* ***** * * * *
*** * * * * *** **** ** * * * *
*** **** ***** * * * * * * * ** * * * * ***  
** ***** * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
**** *** ** ** * *** ** x[] = {77,22,88,11,22};
* *** * * ** * * ** *** size = 5;
    
*** **** ***** ** * * * * print the array */
* * *** **** * ** *** * i = 0; i < size; i++){
* *** ** * * * ** ** ** ** * * * * **** ** *** * * ** ", x[i]); ** * ** ** *** * * * * * * *
* * * * * * *** *
* * * * * * ** * ** *
* ****** ** * ** * * * *
* *** **** * * * ** I need this to happen size-times */
* * * ** ** *** j = 0; j < size; j++){
** ** ** ** ** ***** *** ** * **** **** ** from left to right */
** ** *** * * ** * ** * * * * * *** * i = 0; i < size-1; i++){
* ** * * ** ** **** * *** ** ** ****** * *** *** ** * **** * *** * * i-th element with its neighbor to check if they are in order */
** ** ** ** * * ** * * ***** ** * * ** ** * * * * *** ** ** > x[i+1]){
* * * *** *** **** * *** * * * * * ***** * * ** * ** * ** ** ***** * * * ** * *** **** *** ** exchange the values of x[i] and x[i+1] */
** * ** *** *** ** * ** * ** ** * * * *** * * ***** * ** * ** * ** ***** * * *** * **** temporary; * * ***** * ********* ** ***
*** * * *** * ** ** *** ** * * * *** * ** * * * ***** ** *** * * ** * * * ** ** * * = x[i];
* ***** ** ** *** **** * *** *** * *** ** ***** * * * *** **** * * * * ** ** = x[i+1];
* * *** * * * ****** * ** ** ** * * ** * ****** * * * **** ** ** * * * *** = temporary;
* * * * * * **** ** * *** * ** * * * ** *** * * *** *** *** * *
** * * * * ** ** ** * * * * ** * ** *** *
* *** * **** *** * *** **
** ** **** * *** **
* * * * * * ** ** * * print the array */
* *** ** *** * *** * ** *** sorting: \n");
*** * * * * * * *** * ********* i = 0; i < size; i++){
* * ***** **** * *** ***** * * *** * **** * *** ** ", x[i]); * *** * **** *** * * ** **
** ** *** * * * *
* * **** * * * * * ** *** * *
***** * *
* ** * ** ** ****** * *
** *** ** **** ** * ** * * **** * *
* * * * * * ** ** ** * * * * ** * *** *  
** ** * *** ** * ******* * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
** * * * **** * ** * x[] = {77,22,88,11,22};
** ** * * ** *** size = 5;
    
* * ** * * * print the array */
* * **** ** ** * * * *** i = 0; i < size; i++){
* *** *** *** ** * * ** ** * ** ** * * ** ** * * *** ", x[i]); ** ** * * *** * * * * *** **
** ** * * * ** * ********
***** * **** ** *** * * *** * * * * **
** ** * * * *** * * ** *
* ** * ** *** * I need this to happen size-times */
* * ** * *** ** *** * ** j = 0; j < size; j++){
* * **** ** **** * * * * ** * * * *** * * * from left to right */
**** **** * ** * *** ** * *** * * ** ** *** i = 0; i < size-1; i++){
* *** * ** ** * ***** ** *** ** * ** ******* * ** * * ** ** i-th element with its neighbor to check if they are in order */
* * *** * * ** ** * * ** ** ******** ** **** * * * *** * * > x[i+1]){
* * **** ** * * *** * * ** * *** * * ** **** **** * ** * *** ** ** * * exchange the values of x[i] and x[i+1] */
* *** * * * *** * * ** * * * ********* * * ** * *** * *** * ** * * ** * * *** * temporary; * * ** * ***** * * * * ***** *
** *** *** ** * * *** * * ***** * *** ** * ** * ** *** *** ** **** * * ** *** = x[i];
**** *** ** * ************ * * ***** ** * * * ****** ** *** * * ****** *** ** ** * = x[i+1];
* * *** ** * ** ***** ** ** * ** ************* *** **** ******** ** * * ** *** ** ** ** * ** = temporary;
****** * ** ** * **** **** ** **** **** * * * * * * **** ** * * *** * *** *** **
** * **** ** * **** * **** ** * * * * ****
****** * * * * * ** *****
** ** * * ** *** *
****** * * * **** *** * print the array */
** * * * ** ** ** ******* * * sorting: \n");
*** * *** * * * * * * ** * i = 0; i < size; i++){
* * * ** * * * * * * * ***** *** * * * * **** ** ** * * ", x[i]); **** *** * ** **** * * ****
**** ** * * *
* * * *** ** ** *** ** ** *
***** * **** * ** *
* ** **** *** ** * * *
******* * ******** ** **** * * ** * * **
* * * ** * * *** * ** * * * * * * **** *** **  
*** ** * * * ** * * *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * ** ****** x[] = {77,22,88,11,22};
* **** ** ** * * ** *** * size = 5;
    
* ** ** * ** ******* * ** * print the array */
* ** **** * ** * * ** i = 0; i < size; i++){
* ***** * *** ****** * * * * *** *** * * * * ", x[i]); ** **** ** ***** * *** **** ***
** * ** * ***
*** * * *** * * ******* ** ** *
***** * **** * ** * *** *
* **** * ** ** * * * I need this to happen size-times */
*** * ** * * * *** * j = 0; j < size; j++){
* * * **** ****** **** * *** ** **** * * ** * from left to right */
***** * * * *** ** * * ** * *** * ** * * * *** i = 0; i < size-1; i++){
** *** * * ** * ** * **** * * *** ***** **** ** * ** * ** *** * i-th element with its neighbor to check if they are in order */
** ** ** * * * ** ** ** ***** **** ***** ******* * * * * **** * > x[i+1]){
** * ** ** ** **** * **** **** * * * * * *** * ** * * *** *** *** * ** exchange the values of x[i] and x[i+1] */
** ** * *** * * *** * * *** * * *** ** * * * *** ** *** **** * * *** * * ** ** ***** temporary; * *** * ** * * ********* * ** *
** *** * * ** * ** * * ** ** **** ** ** ** * *** ** *** * ** * ** ***** ******* ** = x[i];
**** **** * ** *** ** ** *** * * * ** * *** * **** ***** * * **** * ** * * * ** = x[i+1];
* ** * * ** * *** * ** * * ** * * ** * * ** ***** *** * * *** *** ** * * **** *** ** = temporary;
* *** ***** ** * *** *** ** * ** * * * * *** ** * ** ** **** * * * *
*** * * * * * * ** ** * **** ** * * ** ** *** *
* * * * * *
**** *** *** * * **
** * ** **** ** *** print the array */
** * ** * * ** ** ** * * sorting: \n");
* * * * * * **** * * i = 0; i < size; i++){
* * **** ** * * ** ** * * ***** ** ** * * ** ", x[i]); ***** * ****** *** * **** * * * ** *
* * * ** ** * * * *
**** * * ** * * * * *** ** * ** * * ***
*** *** ** * *
* ** *** * * * * ** *
* ** * ** ***** ** * * **** ** ***
* **** * *** * ** *** *** * * * *********  
* * ** ** * * * * * * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
* * * * * * * * * * * x[] = {77,22,88,11,22};
*** * * * ** ** * ***** * size = 5;
    
**** * * * * ** * print the array */
** *** * * **** * *** ** i = 0; i < size; i++){
* ** * **** *** ** ** *** *** * *** * ** ", x[i]); ** * * * ** * ** *** *** *
** **** **** * ** ** ** **
**** ** * * * ** ** * * * ** *
* ** **** *** * * *
* **** *********** * * * * I need this to happen size-times */
**** **** * **** * * * ** j = 0; j < size; j++){
**** ** ****** * * * *** * * ** * from left to right */
* *** ** ** ** ***** *** **** **** ** ** * i = 0; i < size-1; i++){
** * * * * * ** * ** * *** ***** * ** * *** ****** * * * *** i-th element with its neighbor to check if they are in order */
* * * ** * * ** ** * * *** ** ******* * * * ** ****** ** * *** *** **** > x[i+1]){
* ** *** ** * ** * ** ***** ** ** * ****** ** * * * **** *** ** * * *** **** ** * * * exchange the values of x[i] and x[i+1] */
* * * *** * ** * * * * ** *** ** * ** * * * * * * ** * * * * * * *** ** ** * ** * temporary; ** * ** * ** * ** ** * ** * * *
*** *** * * *** ** *** * ** **** *** ***** * *** *** *** **** * *** * * **** ** * * * = x[i];
**** * **** * * * * ***** ** * ** * * **** * **** **** * * ******* *** * ** **** * *** * = x[i+1];
* *** *** ***** * * * **** * * * * ** ** ** ** **** * ** * * ** * *** *** ** **** **** * ** = temporary;
** * **** * ** * * *** *** ** * ** *** ***** * * **** * * *
* * * ** * * ** **** * ** *** ** **
* * * * ** * **** *
** * * * ***
** * * * * ** **** **** * *** print the array */
* ** *** **** * *** * * *** sorting: \n");
* * ***** ** *** **** * * i = 0; i < size; i++){
* * * * *** * ***** * **** * * * * *** ", x[i]); * **** *** ** * * *** **** ******* **
* * * ******** * *
** * *** * ** * * * ****** * * *** **
****** *** * * *** * **
* ***** ** *** ** ***
* **** * ** **** * * * **** ** *** * * ** **
* * * **** ** * ******* *** * *** ** **  
*** * * * * ** * 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
*** *** ** * ** ***** x[] = {77,22,88,11,22};
* * *** * *** * ** * ** size = 5;
    
* * * * * *** ** * print the array */
***** * ** *** * ** ** i = 0; i < size; i++){
** * * ** * * ***** * *** * * ***** * * ***** * * * * ", x[i]); *** ** ** * * *** * * ***** * **
** ***** *** * * * *
* ** *** * ** ****** * **** *** * * * *
* * ** * ****** ** ** **
* * * **** ** * ** * ** I need this to happen size-times */
* ** **** ***** * ** * * * *** j = 0; j < size; j++){
*** * ** **** ** * * *** *** ** ** * *** * from left to right */
* ******* *** * *** * ** *** * * * * * * * * * i = 0; i < size-1; i++){
* * ** * *** * * ** ** * * * ** ** * ** * * * * * * * * i-th element with its neighbor to check if they are in order */
* *** *** ** * * * * ** ** * * ** ** ** * ******** ** * > x[i+1]){
* * * * * * ** ******* * ** *** ** * * ** ** * * ** ******** * * * * * ***** * * * *** exchange the values of x[i] and x[i+1] */
* ** * * * * * * * ** * *** ** * * *** * ** **** * **** * ** ** * * *** **** * * * * * temporary; *** ** * * * * *** ** * **
* * ** *** ** * ** ** ** * * ****** * ** * * ******** * * * ** * ***** **** * * * **** = x[i];
** ** ****** ** * * **** * * * * * * * * ** ** * **** *** * * * **** * * = x[i+1];
* ** ** * * * * ** ***** **** *** *** * ** * ***** ** ** * **** * ****** * * * * * = temporary;
* ** * * * * *** *** *** * * ** ** * ***** ****** ********** *
* * ** ** *** *** * *** ** * **
** ** * * ** * *** * *
* ***** * * *
* * * *** **** * ** ** print the array */
* *** ****** ** * ** * * sorting: \n");
** * * * **** * **** ** i = 0; i < size; i++){
* * ** * * ** *** * ** ****** * *** * ** ** * *** ", x[i]); **** * ****** * * **** ** ***
** * * * * * * *
* ** * **** * ** * ** ** * * * **
* * * * ** ** * *** **
** * * ** * * * ****
** **** * *** ** ** * * ** * *** *** * ***
********* ** * * ***** **** **** ** ** *** * *  
** * *** ** ** *** 0;
}
answered by (153 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.59
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37571 - Available when: Unlimited - Due to: Unlimited
| 6 views
0 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Jan 5, 2018 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 41054 - Available when: Unlimited - Due to: Unlimited
| 4.2k views
0 like 0 dislike
20 answers
[Exercise] Fill in the blank - asked Dec 15, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 37578 - Available when: Unlimited - Due to: Unlimited
| 2.1k views
0 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35804 - Available when: Unlimited - Due to: Unlimited
| 3.5k views
0 like 0 dislike
18 answers
[Exercise] Fill in the blank - asked Dec 7, 2017 in Chapter 4: Arrays by nat236919 (5.9k points)
ID: 35798 - Available when: Unlimited - Due to: Unlimited
| 1.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users