3 like 0 dislike
9.5k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 9.5k views

86 Answers

0 like 0 dislike
Hidden content!
#include * ** ** **

int main(){
** ** * * **** *** ** ** a,b;
** **** * ** * * * passed,failed;
** * * * *** ** ** * total;
** **** ***** * *** ***
**** ** ** ** ** ** *** * * ** * * ** * *** *** *
** ** * * * * ** ** * * ** = a+b;
* * * ** * **** * * **** * ** = (float)a/total*100;
* *** *** ** * * * = (float)b/total*100;
** * * * * ** ** * *
* * * *** * **** * * ****** *** ** ** * Ratio: %d%%\n", passed);
** *** * * * * ** ***** Ratio: * ** *** *
******* * * *** * **
***** ** * * ** ** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * ** ** ** * a,b;
** * ** * * *** ** * *** passed,failed;
*** * ********* *** total;
* ** * * ***
* * ** ** ** * **** * * ** ** * * ** * * * ***
**** * ******** *** * * ** = a+b;
* ***** *** ******* * * **** * * = (float)a/total*100;
** ** *** * * * ** = (float)b/total*100;
*** * * * * * * ** ** * *
** * * * **** ** **** ** * * ** * passed);
* ** ***** * *** **** * * ***** *** * ** * **
* ** * * * ** ** *
*** *** ** * ** *** 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* **** ** *** * ******* a,b;
** * * * * * **** * ** passed,failed;
* * * *** * * total;
** * * * **** *** **
** * ** * * ** ** * * *** * ** * * * * ***** * ** **
* *** ** ** * ***** ** = a+b;
* ** * ***** ** * ** = (float)a/total*100;
**** *** * ** ** * ** * = (float)b/total*100;
* * ****** ** *** ***
** * * * *** ** * *** ** * ** * *** ** passed);
* ** ***** ** **** * ** * * ***** *
** * * ** *** * ***
* ** *** * ** * ** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * * ** * * * *** a,b;
** ** * *** * * ****** passed,failed;
*** * *** * * *** * *** *** total;
* **** ** *** ** *
******* ** * ** * * ** * * ** * * ****** ** * **
** **** **** ** ** * * = a+b;
** * ** * ** ** ** *** = (float)a/total*100;
**** **** ** **** = (float)b/total*100;
* * * ** * * ***
* * ** * ** * * * * * * * * * ** ** passed);
*** * * * *** * * ** **** ** *** *** * **
** **** * *** *
*** * * ***** * ***** ** *** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * **** * *

int main()
{
**** ***** * * * ***** *** pass,fail;

* * ** * * ** * ** ** * * * * * * * * * * * * *

**** * * ** *** **** **** **** * *** * Ratio: ** * **** **** **
* ***** *** *** * * ***** ** * * Ratio: *** ** ** **** * ***** *

* * * * **** * * *** * ** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
******* * ***** * * *
int main()
{
* *** *** * * * * * * a,b;
* * *** * * *** **** * ** ** * ** *** **
* * * ** *** **** * ** * ** ** Ratio: * ** ***
* * * *** * * * * ******* *** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** ** * *
int main(void)
{
* * * ** * * a, b,success, fail ;
* * ** * ** ** * * * * * * * * * *** * ** * ** *
*** * * ***** * * *** *** **
* ** ***** * ** * **** **** ** **
** ** ** *** * ****** ** ***** ** ** Ratio: %g%%\nFail Ratio: * * *** success, fail);
** ** * ** * *** *** ** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** * * **** * * *** a,b;
* ** * **** ** ** *** * ******* ****** * * ** ** * **

* * **** * * * **** ** * *** * * Ratio: * ** ** ** *** **
* * ** * ** *** *** ** * Ratio: * ** ** * ***

****** ** * ** ** * ** ** ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * ** ****** * *
int main()
{
***** ****** * ** **** a,b;
* *** * * ****** ** * ** ** ** * * * ** *
** *** * * *** * ** ** * ** * Ratio: **** * * ***********
* *** * ** *** ** ** * ***** * Ratio: %g%%",100*(b/(a+b)));
********* * * **** * ** ** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** ** **** ** **
int main()
  {
*** * *** * **** * * **** * a,b;
* ** *** *** * ** ** * * *** * * ** **** * * * ***
* * *** * ** *** ** *** ** *** Ratio: * * * ** * ** **
*** * ** * * ** * *** * Ratio: * *** *** ** **
*** * *** * *** * * * 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.216.51
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users