3 like 0 dislike
14k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 14k views

86 Answers

0 like 0 dislike
Hidden content!
#include * * *** *

int main(){
** * * *** **** *** *** a,b;
** ** * * * ** * ***** passed,failed;
** * * ** * * total;
* * * * * * * * *
* * ***** * *** ** ** * ***** ** * ** * **** * *
** ** * * * *** * *** * = a+b;
* ** *** * * * * * = (float)a/total*100;
* *** * * * * * = (float)b/total*100;
******** * * * *****
** ** * ***** ** ** **** ** * * *** ** ** Ratio: %d%%\n", passed);
***** ** **** * ** ** * * *** *** ** ** Ratio: * * * ***** *
**** * ** **** **
* * ** * * *** * ***** 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * ******** * *** ** * a,b;
** * *** * ** * * passed,failed;
** ** * * * * * * total;
** ** ** *** * *
*** ***** * ** * * ** *** ** * * ** ** ** * **** ***** * *
*** * ** ** * = a+b;
* *** * ** * **** * ** = (float)a/total*100;
* *********** * ** * * * = (float)b/total*100;
** * ******* * ****** *
* ** *** *** ** * *** ** ** * ** ** passed);
* * * ** *** **** * ** *** * * ** *
******* **** * ** * *** **
*** * * * ** ** * ******* 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * *** * * a,b;
* * *** ** * ** ** passed,failed;
* * ** ** * *** * * * total;
* *** ** * ***** * **
* **** **** *** * ** *** * *** * ** * ** ******* ****** **
* *** * * ** * ** ** * * * = a+b;
** * * * * * * ***** * * * = (float)a/total*100;
* ** * ** * * * * * = (float)b/total*100;
** *** ***** * ** ***
* * **** ** *** * * * ** ** ** **** * ** * * passed);
* * * ** * *** * * *** * ** * * * ** **
* * * * * * ** * *
** * ** ** ** * **** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * *** * * a,b;
** *** ** * ** **** * passed,failed;
*** * ** *** ** * ** ** * ** * * total;
* * ***** ** *****
* * * ** **** ****** *** ** ************ ** * *** *
* ** * * * **** * * * *** = a+b;
** ** *** ******** *** = (float)a/total*100;
* * * ** * ** * ** = (float)b/total*100;
**** * * * ** * ** **** *
**** * * * ** ** **** ** **** * * * ****** ** passed);
** *** * * * *** ** ** * ** * * *** ** * ** *
** ** ** ****** * **
** ** ** * * ***** *** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * **** *

int main()
{
*** * * * ** ** **** * pass,fail;

** ** ***** ** ** * * * * **** * *** ** ** **** **

******* * * ** ** * * * * ** *** ** ** * Ratio: *** * * * *** * * * *
* ** * * **** * ** ** * Ratio: **** ** * ** *** *

* ***** * * * * * * ** * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** * * ** * ****** *
int main()
{
** ** * * * * *** a,b;
** * ** * ****** ** * * ***** **** * * * ***
** * * **** * * ** *** **** Ratio: * *** ******* ** * **
**** ** * ** * ** **** *** **** Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** * * *** ***
int main(void)
{
* * *** **** ** * * * ** a, b,success, fail ;
* *** ***** * **** **** * * * **** ** ***** * * *
* ** * * * ** ** * * * * **** **** *
**** ***** ** ** * * ** ** * *
* *** * * *** * * * **** * * **** Ratio: %g%%\nFail Ratio: *** * success, fail);
** ** ** ** * * * **** * * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
***** ** *** * ** ** * * * a,b;
** * * ***** * *** * ** ****** * * ** ** * ** *

** * * * * * *** ***** * * * Ratio: * * ** * * *** **
* * * ** * * * ***** *** * Ratio: * * * * *** ****

* * ** ** * * * *** * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * ** ***
int main()
{
* ** * ** *** *** a,b;
*** * * * *** * ** * ** ** ** * * *** * * *** ***
** *** ** * ** **** * ** ** * *** *** Ratio: * ** * * ** * *
** *** * ** * * ** *** *** Ratio: %g%%",100*(b/(a+b)));
* ** ** * * ** *** * *** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
**** *** * *
int main()
  {
*** ****** * ****** * * ** a,b;
** ***** * **** * * * * * *** *** * * * * * ** *
* * * *** **** *** ******** * * Ratio: * ** ** * * **
** ** **** * ** * ****** ** ** Ratio: ******* ***** *
** **** ***** * * * 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.205
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users