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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 18.6k views

86 Answers

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Hidden content!
#include *** *** *****

int main(){
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** * * * * *** * * * * passed,failed;
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**** *** *** ** *****
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}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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* ** * ** ** ** passed,failed;
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*** * ** * *** ** * * * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* ** ** *** *** ** a,b;
** ** * *** * * *** ** passed,failed;
* * * ** ** * ** * total;
* *** * ** * **
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* * * * * ** * *** * * * ** * * passed);
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* **** ** * * ** ** **
* * ***** ** * * * * ** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include *** *

int main()
{
* ** * * **** *** * * * pass,fail;

****** * ** ** * ** * ** * *** * ***** ** ** * *

***** * * ** * * ** * * * ** ** *** Ratio: *** * ** ** ********
* * * ** * * **** * * ** ** * Ratio: *** * * ****** ** ** *

** * ** ** * ***** * ** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** ********
int main()
{
*** * ** * ** **** * * a,b;
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***** * *** ** ** ****** * * Ratio: * * ** * ***
* * ** * **** ** * *** **** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* **** ** * * **
int main(void)
{
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** * ******** * ** * **** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** * * *** * ***** ** a,b;
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* ** ** ** ***** ** * *** * Ratio: * ** * ** *** ** *
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* *** *** * * * * * * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
****** * *
int main()
{
**** * * *** **** ***** * a,b;
*** *** ** * * ** *** ** **** ********* *** **
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* * * ** * * * ** ** * ** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * ** *
int main()
  {
*** ***** *** * ** ****** a,b;
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}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
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