3 like 0 dislike
18.5k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 18.5k views

86 Answers

0 like 0 dislike
Hidden content!
#include ***** *** * *

int main(){
* * * *** * * ***** ** ** a,b;
** * * * * *** * * * passed,failed;
* * ** * * ** * *** * ** total;
* * * **** * * * * *** *
* * ** ** ** * *** ** ** *** * ** ** * * * **
* ** ** **** *** * ** * = a+b;
*** *********** **** ** ** = (float)a/total*100;
* **** **** ** * ** * = (float)b/total*100;
* ** * * *** *****
******* * **** *** * *** * **** * * Ratio: %d%%\n", passed);
****** * * * * ** ** * *** ***** Ratio: * * ***
** * * *** * * **
* * *** ***** ** ** * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* *** **** ** * * ** a,b;
**** ********* ***** * passed,failed;
* *** ****** *** ** total;
* * * ** ****** *** * *
* * * ** * * * *** * * * * * * ** ** ** * **** ***
* * * ****** * *** * * * = a+b;
** * * ** ** *** * ** ***** = (float)a/total*100;
* *** ***** * *** ***** * * = (float)b/total*100;
***** * ** *** * * *
* ** ** * * * * * * *** ***** *** * * passed);
* * * ** **** ** * ** *** * * * *
********* ** ******* * *
* * * *** * * * ** *** ** * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** ***** ** **** ** * a,b;
** * * ** * ** ** *** passed,failed;
* * ** ** ******** * ** total;
** * * * ****
** * **** ****** *** * *** *** ** * ** * * ** * * ***
** ****** * * ** * * ** * = a+b;
* * ** ******* * * * ** = (float)a/total*100;
** *** * * * * ** = (float)b/total*100;
* *** *** ** ** **
**** ** * * ** ** ***** * * * ** **** ** passed);
*** *** *** ** * ** ** ** * *** ** **
* * ** * * *** ***
* * ** * *** *** * * ** * ****** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * ** * * *** * * ***** a,b;
** * * ** ** * * * * * *** passed,failed;
* ********** *** ***** * * * total;
*** * * * * * ** *** * *
* * **** * ***** ** * *** *** ** ** ** ** ** * ***** * *
* ** *** ** ** ** ** * ** = a+b;
* * * * * * *** * **** ** = (float)a/total*100;
** * ****** * ** *** ** * = (float)b/total*100;
*** * * *** *** * ***
** ** *** * * * * ** * * ** * * ** passed);
**** * *** * ** * ** *** *** **** ** **
** **** * * * * ***
* * ** *** *** *** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * * * * *

int main()
{
** ** ** * * **** pass,fail;

** * * ** ** ** ** ** * * * **** ** * ** *** * ******

* ** * *** ** * *** **** *** * ***** *** Ratio: ****** ** * * * ** **
** ** * * ** *** * ** * * ** Ratio: * * ** ** ** * *

* ** **** * * ***** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ***** * * *** **
int main()
{
****** *** * a,b;
*** * * * * * **** ** * * * * * ** * * *** ***
** ** * * * * *** * * ** ** ** * Ratio: ***** ** ** ***
** * * * * * * ** * * Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** ** ** ** *
int main(void)
{
*** ** ** * ** * * * a, b,success, fail ;
** * * *** * ****** * *** * * ** **** * * ** * *
* *** * *** * * * ** ********** **
** ** **** ***** * ***** * *
* * * ** * * * ****** ** * * ** Ratio: %g%%\nFail Ratio: *** ** ** success, fail);
** * * * * * *** * ** **** 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* *** *** * a,b;
* * * * ** * * * * * ** *** * ** * ** * *** *

* ** * ** **** ** *** * * * * * Ratio: * ** * * ***
** *** *** **** * * ***** * * * *** Ratio: *** *****

****** **** * * *** *** * ** * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* **** * ** * *
int main()
{
* * * * * *** *** ** a,b;
***** * * * * * ** * * ** * * *** * * * **
*** * *** **** * * * *** *** *** ** Ratio: ** * * * ***
******* *** ** * ** ** * *** Ratio: %g%%",100*(b/(a+b)));
* * ** * *** * * ** *** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** *** * * * ***
int main()
  {
** * * * ** ** * ******* a,b;
* * **** * * **** ** * ** * *** *** * * ** * ** *
* * ****** ** *** * *** * * * * Ratio: * * * *** ****** *****
* * * * ** * * * Ratio: ***** ** ****** *
* * *** * *** *** ** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.65
©2016-2026

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users