3 like 0 dislike
14.2k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 14.2k views

86 Answers

0 like 0 dislike
Hidden content!
#include * * ** *

int main(){
* * * *** * ** ** ** * a,b;
* * * * ** * ** ** passed,failed;
****** *** * * ** * * * total;
* *** * *** * *
**** * **** **** * ** * * * ** * **** * *
* ** * * * ** * * * ** = a+b;
*** * ** * ** * * * = (float)a/total*100;
* * ** ** ** ** * * * * * * = (float)b/total*100;
* ** ***** ** *** * * *** * **
**** * *** ** * * * * * * * Ratio: %d%%\n", passed);
** **** * *** * * * **** * Ratio: ** **** ***
** ** * * * ***
* * ** ***** * ** **** *** * * * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** ** **** ** * **** * a,b;
** * * *** * *** passed,failed;
*** * * ** ** * * * ***** total;
** ** * ** *** ** ***
* * *** **** * **** * * * * * *** * * *** *** ** *
* *** *** * *** *** * * = a+b;
* * * *** *** * *** * = (float)a/total*100;
* * * * * * **** * ** * = (float)b/total*100;
* ** * ** ** ***
* * **** **** * ** * * *** * *** passed);
* * ****** * * * * ***** * * **
* *** *** * * *** *** *
*** *** ** * ******* * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* * ** *** ** *** * * * a,b;
* * * * * * **** * * passed,failed;
*** * *** ** total;
* *** * * * * *** ** *
* *** * ** ** ** *** *** *** ** ** ** ** ** * *****
** ** ** * *** ** * *** = a+b;
*** ** *** * * * * * * = (float)a/total*100;
* ** * *** * ******* = (float)b/total*100;
** **** * **** * ****
* ** * *** ** ** **** ****** ** ** * *** *** passed);
* * * * ***** ** ** * ** * ** * *** * ** *
* * *** * * * *****
**** * * * * ** ** ** * * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** * ** * * ** ** a,b;
* * ** * * *** ** passed,failed;
* * ** *** ** *** total;
*** ** ** ** ** *** ***
* * * ** * ** ***** * * * * * * ** * ** *
***** * ** ** *** *** * = a+b;
* *** * **** ** * ** ** = (float)a/total*100;
* * * * * *** * ** = (float)b/total*100;
* **** ** ** *** *** *
** * * ** * ********** **** *** * passed);
* * * *** **** ***** * ** ** ** * * ***
* ** ** ** *** **
* ** * * ** * * * * * * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** * **

int main()
{
* * * * ** * pass,fail;

** * * ** * ** **** * ** ** *** ** ** ***** ** ***

* * **** * * * ****** *** Ratio: ** ** ** * * *
** ****** ** ** **** * * * * Ratio: * ** *** * ** * ** *

* ****** *** ** ** *** ** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** *** *** *** **
int main()
{
* * *** * * * * * * ** * a,b;
* * ** * * * ** *** *** * ** ** * * * ***
** ** * * * ** **** *** * *** * * Ratio: * * ** * * * * *
* * *** * ** ** *** * * * *** Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** ** * * **** *
int main(void)
{
** * * ** **** * a, b,success, fail ;
**** * * * *** * ** * *** *** * * ** * ** * * ** * ** *
* * ** * ** * * ** ****** ** ****** ***
****** ** * * * ** * * * ******** *
* ** * * * ** * * ** * **** Ratio: %g%%\nFail Ratio: ******* * ** success, fail);
* **** * ** ** * * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * ** ** * * * * * a,b;
* * **** ** *** *** ** ** * ** * * *** ***** *

* * *** * *** **** *** * ****** ** ***** *** Ratio: ** * * * * **
* * * *** ** * * ** * * *** * * * Ratio: * * **** * ** *

* * * **** * * ** **** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** ** * ** *
int main()
{
** * * * *** *** *** * *** a,b;
* ** *** ** * *** * **** * *** * * ** ** *** *
**** * * ** ** * ** **** ** **** * * * Ratio: * ** * * * * * ****
* *** * * **** * * * * * * Ratio: %g%%",100*(b/(a+b)));
* ** *** ** ** * * * *** *** 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * * *** **
int main()
  {
** * * *** * **** * * a,b;
* ***** *** ** *** * * * ** * *** ** *** * ** *** * **
**** ** * * * ** ***** * ** *** Ratio: * * * ** ***** * **
* *** * * ** * ****** * * Ratio: * * **** * * *
*** * * *** ****** ** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.53
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users