3 like 0 dislike
12.9k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.9k views

86 Answers

0 like 0 dislike
Hidden content!
#include *** *** *

int main(){
* ** ***** ** * **** a,b;
** *** * * * ** ***** *** passed,failed;
** ** ******** * * ** ***** total;
* ** ** * * * * * *
** *** * ** **** * ** *** *** ** * ** ** * *** ***
***** * ***** ******** * = a+b;
* *** * * ** *** ** * = (float)a/total*100;
* ** ** * ** * *** * * * ** = (float)b/total*100;
** * *** * * ******
** ** **** ** * ** ** * * ** Ratio: %d%%\n", passed);
* * *** * * * ** *** ** ** * * Ratio: ** ***
* * ** *** ** * **
* * ** ** * ** ** *** * 0;
}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
*** * * ***** * * a,b;
** ** * ***** * ** * passed,failed;
** * * *** *** * * * * *** total;
* ***** * * * ***
* *** ** * * * *** ** * ** * ** * **
* * * *** ** * ** * = a+b;
* * * ** ** * * *** * = (float)a/total*100;
* ******** * *** ** * * = (float)b/total*100;
** * * * ** * * * **
** **** * * *** ** ***** ** * ** * * passed);
********* **** ******* * *** ** *** *** *
* * * *** * *** ******* * * * *
** * **** * * * * * 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
* ** * *** * * * **** a,b;
** * * ** ** ******* * passed,failed;
*** * *** ** ***** total;
** ** *** **** ** ***
***** * * * ** ***** * ** * **** * * *** ** * * ****
* * * *** ** * ** * = a+b;
* **** *** ** * **** = (float)a/total*100;
** * * * * * *** = (float)b/total*100;
* * ** * *** * *** ** *
* ** ** ** * * * * * * * * * passed);
* ***** * * * **** * **** ** * ** * *
* ** ** ***** * ** *
* ** * * ** * ** ** * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ** *** ** ** * ** *** * * a,b;
* **** * * **** * ** **** passed,failed;
** ** * ** *** ** * *** total;
** *** * * * **
** **** * * * ***** * * *** *** ** * * ** * *** **
* * * * * * ** * * = a+b;
** **** * * *** ********* = (float)a/total*100;
*** * * ** ***** * ** = (float)b/total*100;
***** * * * * * * ** **
* ** ** * * *** * * * ****** *** * * ** *** passed);
* ** * *** *** * ** * ** ** * * *****
* ** *** ** * ****** *
* ** *** * ** *** * * ** * * 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** * * *

int main()
{
** * *** * * * * *** pass,fail;

** **** *** * ** * *** * **** * * * * * * * ** ** * ** ** *

***** ** * ** * ** *** ** *** * Ratio: **** * * * * ** * * * **
** **** * * * ** * ** ** *** * Ratio: ***** ** * * **** ***

**** * * * * ** 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** * ** * * *
int main()
{
** ** **** ** * * a,b;
* ***** * *** ** * * * *** * ** *** * * ** * ** *** **
** * ** * ** * * ****** * ** * Ratio: ** * ** *
* * *** * * *** * * * ** * * **** ** Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** * ********
int main(void)
{
** * * ** * * ***** * * ** a, b,success, fail ;
** **** * * ***** * ** * *** * *** ** *** ** ****** *
* * * * ****** *** ***
***** * * * * ** ** ** * *** **
** * * *** **** * * *** * ** ** Ratio: %g%%\nFail Ratio: ** ** success, fail);
** **** * **** * * * * 0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
* * * ** * *** ** * ** * a,b;
** * * * ** ** **** * * * * * * * ****** * * *

* * * ** * ** * * *** * ** * Ratio: * *** * * *** ** **
** * ** ****** *** * * **** Ratio: * * *** * *** * *

** ** * *** ** ***** * ** 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
**** ***** * *
int main()
{
* * ** * * * ** ** * a,b;
** *** **** * * * * ** *** * * * * ** * ** * ***** ** *
** * * ** * **** * * ** * * * * *** Ratio: * **** * *** **
**** * * * *** * * * * *** * * * Ratio: %g%%",100*(b/(a+b)));
* * *** * * * ** * * ** * 0;
}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
***** * * ** *
int main()
  {
* ** * * * * ** * ****** * a,b;
* *** * ** ** *** * * * * * ** *** * * * ***
* * ****** * * * ** ** ** * *** ** * ** Ratio: * ** * *** *
* **** * **** ** ** * ** ** Ratio: * ** ** ** * *** *
* * * ** * * ** * *** 0;
}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:108.162.241.240
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users