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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 9.5k views

86 Answers

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Hidden content!
#include * * **

int main(){
* * * * *** a,b;
** * * *** * * * **** *** passed,failed;
* * ** ** ** * * ***** total;
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}
answered
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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** ** * *** *** ** passed,failed;
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*** * * * ** * *** *
*** ** * ** ** * *** * ** 0;
}
answered
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
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}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%d%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main(){
** ** ** * ** * ** * * a,b;
* * *** ** ** * * passed,failed;
***** * * total;
***** * **** **
* * * * ** ***** * **** * ** ** *** * ** ** * ** ** *
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* * ** * ** * * * ** * *
* ** ** ** ** * *** * ** 0;
}
answered
0 0
prog.c: In function 'main':
prog.c:13:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n", passed);
                ^
prog.c:14:16: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("%g%\n",failed);
                ^
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include * ** ** *** * *

int main()
{
*** ** ** *** *** *** *** pass,fail;

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* * * * ** ** * *** ** Ratio: * * * ** ** ** **
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** * ** * * ** * 0;
}
answered by (-16 points)
edited by
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
             ^
prog.c:9:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d %d",&pass,&fail);
                ^
0 0
Case 0: Correct output
Case 1: Correct output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * ** * ***
int main()
{
***** ** * * * * ** a,b;
* *** * * *** ****** ** * **** * **
** * * * ** ** **** ** *** * Ratio: * * ** ** **** *
* ** *** * ***** ** ** * * ** **** Ratio: %g%%",(b/(a+b))*100);
}
answered by (-214 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** ** ********
int main(void)
{
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}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>

int main()

{
** * * * * *** * *** a,b;
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* * * ** ******* * **** * *** ** Ratio: ** ** *** * * **

** * ** * *** **** *** * 0;

}
answered by (-249 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ***** ** *
int main()
{
* *** * * ** * * a,b;
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}
answered by (-329 points)
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** **** *** ***
int main()
  {
** * * * ** ** ** * * a,b;
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}
answered by (-329 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
             ^
prog.c:5:15: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
     scanf("%d%d",&a,&b);
               ^
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