第二次期中考 -3 稀疏矩陣

6 like 1 dislike
2.6k views
如果在矩陣中，多數的元素並沒有資料，稱此矩陣為稀疏矩陣（sparse matrix），由於矩陣在程式中常使用二維陣列表示，二維陣列的大小與使用的記憶體空間成正比，如果多數的元素沒有資料，則會造成記憶體空間的浪費，為 此，必須設計稀疏矩陣的陣列儲存方式，利用較少的記憶體空間儲存完整的矩陣資訊。

在這邊所介紹的方法較為簡單，陣列只儲存矩陣的行數、列數與有資料的索引位置及其值，在需要使用矩陣資料時，再透過程式運算加以還原，例如若矩陣資料如下 ，其中0表示矩陣中該位置沒有資料：

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

這個矩陣是5X6矩陣，非零元素有4個，您要使用的陣列第一列記錄其列數、行數與非零元素個數：

5 6 4

陣列的第二列起，記錄其位置的列索引、行索引與儲存值：

1 1 3
2 3 6
3 2 9
4 4 12

所以原本要用30個元素儲存的矩陣資訊，現在只使用了15個元素來儲存，節省了不少記憶體的使用。

 

請寫一個程式用上列的方法壓縮稀疏矩陣。

 

輸入說明：

一開始會輸入兩個正整數M N，代表矩陣的大小。接下來會有M行，每行N個數字。

 

輸出說明：

請輸出壓縮過的矩陣

 

輸入範例：

5 6

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

 

輸出範例：

5 6 4
1 1 3
2 3 6
3 2 9
4 4 12
[Exam] asked in 2017-1 程式設計(一)AD by (18k points)
ID: 36176 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00 | 2.6k views

6 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(void)
{
    ***   *      * ** A[m][n];
*    ** *  ** ** **** *  *  *  * *  **  *    ***** **    
 ******* ** **** ** ********     *   *  *** ***   *  * **
**  * * **      ****  ** *
****  ***   ***  ** *   
 * ** **      **   *  *** **
* ******* ** ** ***  **  *** ***
   *** *  * *    ** * *    ** **  * **  * *   ** **
   *  *** *  *  ** *    *  *** 
 **** *  ***** * * * * * * * *****  *   * *** ***   ** 
 **   **  *  *** ** ** *   
    
    return 0;    * ***** ***     ** **** *  * *    ** ** * **** **** *
 }
answered by (144 points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
    
  ** * *  * *   * * **   a,b,x,y,i=0;
 *     ****   * ** *******   ** *     %d",&a,&b);
    
*  *   ** *  * ** *    *         ch[a][b];
    
**  *******  *** * * ** *** * *  *  *   * *
*** **** **   *****    ***  ** ** *  ** *  * *  *      ****   *   
** *** * ***  *        * ***   * * **  *       ****  **** ** * * ******    *** * ** ***  * *  * *****  ** *  ***  *
 *     * ** **   **  * ***  *****  **** *  **  * **  * ***   ******   *
*  ** * ****    *   *   *** *        **  **  * *   **     ** *    *  * *** *  
**  * *******   **  *  **** **     *   * *** * *** * * ***  *  **  
**  *** **  ** * *** *  *  *  *      **    ***  *****
  ***  * *      ****  *  * *      * %d %d\n",a,b,i);
****   *  ***  * **   **  * *   **  **
*    * *   *   * ***** ****            *  *** *** **  * ** **    
 ** ***** *  *** ****  * * * **  * * ** *    ***  *   *   *** *** **  ***  
* *****     *  ***** ** *  **   * **** ***  *  ** ****   *  * **           %d %d\n",x,y,ch[x][y]);}
 ******   * ******     ***  ** ***  ** ******* *** ****  *** * *  ** 
 * ** * **   *  **  ***   * *  *  **   *** * 
 **  **  * * ****   ** *  **    *    ** system("pause");
}
answered by (192 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
 *** *  * ** *    **  *
answered by (131 points)
0 0
/usr/lib/gcc/x86_64-linux-gnu/6/../../../x86_64-linux-gnu/Scrt1.o: In function `_start':
(.text+0x20): undefined reference to `main'
collect2: error: ld returned 1 exit status
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***** *** ****  *   
int main ()
{
**   *** **** * ***** ** * M,N;
 *  **** *  *  *    ***   *    * * * *   **  ***** *
*  *  **      *  **   *   **      *  * %d",M,N);
 *  ***** ***  **     ***  
*  *  ********  *     ** 0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
    int row,col;
    while(scanf("%d %d",&row,&col)!=EOF)
    {
* *     **   *      *** ***  **   ** *  *     * ** *  ** *  array[row][col];
  ** **  **       **  **  * * * * **  ***     **** * * save[row*col][3];
**  * * * * ** * ** ** ***   *  *  ****  * * *  **  * ** *  **** *** i,j,count=0;
 **   *  ***      **** ***  ****   *****  ** ** * ***  *  * ** *   * *  ***
        {
 *   *** * * ***  * * * *** *    ** *** *   *   * **   **   * *    * **  * *   **        ** *****  *   
 * *  * *** * ************ *** *** *    **  **  *    ** * *** **** **   * **** ****  * ** *** *****  *     * *     * **  *** ** * **  *   *    ***** 
        }
  **      * *    * ***   *   * * * *   **** *  *    *   *    ****  *
        {
* * * **** *  *** ** **   **  ****  ** *   **     * * **  **  ** ***      ****  *   * ** *****    *** **** 
 **  **      * ****   * **  *  *  *** **     ***  *   * *  *  **** ***  *  * * *  *   
****   **  *****   ***  ***  ** *   ** **   ** *******    ** * ***     *** * ***  *    *  **  * **      * **  ***** * ** 
  *  **       *  *       * * *   * *  *  *  *   **  ** * *** * **  ** **  * *    *  * ** *  *  * 
*  * **  ***    * **     * ** ** *  * ** ** ** * ** ** *  * *  ** * *   * *  * ***  **  *    * ** ***** * ***    **** ** *   ** * **  ** **
* *******  *  **  * ******* * *     * * *** *   **      ****** * ***  *  * *  * *  * ****    ** ****  ***   *    **    * ** *  * *   * * ****  ******* ****** 
*   * **  *   *  * *** ** ****     **** *  *   * **** **  *   ***** *   **     * ***   *** **** * *** ** * * *  * *** *** *** * **** * *****   *****  ** 
* *** ** *   *** *    *  * *   **   **  * * ****   * * *    **   **** *    **   * *     * ****  **** **     * *****  **** *  *** * * ** ***  **
  **   *   ** *  ** * *    **** **** *    ** ***    **   ** ***  * ** *  *    *  * *    *** *  ** *   * ** *
 * **  ******** * *  *******   * *  *  *** *  * * **** ** * * **   ** ** **** ***    *****
  * **  *    ***   * *  *     * ** * *** **** **** *  *
******   *        *****   *     * ***  *** * *   ** ** **  **** *  *** %d %d\n",row,col,count);
  **  **** * *** *   *       ****  * *     * ** *  * * *** *    **  *   * **
        {
 ***    *  *      **        **  *** * * *  ***  *      * ***** *   *  ** * ******* ****  **** **  *    *  
 * * *** **   ***  ***  ** * **  ** * **  * *   *  * * * *     * * **    *   * * ***  *************       *  ** ***  **** *     * ****  *  * ** *****  ",save[i][j]);
   ** *  ***** *** * ****  **   ***   ***  *    * *****  * ** * *  * * *   *  * *** * **    ** *****  
*   ***   ****   * ** **** *** *  ****      ***   * 

    }

    return 0;
}
answered by (114 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before numeric constant
 0 0 0 0 0 0
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
* *   * **  **  *  ** **  *  * *  *  a,b;
**  ***** * **** **    *   *  * ** * *   %d",&a,&b);
    *   ** ** *  ** *******  ** arr[a][b];
    int i,j,count=0;
 * ** *  **    **    * *** **  *   **  * *  
    {
 ** *** *   ***   *  ****       **      *  **  **     **     ***  *  *****
** *  * *  * **** **  *   * *   ** *   ****   * *  *  
******** *    ** *** * **  *     ** **  ** ** **   * * ** ****  * *   * *   **   ** *  ** * * **  ***  *** *
* *   *  *  ****  * **    *  *  **  * *** *      ***  ***      *   * *** *  *  *   *  * * * *  ***** *****  **
 *       *******  ***** **     ** ****    * * ***
    }

*    ** *     * ***** **   ***** ** ****
    {
 ****   * *  *** * *** ****   * * * *   ** *   ***   **** *** * **  * 
   ** ***  * ** *  * **  ***    *** ******* *   ** *
*** ****  **   ** ** *** ****  ****  ** **   ** *  **  **  *  *     *   * *  * **    *** 
*   **       ***  *** * *         ***  ********** ** ** **   *        *  * ****** *     *    ** * * ****  *****  * 
      *** ***  *  ***  *  **   **  *****      *
    }
*   *   ******   *** ** ***    ***     %d %d\n",a,b,count);
  ** *  **** **  * *   * *** ****  **   
    {
   *** *    * * * * * * *     **  ******* * **   **** *** *** **  * **
*   **** *  ** ** ****   ***** *** *   *  * ****     
  *   * *     *   ****         *** **    ** ** ********  *  * **  ***** * * * ***    * ** * 
  *** *      *  * *  **   ***   **  **  ****** ***  *  * **   * * * ** **  * * *****   **    *** ** *    * **   * *** ****      ** * %d %d\n",i,j,arr[i][j]);
 ** ***** * *  *  **   *  * ** ** *  *  ** * ******   
    }
***** **     *   * ****    * *  0;
}
answered by (100 points)
1 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.197.64
©2016-2026

Related questions

3 like 0 dislike
5 answers
第二次期中考補考題庫 -3 稀疏矩陣
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38153 - Available when: Unlimited - Due to: Unlimited | 2.4k views
2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.9k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 7.6k views
12,783 questions
183,442 answers
172,219 comments
4,824 users