第二次期中考 -3 稀疏矩陣

6 like 1 dislike
2.1k views
如果在矩陣中，多數的元素並沒有資料，稱此矩陣為稀疏矩陣（sparse matrix），由於矩陣在程式中常使用二維陣列表示，二維陣列的大小與使用的記憶體空間成正比，如果多數的元素沒有資料，則會造成記憶體空間的浪費，為 此，必須設計稀疏矩陣的陣列儲存方式，利用較少的記憶體空間儲存完整的矩陣資訊。

在這邊所介紹的方法較為簡單，陣列只儲存矩陣的行數、列數與有資料的索引位置及其值，在需要使用矩陣資料時，再透過程式運算加以還原，例如若矩陣資料如下 ，其中0表示矩陣中該位置沒有資料：

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

這個矩陣是5X6矩陣，非零元素有4個，您要使用的陣列第一列記錄其列數、行數與非零元素個數：

5 6 4

陣列的第二列起，記錄其位置的列索引、行索引與儲存值：

1 1 3
2 3 6
3 2 9
4 4 12

所以原本要用30個元素儲存的矩陣資訊，現在只使用了15個元素來儲存，節省了不少記憶體的使用。

 

請寫一個程式用上列的方法壓縮稀疏矩陣。

 

輸入說明：

一開始會輸入兩個正整數M N，代表矩陣的大小。接下來會有M行，每行N個數字。

 

輸出說明：

請輸出壓縮過的矩陣

 

輸入範例：

5 6

0 0 0 0 0 0
0 3 0 0 0 0
0 0 0 6 0 0
0 0 9 0 0 0
0 0 0 0 12 0

 

輸出範例：

5 6 4
1 1 3
2 3 6
3 2 9
4 4 12
[Exam] asked in 2017-1 程式設計(一)AD by (18k points)
ID: 36176 - Available when: 2017-12-08 18:30 - Due to: 2017-12-08 21:00 | 2.1k views

6 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main(void)
{
***** * *  **** * * *** **  *   A[m][n];
* *   **  * * * **     * ***** *** ***   *    **  ***   * *** *
*  *    * *** * *  **** ** ** *   *** * *   *   *     *** *
*   **  * *    *****     ** 
**  *   * ***      * ***  ***
  *       **   *  *  *  ** *
**     *  *  **   *  *
 *** *****   *    *    *  ** * **    *  ** ** **  
 ***** **        * *     *** *
 * ** ** **  * ** *** *****  * ** * *  * *    **  **
** **** *** **  ***      *** ** 
    
    return 0;     * **  **  ** *     **** *  ****   *  *  **  *  **
 }
answered by (144 points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:4:11: error: 'm' undeclared (first use in this function)
     int A[m][n];
           ^
prog.c:4:11: note: each undeclared identifier is reported only once for each function it appears in
prog.c:4:14: error: 'n' undeclared (first use in this function)
     int A[m][n];
              ^
prog.c:11:23: error: expected expression before ')' token
     printf("%d%d%d\n",)
                       ^
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main(){
    
 **  *  *   * **  *** *    *** *  a,b,x,y,i=0;
 ** *   ** * * *     *  *    ** %d",&a,&b);
    
 **      ****  **  ****  * ch[a][b];
    
 * * ** *  **   **** * ** * *  * * * * *      
*  *  *  *     ** ***** *   * *** *****  ***  **   *    *  *  
 **** *   * *   **   **** *  *** *     ** * *  ***   * * *   *   **   ***  *  *** ****    * * *  *** ** * 
*  **  *  *****   *   *  *  *     *** ** *  ** *  *******  *  *****   *** ***** ******* 
  * *****  *    *  * *    *     * *  * * *    **   *   ****  *  *** **  **
* * *   ** * *       **   *** *  ****   * *   *  *  *  ** *  *****  
   *  * ** * * *  *   **  * **   *  ***     
**  * **  * *     ** * * ****  * *  * **  *   %d %d\n",a,b,i);
 ***     *** **   * ***           **  
*  ***** ****    * * **  **  *      ****    ***** * **** * * 
* **** *  *   ** ***  **  ****    *   *    *  *     ** ***** *****   **** ** * * * 
*   ***  **   ** * ** *    *******       ***  **  *  ***  *       * **   **** * %d %d\n",x,y,ch[x][y]);}
* ** * ***    **   ** * *    **    * ***      ***  **  * * ** ********
  ** **  *   *   ** *      * * ***   *  **    *
*   * *** *** **  * * ** ** *  ****  system("pause");
}
answered by (192 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *** **  **  *  *  **
answered by (131 points)
0 0
/usr/lib/gcc/x86_64-linux-gnu/6/../../../x86_64-linux-gnu/Scrt1.o: In function `_start':
(.text+0x20): undefined reference to `main'
collect2: error: ld returned 1 exit status
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
***     * * * *     
int main ()
{
 * *  **  *   *** *  * *** *  M,N;
** **   ** *   *    **   ****  *  * * **     * ***  **  ******* *  *
*  *  * ** ** * *  *  * * ****   * *  %d",M,N);
***  ***** * **** **** 
 * ** ***     *   *   ** ** *  0;
}
answered by (215 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>

int main()
{
    int row,col;
    while(scanf("%d %d",&row,&col)!=EOF)
    {
* * ** *  *  *   ** * ** * * * ******* **  * *  ***      array[row][col];
   ** *   **   ** *      **  *   *** * * *** *    *** *   ****     save[row*col][3];
  * ***  ****  *  *  **     ******   * ** *  *  * *     **   i,j,count=0;
 *  * *****  *** **     *     ****  **   *   *  ** ** *          ****  * ***
        {
**  * **    **  * ** **  *  * *     *    ** * ** ** **** *  ** **    ***** ****  * ******* ***   
  *** **  *****    ** * **   ***** * * * * *** **** ***   * ****  * *  *  ******* * **  *** ***  ** *   * ** * * *      * * **   ** **** * * * *   **
        }
***   ***  *  ***      ** **** **   * *     * *  ** *  **  ** ** *** *
        {
* *    **   **  *  ***  **  ***  * **** ** ****** * *  ** *  **** **  * **  ******  ** * * **  ** **
*         * * ***   **   * *  ******** * ***** *******  *    ** ***** *    * *    *  *  
 *    *   **** * *   * *   *** *  *****     *   *******  *  *  ****    ***  *** *** **  ***    ** *****   
 ** *       **    * *** *    * **   *    ** ** ** ***    *    *   **   * *   *   *  *   *     *** *      
  **  * ** ** *  *             **  *** *   ****** * *  * **** ** * ******** ** ** *  **   *  * **   *  * **** *****     * **   * 
*****      * *  ** * **    ** *** **   ***  ***   *   *     *   ** *   *****   *   * ***  ***  **   * *** * *    ***** ***  ** *  ****    ** *  *
**    **  **        ****   ** **** * *****   ** *  *  *** ** *    *  **  *  * ** *****   **  *   **   * * *   **   *  **** * * ******* *   **** ***    * * *
  *  *  * *** **   **    ******* **  * * ****** **  ** *******  * * *   **   *   ***  *  ** *** * ***  **** **    ** *** * **** ******** 
   *** * * * * ** ** *** * * ***  * ** *  *   *** ** * *    * **** * *    *** * *    *      ** ** * *  *   *  ***** *
**  ** *  ** ** *** * *   ***** ***  ** * * ** * * *  ***      ***** * ** ** * * * 
 *   * ** ***  ****    *  ****  * *  *  * *   * * ** **
*    ***  ** * *     ** **   *      *  *****  ***  ********  %d %d\n",row,col,count);
  **  **      ***** *   *****  * ****  * *     *** **    *  ** ***   *  * * **
        {
*** *   * ****** *   *  **   **  * *  ** **     ****** **      *  * ***** *   ** *  ***  *
     ***** ** *** ** **** * *** *  ** *  *** *****  **   *** *****       *     ** * **  * **    * *    *** ****  * * **  ** *  ***   ** **   **      ** ** *  ",save[i][j]);
*    ** * *  ** **  *  * * * * ** *   * *** *  ** **** * * *  * **  * ****  * **  ** *  * * ***  ****  *  ***  
*** * *  ***  ***  *  * * * * *  ***      **   * * *****  

    }

    return 0;
}
answered by (114 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before numeric constant
 0 0 0 0 0 0
 ^
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
int main()
{
*    **  * ***    ****   **  ****  a,b;
  **  ** *****       * ***** ****   ** *   %d",&a,&b);
 *  *   * *** * * ** * * * arr[a][b];
    int i,j,count=0;
   **   *** *    *   *  ** ***  **** ****  * *
    {
  *  *     *  * *** ** **   ** *** **  * ** *   **  ****** ***** **
** ** *  * **  *  * * ***   ***** *  ** * *   ** **  *     
 *  **** ****** * *** *   *    * *  ** ****      *    * **  ***  *  *  ** **   *     ** **** * 
  ** ** *   * *  * ******* * *  *  * **** **     **   **  ***     *  **** * **  ***** *** *** *  * ** **
 ** *  *   ** * **     * *     *****   ** *  *** * 
    }

*  * *   *    *****    ** * *   ***  * *** * 
    {
* *     ****    * *** * ** *  * * ** ******* ** **  * *   ***   *  *    
  ** **** *****  *****   * *    ** *  * *** *   *** ***
 *  * ** * *** * *** *  ** *** * **  ** ** **  **  * *   * **    **** ***** *   *** ***  * 
* **** *  *  ** **  **  ** **** ****    * * **   ****      *   ** * * *** ** ***  ** **    *  * * ** *   **  ** * *  *
***   * *******  *  ***     **    *** *********  ****** **
    }
* ** ***** * * *    ** *  * * **  *   %d %d\n",a,b,count);
  **  * *   ** * *       ***   *  * *  * **  
    {
 *** **    *****     * ****  * * *   *  ***  ***  *         * * ** 
 * *   *  * ******* * *** ** *    *  ***  **
 *** *   * *  **   *   *** * * ****** *** *  ***  * **   **      *** ***      * *   **  **   *  *
 *******     **    *  *  *   *** **    ** *  *  *  ***  ****  ** **    ** ** *  ****    ***        *** *** **  * *  *  *  * *  %d %d\n",i,j,arr[i][j]);
*** ****  *  ******** ***   *  ****  *  *   * * *  ** 
    }
*      ** *  *  * * * ******* *  0;
}
answered by (100 points)
1 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.67
©2016-2025

Related questions

3 like 0 dislike
5 answers
第二次期中考補考題庫 -3 稀疏矩陣
[Normal] Coding (C) - asked Dec 20, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38153 - Available when: Unlimited - Due to: Unlimited | 1.8k views
2 like 0 dislike
5 answers
第二次期中考補考-第五題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38942 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 2.2k views
2 like 0 dislike
18 answers
第二次期中考補考-第四題
[Exam] asked Dec 23, 2017 in 2017-1 程式設計(一)AD by 楊修俊 (30k points)
ID: 38941 - Available when: 2017-12-23 09:00 - Due to: 2017-12-23 12:10 | 6.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users