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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * ** * * * * x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
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if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include * *** * * *
#include ** * * * ** * *
int main()
{
* * * ** * * num;
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}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
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** * *** * * ** *** 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include * * ***
* * * * * * *
int main(int argc, char *argv[])
{
*** * ** * ** * ** * * i,j,n;
* * * * * * ** * ** ** k;
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** * ** ** ** * if(n *** 1170000)
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* * ** ** ***** * * * * ** if(n * * * 2350000)
* * ** * *** * * ** **** ** * * ** ** = (n - 1170000) *0.2 + 26000 + 78000;
* * ** * *** * *** * if(n ** 4400000)
* * * * * ** * * * * ** * * * * * **** * * = (n - * * * *0.3 + 26000 + 78000 + 236000;
* * * * * * * ** * * if(n * * ** *
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* * * * *** *** * ** ** ******* 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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-216
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Hidden content!* * * * * ** * * *
int main()
{
* * * ** * * A,B,C,D,E,F;
*** *** ** *** * * *
*** * * ** * (A<=520000)
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* ** ** * * * ** * ** *** * *
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include * * * ** **
#include ** * * **
int main()
{
**** * * * ** * * * * ** num;
* ** ***** * * * ** * * * * * * &num);
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* ***** * * ** ** **** * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content! *** ** **
int main()
{
* * * * * * A,B,C,D,E,F;
* * * *** * ** *** * * * * * **
if (A<=520000)
* * *** * * *
* * * ** if (A<=1170000)
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** * *** ** * *** * if (A<=2350000)
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** * * * * * * if (A<=10000000)
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* * * *
** * * * ** *** ** *** ** * * *** * ** * ** ** * ** ** * *** * * ** ** * * * ** **
* * * * * ** * * * * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
** ** * ** * * * * *
int main()
{
* * * *** * ** * i;
* * *** ** * * * * a;
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{
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{
* * **** *** * ** *** * * * ** * * * ** 470000;
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}
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{
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* * * * * * ** * * * * * * * * *
}
* ***** * * **** * * ** 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * ** *** * * ** * ** * ** * * * * **
* * *** * * ** ** * * ** *** * ** * **
** * *** ** **** ** ** * * **
* * * * * ** * * *** if(in<1170000)
* * * ** ** * ** ** * ** * * * * *
* ** ** * * * ** ** if(in<2350000)
* * * * ** * ** * * * * ** * * ** * ** * * * ** ** *** * *
** ** * * ** *** * * * if(in<4400000)
* * * * * * *** * *** ** * * *** * * * * * * **
** * ** ** * * ** ** if(in<10000000)
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** ** * * * * * * * ** ** ** * ** ** ** * **
* **** *** * ** * * * *** * * * * ** * ***
* * ** ** ** ** *** * * ** ** * ** 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
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ID: 15448 -
Available when:
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AD 20161027 期中考 9
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2016-1 程式設計(一)AD
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(
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ID: 15445 -
Available when:
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AD 20161027 期中考 8
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AD 20161027 期中考 7
[Exercise]
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
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