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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * ** ** **** * * * * * * * * x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * ** * * * * ** *** ** ** * * *** * *** * ****
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
(
-202
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Hidden content!#include * *
#include ** * * * * * * *
int main()
{
* ** * * * * * * * num;
** * ** *** * *** * ** ** * ** *** * * &num);
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}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* ** * * * * * * ** * * i=0,
** * * * ** * * * * * * * * * ** * * * * * ** ** **
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* * * * * * * * * 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include ***** *
** * * * * * *** *
int main(int argc, char *argv[])
{
**** ** ** * ** * * ** * * * i,j,n;
** * ** ** * * * * * * *** k;
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** * ** * * * *** * * * * ** ** ** * ***** * * ** * = n*0.05;
* * ** * ** ** * ** * ** if(n * * 1170000)
* * * ***** * * *** *** ** * * * ** **** * ** * *** * = (n - 520000) *0.12 + 26000;
** ** * * * * * * ** ** ** * if(n ** 2350000)
* ** * * * * ** * ** * ** **** * ** **** ** * * * * = (n - 1170000) *0.2 + 26000 + 78000;
* * * *** ** **** * * * if(n * ** 4400000)
* * * * * ** * * * * * * * * * * ** * *** * *** ** *** = (n - *** *0.3 + 26000 + 78000 + 236000;
** * * * * * * **** if(n * * * *
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** * * **** * * * * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content!** ** ** *
int main()
{
* * * * A,B,C,D,E,F;
* ** ** * ** * * ** * * ** * * ***
* * * * *** * (A<=520000)
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****** ** ** *
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* * *** ** *** * ** * * * ** * * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * * *
#include * * *** *
int main()
{
** * ** * * ** num;
* * * * *** ** * * * ** * * *** * * * &num);
* ** * * * * *
* ** * ** * * * * >= 10000001)
* * * * * * * *
* * ** ** ** ** * ** * * * * = * * * * * * * * 0.45;
* * * * *** * * *
**** *** * **** * * * if (num >= 4400001)
*** * ** ***
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** * ** * * * ** *
** * * ** * * ** * * if (num >= 2350001)
** * * * * * * *
** ** * * * ** * *** * * ** *** ** = ** * ** * ** * ** * *0.3;
* ** ** * *** * * *
** * ** * ** * * ** * if (num >= 1170001)
* * * * * * *
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** ** * * ** * * *
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*** * * * *** * **
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**** ** * *** *
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* * * * ** ** * * ** ******** * *** * * * num);
** * * *** * ** * ** * ** * * * ** *
** * * * ** * ** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! ** ** * * *** *
int main()
{
* * * ** * * A,B,C,D,E,F;
* * ** * ** * * * *** * ***
if (A<=520000)
* * * * * * * **
* * * *** *** * ** if (A<=1170000)
* * * * * ** * ** ** * ** *
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* * ** ** * **** * ** ** ** ** * * * * * * * * *
* * * * * * * if (A<=4400000)
* * * * ** **** * * * * **** ** *** ** ** * *** **** *
* * * ** ** *** * if (A<=10000000)
* * * * * * ** * * * * * ** * * * * ** * * * * * * *** * ******* * *
* * * ** ** **
** *** * * * * * * *** ** * * * * *** * * * * * * * * * * *** ** * * ** ***** ** * * *
* * * ** * * * * ** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * ** * **
int main()
{
* * * * ** * * * * i;
* * * ***** ** *** a;
* * ** * * * * *** * *** ** ** * *** *
** * ** ** * *** * *** * *
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** * ** * * * *** * *** * * *
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* * * * * * * * **
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{
* * * * * ** * *** * * * * *** ** * *
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** * ** ** *
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* * * * ** * *
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* ** * * ** ** * * * * * * * * * * * *
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{
* **** * * * * ** ** * * * * * 470000;
** ** * * ** * * * * *** ** * * ** ***
}
* * ** * * * if(i<=10000000)
** * ** * *
**** ** ** * ** * * * ** ** * ** ** ** *
*** * *** ** * * * * * * * * *
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* * ** * ** * * *
{
* * * * * **** * ** * * ** ** * * *
* ** * * * * * * * ** *
}
* * * * * * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * *** * * * * * ** * ** *** * * * *** *
* * ** * * ** *** * * *** * *
* * * * * * * *** *** * * * ** *
* *** * ** ** * *** * * ** if(in<1170000)
* * ** ** * ** * * ** * * * * * ** **
* * ** * ** * ** * * * ** if(in<2350000)
* * * ** * *** ** * ** **** **** *** * * * *** * * *
* ** * ** * * * * *** **** if(in<4400000)
* ** *** * * *** * * * * * ** * *** * * * * * * **** *** * ** ** * **
** ** * * * * * * * * * * if(in<10000000)
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* ** * *** *** * * * * ** * ***** * * * * **
* *** * ** * * * * ** * * * * *** ** * **** *
** * *** * * ** * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
1k
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33
answers
AD 20161027 期中考 9
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15445 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
3.9k
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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asked
Oct 27, 2016
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2016-1 程式設計(一)AD
by
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(
18k
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ID: 15441 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
|
2k
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73
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
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ID: 15439 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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asked
Oct 27, 2016
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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