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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * ** * * * * ** * * x=0,i=0;
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*** ** * * ** ** 0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * *** *** * ** * * *** * **** * ** **
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include * ** * * * *
#include * ** * ** ** *
int main()
{
* * * * ** * * ** * * num;
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}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* *** * ** * ** * ** i=0,
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* ** * * * * * * * * * 0;
}
answered
Oct 27, 2016
by
410423016
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-170
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Hidden content!#include * * ** ** * * * *
* * * * **** * ** *
int main(int argc, char *argv[])
{
* * ** * * ** * * * * * *** ** * i,j,n;
* ** *** * ** * * * * * * * k;
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* ** * * * * ** **** **** if(n * ** 1170000)
** * * ** * * * *** * ** ** *** **** * ** *** ** ** * = (n - 520000) *0.12 + 26000;
* * * *** * * * * * * *** if(n ** **** * 2350000)
*** ** *** * * * * * * * * *** **** * * * ** * * ** = (n - 1170000) *0.2 + 26000 + 78000;
* * * * * *** * ** if(n * * * 4400000)
* ** **** * * * * * ** * * * * * * = (n - ** ** *0.3 + 26000 + 78000 + 236000;
*** **** ** * * ** * *** if(n *** **** * *
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* ** * ** * * ** *** * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! ** * * * ** *
int main()
{
* * ** ***** * A,B,C,D,E,F;
* * * * * * * * ** * * * *** * * * **
**** * * * * ** (A<=520000)
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** ** * **** * ** ** *** * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * ** * ****
#include * * * *
int main()
{
*** * *** * * * ** num;
* * * * * ** * **** * * ** ** * ******* &num);
* ** ** ** * ** *
* * * * * * * * ** >= 10000001)
* **** ** ** *
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* ** * ** * *
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**** * * * * * * ***
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** ***** ** * * ** *** * **** * * * * num);
*** * ***** ** * **** * ** * * * * ** * *
* * * *** ** * * * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content!* * * * * * ** * ***
int main()
{
** * * **** * * A,B,C,D,E,F;
* ** ** *** * ** * * * *** * * * *
if (A<=520000)
* * * * * * *
* * * * if (A<=1170000)
* * * *** * * ** ***** * * *** *****
* * * ** * * if (A<=2350000)
* * ** * * * * * * * * * ** * * * * * * *
*** * * * if (A<=4400000)
* * * * * * * * *** *** * *** ** * * * * * *** * *
* **** * * * * if (A<=10000000)
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*** * ** *
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* *** * * * * ** ** ** *** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * * * ** **
int main()
{
* * * * * * ** * i;
* * * *** * * * ** * a;
* * * *** * * * *** *** * *** ** * ** *
** * ** ** * * * * * *
*** * * * * * ** * *
* * * * ** * * ** ** * **
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{
* * * * ** * * ** * ** ** *
* * * ** * * * * ** * * * * * * ** * *
* ** ** * * * * *
** * * * ***** ** ** * * * if(i<=2350000)
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* * ** * **** * * * ** ** ** * ** *** *
* * * * * * ** * * * * * * * * ** * ** *
* * * * * * ** **
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{
* * *** * ** * * ** * * * * *** * ** 470000;
** * * * * ******* ** *** * * * ** *
}
** * * * * * if(i<=10000000)
** * ** * * * * *
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* * ** * ** ** * **
** * * *** *
{
* * * * * *** ******* * **** * ** *****
* * * *** * ** * * ** * * * * *
}
* * * *** * *** ** 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * * ** *** * * *** * ** * * ** ** ** * * * *
* * **** * * *** *** * * * ***
*** ** ** * *** *** ** * ** ** ****
* * * * *** ** ** * * ** ** * if(in<1170000)
** * * ** * **** * ** **** *** * ** **** ****
* * * * * * ** * * * if(in<2350000)
* * * * ** ** ** * * * ** * ** * * * ***** * ** * *
** ** *** * * * ** * if(in<4400000)
* **** * * * * * * ** **** * * * ** * * * * * ** * * * *
* * ** ** * * * **** ** ** * * if(in<10000000)
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** ** * ** * * * * * **
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* * * * ** * * * * * * * * * * * *
* * * ** *** * * ** ** * * ** * * * * * * **
* * ** * * ** ** * * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
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(
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Available when:
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AD 20161027 期中考 9
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(
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ID: 15445 -
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AD 20161027 期中考 8
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AD 20161027 期中考 7
[Exercise]
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
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Available when:
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