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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * *** * ** * *** * x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include ** * * ** **
#include * * * *
int main()
{
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}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
** * * * * * * ** *** i=0,
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* * * * * ** ** * *** * * *** 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include **** * * * *
* *** ** * ***
int main(int argc, char *argv[])
{
* * * * * ** * * * * ** i,j,n;
* ** ** *** * * *** * * * * k;
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* * * * ** * * * if(n * * 1170000)
* * * * * * **** *** ** * ** * * * ** * * *** * * * = (n - 520000) *0.12 + 26000;
* * * ** * * * * ** ** if(n * * * 2350000)
* ** * * * * * * * * ** * ** ** * *** * * * ** ** *** **** ** * ** * = (n - 1170000) *0.2 + 26000 + 78000;
* * * * * * ** **** * * *** if(n * * 4400000)
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** ** ** ** * ** * * if(n * * * *
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*** * * * *** * **** * *
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** *** * * * * *** ** * **** * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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Hidden content! * ** * * * *** *
int main()
{
** * * * ** A,B,C,D,E,F;
* ** * * ** * * * ** * * **
* * * * * * (A<=520000)
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* * * * * ** * * ** * ** * * **
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * ** * * *
#include ** * * *
int main()
{
** * ** * * *** ** * num;
** * * *** ** * * *** * ** * ** * * **** &num);
* * ** *
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* * * * * ** ****
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* * ** * *
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* * * * **** * **
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* ** * ** * * **** * *** ** * **
* * **** * * * ***** 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!** * * ** * ** * ** *
int main()
{
** * * * ** * A,B,C,D,E,F;
* *** * * *** **** * * * *
if (A<=520000)
* ** * * * ****
* ** * * ******* if (A<=1170000)
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* * ** ** if (A<=2350000)
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* * ** * if (A<=4400000)
* * * ***** ** * ** * * * * ** * **** * ** * * *
* * * ** ** if (A<=10000000)
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* * ** *** *** *
* ** ** * ** * * ** * * * * * ** * * * ** * * ** * * * ** *** ******
** * * * * * * * *** ****
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * ** * * *
int main()
{
* * * * * ** **** i;
* ** * * * *** ** ** a;
** *** * * * * * * * * * ** ** *** *
** * * * ** * * * * *** * * * * *
** * * ** ***
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{
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*** * * * **** ****** ** *
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{
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* * * * * *** * * * * * * *
}
* * *** * ** * **** * if(i<=10000000)
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* * * ** * * * * **
{
** * * * * *** * * * * * ** * * **
* * * ** * * * ** * * * ** ******
}
*** * * ** * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
** ** ** ** **** * ** ***** * * * * * **** ** * * *
* * ** ** * * ** * * *** *
* * * * * * * * * * * * * *
* * * * ** * ** * ** * if(in<1170000)
** * * * * *** * * ***** * * * * ** * **** *** **
* * * * * * * ****** * * ** ** if(in<2350000)
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* * * * ** ** *** * ** * * ** ** * * * * * * *** ** * * * *
* * * **** * ** * * ** if(in<10000000)
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***** ** ***** ** * * * * ** * * * * * * ** ** * **
* * ** * ** * ** * * * * * ** ** * * **** *** *
* * *** ** ** ** ** * * *** * ** 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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AD 20161027 期中考 9
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15445 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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18k
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ID: 15441 -
Available when:
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Due to:
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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asked
Oct 27, 2016
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2016-1 程式設計(一)AD
by
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(
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ID: 15439 -
Available when:
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15421 -
Available when:
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2016-10-27 21:00:00
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