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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * * * ** * x=0,i=0;
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* *** * * * * *** * ** ** * ** * **** ** ** *** **
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* ** *** * * * ** * * * * * 0;
*** *** * * ** ** ** * * *
}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
*** * * * ** * ** * * * ** * * * ** *** * * ** ** *
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include *** * * * *
#include * * * * * * *
int main()
{
**** ** * * * num;
* * * * ***** * * * **** * **** &num);
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** * * * ** * * **** * ** * num+1);
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** * ** *** *** * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
**** ** ** * ** * * ** ** * i=0,
* ** * * * * ** * **** * ** * ** * * * * *
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* *** * * ** *** ** ******* *** * = i*5/100;
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* * * * * * * ** = ((i-520000)*12/100)+(520000*5/100);
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** ** *** * * * ** * ** * ** ** *** ** * * ** * *
*** ** ** * ** * * *** * ** 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include ** * * ** *
** ** * * * ** * *
int main(int argc, char *argv[])
{
* * * * *** * * ** ** * ** * i,j,n;
* ** ** * **** * * * *** k;
** * * * ** *** * * * ** * ** **** * ** **
** * * *** * * *
** ** * * * * ** **** * * 520000)
** * * * * ** *** * * **** ** * * * * * * ** * *** ** * * * * * * = n*0.05;
** * * * * * * * * ** *** if(n * ** * * 1170000)
* * * * * * * * ** * * * * * * ** ** * ** * ** = (n - 520000) *0.12 + 26000;
** ** * *** * * *** * *** * if(n * ** 2350000)
** ** ** ** *** **** * * *** * ** **** * * * * * = (n - 1170000) *0.2 + 26000 + 78000;
* ** ** * * * * if(n * * 4400000)
** * * * ** ***** * * * * *** ** * ** * *** ** ** = (n - ** * * *0.3 + 26000 + 78000 + 236000;
* * * * *** * *** * *** * * if(n ** * * *
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* * *** * ** * * ** * * * *
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**** * * * * * ** * ** * * * ** * * * * * *
* * **** * * * * * * * * * * * *** *
* * ** * * * * ** * ** * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content!* * * * *** *** * ** **
int main()
{
* ** ** *** ** * * * A,B,C,D,E,F;
* * ** * * ** * * * * * * * *
* *** (A<=520000)
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* * * * * * * * if (A<=4400000)
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* ** * * * * ** if (A<=10000000)
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* ** * ** * * * ***
** * **** * * ** ** ****** ** * * ** * * * ** * ** *** ** * **** **
** ** * * **** ** ** * * ** ** * * * * * *
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include ** * ** * * * *
#include *** *** * ** * *
int main()
{
** ** ** * * * * * num;
** * *** * * *** ** * * * * * ** &num);
* * * *** * *
* * * * * * * * * * >= 10000001)
* *** * *** * * ****
* * * * ** * * * * = *** ** * ** * 0.45;
* * * ** * ****
* ** * * * ** if (num >= 4400001)
** * * * ** *
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* ** * **** *
* **** ** *** ** ** ** ** * * if (num >= 2350001)
* * * * ** *
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* * * **
* * ** ** * * * * ** * if (num >= 1170001)
***** * * * * * * ****
*** * * *** ** * * * ** ** * = **** * * * * * ** * *0.2;
* * * * ** * **
* * * * * * * ** if (num >= 520001)
** ** ** * * * *
* * * **** ** ** * = ** ** * ** * * * * * *0.12;
* * * * ** ** * * ** *
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* * * * ** ** * * * ** * *
* * * * ** * ** * * * * * * * ** * * num);
* *** * * * * * ** * * *** *
* * ** *** * * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content! * ** *
int main()
{
* * ** ** * A,B,C,D,E,F;
** * *** ** * ** *** *** ** *
if (A<=520000)
******* ** * * *
* ** * ** if (A<=1170000)
* * * **** * ******** ** * ** * **
* ** * * * if (A<=2350000)
* * ** * ** * ** * * * ** ** * *****
* * * * * if (A<=4400000)
** * * * * ** * ** * * * ** ** * * * * * * * * **
**** * if (A<=10000000)
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** ** * * * *
* *** * * * ** * * ** ** * ** * * * * * ** * * * * ** ** * * *** *** *
* * ** * *** * ** * * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * * *** * ** *
int main()
{
* * * ** * ** * * ** i;
** ** * *** * * ** a;
* * * * * **** * * * * * * * * ***
*** * *** **
** * ** * *** * * **
* * ** ** * ** * * * *** *
* * ** * ** *** ** * * * * * ** ** * *
* * * * * ** ** *
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{
* ** * ** * *** * ** * * *
** * * * ** * * * ** * * ** * *
** ** *
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** * *** * *** * * ** ** * * * *** *** * ** *** *
* * ** * * ***** ** *** * * * * *
* * **** * * * * * *
*** *** * * * * if(i<=4400000)
{
* * * * * ** * * * * * ** * * * * * 470000;
* * ** ** * * * * * * * * * * * ** **
}
** * ** * * * * * * if(i<=10000000)
* * *** * ** ** * *
* * * ** ** *** * * * ***** ** ** * * *
**** * ** * * ** * * ** * * * * * * * * * * *
* * * * * ** * ** *
* *** * * *
{
* * * * * * **** * ** ** * *** * *
* * * * * **** *** ** * * * * ** * * * ** **
}
* ** ** * * ** * * *** 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* ** ** * * * *** * * ** * ** * * * ** *** * * * * * * **
** * ** *** * * ** ** **** * * * *** *
* * * * ** * * * ** ** * *** *
* * * ** * * * ** * * * if(in<1170000)
** * ** ** ** * ** ** * *** * * * * *
** * * * ** * ** * * * if(in<2350000)
** * * *** * * * * ** * ** * ** * * * * *
* *** ** **** * ** ** * ** if(in<4400000)
* * * ** * *** ** ** * ******** * * ** ** * * * *** * * ***** *
* ** ** * ** * * * * if(in<10000000)
* * **** * * ** * * * * * * ** ** ** * * **** **** * * ** * * * ** *
*** * * * * * *** * * **** *
* ** * * ***** * *** * * *** * * *** * **** ** * * *** ** * *** * * * * * * * ******* *
* * * * * *** * *** *** * ** * * ***** ** *
** * * * ** * * ** *** *** ***** *** * ** *
** * * * ** ** * ** ** * 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
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2016-1 程式設計(一)AD
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ID: 15445 -
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[Exercise]
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AD 20161027 期中考 5
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