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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * ** ** *** * *** * x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
***** * * ** * ** * ** * * * ** * * * ** ** ** *
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include * * * *
#include * * * * *****
int main()
{
* *** * * * num;
* ** * * * ** * * * * ** * * &num);
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* * ** *** * * * * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
**** ** **** * * * * ** * * * * i=0,
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** * ***** * * ***** * ** ** * * * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include * * ** * * * ** *
*** ** * * ** * * * * *
int main(int argc, char *argv[])
{
** * ** * *** * ** * * ** * i,j,n;
* * * * *** * * * ** * k;
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* * *** * * * ** ** ** * *** * * *** ** * 520000)
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* * * ** * * * * * ** if(n * * 1170000)
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* ** * * * * *** * ***** * ** *** if(n *** 2350000)
* * * * * ** * ** * * ** * * * * **** * * * * = (n - 1170000) *0.2 + 26000 + 78000;
**** ** * ** * ** * ** if(n ** 4400000)
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* * * ** * ** *
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* ** * * * * * *** *** * ** 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! ** * ** ** *** ***
int main()
{
* * * ** ** * A,B,C,D,E,F;
*** * ** *** * * * * * * * * * ** *
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* * ** ** * * * *** ** **
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * *** **
#include * * * ** * *
int main()
{
* * * * * * *** * num;
** * * * ** ** * * ** *** * * * &num);
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** * *** * ** * * *
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* *** * * *
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** **** * * * * * ***** * *** ** * **
* * ** * * * * * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content! * ** * **** ** * ** *
int main()
{
* * * * ** A,B,C,D,E,F;
* * ** * *** ** ** ** * * *
if (A<=520000)
** * ** * ** * * ***
* * * * * if (A<=1170000)
* * **** * * **** * ***** * * ** *
** * * ** * if (A<=2350000)
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* * ** * * * * if (A<=4400000)
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* * * * * * * ** ** if (A<=10000000)
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* * *** ** * * *** ** *** ***** * ** ** *** * * * * * * * ** * * * * * * ***
*** ** ** * * * * * * * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include<stdio.h>
* * ** * * * * *
int main()
{
**** * * ** * *** i;
** ** *** * * a;
* * * ** * ** ** * **** ** * ** * * *
* * * * ***** * ** * * * ** **
** * * * * ***
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{
** * * * *** * ** * *** * * * * ** *
* * * ** * ** * * * * * *** ** * * ** * **
* * ** * * * * * *
** * * * * *** * if(i<=2350000)
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** ** ** * * * * * **** ** ** *
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** * * * ** * ** * * * * if(i<=4400000)
{
*** * * * * **** * *** * ** * 470000;
* ** * * * * * * ** ******* * ** * * *
}
*** * * * * * * * * * if(i<=10000000)
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* * *** * ** **** *** *
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{
* * *** * ** * * * * * * * * * * **
* * ** ** ** * * * * *** *
}
* * * * ** * ** *** ** * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
** * ** * * * * * * ** ** * * ** * ** * * * * * * *
** *** ** ** * * * * * * * *
**** ** * * ** ** * * ** **** **
** * * ** * ** * ** ** ** if(in<1170000)
* * * * * ** ** * * ** * * ** * **** * ***
* * *** * * **** *** * * if(in<2350000)
* * * * * * * * * ** * ** * ** * * **** * * *** *
** *** * ** * * * * ***** ** if(in<4400000)
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* * * ** ** *** * * ** * if(in<10000000)
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** * * * * ** ** ** * * *** * *** ** * * * **
* *** ** * * * * * * * * *** * *** * *
* * * * ** * ** * ** *** 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
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Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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AD 20161027 期中考 9
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(
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ID: 15445 -
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AD 20161027 期中考 8
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AD 20161027 期中考 7
[Exercise]
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
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2016-1 程式設計(一)AD
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ID: 15421 -
Available when:
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