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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* *** ** * * * ** * *** ** ** ** * ** *** **** * ** *
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include ** * * * ** *
#include * * ** * * *
int main()
{
* * ** * *** ** num;
** *** ** * * * * * ********* * * * * &num);
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* * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* ** * * **** * * * * ***** * i=0,
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** ** * * ** * * * **** * * * * * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include ** * * *
** *** * *** *
int main(int argc, char *argv[])
{
* * * * * **** *** * i,j,n;
* ** * ** * * * *** * * k;
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** * * * * * * * 520000)
* ** * *** *** * ** ** * * * * * * * * **** * * = n*0.05;
** * * * * * ** *** * *** if(n **** * 1170000)
*** * ** *** * ** ** * ** * * ** * * * * * = (n - 520000) *0.12 + 26000;
* * *** * **** ** * * * ***** if(n * * ** 2350000)
* * * * * * * ** * ** * * * * * ** * * *** *** ** ** = (n - 1170000) *0.2 + 26000 + 78000;
* * **** ** * * * ** *** if(n * * * 4400000)
* *** * * * * * ** *** * * * ** * ** * * * * * * * * = (n - *** *0.3 + 26000 + 78000 + 236000;
* ** * * * * * * * ** * if(n * ** ** * * **
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******* ** * ** ** * * *
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* * * ** * * * * * * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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Hidden content! *** * ** ** * * * *
int main()
{
* ** A,B,C,D,E,F;
** * * ** * * * ** ** * * *** **** * * * *
* * *** ***** (A<=520000)
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* * * * if (A<=1170000)
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** * * * * * * * * ******* * * * **
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * ** * * * ** *
#include * * * *** *
int main()
{
** ** * *** **** num;
* ** * ** * * * ** *** * * &num);
* * **** * ***
* ** ** * *** >= 10000001)
* ** * * * * *
** * *** ** * * * * * * * * = * * * **** * * * 0.45;
* **** * *** * **
* * * ** * * * **** * if (num >= 4400001)
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** * ** * * **
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** * ** **** * * ** *
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* * *** * * *** * ** *
** * * * ** * * * if (num >= 1170001)
** * ** ** * ** * *
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* ** * ** * * ** *
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** ** * * * * **
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*** * * * * * * * * * ** * **** * * num);
* ** **** * * * ** * * * * * ** * ****
** * ** ** * *** * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content! * * * * * ** * ** **
int main()
{
* ***** ** ** * A,B,C,D,E,F;
* * ** *** * * ** ** * * ** * * ** **
if (A<=520000)
* * * ** ** *
***** **** if (A<=1170000)
* * * * * * * * * * **** *
* * * * * * * * if (A<=2350000)
** ** * ** * ** * * * * * * * *** **
*** * * * if (A<=4400000)
* ** ****** * * * * * * * * **** ** * **** * * *
* ** * *** if (A<=10000000)
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** **
** * * * * ** * * * ***** * * *** ** ** * * ** ** * * * * ** * * *
* * ** * * **** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * ** * ** * * * *
int main()
{
* * * * * * * ** i;
** * * * * * * * a;
* * ** ** *** * * ** **** * ** * * **
* * * * **
** **** * ** * * * *
* * * * * **** * * * * * * *
** *** ** * * * *** * ** * * * * * ** *** * ****
* ** * * * * *
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{
* * ** * * * ** ** ** * * *
** * * ** * ** ** * * * * * *
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* * * * ** * ** ** * *
** ** ** **** * ** * * ** * * ** *
* ** ** ** ** ***** * ** * * ** * *** **
* * * * * * **
** * ** * * * * * * * if(i<=4400000)
{
**** * * ** ** ** * *** * ** ** ** ** 470000;
** * * * * * ** ** * * ** * * *
}
* ** * ** * * **** ** if(i<=10000000)
* * ** * ***
* * ** * ** ** * * * * ** * * * * * * * * *
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* * * * *
{
* ** * ** * * ** ** * *** * ** * ** *** * *** *
* * * * * * * **** * * **** * * * ***
}
* ** * * ** ** * ** * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * * * * ** *** * * * * * *
** **** *** * * ** * ** * * * * ** ** *
** ** * * * ** * * ** ** * *
*** * * * * * * * if(in<1170000)
** * * * * * * ** * * ** * * *** *** ** *
* ** * * ** * * * *** * * if(in<2350000)
* ** * * * * * * * * * * * *** * * ** * * * ** * * * * *
* *** * ** ** ** * * * * * ** if(in<4400000)
* * * ***** * * * ** ** * * ** * * * ** ** * * ** **
* * * ** * * * *** * if(in<10000000)
* ** *** * * ** ** * * **** ** **** * * *** * ** * * * * *** * * * ** * *
** *** * * * ** * *
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* * * * ** * * * * **** ** * * **** * * *
** **** ** * ** * * * * ** * * *
* ** * ** * * * * ** * ** * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
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AD 20161027 期中考 9
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ID: 15445 -
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AD 20161027 期中考 8
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AD 20161027 期中考 7
[Exercise]
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