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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** *** *** * * * * * *** *** x=0,i=0;
** * *** ** * *** *** *
*** * ** ** ** * * * * * ** ** * **** * * * *
* ** ** ** ** * * *
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* * * *** * ** ** * ** * *
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** * ** ** *** ** **** * * if(1170001<=x<=2350000)
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* * * * * * * * * **** * * * 0;
* * ** ** * * * *
}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* ** ** * * * ** **** * * * ** * ** ** ** ** * ** *
if(i <= 520000)
* **** * * * ** * * * * * * * * *** ** * ** * * **
* *** ** * * * * * * * * * ** * * ** * * **** *** ******** *
else if(i <= 1170000)
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* ** ** ** * * * ***** ** ** * ** * * * * * * * * * * *
**** * * * ** *** * *** * * ** * *** * * * ** * * * * ***
else if(i <= 2350000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include *** * *** * * *
#include ****** * ***
int main()
{
* ** * * * ***** num;
* * * **** *** **** * ** * * &num);
** *** **** * * *
* * * * ** * ** >= 10000001)
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* *** *** ** * * ** * * * * ** ** = * ** * * ** * 0.45;
* * *** **
* ** ** *** ****** * ** if (num >= 4400001)
* * * * ** *
** * * * * * * * ** * * = * ** * * 0.4;
* * * * * *
** * * * * * *** *** * if (num >= 2350001)
* ** * * **** * * *
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* * * * * * * * * * *
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* * *** * * *
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* * * * * * * * * * if (num >= 520001)
* * * **** * * *
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* * ** * ** * ** * * * *** * num+1);
* * * ** *** ** * * * *** *** * * *
* * * * ** * ** ** * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* **** * * * * * * i=0,
* * * * * ** * * **** *** * * * ********* ** * *** ** *
* ** * ** ** * * * ** * ** * * * * * *** *
*** * * ** * * * * * * * **** ** * * * * ** * * * ***
* * * * * * * * ***** * * ** ** = i*5/100;
* *** ** * * * * * * ** ** * * * * * * * * * * * * ** *
* * ** ** * * * * * = ((i-520000)*12/100)+(520000*5/100);
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*** * * * * *** ** * * ** * * if(i>=10000001)
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* * * ******* * *** ** * **** * * * * * * *
*** *** *** * * *** ** * **** * ** ** ** * * * * **
* * * ** * * * * * ** 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include * * * ***
** * * * *** *
int main(int argc, char *argv[])
{
* * ** *** *** * * * * i,j,n;
* * * * *** ** * * k;
** ** *** * ** * * ** * * * ** *** * ** *
* * * ** ** * *** ** *
* **** ** ** * ** * * * * * * 520000)
* * ** ** * ** ** **** * * * * ** * * * ** ** ** * * * ** * = n*0.05;
** * * * * * * ** * * *** * if(n *** 1170000)
* * * *** **** * ** * * **** * * *** * * * = (n - 520000) *0.12 + 26000;
***** * * * * * * ** * * * if(n ** * 2350000)
* * **** * * * * * * ** ** * * * * * * *** * * * * = (n - 1170000) *0.2 + 26000 + 78000;
* * * * * * * **** * if(n * ** *** 4400000)
* * *** *** * *** ** * * * ** ** * * *** *** * * *** * * ** = (n - * * *0.3 + 26000 + 78000 + 236000;
* **** * * *** * * * ** * * * * if(n *** * * **
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* ** * * * *** * **** * * *
*** * * *** * ** * * ** * * * ** * *** * * * * * * ** = (n - * *0.45 + 26000 + 78000 + 236000 + 615000 * **** *
**** ** * * * * * ** ** * **** * * * * **
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* * * * * ** * ** * * * * * * * * * * * * * * * *
* * ** ** *** * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! ** * *** * * **
int main()
{
* * * *** A,B,C,D,E,F;
* * * ** * ** ** * * ****** ** * *
** * * ** * * * (A<=520000)
** *** * * * ** * *
* * ***** ** * * if (A<=1170000)
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* * * * * * * if (A<=2350000)
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* ** *** * if (A<=10000000)
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* *** * ** * *
**** * * * ** ** * * ** * ** * * * * * * * ** ** *** * *
* * * ** ** * * * * * ** *** *
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include * * * * * ***
#include *** * ** * * *
int main()
{
* ** * * * * num;
* * * ** ** * * * * * * * ** ** * * &num);
* ** ** * ** * ** * *
* * *** * * * * * * * * * ** >= 10000001)
* *** * * * * *
** * * * * * * * * * * * * = ****** * * * * 0.45;
* * ** * ** * * ** * *
** * *** * ***** ** * if (num >= 4400001)
* * ** *** **
* * ** * * ** *** *** ** * ** = ** * * * * *** * * * 0.4;
** ** * ** * * *
** * * * * * ** * * * ** * if (num >= 2350001)
** * * ** * ** * *
*** ** * * * ** * ** *** * * = * * ** ** *** * *0.3;
* * ** * * * *
**** ** * * * *** * ** if (num >= 1170001)
** * * * * * * * **
** * *** * * ** **** * ** * ** = **** ** * *** *** * *0.2;
* * * ** * * * *
**** *** * * * if (num >= 520001)
* * *** * * * *
* * ** * * * * * * ** * * * = * *** * ** * *0.12;
** * * * ** * **
* ** *** * * ** * * ** if(num >= 0)
** ** *
** ** ** *** * * = *** ** * ** * * *0.05;
* ** ** ** *
* * ** ** * * ** * ** * ** * ****** *
* ** ** ** * * * *
** * * * * * * * * ** ** * num);
** * * * * * * * * * * *
* * * ** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! * * *** * * * *
int main()
{
* * * **** * * * A,B,C,D,E,F;
* * * * * *** * ** ** ** ** ** *
if (A<=520000)
* * ** ** *
* ** *** * * * if (A<=1170000)
*** * * * * *** * * * ** ** * **** * **
* * * if (A<=2350000)
* ** ** *** * * * * * * ** * * * * ***
* * * ** * ** if (A<=4400000)
* * ** * * ** *** * * * * ** ** * * *** * * ** **
* * * *** if (A<=10000000)
* * **** * ** ** *** ** * * ** ** * ** * ** * * * * * ** * *** *
** * * ** * ** * **
* * * *** * * ** ** * ** * * * * * * * * * * ** * * * ** * ** * * * * ****
* ** * * ** * * * **** * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
** * *** * * * * *
int main()
{
* ** *** * * * *** ** * i;
** * * ** * * ** ** **** a;
* ** * * * * * *** * ****** * ** *
* * * * * *** **** * ** * ***** *
** * * ** * * * *
* * * * * ** *** ** * *
* * * ** *** * **** * * * * ** ** * * ***** * *
* * *** ** ** * * *
* ** * * * * ** * * * if(i<=1170000)
{
* * * * ** * * * * ** *** ** * ** *
* *** ** * * * ** * ** * * * * * * * *** * *
*** * *** * * * * **
* * * * if(i<=2350000)
*** *** *** *** * * *
* * * * * ** *** * * ** * * ** * * * *
* * * * * * * * *** * * * * ** *** * * * ** * *
* * * * * **** *
*** ** *** * * ** * ** if(i<=4400000)
{
*** * * * ** * * ** * * * * 470000;
*** **** ** * ** * ***** * * * * * *** ** * * * *
}
* ** * * * * ** ** if(i<=10000000)
* * ** *** * * *
*** ** ** * ** ** ** ** * **
** * * ** * * * * * ** * * *** ** *
*** * * * * * **
* * * * *** * * ** *
{
* * * * * *** ** * * * ** ** * * *
**** ** ** * ** * *** * ** * * * **** * ***** * *
}
* * * * * ** * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * **** * * * * * * *** * ** * * * * * * **
* * * * * *** * * ** * * ** *
** * * * ** *** * ** * * *
** * * * *** * * * * ** **** * ** if(in<1170000)
** * * * * * * * ** * * * *** * * ** * *
** * ** **** * * ** ***** * * * if(in<2350000)
* * ** * *** * * ** * * * * * * * *** ** *** * ** **
* **** ***** * * ** * * ** if(in<4400000)
** * ** ** * * * * * * * * ** ** * * * * ** * ** *** * * *
** ** * * * * ** **** if(in<10000000)
** *** * * * *** * * ** * * * ** *** * **** * * * *** * * * * * ** * * *
** * ** ** * * ** * * **
* * * * * ** ** * * * * * * * * * * * ** * * * * ** * * * * * * * ***
** * *** * * * * * ***** * **
* ** ** * * * * * ** * ** ** * ** * * *
* ** * ** ** * ** ** * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
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33
answers
AD 20161027 期中考 9
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15445 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
3.9k
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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asked
Oct 27, 2016
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2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15441 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
|
2k
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73
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
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ID: 15439 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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6.9k
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AD 20161027 期中考 5
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
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2016-1 程式設計(一)AD
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(
18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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