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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ** * * * ** x=0,i=0;
** * * ***** ** * * * **
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* * * * * * * * ** * * ** * 0;
** ** ** * * * ** *
}
answered
Oct 27, 2016
by
410523005
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122
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* ***** * * * * * * ** ** * * ** * * * **
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include ** ** * * *
#include * * * * *
int main()
{
* * ** * * num;
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}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* ** * * * *** * * ** ** * i=0,
** * *** * * * * ** * * * * * * * ** * * *
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** * *** ** * ** * ** ** ** 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include * * * *** * *
** ** *** * * ** *
int main(int argc, char *argv[])
{
* ** ** * * * * * * * * * i,j,n;
** ** * * * * * ** * * * * k;
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* ** *** * * * ** * * ** ** 520000)
** ** *** * ** ** * * * **** ***** ** * * * * ** = n*0.05;
* * ** * * * * *** * ** * if(n ** 1170000)
* * ******* ** * ** * * * * * * * *** * ***** * * * * = (n - 520000) *0.12 + 26000;
* * * * ** ** * * * * if(n 2350000)
* * * * ***** * * * * * ** * * * * = (n - 1170000) *0.2 + 26000 + 78000;
*** * * * * * * * * if(n ** ** 4400000)
* * * * *** *** ** * * ** * * * * * * * * **** * * = (n - * ** *0.3 + 26000 + 78000 + 236000;
* * * *** * * ** * **** * if(n * * ** * *
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* *** ** *** * ** **
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*** ** * ** * * * * *** ** * * * * * * * ** * * * * *
* * * ** * * * * * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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-216
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Hidden content! * ** *
int main()
{
* * *** * A,B,C,D,E,F;
* * * * * * * * ** * * *** * *** ** *
** * (A<=520000)
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** * * * ***
** * * * * * * *** * **** * ** * * ** ** * * ** ** * * ** *
* * * ** * * * *** * *
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include * ** * * **
#include ** ** *** * ** **
int main()
{
* * ** * ** * ** *** num;
* * ** *** *** * ** * *** * * * &num);
** ** * *** *
* * ** *** * ** * * **** * ** >= 10000001)
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* * ** * ** *** * * * ** * ** = * *** * ** ** ** * * 0.45;
* * * * * ** * *
*** * * * *** * *** * * if (num >= 4400001)
* * * * * ** * *
* ** ** * ** * * * * * ** = ** * * * * ** * 0.4;
* * * *** * * * *
** * ** * * * * *** * if (num >= 2350001)
* * ** * ** *
** ** * * *** * ** * ** * * * ** * = * ** * ** ** *0.3;
* *** *** ** * *
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** * * ** * * **
* * ** * *** ***** * * * * * * = * * * * ** * * * *0.2;
* ** * *** * * **
** * ** *** * **** *** if (num >= 520001)
* * * * * ** * ***
* * * * * ** * * * * * ** * * * = *** * ** * * *0.12;
*** * ** * * * ****
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* ** * **** * * * **
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* * * * * * * ** *
* * **** * *** * * ** * * *** * * * * * * num);
** *** * * * ** * *** * * * * * *
* ** * * * * * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! ** * * * * ***
int main()
{
** ** * * * * * A,B,C,D,E,F;
** * * * * * ** * *** * *** * * * * * *** *
if (A<=520000)
* * * *****
* * * * * * * * if (A<=1170000)
* * * * * * * * * *** * * * ** * *
* ** * ** *** if (A<=2350000)
* * * * * * * * * * ** * **
*** * * ** ** if (A<=4400000)
* * * * * ** ** * * * * **** * ** * * ** *
*** ** * * ** if (A<=10000000)
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* * * *** **
* * * * * ** * * * * ** ****** ** * * ** * * * ** *** ** *** ** *
** ** * * * *** * ** * ** * ***
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
**** ** *** * ** *** * *
int main()
{
* * * * ** * ** * ** i;
** * * ** * *** * ** ** * a;
* * * * * * * * * * * * * ****** * ** * **
* * * * * * * *** * *** * *
* * * *** * * * ** *
* * *** ** * * * * * ** * * * *
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** * * ** ***
**** * * * * * * * if(i<=1170000)
{
* * * ** * * * * * * * * * ** * * * * ** *
* ** ** * * *** * * *** ** *
* * * * * *** ** *****
*** * *** * ** ** * ** ** if(i<=2350000)
*** * * * ** * ** *
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* * * * **** * * ** * *** * * ***** * * ** *
* * * * * * ** ** * *
*** * *** *** * ** ** * if(i<=4400000)
{
* *** ** * ** *** * *** ** * *** 470000;
** * * * ** ** * * * * *
}
* ** ** * ** * *** ** * if(i<=10000000)
** * *** * * * ** *** *
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* * ** * * * * *
{
* ** ** * ** ** * * ** * ** * * * ** *
* * ** ** * * * **** ** * ** ** ** * **** **
}
** * * * ** *** * * * ** * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
** * ** * * * * * *** * * * * * * * *
* * * ** * ** * * * * * * * *** * ** *
* * * * * ** ** * * * * ** *
* ** * * * *** * ** * *** if(in<1170000)
** * * ** ** * * ** ** * ** * * *
* * * * ** ** ** **** * * *** if(in<2350000)
*** * * ** ***** ** * * ** *** * * * * * * * * **** *
* * * * * ** * *** * if(in<4400000)
** * * * * * ** * ** * * ** * * ** * ** * *** * *** * * *
* *** * * * ** * * ** * ** * if(in<10000000)
* ** * * * * *** * ** * * * * * ** ** * * * * * * ** ****** ** * *
* * * *** ** * ** * * *** * *
** *** * ** *** ** * * * ** * * * *** * *** * * * ** *** * ***** * ** * * * * * * ** *** ***
* ** * ** * * * * * * **** * ** * *** * * ** * * *
** * * * ** ** ** *** * * ** * * *** * *** * *
** * * * ** * ** * * * * ** 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
-
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2016-10-27 21:00:00
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33
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AD 20161027 期中考 9
[Exercise]
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in
2016-1 程式設計(一)AD
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(
18k
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ID: 15445 -
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AD 20161027 期中考 8
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73
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AD 20161027 期中考 7
[Exercise]
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2016-1 程式設計(一)AD
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(
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ID: 15439 -
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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