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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * ** * * ** ** * * * * * * * x=0,i=0;
* **** * * * *** * * * * *
* ** * * * * ** * * * ** * * * * *** ** *
* * **** * * ** **** *
** * * * * * * * ** * (x<=520000)
** ** ** *** * ** * * * * **
*** **** * *** * * * * * *
* ** * * ** ** * * * *
* * * ** * *** * ** * ** * if(520001<=x<=1170000)
*** * * *
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***** * * * *** * * * *****
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* * * *** ** * ** * * * * ** * ** if(2350001<=x<=4400000)
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* * * ** * * ** * * *
** * * *** * * ****** * *** * * ** * **
* ****** * * *** * 0;
** * *** ** * ** * ** *
}
answered
Oct 27, 2016
by
410523005
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122
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * * * * * ** * * *** * * * * * * * ** ** ***** *
if(i <= 520000)
* * * *** *** * ** * * ** ** * * * ** * * * * * *** *
** * * ** * * * * *** ** * * * * ** * ** **** ** *** * * * * ** *
else if(i <= 1170000)
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* * * * * * **** ** * ** * * * ** *** ** * * * * * * *** *
else if(i <= 2350000)
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** * ** * * * * * * ** * * * ** * * * * * * ** * *** * * * * * ** * * ** * ** * * * * *
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include * * * *
#include * ** * * *
int main()
{
* ** * * ** **** * * num;
* * ** ***** * * ** * ** ** * ** ** ** * &num);
* ****** ** * *** ***
* ** * ** * * ** >= 10000001)
* * ** ** * * * ** **
* * *** * * *** * * ** * * * = ** * * * * 0.45;
*** * * * **
*** * * * * * * if (num >= 4400001)
* * ** * ** ** **
* * **** *** **** ** ** *** * * ** * * = ** ** * ** ** * * 0.4;
* * * * * * *
* * * * * * ** * if (num >= 2350001)
* ** * * * * * *
* *** * * * ** * * * ****** * * = * * * * *0.3;
* * * * * *** * * *** *
* * *** *** ** * * if (num >= 1170001)
* * ** * * ** * *
* * * ** * ** ** * ** * ** * *** = * * * * ** *0.2;
* * *** * * * ** *
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* ** * ** ** * * ** *
* * * * * * ** * * * * * * * * * num+1);
** * * ** * **** * * ** * * *
* * * * * * *** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * * ** * ** *** * * * * * i=0,
* * * ** ** ** *** ** ** * *** *** ** * ******** ** *
** * * * * * * * * ** * * * * * * * * *
*** * * * *** ** * * * * ** * ** * ** **
** ** *** * * *** * = i*5/100;
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* * * ** ** ** ** = ((i-520000)*12/100)+(520000*5/100);
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** ** * ** * ** *** * if(i>=10000001)
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* ** * ***** ** * * ** * * * **
** ** * * ** * * **** * * * * * * *** * * * ***
* * * * ** ** * * * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include * * **** *
* ** * * * * *
int main(int argc, char *argv[])
{
*** * ** * * * * * * * i,j,n;
* *** ** * * * * * * ** * k;
** * * * * * * * ** ** *** * **** ** * * *** *
*** ** *** * **** * *
* * * * * ** * ** * *** ** ** 520000)
* * ** * * *** *** * * * **** *** * ** * * * *** * ** = n*0.05;
* * * * ** * * * ** * * ** *** * if(n * 1170000)
****** * * * * * * * * * * * ** * ** ** * *** * = (n - 520000) *0.12 + 26000;
* * * ** ** * * * ** if(n * **** 2350000)
* ** * * * * **** *** * *** * * * ** * * * ** = (n - 1170000) *0.2 + 26000 + 78000;
* * * * * * ** ** * * * if(n * 4400000)
** * * * * ** * * * ** * * ** ** * ** * * * * * * * = (n - ** *0.3 + 26000 + 78000 + 236000;
* *** * * * * ** ** * * * * * * if(n * ** * * **
* * ** * * * *** * ** * ** *** * ** * * ** ** * * = (n - ** **** *0.4 + 26000 + 78000 + 236000 + 615000;
*** *** ** *** * * * * ** * **
* * * * * * ** * * * * * * ** * * * * * = (n - ** * *0.45 + 26000 + 78000 + 236000 + 615000 * * * *
* *** * * * * * * * **** * * * * *** * *
* * *** * ** * * * * *** ** *** * * * *
** * * * * * * * * * * ** * ** * * * * * * * ** **
* ** * * * *** * *** * ** * **** * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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-216
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Hidden content! * * * * * * * *
int main()
{
* ** * * ** ** A,B,C,D,E,F;
*** * ** * * ** * * * * *** * * *
** * (A<=520000)
**** *** * * * ** * *
* ** ** * ** if (A<=1170000)
* * * * * ** * * * * ** ** *
** * ** ** ** * if (A<=2350000)
* * * * * * * * * * * ** * * *** * *
* ** * * * if (A<=4400000)
* * * * ** ** * * ** * * * * * * * * * * * *
* * * * ** * if (A<=10000000)
* ** ** * * ***** ** * ** * * * * ** * * ** ** ** * *
* * * **
* ** * * * ** ** ** * * * * *** ** * * ** * * * * ** ** **
****** * * * * ** ** * * * ** ** *
}
answered
Oct 27, 2016
by
chen
(
-102
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Hidden content!#include * * ** * *** *
#include * *** ** *** *
int main()
{
* * ** * * *** * ** **** num;
** * * *** * * * *** *** * ** *** * * &num);
* * *** * * * *
** * ** * * *** **** * * >= 10000001)
* * *** *** * * *
* * * * ** * * ** * * * ** = ** ** * * ** **** * 0.45;
* * * *
* * * ** * * *** * ** * * * if (num >= 4400001)
** * * ** * **
* * *** * * * ** * * * ** = * * * * * * 0.4;
* * ** * ** * * * *
** * * * * * * * ** ** if (num >= 2350001)
* * ** * * ** *
*** ** ** * * * * * * **** * * *** = ** ** ** * * * *0.3;
* * * * * * **
* * * * * * * *** * if (num >= 1170001)
* * * * ** * * * *
** *** ** **** * ** * * * * = * * ** * *0.2;
** * * **
* * * * * ** * * ** * if (num >= 520001)
* * * *** * *
* **** * ** * ** * * * * * * **** * = ** * ** ** ** *0.12;
* * * * * * **
*** ** ** * * * *** if(num >= 0)
* * ** *** *
** * * ** * * *** = * ** *0.05;
* * **** * * * *** *
* ** * ** * * * * * * * ** ** *
** * * *** * ** ** ** *
*** * *** * * * * * * * *** **** num);
* * * ** ** * * *** *** * ** * * *
*** ** * * * * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content!* * * ** * *
int main()
{
* * ** * * **** * A,B,C,D,E,F;
* * * * ** * * *** *** ** * * * * * *
if (A<=520000)
* * * * ** * **
* * ** * * if (A<=1170000)
* *** * * * * * * * * ** *
* * * * ** * ** if (A<=2350000)
* * * *** ** ** * *** * ** ** * * ** ***
** ** ** * * if (A<=4400000)
* * * * ** * ** ** * *** * * ** *** * ** *** * ** * * **
* ** ** ** * * * if (A<=10000000)
* *** * *** * ** * * * ** ** * * * * ** * * * * **** ** *** * * *
* * ** ** *
* ** * **** * *** * * * * * *** * * * * ** * ** ** * ** * * ** * * ** ** * *
* * * * * ** * *** * * * ****
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * *** *** *** *
int main()
{
*** * * * * ** i;
* ** * * * ** * * * ****** a;
** * *** * * *** * * * ** *** * * * * * * ** * * ***
** * * * * * * * ** * *** * *
* * ** * * * * **
* * * ** * ** * * ** ** * * **
*** * * ** ** * * ** * * * * * *** *
*** * ** **
* * * *** * ** * if(i<=1170000)
{
** * ** ** * * * * * * * * ** * * *
* ** ***** * ** * ** * * *** ** * *** * * * *** * **
* * * *** ** **** ** *
* ** ** * * ** * * *** if(i<=2350000)
**** * * * * **
* * * * * * *** * * *** ** * * *
* * * * * * ** * * * * * * * ***
** *** * * * * * * ***
** * ** * if(i<=4400000)
{
* ** * ***** * * * * * 470000;
* ** * * ** * ** * * * ** * * ** ** *
}
** ** * ** **** if(i<=10000000)
* * ** * * * *** *
* ** * * * * * * ** * ** * * * * *
* *** ** ***** * ** * * * * * * * * ** ***
* *** * ** * * *
* * * **** * * * **
{
** * * *** * *** * *** * * * ** ** *
* * * ** ** * * * ** ** ** * * * ** * *
}
* * * ** * ** ** * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
*** * ***** * * *** * * * * ** ** * * ** * ***
* ** * * * *** ** * ** **** * ** *
* * * * * * * ** * * * **
** * **** ** *** ***** * if(in<1170000)
* **** * * ** *** * * ** * *** ** *
* ** * * * * * * ** * * if(in<2350000)
* ** * * ** * ** ** * * * ** ** * ** * * * * * *** *
* * * *** * * * ** * ** * *** ** if(in<4400000)
*** * * * * * * ** * * * ** ** * ** ** * ***** ** * ** ** * * *
** * * * * **** if(in<10000000)
* * ** ** * * * * * * ***** *** * * * * ** ** * * *** * * * * *
* * * * * * * * ** * ** * ** *
** ** *** ** * * *** * * * ** * * * * * * ** * * ** * * * * ** * *** * * ** * * ** * **
* * ***** * * * * ** ** * ** * * * * * **
** * * * ** * * * * *** * ** * * * * * * ** * **
* ** * *** ** * * * * ** ** 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
|
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33
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AD 20161027 期中考 9
[Exercise]
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Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15445 -
Available when:
2016-10-27 18:30:00
-
Due to:
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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(
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ID: 15441 -
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73
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
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ID: 15439 -
Available when:
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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