0 like 0 dislike
2k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** ** * * * * * ** ** * * ** %s",&s1,&s2);
***** ************ * ***** ** *** **** *

///get space
* * * *** *** * *** *** ***** * * ****
* *** ** ** ** * ** ** * * ****** * * * **** ** ** * *** '){space=i;}
    }

///get s1
* * *** **** * ** * ***** * *** ';i++){
* * ** *** * ** * **** * * ** * ** ** * ** *
    }

**** ** *** * * ** ********* * ***
///reverse input
** ** ****** ** ** * * * ** **** * *
** ** ** * ** * *** * * *** * *** * ****** * *
* ** **** ** ** *** ** * * *** ** *** ** * * * ** *** ***** **** *
**** * * **** * *** *** * * *** * ** *** ** ***
    }

///get reversed s2
* * * * * * * ** * *** * ** * ** ';i++){
* * ** ** * * * * ** ** **** * * * * * * *
    }

///reverse s1

***** * * *** * ***** * * * ** * * * ** *
* ***** * * ***** ******** ** * * * *

** * * * ** *** ** * * * **** ** * * *** ** * * * *
*** ***** *** * ** ** * * * * ** *** ** ** ******
    }

///sum s1 and s2
* * ******** *** ** ***
** *** * * * * * * **** *
*** *** *** * **** *** * ** ** ** **** *** * * ** * **** * ***
* * ** **** * * ** ** ***** ** *** * * ** ** * * ** ** ** ** ****
* * * * ** **** ** ** * * * * * * ** * * **
* * * * **** ** * * *** * * ** *** * ** *
*** ** * * ** ** * *** **** *** *

    }

* ***** ** ** * ** ** *** * ** * * rev:%s\n",input);
* *** * *** * ** ** * ** ** ** * rev:%s\n",s1);
* ** * *** * * ** ** * * * * **** * * rev:%s\n",s2);
* ** * ** * ** *** * ** ** * ** *** **** * * ** * * * * ***** ** *** *

///reverse output
*** * *** ********* ** * ** * * **
*** * * * ** ** * ** * ** *** *** * ** * **

* ** *** * * *** * **** ** ** ** ** **** *** ****** ***** *
* * ** * ***** * * * * * * ** * ** * ** * * ** ** **
    }

///print
** ********* ** **** ***** **** ** * *
*** * *** * ** *** ***** * **** * * * ** **** ** ** * * ***** ** ** ***** **
* ** ** * * * ******* * **** * * * ** * *** ** ** * ** ** ****
** * ** * * * ** ***** ** * *** * * **** *** ** * * ** * ******* ** *** *** * ** ***** * **** * *** *
**** ***** ** * * * * * ** * ***** * * ** * * ** ** * **** * * * * * **** *
**** ** * ******** * * ** * ** * ** ** **** * ** **** * *

** *** ***** * * ** * *** * *** ** * * * *

    }
* **** * *** *** ** * * * * ** ******* *
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
** *** * * ** ** string1[50];
* **** * * *** *** string2[50];

** * ** * ***** * * *** ** *** ** string1);
*** * **** * * * * * * *** *** ** * string2);
* * * * ** * ** * * * arr[51]={0},i;

* * *** **** ** ** *** ** * * i<strlen(string1); i++)
** ** ** ** *** *** * *
*** *** ** * **** ** ** ** ** * ** * ** ** **** * * += string1[strlen(string1) - 1 - i] - 48;
    }

* ** * **** ** *** * ** i<strlen(string2); i++)
****** * *** * * ** *
* * * * * ** * **** ****** * ***** * += string2[strlen(string2) - 1 - i] - 48;
* * ***** *** *

* * * ** * * * *** * ***** i<50; i++)
** ** *** ** * ** * ****
******** ** *** * *** *** * ***** * *** ***** * **** > 9)
** * * ** ** * * *********** * **
**** ** **** * * * *** *** *** ** *** * * * ** * ** ******* *** -= 10;
** * ** ***** *** ** ** * **** * * * * * * **** ** ** **** * * * *** * *
* ** * * *** ** *** * *** * *** * *****
** * * * * * * *** * * ***

* * * ***** * ** *** i>=0; i--)
**** * * * * *
* ** **** * * ** *** ** * * **** ** ** * != 0)
* ** ****** ** ** ** **** ** * * *** * * * * * *** * ***
*** ** * * ** * * * ** * *

* ** * * ** * ******* * ** * * * i--)
* **** * * * * *** *** *** ****** *** * * * *** *** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
** * ** ** *** ** ***
printf("enter input 2: ");
** * * ** * **** ***
for(l1=s1[l1]!='\0')
* * *** **** ***
for(l2=s2[l2]!='\0')
* * *** **** ** *** **** * *
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
* ** ** * * * *
{
* * * *** * * * *
* *** *** * * ***
* * ** *** ***** * * ** * ** *** * * * * *** ** **
* * ***** * ******* ** * ** * * * **** **** * * ** ** * * ** ** ** **** * * ** **
** ** * **** * *** *** * ** * * * ** ** * * * * * * **** * ** *
**** * ** * * * * ** if (j>=0)
** ** * *** ** * * * * * * * ** ** * * ** ** **
* * * * **** ** * **** * *** * ** ** * * * ** * ******** ** ** **** ******** ** ** **
*** * * * * *** *** ** * * * * * ** ** *** * *** *** ** * * * * * * ***
* ** * * * * * * *** *** * ** * *** * * * ** if(carr>0)
* ** ** **** * * ** *** * * * *
*** *** * *** *** ** * * *** *** *** * * *** * * * ");
* * ****** * ** * * *** * ** * ** ** *** * ****
}
for(k--;k>=0;k--)
** ****** * * ***
* * **** ** * * * * ** * ** * *
** * ***** *** ** * * * *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
** **** *** ** * ** **** ** a[50],b[50];
* * *** ** *** c[51]={0};
**** *** * ****** *** * * * * i;
* ** * ** * *** * * * x=0;

**** **** **** * ** * *** ********* ** %s",a,b);

** * ** ** **** ** ******** * * ** *
    {
**** * * * * * * * * * ** * *** ** *** * * * *
    }

** *** * ** *** ** ******* * * ** * ***
*** ** ** * * ******
* * * ** ** ** ** * * * * *** * * * ****** * ** *
** * ** **** ** ** ** *** **


*** * * * **** * * * *** * *
*** ******* * * * * * **
* * * * ** * *** * *** **** **** **** * *** *
* * ** ***** ** ***** ** * *** * * * * * * **
*** * * * * * * * **** ** * * * * * * * * ***** ** **** ** ** ** * *
** ***** * * ** *** ****** ** **** *** * * * * * ** ***** ** ** * * ***
* * * * *** **** *** ** ** ** ** * ****** * **
    }

** **** **** *** * *** ** *** * * * *
*** * * *** * **
* ***** *** * * * * * ****** * * ** * ** ** * != 0)
* * * ** ****** ***** ** * **** * * ** **
*** **** * * * * * ** ****** ***** ** ** * * *** * ** **
*** *** * * *** ******* * * ** ** ** ****** * * ******* *
*** ***** * ** ** ** * ** ** * * ******
    }

*** ******** * *** * * *
    {
* * ** * **** *** *** * ** * *** ** * ** *
    }


* ****** * * **** * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.40
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 1.7k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 3.3k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 10.1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users