0 like 0 dislike
2.6k views

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 43460 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.6k views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
* * ***** * ** * * * ** ** *** %s",&s1,&s2);
* * ****** *** ** * * * **** *

///get space
***** * ** **** * *** *** ** ** ** ** **
* * ** * ** * ** *** *** * ** * *** '){space=i;}
    }

///get s1
** * *** * * ** ***** ** ****** ** ';i++){
** * * ** * * * * * * * ** ** ***** ** *** *** *
    }

*** ** * **** *** * ** * * * * *
///reverse input
* * *** **** *** * ** **** ***** *
* ** ** * * ****** **** ** * *** ** ** ** * * **
* * *** * * * ** ***** ** ** * * * **** ******* * ** * *
** ** * * * *** **** * *** * *** **** * *** * **** ***
    }

///get reversed s2
* * * ** * * ** * ** ** * ** ** ';i++){
* * ** *** ** * *** * * * ** ******
    }

///reverse s1

** * * ***** **** * ** * * * ** ** * ** * *
* * * **** ** * ** **** ** ****** * ***

* **** ** ** * * * ** * ******** * *** ** ** ** ** * ******* ***
** ** *** **** * ** * * * * ** ** ** *** * * *** *
    }

///sum s1 and s2
*** ** *** * ** * * * * * * * * *
*** * * * ** ** * ** ***** ** * **
**** *** * ** * * *** ****** * *** * * * * **** * * ** * * **
******* * **** ** * * * *** ** * * *** ** ** * * * * *
****** *** ** *** * ****** ** ****** ***** * * * *
** * * ** ****** *** ** ** ***** ** ****** ** ****
* ** ** *** * * * ** ** * *** * ***** * *

    }

*** * * ** * ****** ** * * rev:%s\n",input);
* *** * * *** ** *** * * *** rev:%s\n",s1);
* * * *** * ** * ** ** * ** rev:%s\n",s2);
**** *** *** * ** * * **** * * ** *** ***** * ** ** *** * * ** ****

///reverse output
* ** ****** ****** *** * * * * **
* * ** * *** *** *** ********* ** ** ** **

* **** * ** ** ** * *** * * * ** **** * * ** **** *
* ** *** ******* * * * *** * * ** * * * * ** * * * *
    }

///print
** ** ** * * ** * * *** * ****** ** **
* **** * *********** ** * * **** * * * ** * * * * ** * ** *** ******* **
* *** **** * * ** ** ******* ** * * *** ***** **** * * * ** ** **** * **
** ** * * ** *** ** * * *** ** * * * * * * *** * * ** * ****** * * * ***** *** ** *** ** **** ** ** * *
* ** * * **** * * * * ** * * ** * ** ** * *** * ** * * ** * ** *** ** ** * *** ** **
* * ** * ** ** ** * * * **** * * * * **** ** ** **** * **

* * * ** * * *** *** ***** * * ***

    }
** * * * * ** * ** * * ***** ** ***** ** *
    return 0;
}
answered by (-286 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ** * ** * * * * string1[50];
*** * **** ***** *** * **** string2[50];

** ** ***** * ** * * * * * ** * * * * * string1);
* * * * * *** * ** * *** * * * *** string2);
* * * * * * **** * * ** * arr[51]={0},i;

* ***** * ** *** ** * i<strlen(string1); i++)
* ** ** * * **** * *
* * * * *** **** ** * * * ** * * ** += string1[strlen(string1) - 1 - i] - 48;
    }

**** **** ***** ** * * ** * i<strlen(string2); i++)
* *** * * *** * * *
** * *** ** * * * ** * ** * * ****** ** ** *** * += string2[strlen(string2) - 1 - i] - 48;
*** ** *** * **** **

** * *** ** * **** * * **** i<50; i++)
* *** * * * ***** ***
** * * * * ** *** * ** * * * * * ***** * ***** * > 9)
** ** * *** *** *** * ** *** ***** ** *
* **** ** * *** ** *** ** **** * * *** * ** **** ***** ** *** ******* -= 10;
* *** * * ** * ** ** *** * * ** * ** * ** ** * ** **** * *** **
* ** ** **** ** * ** * ***** *** * * *** *
* * * * * * * **

* ** ** * ** * * ** i>=0; i--)
*** * * ** *
*** * * *** * * ****** ** ** ** * ** * *** * ** != 0)
* * * * ** * * * * ** * **** * * * ** ***** ******** ** *
* * ** * *** *** * *

* ** *** * * ** ** **** *** * **** i--)
* *** **** ** * **** ** *** * ** * ** * * * ** * * arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
**** **** * * * *
printf("enter input 2: ");
* * * * ** *****
for(l1=s1[l1]!='\0')
** * * * ****** * ** ***
for(l2=s2[l2]!='\0')
* ** * * * * * ** * *
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
***** *** *** **** ** **
{
* * *** * * ** * * * ** * **
** * * * * ** * ***
* * **** ** * ************** * * * ** * * ** * * *
* * * * * ** * * ** ** * ** * * ***** ** ** * * **** ** * **** ** * ** * ** * *
** * ** ** * *** ** * * * * ** * *** * *** * **** *** * ** ** * * ** **** * *
****** ** ***** ** * ****** if (j>=0)
* * ***** **** ******** ** * * ** * * *** * * **
* * ** *** *** * * **** * *** * * ** * * * ** **** * ** * * * * * *
* ** ** *** ** **** * * * *** * *** * * * ***** * ** ** *** * **** *
**** *** * * ** ** *** * * **** * *** * * ** * if(carr>0)
*** **** ** * ** * ** * ** * * * *** * * * ***
** * ** * *** * * ** * *** ** ** *** ***** ***** * * * ");
* * * ** ** ** * *** * * ** ** **
}
for(k--;k>=0;k--)
* *** * ** * * * **
* ** ** *** ** * * * * ** * ** * * ** ****
* **** ** * **** ***
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
** * ** **** * ** *** a[50],b[50];
* *** * ** ** * * ** c[51]={0};
** * *** * * * ***** i;
*** *** ** * ****** x=0;

* ****** * ** * * * * ***** **** * %s",a,b);

* *** ** * **** ** *** * **** ** ** * *
    {
** * * * * * * ** * * ** *** **** ** * ** *** **** * **
    }

** *** * * * * * ** ** *** * * ** **
* ** *** * * ***** **
* * * ** * ** **** *** *** * *** ** * *** ** * * * * * *
** *** * ** * *** **


**** ** *** **** * ** * **** ****
* **** ******* ** ****** **
* *** ** * * ** *** *** * ** * ***** *** * ** * ** *
* *** * *** * **** * **** * ** * *
*** ** **** * * ***** * * ** ***** ** ***** **** ** * *** * ****
* *** ** ** *** * * * *** ** * *** **** * * * * ** ****** ** ***
* * *** * *** * **** *** * * * *
    }

*** ***** ** **** * **** * * * *
****** * ****** *
* * * * ** * * *** * *** * * * *** ** != 0)
*** ******* ** * * ** * ***** ** * * * * ** * * * * ***
* ** * * ******* *** **** * ****** ** ** **** * * ** **** ** **
** ********* ** ** * * * * * * * * * * ***** ** ** ** * * ** ****
* * *** * * ** ** * ** ** *** * * ** **
    }

* * ** ** **** ** *** **
    {
*** * * ** ** * * * * * ** ** * * **** ***** * **
    }


** * **** **** ** ***** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.204
©2016-2025

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43463 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 4.2k views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43462 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.3k views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43461 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 2.7k views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
ID: 43459 - Available when: 2018-01-20 09:00 - Due to: Unlimited
| 4.4k views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
ID: 42299 - Available when: 2018-01-17 14:00 - Due to: Unlimited
| 13.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users